Getting an error while doing Newtonsoft JSON Deserialize for apostrophe strings in C#
I am getting below exception when I try to execute below snippet code while doing Newtonsoft JSON Deserialize.
Error: After parsing a value an unexpected character was encountered: s. Path 'Name', line 1, position 14.
static void Main(string args)
{
var definition = new { Name = "" };
string json1 = @"{'Name':'Jame's'}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);
Console.WriteLine(customer1.Name);
}
c# visual-studio
asked Nov 27 '18 at 12:02
PanchetiPancheti
1076
add a comment |
I am getting below exception when I try to execute below snippet code while doing Newtonsoft JSON Deserialize.
Error: After parsing a value an unexpected character was encountered: s. Path 'Name', line 1, position 14.
static void Main(string args)
{
var definition = new { Name = "" };
string json1 = @"{'Name':'Jame's'}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);
Console.WriteLine(customer1.Name);
}
c# visual-studio
asked Nov 27 '18 at 12:02
PanchetiPancheti
1076
2
The string is'Jame'. It's followed by some a non-string character,n. You can't have an unescaped single quote inside a single quote string, just as you can't have a double quote inside a double quote string
– Panagiotis Kanavos
Nov 27 '18 at 12:04
add a comment |
I am getting below exception when I try to execute below snippet code while doing Newtonsoft JSON Deserialize.
Error: After parsing a value an unexpected character was encountered: s. Path 'Name', line 1, position 14.
static void Main(string args)
{
var definition = new { Name = "" };
string json1 = @"{'Name':'Jame's'}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);
Console.WriteLine(customer1.Name);
}
c# visual-studio
asked Nov 27 '18 at 12:02
PanchetiPancheti
1076
I am getting below exception when I try to execute below snippet code while doing Newtonsoft JSON Deserialize.
Error: After parsing a value an unexpected character was encountered: s. Path 'Name', line 1, position 14.
static void Main(string args)
{
var definition = new { Name = "" };
string json1 = @"{'Name':'Jame's'}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);
Console.WriteLine(customer1.Name);
}
c# visual-studio
c# visual-studio
asked Nov 27 '18 at 12:02
PanchetiPancheti
1076
asked Nov 27 '18 at 12:02
PanchetiPancheti
1076
asked Nov 27 '18 at 12:02
PanchetiPancheti
1076
asked Nov 27 '18 at 12:02
PanchetiPancheti
1076
asked Nov 27 '18 at 12:02
PanchetiPancheti
1076
1076
2
The string is'Jame'. It's followed by some a non-string character,n. You can't have an unescaped single quote inside a single quote string, just as you can't have a double quote inside a double quote string
– Panagiotis Kanavos
Nov 27 '18 at 12:04
add a comment |
2
The string is'Jame'. It's followed by some a non-string character,n. You can't have an unescaped single quote inside a single quote string, just as you can't have a double quote inside a double quote string
– Panagiotis Kanavos
Nov 27 '18 at 12:04
2
2
The string is
'Jame'. It's followed by some a non-string character, n. You can't have an unescaped single quote inside a single quote string, just as you can't have a double quote inside a double quote string– Panagiotis Kanavos
Nov 27 '18 at 12:04
The string is
'Jame'. It's followed by some a non-string character, n. You can't have an unescaped single quote inside a single quote string, just as you can't have a double quote inside a double quote string– Panagiotis Kanavos
Nov 27 '18 at 12:04
add a comment |
2 Answers
2
active
oldest
votes
That's a single quote, not an apostrophe so it needs to be escaped :
string json1 = @"{'Name':'Jame's'}";
You can't include the string delimiter inside a string without escaping it.
answered Nov 27 '18 at 12:08
Panagiotis KanavosPanagiotis Kanavos
55.7k483112
add a comment |
message:
After parsing a value an unexpected character was encountered: s. Path 'Name', line 1, position 14.
string format is bad :)
change like that
static void Main(string args)
{
var definition = new { Name = "" };
string json1 = "{"Name":"Jame's"}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);
Console.WriteLine(customer1.Name);
}
answered Nov 27 '18 at 12:10
Seungbin YangSeungbin Yang
11
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53499266%2fgetting-an-error-while-doing-newtonsoft-json-deserialize-for-apostrophe-strings%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
That's a single quote, not an apostrophe so it needs to be escaped :
string json1 = @"{'Name':'Jame's'}";
You can't include the string delimiter inside a string without escaping it.
answered Nov 27 '18 at 12:08
Panagiotis KanavosPanagiotis Kanavos
55.7k483112
add a comment |
That's a single quote, not an apostrophe so it needs to be escaped :
string json1 = @"{'Name':'Jame's'}";
You can't include the string delimiter inside a string without escaping it.
answered Nov 27 '18 at 12:08
Panagiotis KanavosPanagiotis Kanavos
55.7k483112
add a comment |
That's a single quote, not an apostrophe so it needs to be escaped :
string json1 = @"{'Name':'Jame's'}";
You can't include the string delimiter inside a string without escaping it.
answered Nov 27 '18 at 12:08
Panagiotis KanavosPanagiotis Kanavos
55.7k483112
That's a single quote, not an apostrophe so it needs to be escaped :
string json1 = @"{'Name':'Jame's'}";
You can't include the string delimiter inside a string without escaping it.
answered Nov 27 '18 at 12:08
Panagiotis KanavosPanagiotis Kanavos
55.7k483112
answered Nov 27 '18 at 12:08
Panagiotis KanavosPanagiotis Kanavos
55.7k483112
answered Nov 27 '18 at 12:08
Panagiotis KanavosPanagiotis Kanavos
55.7k483112
answered Nov 27 '18 at 12:08
Panagiotis KanavosPanagiotis Kanavos
55.7k483112
55.7k483112
add a comment |
add a comment |
message:
After parsing a value an unexpected character was encountered: s. Path 'Name', line 1, position 14.
string format is bad :)
change like that
static void Main(string args)
{
var definition = new { Name = "" };
string json1 = "{"Name":"Jame's"}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);
Console.WriteLine(customer1.Name);
}
answered Nov 27 '18 at 12:10
Seungbin YangSeungbin Yang
11
add a comment |
message:
After parsing a value an unexpected character was encountered: s. Path 'Name', line 1, position 14.
string format is bad :)
change like that
static void Main(string args)
{
var definition = new { Name = "" };
string json1 = "{"Name":"Jame's"}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);
Console.WriteLine(customer1.Name);
}
answered Nov 27 '18 at 12:10
Seungbin YangSeungbin Yang
11
add a comment |
message:
After parsing a value an unexpected character was encountered: s. Path 'Name', line 1, position 14.
string format is bad :)
change like that
static void Main(string args)
{
var definition = new { Name = "" };
string json1 = "{"Name":"Jame's"}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);
Console.WriteLine(customer1.Name);
}
answered Nov 27 '18 at 12:10
Seungbin YangSeungbin Yang
11
message:
After parsing a value an unexpected character was encountered: s. Path 'Name', line 1, position 14.
string format is bad :)
change like that
static void Main(string args)
{
var definition = new { Name = "" };
string json1 = "{"Name":"Jame's"}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);
Console.WriteLine(customer1.Name);
}
answered Nov 27 '18 at 12:10
Seungbin YangSeungbin Yang
11
answered Nov 27 '18 at 12:10
Seungbin YangSeungbin Yang
11
answered Nov 27 '18 at 12:10
Seungbin YangSeungbin Yang
11
answered Nov 27 '18 at 12:10
Seungbin YangSeungbin Yang
11
11
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53499266%2fgetting-an-error-while-doing-newtonsoft-json-deserialize-for-apostrophe-strings%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
The string is
'Jame'. It's followed by some a non-string character,n. You can't have an unescaped single quote inside a single quote string, just as you can't have a double quote inside a double quote string– Panagiotis Kanavos
Nov 27 '18 at 12:04