Dynamically search for null in sqlite select query using python












2














I'm new to python and I want to do a similar query to this one:



_c.execute('select * from cases where bi = ? and age = ? and 
shape = ? and margin = ? and density = ?',(obj['bi'],
obj['age'], obj['margin'], obj['density']))


When some of the parameters are None, for example obj['bi'] = None, the query searches for the row when bi = 'None'. But I want it to search for the row when: 'bi is NULL'



A possible solution is to verify the values of the parameters one by one in a sequence of if-elses. For example:



query = 'select * from cases where'

if obj['bi'] is None:
query += ' bi is null'
else:
query += ' bi = ' + str(obj['bi']) + ' and '
...
# do the same if-else for the other parameters
...

_c.execute(query)


But, it doesn't seem to me as the best solution.
The question is, what is the best solution to the given problem and how to avoid SQL injections.










share|improve this question




















  • 2




    (CASE WHEN ?1 = 'None' THEN bi IS NULL ELSE bi = ?1 END) AND ...?
    – Shawn
    Nov 22 at 20:15








  • 1




    @Shawn What is ?1? I don't know this syntax
    – roganjosh
    Nov 22 at 20:16








  • 1




    It's the first bound parameter. ?2 is the second, and so on. sqlite.org/lang_expr.html#varparam
    – Shawn
    Nov 22 at 20:20






  • 1




    @Shawn 3 years of using SQLite and never once encountered that. Thanks. I suggest you answer the question if you think you can solve the problem; it's not a trivial-answer-in-commments type of problem
    – roganjosh
    Nov 22 at 20:22








  • 1




    @Shawn could you please explain more your idea?
    – Bentaiba Miled Basma
    Nov 22 at 20:47
















2














I'm new to python and I want to do a similar query to this one:



_c.execute('select * from cases where bi = ? and age = ? and 
shape = ? and margin = ? and density = ?',(obj['bi'],
obj['age'], obj['margin'], obj['density']))


When some of the parameters are None, for example obj['bi'] = None, the query searches for the row when bi = 'None'. But I want it to search for the row when: 'bi is NULL'



A possible solution is to verify the values of the parameters one by one in a sequence of if-elses. For example:



query = 'select * from cases where'

if obj['bi'] is None:
query += ' bi is null'
else:
query += ' bi = ' + str(obj['bi']) + ' and '
...
# do the same if-else for the other parameters
...

_c.execute(query)


But, it doesn't seem to me as the best solution.
The question is, what is the best solution to the given problem and how to avoid SQL injections.










share|improve this question




















  • 2




    (CASE WHEN ?1 = 'None' THEN bi IS NULL ELSE bi = ?1 END) AND ...?
    – Shawn
    Nov 22 at 20:15








  • 1




    @Shawn What is ?1? I don't know this syntax
    – roganjosh
    Nov 22 at 20:16








  • 1




    It's the first bound parameter. ?2 is the second, and so on. sqlite.org/lang_expr.html#varparam
    – Shawn
    Nov 22 at 20:20






  • 1




    @Shawn 3 years of using SQLite and never once encountered that. Thanks. I suggest you answer the question if you think you can solve the problem; it's not a trivial-answer-in-commments type of problem
    – roganjosh
    Nov 22 at 20:22








  • 1




    @Shawn could you please explain more your idea?
    – Bentaiba Miled Basma
    Nov 22 at 20:47














2












2








2







I'm new to python and I want to do a similar query to this one:



_c.execute('select * from cases where bi = ? and age = ? and 
shape = ? and margin = ? and density = ?',(obj['bi'],
obj['age'], obj['margin'], obj['density']))


When some of the parameters are None, for example obj['bi'] = None, the query searches for the row when bi = 'None'. But I want it to search for the row when: 'bi is NULL'



A possible solution is to verify the values of the parameters one by one in a sequence of if-elses. For example:



query = 'select * from cases where'

if obj['bi'] is None:
query += ' bi is null'
else:
query += ' bi = ' + str(obj['bi']) + ' and '
...
# do the same if-else for the other parameters
...

_c.execute(query)


But, it doesn't seem to me as the best solution.
The question is, what is the best solution to the given problem and how to avoid SQL injections.










share|improve this question















I'm new to python and I want to do a similar query to this one:



_c.execute('select * from cases where bi = ? and age = ? and 
shape = ? and margin = ? and density = ?',(obj['bi'],
obj['age'], obj['margin'], obj['density']))


When some of the parameters are None, for example obj['bi'] = None, the query searches for the row when bi = 'None'. But I want it to search for the row when: 'bi is NULL'



A possible solution is to verify the values of the parameters one by one in a sequence of if-elses. For example:



query = 'select * from cases where'

if obj['bi'] is None:
query += ' bi is null'
else:
query += ' bi = ' + str(obj['bi']) + ' and '
...
# do the same if-else for the other parameters
...

_c.execute(query)


But, it doesn't seem to me as the best solution.
The question is, what is the best solution to the given problem and how to avoid SQL injections.







python sqlite sqlite3 null sql-injection






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 30 at 16:47









Brad Larson

161k40363541




161k40363541










asked Nov 22 at 20:05









Bentaiba Miled Basma

3401415




3401415








  • 2




    (CASE WHEN ?1 = 'None' THEN bi IS NULL ELSE bi = ?1 END) AND ...?
    – Shawn
    Nov 22 at 20:15








  • 1




    @Shawn What is ?1? I don't know this syntax
    – roganjosh
    Nov 22 at 20:16








  • 1




    It's the first bound parameter. ?2 is the second, and so on. sqlite.org/lang_expr.html#varparam
    – Shawn
    Nov 22 at 20:20






  • 1




    @Shawn 3 years of using SQLite and never once encountered that. Thanks. I suggest you answer the question if you think you can solve the problem; it's not a trivial-answer-in-commments type of problem
    – roganjosh
    Nov 22 at 20:22








  • 1




    @Shawn could you please explain more your idea?
    – Bentaiba Miled Basma
    Nov 22 at 20:47














  • 2




    (CASE WHEN ?1 = 'None' THEN bi IS NULL ELSE bi = ?1 END) AND ...?
    – Shawn
    Nov 22 at 20:15








  • 1




    @Shawn What is ?1? I don't know this syntax
    – roganjosh
    Nov 22 at 20:16








  • 1




    It's the first bound parameter. ?2 is the second, and so on. sqlite.org/lang_expr.html#varparam
    – Shawn
    Nov 22 at 20:20






  • 1




    @Shawn 3 years of using SQLite and never once encountered that. Thanks. I suggest you answer the question if you think you can solve the problem; it's not a trivial-answer-in-commments type of problem
    – roganjosh
    Nov 22 at 20:22








  • 1




    @Shawn could you please explain more your idea?
    – Bentaiba Miled Basma
    Nov 22 at 20:47








2




2




(CASE WHEN ?1 = 'None' THEN bi IS NULL ELSE bi = ?1 END) AND ...?
– Shawn
Nov 22 at 20:15






(CASE WHEN ?1 = 'None' THEN bi IS NULL ELSE bi = ?1 END) AND ...?
– Shawn
Nov 22 at 20:15






1




1




@Shawn What is ?1? I don't know this syntax
– roganjosh
Nov 22 at 20:16






@Shawn What is ?1? I don't know this syntax
– roganjosh
Nov 22 at 20:16






1




1




It's the first bound parameter. ?2 is the second, and so on. sqlite.org/lang_expr.html#varparam
– Shawn
Nov 22 at 20:20




It's the first bound parameter. ?2 is the second, and so on. sqlite.org/lang_expr.html#varparam
– Shawn
Nov 22 at 20:20




1




1




@Shawn 3 years of using SQLite and never once encountered that. Thanks. I suggest you answer the question if you think you can solve the problem; it's not a trivial-answer-in-commments type of problem
– roganjosh
Nov 22 at 20:22






@Shawn 3 years of using SQLite and never once encountered that. Thanks. I suggest you answer the question if you think you can solve the problem; it's not a trivial-answer-in-commments type of problem
– roganjosh
Nov 22 at 20:22






1




1




@Shawn could you please explain more your idea?
– Bentaiba Miled Basma
Nov 22 at 20:47




@Shawn could you please explain more your idea?
– Bentaiba Miled Basma
Nov 22 at 20:47












1 Answer
1






active

oldest

votes


















3














Okay, after firing up a python REPL and playing around with it a bit, it's simpler than I thought. The Python sqlite bindings turn a Python None into a SQL NULL, not into a string 'None' like it sounded like from your question. In SQL, = doesn't match NULL values, but IS will. So...



Given a table foo looking like:



a     | b
--------------
NULL | 1
Dog | 2


Doing:



c = conn.cursor()
c.execute('SELECT * FROM foo WHERE a IS ?', (None,))
print(c.fetchone())


will return the (NULL, 1) row, and



c.execute('SELECT * FROM foo WHERE a IS ?', ('Dog',))
print(c.fetchone())


will return the ('Dog', 2) row.



In other words, use IS not = in your query.






share|improve this answer





















  • It worked! Thanks a lot
    – Bentaiba Miled Basma
    Nov 22 at 21:17











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














Okay, after firing up a python REPL and playing around with it a bit, it's simpler than I thought. The Python sqlite bindings turn a Python None into a SQL NULL, not into a string 'None' like it sounded like from your question. In SQL, = doesn't match NULL values, but IS will. So...



Given a table foo looking like:



a     | b
--------------
NULL | 1
Dog | 2


Doing:



c = conn.cursor()
c.execute('SELECT * FROM foo WHERE a IS ?', (None,))
print(c.fetchone())


will return the (NULL, 1) row, and



c.execute('SELECT * FROM foo WHERE a IS ?', ('Dog',))
print(c.fetchone())


will return the ('Dog', 2) row.



In other words, use IS not = in your query.






share|improve this answer





















  • It worked! Thanks a lot
    – Bentaiba Miled Basma
    Nov 22 at 21:17
















3














Okay, after firing up a python REPL and playing around with it a bit, it's simpler than I thought. The Python sqlite bindings turn a Python None into a SQL NULL, not into a string 'None' like it sounded like from your question. In SQL, = doesn't match NULL values, but IS will. So...



Given a table foo looking like:



a     | b
--------------
NULL | 1
Dog | 2


Doing:



c = conn.cursor()
c.execute('SELECT * FROM foo WHERE a IS ?', (None,))
print(c.fetchone())


will return the (NULL, 1) row, and



c.execute('SELECT * FROM foo WHERE a IS ?', ('Dog',))
print(c.fetchone())


will return the ('Dog', 2) row.



In other words, use IS not = in your query.






share|improve this answer





















  • It worked! Thanks a lot
    – Bentaiba Miled Basma
    Nov 22 at 21:17














3












3








3






Okay, after firing up a python REPL and playing around with it a bit, it's simpler than I thought. The Python sqlite bindings turn a Python None into a SQL NULL, not into a string 'None' like it sounded like from your question. In SQL, = doesn't match NULL values, but IS will. So...



Given a table foo looking like:



a     | b
--------------
NULL | 1
Dog | 2


Doing:



c = conn.cursor()
c.execute('SELECT * FROM foo WHERE a IS ?', (None,))
print(c.fetchone())


will return the (NULL, 1) row, and



c.execute('SELECT * FROM foo WHERE a IS ?', ('Dog',))
print(c.fetchone())


will return the ('Dog', 2) row.



In other words, use IS not = in your query.






share|improve this answer












Okay, after firing up a python REPL and playing around with it a bit, it's simpler than I thought. The Python sqlite bindings turn a Python None into a SQL NULL, not into a string 'None' like it sounded like from your question. In SQL, = doesn't match NULL values, but IS will. So...



Given a table foo looking like:



a     | b
--------------
NULL | 1
Dog | 2


Doing:



c = conn.cursor()
c.execute('SELECT * FROM foo WHERE a IS ?', (None,))
print(c.fetchone())


will return the (NULL, 1) row, and



c.execute('SELECT * FROM foo WHERE a IS ?', ('Dog',))
print(c.fetchone())


will return the ('Dog', 2) row.



In other words, use IS not = in your query.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 22 at 21:10









Shawn

3,4531613




3,4531613












  • It worked! Thanks a lot
    – Bentaiba Miled Basma
    Nov 22 at 21:17


















  • It worked! Thanks a lot
    – Bentaiba Miled Basma
    Nov 22 at 21:17
















It worked! Thanks a lot
– Bentaiba Miled Basma
Nov 22 at 21:17




It worked! Thanks a lot
– Bentaiba Miled Basma
Nov 22 at 21:17


















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