Assert same condition on all elements of a collection
I'm working with AssertJ and I need to check that all objects in a list have intField > 0. Something like this:
assertThat(myObjectList).extracting(p -> p.getIntField()).isGreaterThan(0);
What's the correct way to achieve this? Should I use some other library?
java unit-testing assertj
asked Nov 28 '18 at 18:48
daviooohdavioooh
10.7k2698200
add a comment |
I'm working with AssertJ and I need to check that all objects in a list have intField > 0. Something like this:
assertThat(myObjectList).extracting(p -> p.getIntField()).isGreaterThan(0);
What's the correct way to achieve this? Should I use some other library?
java unit-testing assertj
asked Nov 28 '18 at 18:48
daviooohdavioooh
10.7k2698200
add a comment |
I'm working with AssertJ and I need to check that all objects in a list have intField > 0. Something like this:
assertThat(myObjectList).extracting(p -> p.getIntField()).isGreaterThan(0);
What's the correct way to achieve this? Should I use some other library?
java unit-testing assertj
asked Nov 28 '18 at 18:48
daviooohdavioooh
10.7k2698200
I'm working with AssertJ and I need to check that all objects in a list have intField > 0. Something like this:
assertThat(myObjectList).extracting(p -> p.getIntField()).isGreaterThan(0);
What's the correct way to achieve this? Should I use some other library?
java unit-testing assertj
java unit-testing assertj
asked Nov 28 '18 at 18:48
daviooohdavioooh
10.7k2698200
asked Nov 28 '18 at 18:48
daviooohdavioooh
10.7k2698200
asked Nov 28 '18 at 18:48
daviooohdavioooh
10.7k2698200
asked Nov 28 '18 at 18:48
daviooohdavioooh
10.7k2698200
asked Nov 28 '18 at 18:48
daviooohdavioooh
10.7k2698200
10.7k2698200
add a comment |
add a comment |
1 Answer
1
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oldest
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Seems the library does not provide an option to assert the way you described (even AbstractIntArrayAssert does not allow to do so), but you can:
1) use AbstractIterableAssert#allMatch(Predicate)
assertThat(asList(0, 2, 3))
.allMatch(i -> i > 0);
2) If you really want to use something like isGreaterThan on ListAssert, you can create a custom ListAssert:
public class CustomListAssert<E> extends ListAssert<E> {
public static <E> CustomListAssert<E> assertThat(List<E> list) {
return new CustomListAssert<>(list);
}
public CustomListAssert(List<? extends E> actual) {
super(actual);
}
public IntListAssert extractingInt(ToIntFunction<E> mapper) {
return new IntListAssert(actual.stream()
.mapToInt(mapper).boxed().collect(toList()));
}
}
public class IntListAssert extends ListAssert<Integer> {
public IntListAssert(List<Integer> actual) {
super(actual);
}
public IntListAssert allGreaterThan(int i) {
allMatch(n -> n > i);
return this;
}
}
And use it like this:
@Test
public void test() {
CustomListAssert.assertThat(asList(0, 2, 3))
.extractingInt(i -> i * 2)
.allGreaterThan(0);
}
What in my case yields:
java.lang.AssertionError:
Expecting all elements of:
<[0, 4, 6]>
to match given predicate but this element did not:
<0>
answered Nov 28 '18 at 19:20
caco3caco3
1,9531720
I didn't knowallMatchmethod. That's exacly what I was looking for. Thank you very much!
– davioooh
Nov 29 '18 at 15:47
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Seems the library does not provide an option to assert the way you described (even AbstractIntArrayAssert does not allow to do so), but you can:
1) use AbstractIterableAssert#allMatch(Predicate)
assertThat(asList(0, 2, 3))
.allMatch(i -> i > 0);
2) If you really want to use something like isGreaterThan on ListAssert, you can create a custom ListAssert:
public class CustomListAssert<E> extends ListAssert<E> {
public static <E> CustomListAssert<E> assertThat(List<E> list) {
return new CustomListAssert<>(list);
}
public CustomListAssert(List<? extends E> actual) {
super(actual);
}
public IntListAssert extractingInt(ToIntFunction<E> mapper) {
return new IntListAssert(actual.stream()
.mapToInt(mapper).boxed().collect(toList()));
}
}
public class IntListAssert extends ListAssert<Integer> {
public IntListAssert(List<Integer> actual) {
super(actual);
}
public IntListAssert allGreaterThan(int i) {
allMatch(n -> n > i);
return this;
}
}
And use it like this:
@Test
public void test() {
CustomListAssert.assertThat(asList(0, 2, 3))
.extractingInt(i -> i * 2)
.allGreaterThan(0);
}
What in my case yields:
java.lang.AssertionError:
Expecting all elements of:
<[0, 4, 6]>
to match given predicate but this element did not:
<0>
answered Nov 28 '18 at 19:20
caco3caco3
1,9531720
I didn't knowallMatchmethod. That's exacly what I was looking for. Thank you very much!
– davioooh
Nov 29 '18 at 15:47
add a comment |
Seems the library does not provide an option to assert the way you described (even AbstractIntArrayAssert does not allow to do so), but you can:
1) use AbstractIterableAssert#allMatch(Predicate)
assertThat(asList(0, 2, 3))
.allMatch(i -> i > 0);
2) If you really want to use something like isGreaterThan on ListAssert, you can create a custom ListAssert:
public class CustomListAssert<E> extends ListAssert<E> {
public static <E> CustomListAssert<E> assertThat(List<E> list) {
return new CustomListAssert<>(list);
}
public CustomListAssert(List<? extends E> actual) {
super(actual);
}
public IntListAssert extractingInt(ToIntFunction<E> mapper) {
return new IntListAssert(actual.stream()
.mapToInt(mapper).boxed().collect(toList()));
}
}
public class IntListAssert extends ListAssert<Integer> {
public IntListAssert(List<Integer> actual) {
super(actual);
}
public IntListAssert allGreaterThan(int i) {
allMatch(n -> n > i);
return this;
}
}
And use it like this:
@Test
public void test() {
CustomListAssert.assertThat(asList(0, 2, 3))
.extractingInt(i -> i * 2)
.allGreaterThan(0);
}
What in my case yields:
java.lang.AssertionError:
Expecting all elements of:
<[0, 4, 6]>
to match given predicate but this element did not:
<0>
answered Nov 28 '18 at 19:20
caco3caco3
1,9531720
I didn't knowallMatchmethod. That's exacly what I was looking for. Thank you very much!
– davioooh
Nov 29 '18 at 15:47
add a comment |
Seems the library does not provide an option to assert the way you described (even AbstractIntArrayAssert does not allow to do so), but you can:
1) use AbstractIterableAssert#allMatch(Predicate)
assertThat(asList(0, 2, 3))
.allMatch(i -> i > 0);
2) If you really want to use something like isGreaterThan on ListAssert, you can create a custom ListAssert:
public class CustomListAssert<E> extends ListAssert<E> {
public static <E> CustomListAssert<E> assertThat(List<E> list) {
return new CustomListAssert<>(list);
}
public CustomListAssert(List<? extends E> actual) {
super(actual);
}
public IntListAssert extractingInt(ToIntFunction<E> mapper) {
return new IntListAssert(actual.stream()
.mapToInt(mapper).boxed().collect(toList()));
}
}
public class IntListAssert extends ListAssert<Integer> {
public IntListAssert(List<Integer> actual) {
super(actual);
}
public IntListAssert allGreaterThan(int i) {
allMatch(n -> n > i);
return this;
}
}
And use it like this:
@Test
public void test() {
CustomListAssert.assertThat(asList(0, 2, 3))
.extractingInt(i -> i * 2)
.allGreaterThan(0);
}
What in my case yields:
java.lang.AssertionError:
Expecting all elements of:
<[0, 4, 6]>
to match given predicate but this element did not:
<0>
answered Nov 28 '18 at 19:20
caco3caco3
1,9531720
Seems the library does not provide an option to assert the way you described (even AbstractIntArrayAssert does not allow to do so), but you can:
1) use AbstractIterableAssert#allMatch(Predicate)
assertThat(asList(0, 2, 3))
.allMatch(i -> i > 0);
2) If you really want to use something like isGreaterThan on ListAssert, you can create a custom ListAssert:
public class CustomListAssert<E> extends ListAssert<E> {
public static <E> CustomListAssert<E> assertThat(List<E> list) {
return new CustomListAssert<>(list);
}
public CustomListAssert(List<? extends E> actual) {
super(actual);
}
public IntListAssert extractingInt(ToIntFunction<E> mapper) {
return new IntListAssert(actual.stream()
.mapToInt(mapper).boxed().collect(toList()));
}
}
public class IntListAssert extends ListAssert<Integer> {
public IntListAssert(List<Integer> actual) {
super(actual);
}
public IntListAssert allGreaterThan(int i) {
allMatch(n -> n > i);
return this;
}
}
And use it like this:
@Test
public void test() {
CustomListAssert.assertThat(asList(0, 2, 3))
.extractingInt(i -> i * 2)
.allGreaterThan(0);
}
What in my case yields:
java.lang.AssertionError:
Expecting all elements of:
<[0, 4, 6]>
to match given predicate but this element did not:
<0>
answered Nov 28 '18 at 19:20
caco3caco3
1,9531720
edited Nov 28 '18 at 19:30
answered Nov 28 '18 at 19:20
caco3caco3
1,9531720
answered Nov 28 '18 at 19:20
caco3caco3
1,9531720
answered Nov 28 '18 at 19:20
caco3caco3
1,9531720
1,9531720
I didn't knowallMatchmethod. That's exacly what I was looking for. Thank you very much!
– davioooh
Nov 29 '18 at 15:47
add a comment |
I didn't knowallMatchmethod. That's exacly what I was looking for. Thank you very much!
– davioooh
Nov 29 '18 at 15:47
I didn't know
allMatch method. That's exacly what I was looking for. Thank you very much!– davioooh
Nov 29 '18 at 15:47
I didn't know
allMatch method. That's exacly what I was looking for. Thank you very much!– davioooh
Nov 29 '18 at 15:47
add a comment |
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