JavaScript RegEx won't match with newline
I'm current making a simple application using NodeJS to translate input into a defined format. For this I'm using the following piece of JavaScript, where content is the input.
content = content.replace(/(.+)n=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)n-+$/gm, '<p>$1</p>');
Using this, I would expect the code below
Message
======
Another Message
------
translate into
<div>Message</div>
<p>Another Message</p>
However, I get the same output as input (so nothing changed),
I tried it with both RegExr and WebStorm's RegEx tester, and both of those find a match. When I log the result of content.match(/(.+)n=+$/gm) I get null.
When I remove the n from the RegEx and the input, it does seem to match, which has me think the n is causing some kind of issue. However, I'm not aware of any issue this could be causing.
javascript node.js regex
asked Nov 28 '18 at 19:02
InzeNLInzeNL
6717
add a comment |
I'm current making a simple application using NodeJS to translate input into a defined format. For this I'm using the following piece of JavaScript, where content is the input.
content = content.replace(/(.+)n=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)n-+$/gm, '<p>$1</p>');
Using this, I would expect the code below
Message
======
Another Message
------
translate into
<div>Message</div>
<p>Another Message</p>
However, I get the same output as input (so nothing changed),
I tried it with both RegExr and WebStorm's RegEx tester, and both of those find a match. When I log the result of content.match(/(.+)n=+$/gm) I get null.
When I remove the n from the RegEx and the input, it does seem to match, which has me think the n is causing some kind of issue. However, I'm not aware of any issue this could be causing.
javascript node.js regex
asked Nov 28 '18 at 19:02
InzeNLInzeNL
6717
Works fine for me: jsfiddle.net/khrismuc/o92sa1mu
– Chris G
Nov 28 '18 at 19:07
^ same regexr.com/43ve3
– zfrisch
Nov 28 '18 at 19:08
There is nothing wrong with your javaScript code. You can test it here
– Alfredo A.
Nov 28 '18 at 19:17
add a comment |
I'm current making a simple application using NodeJS to translate input into a defined format. For this I'm using the following piece of JavaScript, where content is the input.
content = content.replace(/(.+)n=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)n-+$/gm, '<p>$1</p>');
Using this, I would expect the code below
Message
======
Another Message
------
translate into
<div>Message</div>
<p>Another Message</p>
However, I get the same output as input (so nothing changed),
I tried it with both RegExr and WebStorm's RegEx tester, and both of those find a match. When I log the result of content.match(/(.+)n=+$/gm) I get null.
When I remove the n from the RegEx and the input, it does seem to match, which has me think the n is causing some kind of issue. However, I'm not aware of any issue this could be causing.
javascript node.js regex
asked Nov 28 '18 at 19:02
InzeNLInzeNL
6717
I'm current making a simple application using NodeJS to translate input into a defined format. For this I'm using the following piece of JavaScript, where content is the input.
content = content.replace(/(.+)n=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)n-+$/gm, '<p>$1</p>');
Using this, I would expect the code below
Message
======
Another Message
------
translate into
<div>Message</div>
<p>Another Message</p>
However, I get the same output as input (so nothing changed),
I tried it with both RegExr and WebStorm's RegEx tester, and both of those find a match. When I log the result of content.match(/(.+)n=+$/gm) I get null.
When I remove the n from the RegEx and the input, it does seem to match, which has me think the n is causing some kind of issue. However, I'm not aware of any issue this could be causing.
javascript node.js regex
javascript node.js regex
asked Nov 28 '18 at 19:02
InzeNLInzeNL
6717
asked Nov 28 '18 at 19:02
InzeNLInzeNL
6717
asked Nov 28 '18 at 19:02
InzeNLInzeNL
6717
asked Nov 28 '18 at 19:02
InzeNLInzeNL
6717
asked Nov 28 '18 at 19:02
InzeNLInzeNL
6717
6717
Works fine for me: jsfiddle.net/khrismuc/o92sa1mu
– Chris G
Nov 28 '18 at 19:07
^ same regexr.com/43ve3
– zfrisch
Nov 28 '18 at 19:08
There is nothing wrong with your javaScript code. You can test it here
– Alfredo A.
Nov 28 '18 at 19:17
add a comment |
Works fine for me: jsfiddle.net/khrismuc/o92sa1mu
– Chris G
Nov 28 '18 at 19:07
^ same regexr.com/43ve3
– zfrisch
Nov 28 '18 at 19:08
There is nothing wrong with your javaScript code. You can test it here
– Alfredo A.
Nov 28 '18 at 19:17
Works fine for me: jsfiddle.net/khrismuc/o92sa1mu
– Chris G
Nov 28 '18 at 19:07
Works fine for me: jsfiddle.net/khrismuc/o92sa1mu
– Chris G
Nov 28 '18 at 19:07
^ same regexr.com/43ve3
– zfrisch
Nov 28 '18 at 19:08
^ same regexr.com/43ve3
– zfrisch
Nov 28 '18 at 19:08
There is nothing wrong with your javaScript code. You can test it here
– Alfredo A.
Nov 28 '18 at 19:17
There is nothing wrong with your javaScript code. You can test it here
– Alfredo A.
Nov 28 '18 at 19:17
add a comment |
1 Answer
1
active
oldest
votes
are you using windows?
give a try to:
content = content.replace(/(.+)rn=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)rn-+$/gm, '<p>$1</p>');
depending on OS and browser you may get there n or rn (r denotes carriage return, they may be other reasons for them to appear. But in your regex you should expect either n or rn
Edit:
As suggested by Poul Bak you could simply add ? after r to handle both cases:
content = content.replace(/(.+)r?n=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)r?n-+$/gm, '<p>$1</p>');
answered Nov 28 '18 at 19:24
dfensdfens
3,48942547
2
Use: '/(.+)r?n=+$/gm' That makes the 'r' optional.
– Poul Bak
Nov 28 '18 at 19:29
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
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oldest
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active
oldest
votes
are you using windows?
give a try to:
content = content.replace(/(.+)rn=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)rn-+$/gm, '<p>$1</p>');
depending on OS and browser you may get there n or rn (r denotes carriage return, they may be other reasons for them to appear. But in your regex you should expect either n or rn
Edit:
As suggested by Poul Bak you could simply add ? after r to handle both cases:
content = content.replace(/(.+)r?n=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)r?n-+$/gm, '<p>$1</p>');
answered Nov 28 '18 at 19:24
dfensdfens
3,48942547
2
Use: '/(.+)r?n=+$/gm' That makes the 'r' optional.
– Poul Bak
Nov 28 '18 at 19:29
add a comment |
are you using windows?
give a try to:
content = content.replace(/(.+)rn=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)rn-+$/gm, '<p>$1</p>');
depending on OS and browser you may get there n or rn (r denotes carriage return, they may be other reasons for them to appear. But in your regex you should expect either n or rn
Edit:
As suggested by Poul Bak you could simply add ? after r to handle both cases:
content = content.replace(/(.+)r?n=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)r?n-+$/gm, '<p>$1</p>');
answered Nov 28 '18 at 19:24
dfensdfens
3,48942547
2
Use: '/(.+)r?n=+$/gm' That makes the 'r' optional.
– Poul Bak
Nov 28 '18 at 19:29
add a comment |
are you using windows?
give a try to:
content = content.replace(/(.+)rn=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)rn-+$/gm, '<p>$1</p>');
depending on OS and browser you may get there n or rn (r denotes carriage return, they may be other reasons for them to appear. But in your regex you should expect either n or rn
Edit:
As suggested by Poul Bak you could simply add ? after r to handle both cases:
content = content.replace(/(.+)r?n=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)r?n-+$/gm, '<p>$1</p>');
answered Nov 28 '18 at 19:24
dfensdfens
3,48942547
are you using windows?
give a try to:
content = content.replace(/(.+)rn=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)rn-+$/gm, '<p>$1</p>');
depending on OS and browser you may get there n or rn (r denotes carriage return, they may be other reasons for them to appear. But in your regex you should expect either n or rn
Edit:
As suggested by Poul Bak you could simply add ? after r to handle both cases:
content = content.replace(/(.+)r?n=+$/gm, '<div>$1</div>');
content = content.replace(/(.+)r?n-+$/gm, '<p>$1</p>');
answered Nov 28 '18 at 19:24
dfensdfens
3,48942547
edited Nov 28 '18 at 19:35
answered Nov 28 '18 at 19:24
dfensdfens
3,48942547
answered Nov 28 '18 at 19:24
dfensdfens
3,48942547
answered Nov 28 '18 at 19:24
dfensdfens
3,48942547
3,48942547
2
Use: '/(.+)r?n=+$/gm' That makes the 'r' optional.
– Poul Bak
Nov 28 '18 at 19:29
add a comment |
2
Use: '/(.+)r?n=+$/gm' That makes the 'r' optional.
– Poul Bak
Nov 28 '18 at 19:29
2
2
Use: '/(.+)r?n=+$/gm' That makes the 'r' optional.
– Poul Bak
Nov 28 '18 at 19:29
Use: '/(.+)r?n=+$/gm' That makes the 'r' optional.
– Poul Bak
Nov 28 '18 at 19:29
add a comment |
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Works fine for me: jsfiddle.net/khrismuc/o92sa1mu
– Chris G
Nov 28 '18 at 19:07
^ same regexr.com/43ve3
– zfrisch
Nov 28 '18 at 19:08
There is nothing wrong with your javaScript code. You can test it here
– Alfredo A.
Nov 28 '18 at 19:17