React router dom how to set activeStyle to NavLink by default to all current or active links
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I have a simple Navigation component that I created like this below:
const Navigation = () => {
return (
<div>
<NavLink exact to="/" activeStyle={{ color: 'red' }}>Home</NavLink>
<NavLink to="/about" activeStyle={{ color: 'red' }}>About</NavLink>
<NavLink to="/contact" activeStyle={{ color: 'red' }}>Contact</NavLink>
</div>
)
}
Everything works fine when I try to navigate to the URL and it renders the expected component and it also changes the style of the link but How can I refactor or minimize the code of activeStyle={{ color: 'red' }} that is being redundant cause if I have more links or routes this will be a complete mess.
Appreciate if someone could help.
Thanks in advance.
react-router react-router-dom
asked Nov 29 '18 at 3:59
KnowledgeSeekerKnowledgeSeeker
308221
add a comment |
I have a simple Navigation component that I created like this below:
const Navigation = () => {
return (
<div>
<NavLink exact to="/" activeStyle={{ color: 'red' }}>Home</NavLink>
<NavLink to="/about" activeStyle={{ color: 'red' }}>About</NavLink>
<NavLink to="/contact" activeStyle={{ color: 'red' }}>Contact</NavLink>
</div>
)
}
Everything works fine when I try to navigate to the URL and it renders the expected component and it also changes the style of the link but How can I refactor or minimize the code of activeStyle={{ color: 'red' }} that is being redundant cause if I have more links or routes this will be a complete mess.
Appreciate if someone could help.
Thanks in advance.
react-router react-router-dom
asked Nov 29 '18 at 3:59
KnowledgeSeekerKnowledgeSeeker
308221
React router injectsclass='active'into the link element. It'll become something like<a href='/about' class="active">About</a>. You can use CSS to style links that hasactiveclass.
– euvs
Dec 2 '18 at 4:27
So you're saying that theclass='active'comes out of the box already when the link becomes the current url and I would just take care of the css and that's it?
– KnowledgeSeeker
Dec 2 '18 at 23:00
1
Yes. You can see it in the Chrome inspector. It is also documented here github.com/ReactTraining/react-router/blob/master/packages/…
– euvs
Dec 3 '18 at 3:33
add a comment |
I have a simple Navigation component that I created like this below:
const Navigation = () => {
return (
<div>
<NavLink exact to="/" activeStyle={{ color: 'red' }}>Home</NavLink>
<NavLink to="/about" activeStyle={{ color: 'red' }}>About</NavLink>
<NavLink to="/contact" activeStyle={{ color: 'red' }}>Contact</NavLink>
</div>
)
}
Everything works fine when I try to navigate to the URL and it renders the expected component and it also changes the style of the link but How can I refactor or minimize the code of activeStyle={{ color: 'red' }} that is being redundant cause if I have more links or routes this will be a complete mess.
Appreciate if someone could help.
Thanks in advance.
react-router react-router-dom
asked Nov 29 '18 at 3:59
KnowledgeSeekerKnowledgeSeeker
308221
I have a simple Navigation component that I created like this below:
const Navigation = () => {
return (
<div>
<NavLink exact to="/" activeStyle={{ color: 'red' }}>Home</NavLink>
<NavLink to="/about" activeStyle={{ color: 'red' }}>About</NavLink>
<NavLink to="/contact" activeStyle={{ color: 'red' }}>Contact</NavLink>
</div>
)
}
Everything works fine when I try to navigate to the URL and it renders the expected component and it also changes the style of the link but How can I refactor or minimize the code of activeStyle={{ color: 'red' }} that is being redundant cause if I have more links or routes this will be a complete mess.
Appreciate if someone could help.
Thanks in advance.
react-router react-router-dom
react-router react-router-dom
asked Nov 29 '18 at 3:59
KnowledgeSeekerKnowledgeSeeker
308221
asked Nov 29 '18 at 3:59
KnowledgeSeekerKnowledgeSeeker
308221
edited Nov 29 '18 at 5:13
KnowledgeSeeker
asked Nov 29 '18 at 3:59
KnowledgeSeekerKnowledgeSeeker
308221
asked Nov 29 '18 at 3:59
KnowledgeSeekerKnowledgeSeeker
308221
asked Nov 29 '18 at 3:59
KnowledgeSeekerKnowledgeSeeker
308221
308221
React router injectsclass='active'into the link element. It'll become something like<a href='/about' class="active">About</a>. You can use CSS to style links that hasactiveclass.
– euvs
Dec 2 '18 at 4:27
So you're saying that theclass='active'comes out of the box already when the link becomes the current url and I would just take care of the css and that's it?
– KnowledgeSeeker
Dec 2 '18 at 23:00
1
Yes. You can see it in the Chrome inspector. It is also documented here github.com/ReactTraining/react-router/blob/master/packages/…
– euvs
Dec 3 '18 at 3:33
add a comment |
React router injectsclass='active'into the link element. It'll become something like<a href='/about' class="active">About</a>. You can use CSS to style links that hasactiveclass.
– euvs
Dec 2 '18 at 4:27
So you're saying that theclass='active'comes out of the box already when the link becomes the current url and I would just take care of the css and that's it?
– KnowledgeSeeker
Dec 2 '18 at 23:00
1
Yes. You can see it in the Chrome inspector. It is also documented here github.com/ReactTraining/react-router/blob/master/packages/…
– euvs
Dec 3 '18 at 3:33
React router injects
class='active' into the link element. It'll become something like <a href='/about' class="active">About</a>. You can use CSS to style links that has active class.– euvs
Dec 2 '18 at 4:27
React router injects
class='active' into the link element. It'll become something like <a href='/about' class="active">About</a>. You can use CSS to style links that has active class.– euvs
Dec 2 '18 at 4:27
So you're saying that the
class='active' comes out of the box already when the link becomes the current url and I would just take care of the css and that's it?– KnowledgeSeeker
Dec 2 '18 at 23:00
So you're saying that the
class='active' comes out of the box already when the link becomes the current url and I would just take care of the css and that's it?– KnowledgeSeeker
Dec 2 '18 at 23:00
1
1
Yes. You can see it in the Chrome inspector. It is also documented here github.com/ReactTraining/react-router/blob/master/packages/…
– euvs
Dec 3 '18 at 3:33
Yes. You can see it in the Chrome inspector. It is also documented here github.com/ReactTraining/react-router/blob/master/packages/…
– euvs
Dec 3 '18 at 3:33
add a comment |
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React router injects
class='active'into the link element. It'll become something like<a href='/about' class="active">About</a>. You can use CSS to style links that hasactiveclass.– euvs
Dec 2 '18 at 4:27
So you're saying that the
class='active'comes out of the box already when the link becomes the current url and I would just take care of the css and that's it?– KnowledgeSeeker
Dec 2 '18 at 23:00
1
Yes. You can see it in the Chrome inspector. It is also documented here github.com/ReactTraining/react-router/blob/master/packages/…
– euvs
Dec 3 '18 at 3:33