how to replace 'table a'.'column b' with 'table b'.'column b' if 'table a'.'column a' matches 'table...
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I have 2 tables as below:-
TABLE A
-------------------------------
| product_id | price |
-------------------------------
| 1 | 2.2000 |
| 2 | 0.0000 |
| 3 | 0.3333 |
TABLE B
-------------------------------
| product_id | price_discount |
-------------------------------
| 1 | 1.8000 |
How can I using select statement to select out the price range for 2 tables as mentioned above?
Example:- SELECT * FROM TABLE A WHERE **price or price discount** BETWEEN 0 AND 2;
Expected result will show due to product_id have discount_price = 1.8 (within 0 to 2 price range).
-------------------------------
| product_id | price |
-------------------------------
| 1 | 2.2000 |
| 2 | 0.0000 |
| 3 | 0.3333 |
Please help. Thank you.
mysql select
edited Nov 29 '18 at 4:27
Madhur Bhaiya
19.7k62336
asked Nov 29 '18 at 3:51
EddyEddy
80111
add a comment |
I have 2 tables as below:-
TABLE A
-------------------------------
| product_id | price |
-------------------------------
| 1 | 2.2000 |
| 2 | 0.0000 |
| 3 | 0.3333 |
TABLE B
-------------------------------
| product_id | price_discount |
-------------------------------
| 1 | 1.8000 |
How can I using select statement to select out the price range for 2 tables as mentioned above?
Example:- SELECT * FROM TABLE A WHERE **price or price discount** BETWEEN 0 AND 2;
Expected result will show due to product_id have discount_price = 1.8 (within 0 to 2 price range).
-------------------------------
| product_id | price |
-------------------------------
| 1 | 2.2000 |
| 2 | 0.0000 |
| 3 | 0.3333 |
Please help. Thank you.
mysql select
edited Nov 29 '18 at 4:27
Madhur Bhaiya
19.7k62336
asked Nov 29 '18 at 3:51
EddyEddy
80111
add a comment |
I have 2 tables as below:-
TABLE A
-------------------------------
| product_id | price |
-------------------------------
| 1 | 2.2000 |
| 2 | 0.0000 |
| 3 | 0.3333 |
TABLE B
-------------------------------
| product_id | price_discount |
-------------------------------
| 1 | 1.8000 |
How can I using select statement to select out the price range for 2 tables as mentioned above?
Example:- SELECT * FROM TABLE A WHERE **price or price discount** BETWEEN 0 AND 2;
Expected result will show due to product_id have discount_price = 1.8 (within 0 to 2 price range).
-------------------------------
| product_id | price |
-------------------------------
| 1 | 2.2000 |
| 2 | 0.0000 |
| 3 | 0.3333 |
Please help. Thank you.
mysql select
edited Nov 29 '18 at 4:27
Madhur Bhaiya
19.7k62336
asked Nov 29 '18 at 3:51
EddyEddy
80111
I have 2 tables as below:-
TABLE A
-------------------------------
| product_id | price |
-------------------------------
| 1 | 2.2000 |
| 2 | 0.0000 |
| 3 | 0.3333 |
TABLE B
-------------------------------
| product_id | price_discount |
-------------------------------
| 1 | 1.8000 |
How can I using select statement to select out the price range for 2 tables as mentioned above?
Example:- SELECT * FROM TABLE A WHERE **price or price discount** BETWEEN 0 AND 2;
Expected result will show due to product_id have discount_price = 1.8 (within 0 to 2 price range).
-------------------------------
| product_id | price |
-------------------------------
| 1 | 2.2000 |
| 2 | 0.0000 |
| 3 | 0.3333 |
Please help. Thank you.
mysql select
mysql select
edited Nov 29 '18 at 4:27
Madhur Bhaiya
19.7k62336
asked Nov 29 '18 at 3:51
EddyEddy
80111
edited Nov 29 '18 at 4:27
Madhur Bhaiya
19.7k62336
asked Nov 29 '18 at 3:51
EddyEddy
80111
edited Nov 29 '18 at 4:27
Madhur Bhaiya
19.7k62336
edited Nov 29 '18 at 4:27
Madhur Bhaiya
19.7k62336
edited Nov 29 '18 at 4:27
Madhur Bhaiya
19.7k62336
19.7k62336
asked Nov 29 '18 at 3:51
EddyEddy
80111
asked Nov 29 '18 at 3:51
EddyEddy
80111
asked Nov 29 '18 at 3:51
EddyEddy
80111
80111
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
A simple LEFT JOIN may suffice between the two tables. LEFT JOIN is done because we can have non-matching rows between the two tables.
Edit: Previous version did extra checking of tb.price_discount IS NOT NULL; but it is really not needed, and BETWEEN..AND is enough.
It is explained in the OR operator documentation, that 1 OR NULL = 1
SELECT ta.*
FROM tablea AS ta
LEFT JOIN tableb AS tb
ON ta.product_id = tb.product_id
WHERE ta.price BETWEEN 0 AND 2
OR
tb.price_discount BETWEEN 0 AND 2
Above solution is based on the assumption that there will be 0 or 1 rows corresponding to a product_id in the tableb. If there can be more, then a GROUP BY may be needed.
answered Nov 29 '18 at 4:32
Madhur BhaiyaMadhur Bhaiya
19.7k62336
1
thanks @Madhur, u answered my question.
– Eddy
Nov 29 '18 at 4:35
@henry check the updated version please. I optimized it further.
– Madhur Bhaiya
Nov 29 '18 at 4:42
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
A simple LEFT JOIN may suffice between the two tables. LEFT JOIN is done because we can have non-matching rows between the two tables.
Edit: Previous version did extra checking of tb.price_discount IS NOT NULL; but it is really not needed, and BETWEEN..AND is enough.
It is explained in the OR operator documentation, that 1 OR NULL = 1
SELECT ta.*
FROM tablea AS ta
LEFT JOIN tableb AS tb
ON ta.product_id = tb.product_id
WHERE ta.price BETWEEN 0 AND 2
OR
tb.price_discount BETWEEN 0 AND 2
Above solution is based on the assumption that there will be 0 or 1 rows corresponding to a product_id in the tableb. If there can be more, then a GROUP BY may be needed.
answered Nov 29 '18 at 4:32
Madhur BhaiyaMadhur Bhaiya
19.7k62336
1
thanks @Madhur, u answered my question.
– Eddy
Nov 29 '18 at 4:35
@henry check the updated version please. I optimized it further.
– Madhur Bhaiya
Nov 29 '18 at 4:42
add a comment |
A simple LEFT JOIN may suffice between the two tables. LEFT JOIN is done because we can have non-matching rows between the two tables.
Edit: Previous version did extra checking of tb.price_discount IS NOT NULL; but it is really not needed, and BETWEEN..AND is enough.
It is explained in the OR operator documentation, that 1 OR NULL = 1
SELECT ta.*
FROM tablea AS ta
LEFT JOIN tableb AS tb
ON ta.product_id = tb.product_id
WHERE ta.price BETWEEN 0 AND 2
OR
tb.price_discount BETWEEN 0 AND 2
Above solution is based on the assumption that there will be 0 or 1 rows corresponding to a product_id in the tableb. If there can be more, then a GROUP BY may be needed.
answered Nov 29 '18 at 4:32
Madhur BhaiyaMadhur Bhaiya
19.7k62336
1
thanks @Madhur, u answered my question.
– Eddy
Nov 29 '18 at 4:35
@henry check the updated version please. I optimized it further.
– Madhur Bhaiya
Nov 29 '18 at 4:42
add a comment |
A simple LEFT JOIN may suffice between the two tables. LEFT JOIN is done because we can have non-matching rows between the two tables.
Edit: Previous version did extra checking of tb.price_discount IS NOT NULL; but it is really not needed, and BETWEEN..AND is enough.
It is explained in the OR operator documentation, that 1 OR NULL = 1
SELECT ta.*
FROM tablea AS ta
LEFT JOIN tableb AS tb
ON ta.product_id = tb.product_id
WHERE ta.price BETWEEN 0 AND 2
OR
tb.price_discount BETWEEN 0 AND 2
Above solution is based on the assumption that there will be 0 or 1 rows corresponding to a product_id in the tableb. If there can be more, then a GROUP BY may be needed.
answered Nov 29 '18 at 4:32
Madhur BhaiyaMadhur Bhaiya
19.7k62336
A simple LEFT JOIN may suffice between the two tables. LEFT JOIN is done because we can have non-matching rows between the two tables.
Edit: Previous version did extra checking of tb.price_discount IS NOT NULL; but it is really not needed, and BETWEEN..AND is enough.
It is explained in the OR operator documentation, that 1 OR NULL = 1
SELECT ta.*
FROM tablea AS ta
LEFT JOIN tableb AS tb
ON ta.product_id = tb.product_id
WHERE ta.price BETWEEN 0 AND 2
OR
tb.price_discount BETWEEN 0 AND 2
Above solution is based on the assumption that there will be 0 or 1 rows corresponding to a product_id in the tableb. If there can be more, then a GROUP BY may be needed.
answered Nov 29 '18 at 4:32
Madhur BhaiyaMadhur Bhaiya
19.7k62336
edited Nov 29 '18 at 4:41
answered Nov 29 '18 at 4:32
Madhur BhaiyaMadhur Bhaiya
19.7k62336
answered Nov 29 '18 at 4:32
Madhur BhaiyaMadhur Bhaiya
19.7k62336
answered Nov 29 '18 at 4:32
Madhur BhaiyaMadhur Bhaiya
19.7k62336
19.7k62336
1
thanks @Madhur, u answered my question.
– Eddy
Nov 29 '18 at 4:35
@henry check the updated version please. I optimized it further.
– Madhur Bhaiya
Nov 29 '18 at 4:42
add a comment |
1
thanks @Madhur, u answered my question.
– Eddy
Nov 29 '18 at 4:35
@henry check the updated version please. I optimized it further.
– Madhur Bhaiya
Nov 29 '18 at 4:42
1
1
thanks @Madhur, u answered my question.
– Eddy
Nov 29 '18 at 4:35
thanks @Madhur, u answered my question.
– Eddy
Nov 29 '18 at 4:35
@henry check the updated version please. I optimized it further.
– Madhur Bhaiya
Nov 29 '18 at 4:42
@henry check the updated version please. I optimized it further.
– Madhur Bhaiya
Nov 29 '18 at 4:42
add a comment |
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