xmlhttprequest authorization basic response 400 Bad request
0
I´m trying to get a token from a API using Excel VBA. It is working perfectly when I write the encoded value, like this (it is just an example not the real value):
strEncoded = "nQvS3irniorrFE8fjoijBi8W43nS4e9jOJji"
But when I try using the EncodeBase64 function it returns error 400 Bad Request.
I compared the two strings the one generated by the EncodeBase64 and the one I wrote and are identical. Am I missing something??
Public Sub XmlHttpTest()
Dim Json As Object
Dim tokenurl As String, strUser, strPassword As String
Dim strEncoded As String
Dim bearer As String, strDUE As String, strToEncode As String
Dim xmlhttp As New MSXML2.ServerXMLHTTP60
Set xmlhttp = CreateObject("MSXML2.serverXMLHTTP")
tokenurl = "https://apigateway.serpro.gov.br"
strUser = LTrim(RTrim(Sheet1.Cells(3, 4).Value))
strPassword = LTrim(RTrim(Sheet1.Cells(4, 4).Value))
strToEncode = strUser & ":" & strPassword
strEncoded = EncodeBase64(strToEncode)
xmlhttp.Open "POST", tokenurl, False
xmlhttp.setRequestHeader "Authorization", "Basic " & strEncoded
xmlhttp.send ("grant_type=client_credentials")
If Not xmlhttp.Status = 200 Then
MsgBox xmlhttp.statusText
Exit Sub
End If
Set Json = ParseJson(xmlhttp.responseText)
End Sub
Function EncodeBase64(text As String) As String
Dim arrData() As Byte
arrData = StrConv(text, vbFromUnicode)
Dim objXML As MSXML2.DOMDocument60
Dim objNode As MSXML2.IXMLDOMElement
Set objXML = New MSXML2.DOMDocument60
Set objNode = objXML.createElement("b64")
objNode.DataType = "bin.base64"
objNode.nodeTypedValue = arrData
EncodeBase64 = objNode.text
Set objNode = Nothing
Set objXML = Nothing
End Function
json xmlhttprequest msxml6
asked Nov 27 '18 at 18:45
Claudia SanchezClaudia Sanchez
1
add a comment |
0
I´m trying to get a token from a API using Excel VBA. It is working perfectly when I write the encoded value, like this (it is just an example not the real value):
strEncoded = "nQvS3irniorrFE8fjoijBi8W43nS4e9jOJji"
But when I try using the EncodeBase64 function it returns error 400 Bad Request.
I compared the two strings the one generated by the EncodeBase64 and the one I wrote and are identical. Am I missing something??
Public Sub XmlHttpTest()
Dim Json As Object
Dim tokenurl As String, strUser, strPassword As String
Dim strEncoded As String
Dim bearer As String, strDUE As String, strToEncode As String
Dim xmlhttp As New MSXML2.ServerXMLHTTP60
Set xmlhttp = CreateObject("MSXML2.serverXMLHTTP")
tokenurl = "https://apigateway.serpro.gov.br"
strUser = LTrim(RTrim(Sheet1.Cells(3, 4).Value))
strPassword = LTrim(RTrim(Sheet1.Cells(4, 4).Value))
strToEncode = strUser & ":" & strPassword
strEncoded = EncodeBase64(strToEncode)
xmlhttp.Open "POST", tokenurl, False
xmlhttp.setRequestHeader "Authorization", "Basic " & strEncoded
xmlhttp.send ("grant_type=client_credentials")
If Not xmlhttp.Status = 200 Then
MsgBox xmlhttp.statusText
Exit Sub
End If
Set Json = ParseJson(xmlhttp.responseText)
End Sub
Function EncodeBase64(text As String) As String
Dim arrData() As Byte
arrData = StrConv(text, vbFromUnicode)
Dim objXML As MSXML2.DOMDocument60
Dim objNode As MSXML2.IXMLDOMElement
Set objXML = New MSXML2.DOMDocument60
Set objNode = objXML.createElement("b64")
objNode.DataType = "bin.base64"
objNode.nodeTypedValue = arrData
EncodeBase64 = objNode.text
Set objNode = Nothing
Set objXML = Nothing
End Function
json xmlhttprequest msxml6
asked Nov 27 '18 at 18:45
Claudia SanchezClaudia Sanchez
1
I added a comparition between the two values and there is a small difference, the value returned by EncodeBase64 is missing an space...
– Claudia Sanchez
Nov 27 '18 at 18:59
add a comment |
0
0
0
I´m trying to get a token from a API using Excel VBA. It is working perfectly when I write the encoded value, like this (it is just an example not the real value):
strEncoded = "nQvS3irniorrFE8fjoijBi8W43nS4e9jOJji"
But when I try using the EncodeBase64 function it returns error 400 Bad Request.
I compared the two strings the one generated by the EncodeBase64 and the one I wrote and are identical. Am I missing something??
Public Sub XmlHttpTest()
Dim Json As Object
Dim tokenurl As String, strUser, strPassword As String
Dim strEncoded As String
Dim bearer As String, strDUE As String, strToEncode As String
Dim xmlhttp As New MSXML2.ServerXMLHTTP60
Set xmlhttp = CreateObject("MSXML2.serverXMLHTTP")
tokenurl = "https://apigateway.serpro.gov.br"
strUser = LTrim(RTrim(Sheet1.Cells(3, 4).Value))
strPassword = LTrim(RTrim(Sheet1.Cells(4, 4).Value))
strToEncode = strUser & ":" & strPassword
strEncoded = EncodeBase64(strToEncode)
xmlhttp.Open "POST", tokenurl, False
xmlhttp.setRequestHeader "Authorization", "Basic " & strEncoded
xmlhttp.send ("grant_type=client_credentials")
If Not xmlhttp.Status = 200 Then
MsgBox xmlhttp.statusText
Exit Sub
End If
Set Json = ParseJson(xmlhttp.responseText)
End Sub
Function EncodeBase64(text As String) As String
Dim arrData() As Byte
arrData = StrConv(text, vbFromUnicode)
Dim objXML As MSXML2.DOMDocument60
Dim objNode As MSXML2.IXMLDOMElement
Set objXML = New MSXML2.DOMDocument60
Set objNode = objXML.createElement("b64")
objNode.DataType = "bin.base64"
objNode.nodeTypedValue = arrData
EncodeBase64 = objNode.text
Set objNode = Nothing
Set objXML = Nothing
End Function
json xmlhttprequest msxml6
asked Nov 27 '18 at 18:45
Claudia SanchezClaudia Sanchez
1
I´m trying to get a token from a API using Excel VBA. It is working perfectly when I write the encoded value, like this (it is just an example not the real value):
strEncoded = "nQvS3irniorrFE8fjoijBi8W43nS4e9jOJji"
But when I try using the EncodeBase64 function it returns error 400 Bad Request.
I compared the two strings the one generated by the EncodeBase64 and the one I wrote and are identical. Am I missing something??
Public Sub XmlHttpTest()
Dim Json As Object
Dim tokenurl As String, strUser, strPassword As String
Dim strEncoded As String
Dim bearer As String, strDUE As String, strToEncode As String
Dim xmlhttp As New MSXML2.ServerXMLHTTP60
Set xmlhttp = CreateObject("MSXML2.serverXMLHTTP")
tokenurl = "https://apigateway.serpro.gov.br"
strUser = LTrim(RTrim(Sheet1.Cells(3, 4).Value))
strPassword = LTrim(RTrim(Sheet1.Cells(4, 4).Value))
strToEncode = strUser & ":" & strPassword
strEncoded = EncodeBase64(strToEncode)
xmlhttp.Open "POST", tokenurl, False
xmlhttp.setRequestHeader "Authorization", "Basic " & strEncoded
xmlhttp.send ("grant_type=client_credentials")
If Not xmlhttp.Status = 200 Then
MsgBox xmlhttp.statusText
Exit Sub
End If
Set Json = ParseJson(xmlhttp.responseText)
End Sub
Function EncodeBase64(text As String) As String
Dim arrData() As Byte
arrData = StrConv(text, vbFromUnicode)
Dim objXML As MSXML2.DOMDocument60
Dim objNode As MSXML2.IXMLDOMElement
Set objXML = New MSXML2.DOMDocument60
Set objNode = objXML.createElement("b64")
objNode.DataType = "bin.base64"
objNode.nodeTypedValue = arrData
EncodeBase64 = objNode.text
Set objNode = Nothing
Set objXML = Nothing
End Function
json xmlhttprequest msxml6
json xmlhttprequest msxml6
asked Nov 27 '18 at 18:45
Claudia SanchezClaudia Sanchez
1
asked Nov 27 '18 at 18:45
Claudia SanchezClaudia Sanchez
1
asked Nov 27 '18 at 18:45
Claudia SanchezClaudia Sanchez
1
asked Nov 27 '18 at 18:45
Claudia SanchezClaudia Sanchez
1
asked Nov 27 '18 at 18:45
Claudia SanchezClaudia Sanchez
1
1
I added a comparition between the two values and there is a small difference, the value returned by EncodeBase64 is missing an space...
– Claudia Sanchez
Nov 27 '18 at 18:59
add a comment |
I added a comparition between the two values and there is a small difference, the value returned by EncodeBase64 is missing an space...
– Claudia Sanchez
Nov 27 '18 at 18:59
I added a comparition between the two values and there is a small difference, the value returned by EncodeBase64 is missing an space...
– Claudia Sanchez
Nov 27 '18 at 18:59
I added a comparition between the two values and there is a small difference, the value returned by EncodeBase64 is missing an space...
– Claudia Sanchez
Nov 27 '18 at 18:59
add a comment |
0
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I added a comparition between the two values and there is a small difference, the value returned by EncodeBase64 is missing an space...
– Claudia Sanchez
Nov 27 '18 at 18:59