listbox seach delete and add

hello first sorry for my bad english.I have two listbox I want to place randomly on other listbox i want to keep the searchString out of random i want to add first listbox.

    private void Form1_Load(object sender, EventArgs e)

    {

        string names = new string[12];

        names[0] = "Item 0";

        names[1] = "Item 1";

        names[2] = "Item 2";

        names[3] = "Item 3";

        names[4] = "Item 4";

        names[5] = "Item 5";

        names[6] = "Item 6";

        names[7] = "Item 7";

        names[8] = "Item 8";

        names[9] = "Item 9";

        names[10] = "Item 10";

        names[11] = "Item 11";

        this.LB_1.Items.AddRange(names);



    }



    private void button1_Click(object sender, EventArgs e)

    {



        string searchString = "Item 3";



        int number = LB_1.Items.Count;



        for (int i = 1; i <= number; i++)

        {



            //if (LB_1.Items[i].ToString().Contains(searchString))

            //{



            //    LB_2.Items.Add(searchString);

            //    //i cant add and delete LB_1 seached item

            //}

            Random rdn = new Random();

            int rnd = rdn.Next(0, LB_1.Items.Count);

            LB_2.Items.Add(LB_1.Items[rnd]);

            LB_1.Items.RemoveAt(rnd);

        }

    }

    }

}

edited Nov 27 '18 at 18:58

asked Nov 27 '18 at 18:51

foradream

44114

Don't use an array. Use a BindingList<T> as a DataSource of the ListBox. If you delete more than one item, you would have to loop backwards to preserve the indexes.

– LarsTech
Nov 27 '18 at 18:55

Create one and only one Random instance for your entire app - not inside a loop

– Make StackOverflow Good Again
Nov 27 '18 at 19:35

add a comment |

hello first sorry for my bad english.I have two listbox I want to place randomly on other listbox i want to keep the searchString out of random i want to add first listbox.

    private void Form1_Load(object sender, EventArgs e)

    {

        string names = new string[12];

        names[0] = "Item 0";

        names[1] = "Item 1";

        names[2] = "Item 2";

        names[3] = "Item 3";

        names[4] = "Item 4";

        names[5] = "Item 5";

        names[6] = "Item 6";

        names[7] = "Item 7";

        names[8] = "Item 8";

        names[9] = "Item 9";

        names[10] = "Item 10";

        names[11] = "Item 11";

        this.LB_1.Items.AddRange(names);



    }



    private void button1_Click(object sender, EventArgs e)

    {



        string searchString = "Item 3";



        int number = LB_1.Items.Count;



        for (int i = 1; i <= number; i++)

        {



            //if (LB_1.Items[i].ToString().Contains(searchString))

            //{



            //    LB_2.Items.Add(searchString);

            //    //i cant add and delete LB_1 seached item

            //}

            Random rdn = new Random();

            int rnd = rdn.Next(0, LB_1.Items.Count);

            LB_2.Items.Add(LB_1.Items[rnd]);

            LB_1.Items.RemoveAt(rnd);

        }

    }

    }

}

edited Nov 27 '18 at 18:58

asked Nov 27 '18 at 18:51

foradream

44114

Don't use an array. Use a BindingList<T> as a DataSource of the ListBox. If you delete more than one item, you would have to loop backwards to preserve the indexes.

– LarsTech
Nov 27 '18 at 18:55

Create one and only one Random instance for your entire app - not inside a loop

– Make StackOverflow Good Again
Nov 27 '18 at 19:35

add a comment |

hello first sorry for my bad english.I have two listbox I want to place randomly on other listbox i want to keep the searchString out of random i want to add first listbox.

    private void Form1_Load(object sender, EventArgs e)

    {

        string names = new string[12];

        names[0] = "Item 0";

        names[1] = "Item 1";

        names[2] = "Item 2";

        names[3] = "Item 3";

        names[4] = "Item 4";

        names[5] = "Item 5";

        names[6] = "Item 6";

        names[7] = "Item 7";

        names[8] = "Item 8";

        names[9] = "Item 9";

        names[10] = "Item 10";

        names[11] = "Item 11";

        this.LB_1.Items.AddRange(names);



    }



    private void button1_Click(object sender, EventArgs e)

    {



        string searchString = "Item 3";



        int number = LB_1.Items.Count;



        for (int i = 1; i <= number; i++)

        {



            //if (LB_1.Items[i].ToString().Contains(searchString))

            //{



            //    LB_2.Items.Add(searchString);

            //    //i cant add and delete LB_1 seached item

            //}

            Random rdn = new Random();

            int rnd = rdn.Next(0, LB_1.Items.Count);

            LB_2.Items.Add(LB_1.Items[rnd]);

            LB_1.Items.RemoveAt(rnd);

        }

    }

    }

}

edited Nov 27 '18 at 18:58

asked Nov 27 '18 at 18:51

foradream

44114

hello first sorry for my bad english.I have two listbox I want to place randomly on other listbox i want to keep the searchString out of random i want to add first listbox.

    private void Form1_Load(object sender, EventArgs e)

    {

        string names = new string[12];

        names[0] = "Item 0";

        names[1] = "Item 1";

        names[2] = "Item 2";

        names[3] = "Item 3";

        names[4] = "Item 4";

        names[5] = "Item 5";

        names[6] = "Item 6";

        names[7] = "Item 7";

        names[8] = "Item 8";

        names[9] = "Item 9";

        names[10] = "Item 10";

        names[11] = "Item 11";

        this.LB_1.Items.AddRange(names);



    }



    private void button1_Click(object sender, EventArgs e)

    {



        string searchString = "Item 3";



        int number = LB_1.Items.Count;



        for (int i = 1; i <= number; i++)

        {



            //if (LB_1.Items[i].ToString().Contains(searchString))

            //{



            //    LB_2.Items.Add(searchString);

            //    //i cant add and delete LB_1 seached item

            //}

            Random rdn = new Random();

            int rnd = rdn.Next(0, LB_1.Items.Count);

            LB_2.Items.Add(LB_1.Items[rnd]);

            LB_1.Items.RemoveAt(rnd);

        }

    }

    }

}

c# listbox

edited Nov 27 '18 at 18:58

asked Nov 27 '18 at 18:51

foradream

44114

edited Nov 27 '18 at 18:58

asked Nov 27 '18 at 18:51

foradream

44114

edited Nov 27 '18 at 18:58

asked Nov 27 '18 at 18:51

foradream

44114

asked Nov 27 '18 at 18:51

foradream

44114

asked Nov 27 '18 at 18:51

foradream

44114

Don't use an array. Use a BindingList<T> as a DataSource of the ListBox. If you delete more than one item, you would have to loop backwards to preserve the indexes.

– LarsTech
Nov 27 '18 at 18:55

Create one and only one Random instance for your entire app - not inside a loop

– Make StackOverflow Good Again
Nov 27 '18 at 19:35

add a comment |

Don't use an array. Use a BindingList<T> as a DataSource of the ListBox. If you delete more than one item, you would have to loop backwards to preserve the indexes.

– LarsTech
Nov 27 '18 at 18:55

Create one and only one Random instance for your entire app - not inside a loop

– Make StackOverflow Good Again
Nov 27 '18 at 19:35

Don't use an array. Use a BindingList<T> as a DataSource of the ListBox. If you delete more than one item, you would have to loop backwards to preserve the indexes.

– LarsTech
Nov 27 '18 at 18:55

Create one and only one Random instance for your entire app - not inside a loop

– Make StackOverflow Good Again
Nov 27 '18 at 19:35

add a comment |

1 Answer
1

active

oldest

votes

This is what you are looking for:

private void button1_Click(object sender, EventArgs e)

    {

        string searchString = "Item 3";

        LB_2.Items.Add(searchString);

        Random rdn = new Random();



        while (LB_1.Items.Count > 0)

        {

            int rnd = rdn.Next(0, LB_1.Items.Count);

            if (LB_1.Items[rnd].ToString() != searchString) LB_2.Items.Add(LB_1.Items[rnd]);

            LB_1.Items.RemoveAt(rnd);

        }

    }

edited Nov 28 '18 at 18:24

answered Nov 27 '18 at 21:09

Aldert

1,4421212

thank you for the answer. it wasn't exactly what I wanted I don't want to out of the "item 3" on list. I want it in the first place

– foradream
Nov 28 '18 at 16:17

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

This is what you are looking for:

private void button1_Click(object sender, EventArgs e)

    {

        string searchString = "Item 3";

        LB_2.Items.Add(searchString);

        Random rdn = new Random();



        while (LB_1.Items.Count > 0)

        {

            int rnd = rdn.Next(0, LB_1.Items.Count);

            if (LB_1.Items[rnd].ToString() != searchString) LB_2.Items.Add(LB_1.Items[rnd]);

            LB_1.Items.RemoveAt(rnd);

        }

    }

edited Nov 28 '18 at 18:24

answered Nov 27 '18 at 21:09

Aldert

1,4421212

thank you for the answer. it wasn't exactly what I wanted I don't want to out of the "item 3" on list. I want it in the first place

– foradream
Nov 28 '18 at 16:17

add a comment |

This is what you are looking for:

private void button1_Click(object sender, EventArgs e)

    {

        string searchString = "Item 3";

        LB_2.Items.Add(searchString);

        Random rdn = new Random();



        while (LB_1.Items.Count > 0)

        {

            int rnd = rdn.Next(0, LB_1.Items.Count);

            if (LB_1.Items[rnd].ToString() != searchString) LB_2.Items.Add(LB_1.Items[rnd]);

            LB_1.Items.RemoveAt(rnd);

        }

    }

edited Nov 28 '18 at 18:24

answered Nov 27 '18 at 21:09

Aldert

1,4421212

thank you for the answer. it wasn't exactly what I wanted I don't want to out of the "item 3" on list. I want it in the first place

– foradream
Nov 28 '18 at 16:17

add a comment |

This is what you are looking for:

private void button1_Click(object sender, EventArgs e)

    {

        string searchString = "Item 3";

        LB_2.Items.Add(searchString);

        Random rdn = new Random();



        while (LB_1.Items.Count > 0)

        {

            int rnd = rdn.Next(0, LB_1.Items.Count);

            if (LB_1.Items[rnd].ToString() != searchString) LB_2.Items.Add(LB_1.Items[rnd]);

            LB_1.Items.RemoveAt(rnd);

        }

    }

edited Nov 28 '18 at 18:24

answered Nov 27 '18 at 21:09

Aldert

1,4421212

This is what you are looking for:

private void button1_Click(object sender, EventArgs e)

    {

        string searchString = "Item 3";

        LB_2.Items.Add(searchString);

        Random rdn = new Random();



        while (LB_1.Items.Count > 0)

        {

            int rnd = rdn.Next(0, LB_1.Items.Count);

            if (LB_1.Items[rnd].ToString() != searchString) LB_2.Items.Add(LB_1.Items[rnd]);

            LB_1.Items.RemoveAt(rnd);

        }

    }

edited Nov 28 '18 at 18:24

answered Nov 27 '18 at 21:09

Aldert

1,4421212

edited Nov 28 '18 at 18:24

answered Nov 27 '18 at 21:09

Aldert

1,4421212

answered Nov 27 '18 at 21:09

Aldert

1,4421212

answered Nov 27 '18 at 21:09

Aldert

1,4421212

thank you for the answer. it wasn't exactly what I wanted I don't want to out of the "item 3" on list. I want it in the first place

– foradream
Nov 28 '18 at 16:17

add a comment |

thank you for the answer. it wasn't exactly what I wanted I don't want to out of the "item 3" on list. I want it in the first place

– foradream
Nov 28 '18 at 16:17

thank you for the answer. it wasn't exactly what I wanted I don't want to out of the "item 3" on list. I want it in the first place

– foradream
Nov 28 '18 at 16:17

add a comment |

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