Subset of a Pandas Dataframe consisting of rows with specific column values
I'm having a problem with a single line of my code.
Here is what I'd like to achieve:
- reading_now is a string consisting of 3 characters
- df2 is a data frame that is a subset of df1
- I'd like df2 to consist of rows from df1 where the first three characters of the value in column "Code" is equal to "reading_now"
I tried using the following two lines with no success:
*df2 = df1.loc[(df1['Code'])[0:3] == reading_now]*
*df2 = df1[(str(df1.Code)[0:3] == reading_now)]*
python string pandas dataframe
asked Nov 26 '18 at 21:17
segilmezsegilmez
102
add a comment |
I'm having a problem with a single line of my code.
Here is what I'd like to achieve:
- reading_now is a string consisting of 3 characters
- df2 is a data frame that is a subset of df1
- I'd like df2 to consist of rows from df1 where the first three characters of the value in column "Code" is equal to "reading_now"
I tried using the following two lines with no success:
*df2 = df1.loc[(df1['Code'])[0:3] == reading_now]*
*df2 = df1[(str(df1.Code)[0:3] == reading_now)]*
python string pandas dataframe
asked Nov 26 '18 at 21:17
segilmezsegilmez
102
1
Can you provide a example of the string and the dataframe.
– MisterMonk
Nov 26 '18 at 21:19
add a comment |
I'm having a problem with a single line of my code.
Here is what I'd like to achieve:
- reading_now is a string consisting of 3 characters
- df2 is a data frame that is a subset of df1
- I'd like df2 to consist of rows from df1 where the first three characters of the value in column "Code" is equal to "reading_now"
I tried using the following two lines with no success:
*df2 = df1.loc[(df1['Code'])[0:3] == reading_now]*
*df2 = df1[(str(df1.Code)[0:3] == reading_now)]*
python string pandas dataframe
asked Nov 26 '18 at 21:17
segilmezsegilmez
102
I'm having a problem with a single line of my code.
Here is what I'd like to achieve:
- reading_now is a string consisting of 3 characters
- df2 is a data frame that is a subset of df1
- I'd like df2 to consist of rows from df1 where the first three characters of the value in column "Code" is equal to "reading_now"
I tried using the following two lines with no success:
*df2 = df1.loc[(df1['Code'])[0:3] == reading_now]*
*df2 = df1[(str(df1.Code)[0:3] == reading_now)]*
python string pandas dataframe
python string pandas dataframe
asked Nov 26 '18 at 21:17
segilmezsegilmez
102
asked Nov 26 '18 at 21:17
segilmezsegilmez
102
asked Nov 26 '18 at 21:17
segilmezsegilmez
102
asked Nov 26 '18 at 21:17
segilmezsegilmez
102
asked Nov 26 '18 at 21:17
segilmezsegilmez
102
102
1
Can you provide a example of the string and the dataframe.
– MisterMonk
Nov 26 '18 at 21:19
add a comment |
1
Can you provide a example of the string and the dataframe.
– MisterMonk
Nov 26 '18 at 21:19
1
1
Can you provide a example of the string and the dataframe.
– MisterMonk
Nov 26 '18 at 21:19
Can you provide a example of the string and the dataframe.
– MisterMonk
Nov 26 '18 at 21:19
add a comment |
2 Answers
2
active
oldest
votes
Looks like you were really close with your 2nd attempt.
You could solve this a couple of different ways.
reading_now = 'AAA'
df1 = pd.DataFrame([{'Code': 'AAA'}, {'Code': 'BBB'}, {'Code': 'CCC'}])
solution:
df2 = df1[df1['Code'].str.startswith(reading_now)]
or
df2 = df1[df1['Code'][0:3] == reading_now]
The df2 dataframe will contain the row that starts with the reading_now string.
answered Nov 26 '18 at 21:33
brandonbanksbrandonbanks
92111
add a comment |
You could use
df2 = df1[df1['Code'].str[0:3] == reading_now]
For example:
data = ['abcd', 'cbdz', 'abcz', 'bdaz']
df1 = pd.DataFrame(data, columns=['Code'])
df2 = df1[df1['Code'].str[0:3] == 'abc']
df2 will result in a dataframe with 'Code' column containing 'abcd' and 'abcz'
answered Nov 26 '18 at 21:26
HugoHondaHugoHonda
285
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Looks like you were really close with your 2nd attempt.
You could solve this a couple of different ways.
reading_now = 'AAA'
df1 = pd.DataFrame([{'Code': 'AAA'}, {'Code': 'BBB'}, {'Code': 'CCC'}])
solution:
df2 = df1[df1['Code'].str.startswith(reading_now)]
or
df2 = df1[df1['Code'][0:3] == reading_now]
The df2 dataframe will contain the row that starts with the reading_now string.
answered Nov 26 '18 at 21:33
brandonbanksbrandonbanks
92111
add a comment |
Looks like you were really close with your 2nd attempt.
You could solve this a couple of different ways.
reading_now = 'AAA'
df1 = pd.DataFrame([{'Code': 'AAA'}, {'Code': 'BBB'}, {'Code': 'CCC'}])
solution:
df2 = df1[df1['Code'].str.startswith(reading_now)]
or
df2 = df1[df1['Code'][0:3] == reading_now]
The df2 dataframe will contain the row that starts with the reading_now string.
answered Nov 26 '18 at 21:33
brandonbanksbrandonbanks
92111
add a comment |
Looks like you were really close with your 2nd attempt.
You could solve this a couple of different ways.
reading_now = 'AAA'
df1 = pd.DataFrame([{'Code': 'AAA'}, {'Code': 'BBB'}, {'Code': 'CCC'}])
solution:
df2 = df1[df1['Code'].str.startswith(reading_now)]
or
df2 = df1[df1['Code'][0:3] == reading_now]
The df2 dataframe will contain the row that starts with the reading_now string.
answered Nov 26 '18 at 21:33
brandonbanksbrandonbanks
92111
Looks like you were really close with your 2nd attempt.
You could solve this a couple of different ways.
reading_now = 'AAA'
df1 = pd.DataFrame([{'Code': 'AAA'}, {'Code': 'BBB'}, {'Code': 'CCC'}])
solution:
df2 = df1[df1['Code'].str.startswith(reading_now)]
or
df2 = df1[df1['Code'][0:3] == reading_now]
The df2 dataframe will contain the row that starts with the reading_now string.
answered Nov 26 '18 at 21:33
brandonbanksbrandonbanks
92111
answered Nov 26 '18 at 21:33
brandonbanksbrandonbanks
92111
answered Nov 26 '18 at 21:33
brandonbanksbrandonbanks
92111
answered Nov 26 '18 at 21:33
brandonbanksbrandonbanks
92111
92111
add a comment |
add a comment |
You could use
df2 = df1[df1['Code'].str[0:3] == reading_now]
For example:
data = ['abcd', 'cbdz', 'abcz', 'bdaz']
df1 = pd.DataFrame(data, columns=['Code'])
df2 = df1[df1['Code'].str[0:3] == 'abc']
df2 will result in a dataframe with 'Code' column containing 'abcd' and 'abcz'
answered Nov 26 '18 at 21:26
HugoHondaHugoHonda
285
add a comment |
You could use
df2 = df1[df1['Code'].str[0:3] == reading_now]
For example:
data = ['abcd', 'cbdz', 'abcz', 'bdaz']
df1 = pd.DataFrame(data, columns=['Code'])
df2 = df1[df1['Code'].str[0:3] == 'abc']
df2 will result in a dataframe with 'Code' column containing 'abcd' and 'abcz'
answered Nov 26 '18 at 21:26
HugoHondaHugoHonda
285
add a comment |
You could use
df2 = df1[df1['Code'].str[0:3] == reading_now]
For example:
data = ['abcd', 'cbdz', 'abcz', 'bdaz']
df1 = pd.DataFrame(data, columns=['Code'])
df2 = df1[df1['Code'].str[0:3] == 'abc']
df2 will result in a dataframe with 'Code' column containing 'abcd' and 'abcz'
answered Nov 26 '18 at 21:26
HugoHondaHugoHonda
285
You could use
df2 = df1[df1['Code'].str[0:3] == reading_now]
For example:
data = ['abcd', 'cbdz', 'abcz', 'bdaz']
df1 = pd.DataFrame(data, columns=['Code'])
df2 = df1[df1['Code'].str[0:3] == 'abc']
df2 will result in a dataframe with 'Code' column containing 'abcd' and 'abcz'
answered Nov 26 '18 at 21:26
HugoHondaHugoHonda
285
answered Nov 26 '18 at 21:26
HugoHondaHugoHonda
285
answered Nov 26 '18 at 21:26
HugoHondaHugoHonda
285
answered Nov 26 '18 at 21:26
HugoHondaHugoHonda
285
285
add a comment |
add a comment |
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1
Can you provide a example of the string and the dataframe.
– MisterMonk
Nov 26 '18 at 21:19