PHP 7.2 Upgrade Code - REGEX Use of undefined constant
atm i want to prepare my code to upgrade from PHP 7.0 to 7.2.
For this i wrote my own small search & replace script which uses REGEX rules to find incompatiblity code and if possible fix them with preg_replace.
Code Error:
"Warning: Use of undefined constant..."
For this i wrote the follow REGEX:
$search_strings['7.0 to 7.2']['search'] = '#([([^0-9$]w+)](?!'))#i';
$search_strings['7.0 to 7.2']['replace'] = '['$2']';
This works with normal Arrays in code but if they are nested inside a MySQL Query or inside a echo/declaration value it still sucks:
The most rules worked fine, but now i want to fix the follow:
$MyArray[array_level1] = 'sdfsdf [test] my code';
will replace to(wrong):
$MyArray['array_level1'] = 'sdfsdf ['test'] my code';
should be:
$MyArray['array_level1'] = 'sdfsdf [test] my code';
or
$sel = "SELECT * FROM $tbl[my_table_name] WHERE request LIKE '$myArray[test]%' LIMIT 0,1";
will replace to(wrong):
$sel = "SELECT * FROM $tbl['my_table_name'] WHERE request LIKE '$myArray['test']%' LIMIT 0,1";
should be(i think for this is an extra regex needed because to complex?):
$sel = "SELECT * FROM ".$tbl['my_table_name']." WHERE request LIKE '".$myArray['test']."%' LIMIT 0,1";
Which also wrong...i testet several REGEX but didn´t find a solution, i think i need to optimize my negative lookahead, here is my example:
Regex Example
php regex constants upgrade php-7.2
edited Nov 27 '18 at 9:06
Sanu0786
542715
asked Nov 27 '18 at 8:55
TomTom
619
add a comment |
atm i want to prepare my code to upgrade from PHP 7.0 to 7.2.
For this i wrote my own small search & replace script which uses REGEX rules to find incompatiblity code and if possible fix them with preg_replace.
Code Error:
"Warning: Use of undefined constant..."
For this i wrote the follow REGEX:
$search_strings['7.0 to 7.2']['search'] = '#([([^0-9$]w+)](?!'))#i';
$search_strings['7.0 to 7.2']['replace'] = '['$2']';
This works with normal Arrays in code but if they are nested inside a MySQL Query or inside a echo/declaration value it still sucks:
The most rules worked fine, but now i want to fix the follow:
$MyArray[array_level1] = 'sdfsdf [test] my code';
will replace to(wrong):
$MyArray['array_level1'] = 'sdfsdf ['test'] my code';
should be:
$MyArray['array_level1'] = 'sdfsdf [test] my code';
or
$sel = "SELECT * FROM $tbl[my_table_name] WHERE request LIKE '$myArray[test]%' LIMIT 0,1";
will replace to(wrong):
$sel = "SELECT * FROM $tbl['my_table_name'] WHERE request LIKE '$myArray['test']%' LIMIT 0,1";
should be(i think for this is an extra regex needed because to complex?):
$sel = "SELECT * FROM ".$tbl['my_table_name']." WHERE request LIKE '".$myArray['test']."%' LIMIT 0,1";
Which also wrong...i testet several REGEX but didn´t find a solution, i think i need to optimize my negative lookahead, here is my example:
Regex Example
php regex constants upgrade php-7.2
edited Nov 27 '18 at 9:06
Sanu0786
542715
asked Nov 27 '18 at 8:55
TomTom
619
You could replace'".$myArray['test']."%'by simply{$myArray['test']}%in you last case / idem for".$tbl['my_table_name']."->{$tbl['my_table_name']}
– St3an
Nov 27 '18 at 9:18
Anf for your first case, why are you adding quotes in the replacement string if you don't want them...? ('['$2']';)
– St3an
Nov 27 '18 at 9:26
in my first case i want them, but only in$MyArray['array_level1']not in the last part...= 'sdfsdf ['test'] my code';
– Tom
Nov 27 '18 at 10:34
for the last case, this is a good idea and i will try to catch this with an extra regex for mysql queries. TY! If i have a solution i will post this here.
– Tom
Nov 27 '18 at 10:36
add a comment |
atm i want to prepare my code to upgrade from PHP 7.0 to 7.2.
For this i wrote my own small search & replace script which uses REGEX rules to find incompatiblity code and if possible fix them with preg_replace.
Code Error:
"Warning: Use of undefined constant..."
For this i wrote the follow REGEX:
$search_strings['7.0 to 7.2']['search'] = '#([([^0-9$]w+)](?!'))#i';
$search_strings['7.0 to 7.2']['replace'] = '['$2']';
This works with normal Arrays in code but if they are nested inside a MySQL Query or inside a echo/declaration value it still sucks:
The most rules worked fine, but now i want to fix the follow:
$MyArray[array_level1] = 'sdfsdf [test] my code';
will replace to(wrong):
$MyArray['array_level1'] = 'sdfsdf ['test'] my code';
should be:
$MyArray['array_level1'] = 'sdfsdf [test] my code';
or
$sel = "SELECT * FROM $tbl[my_table_name] WHERE request LIKE '$myArray[test]%' LIMIT 0,1";
will replace to(wrong):
$sel = "SELECT * FROM $tbl['my_table_name'] WHERE request LIKE '$myArray['test']%' LIMIT 0,1";
should be(i think for this is an extra regex needed because to complex?):
$sel = "SELECT * FROM ".$tbl['my_table_name']." WHERE request LIKE '".$myArray['test']."%' LIMIT 0,1";
Which also wrong...i testet several REGEX but didn´t find a solution, i think i need to optimize my negative lookahead, here is my example:
Regex Example
php regex constants upgrade php-7.2
edited Nov 27 '18 at 9:06
Sanu0786
542715
asked Nov 27 '18 at 8:55
TomTom
619
atm i want to prepare my code to upgrade from PHP 7.0 to 7.2.
For this i wrote my own small search & replace script which uses REGEX rules to find incompatiblity code and if possible fix them with preg_replace.
Code Error:
"Warning: Use of undefined constant..."
For this i wrote the follow REGEX:
$search_strings['7.0 to 7.2']['search'] = '#([([^0-9$]w+)](?!'))#i';
$search_strings['7.0 to 7.2']['replace'] = '['$2']';
This works with normal Arrays in code but if they are nested inside a MySQL Query or inside a echo/declaration value it still sucks:
The most rules worked fine, but now i want to fix the follow:
$MyArray[array_level1] = 'sdfsdf [test] my code';
will replace to(wrong):
$MyArray['array_level1'] = 'sdfsdf ['test'] my code';
should be:
$MyArray['array_level1'] = 'sdfsdf [test] my code';
or
$sel = "SELECT * FROM $tbl[my_table_name] WHERE request LIKE '$myArray[test]%' LIMIT 0,1";
will replace to(wrong):
$sel = "SELECT * FROM $tbl['my_table_name'] WHERE request LIKE '$myArray['test']%' LIMIT 0,1";
should be(i think for this is an extra regex needed because to complex?):
$sel = "SELECT * FROM ".$tbl['my_table_name']." WHERE request LIKE '".$myArray['test']."%' LIMIT 0,1";
Which also wrong...i testet several REGEX but didn´t find a solution, i think i need to optimize my negative lookahead, here is my example:
Regex Example
php regex constants upgrade php-7.2
php regex constants upgrade php-7.2
edited Nov 27 '18 at 9:06
Sanu0786
542715
asked Nov 27 '18 at 8:55
TomTom
619
edited Nov 27 '18 at 9:06
Sanu0786
542715
asked Nov 27 '18 at 8:55
TomTom
619
edited Nov 27 '18 at 9:06
Sanu0786
542715
edited Nov 27 '18 at 9:06
Sanu0786
542715
edited Nov 27 '18 at 9:06
Sanu0786
542715
542715
asked Nov 27 '18 at 8:55
TomTom
619
asked Nov 27 '18 at 8:55
TomTom
619
asked Nov 27 '18 at 8:55
TomTom
619
619
You could replace'".$myArray['test']."%'by simply{$myArray['test']}%in you last case / idem for".$tbl['my_table_name']."->{$tbl['my_table_name']}
– St3an
Nov 27 '18 at 9:18
Anf for your first case, why are you adding quotes in the replacement string if you don't want them...? ('['$2']';)
– St3an
Nov 27 '18 at 9:26
in my first case i want them, but only in$MyArray['array_level1']not in the last part...= 'sdfsdf ['test'] my code';
– Tom
Nov 27 '18 at 10:34
for the last case, this is a good idea and i will try to catch this with an extra regex for mysql queries. TY! If i have a solution i will post this here.
– Tom
Nov 27 '18 at 10:36
add a comment |
You could replace'".$myArray['test']."%'by simply{$myArray['test']}%in you last case / idem for".$tbl['my_table_name']."->{$tbl['my_table_name']}
– St3an
Nov 27 '18 at 9:18
Anf for your first case, why are you adding quotes in the replacement string if you don't want them...? ('['$2']';)
– St3an
Nov 27 '18 at 9:26
in my first case i want them, but only in$MyArray['array_level1']not in the last part...= 'sdfsdf ['test'] my code';
– Tom
Nov 27 '18 at 10:34
for the last case, this is a good idea and i will try to catch this with an extra regex for mysql queries. TY! If i have a solution i will post this here.
– Tom
Nov 27 '18 at 10:36
You could replace
'".$myArray['test']."%' by simply {$myArray['test']}% in you last case / idem for ".$tbl['my_table_name']." -> {$tbl['my_table_name']}– St3an
Nov 27 '18 at 9:18
You could replace
'".$myArray['test']."%' by simply {$myArray['test']}% in you last case / idem for ".$tbl['my_table_name']." -> {$tbl['my_table_name']}– St3an
Nov 27 '18 at 9:18
Anf for your first case, why are you adding quotes in the replacement string if you don't want them...? (
'['$2']';)– St3an
Nov 27 '18 at 9:26
Anf for your first case, why are you adding quotes in the replacement string if you don't want them...? (
'['$2']';)– St3an
Nov 27 '18 at 9:26
in my first case i want them, but only in
$MyArray['array_level1'] not in the last part...= 'sdfsdf ['test'] my code';– Tom
Nov 27 '18 at 10:34
in my first case i want them, but only in
$MyArray['array_level1'] not in the last part...= 'sdfsdf ['test'] my code';– Tom
Nov 27 '18 at 10:34
for the last case, this is a good idea and i will try to catch this with an extra regex for mysql queries. TY! If i have a solution i will post this here.
– Tom
Nov 27 '18 at 10:36
for the last case, this is a good idea and i will try to catch this with an extra regex for mysql queries. TY! If i have a solution i will post this here.
– Tom
Nov 27 '18 at 10:36
add a comment |
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You could replace
'".$myArray['test']."%'by simply{$myArray['test']}%in you last case / idem for".$tbl['my_table_name']."->{$tbl['my_table_name']}– St3an
Nov 27 '18 at 9:18
Anf for your first case, why are you adding quotes in the replacement string if you don't want them...? (
'['$2']';)– St3an
Nov 27 '18 at 9:26
in my first case i want them, but only in
$MyArray['array_level1']not in the last part...= 'sdfsdf ['test'] my code';– Tom
Nov 27 '18 at 10:34
for the last case, this is a good idea and i will try to catch this with an extra regex for mysql queries. TY! If i have a solution i will post this here.
– Tom
Nov 27 '18 at 10:36