How to print method?
How can I output methodA to my main method?
public class A{
public static void methodA(int c){
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args){
System.out.println(methodA()); // the error that I recieve is cannot be applied to ()
System.out.println(c); // the error that I receive is Expression expected
System.out.println(methodA); // the error that I recieve is Expression expected
}
}
My code is a lot more complicated, but this is the outline of what I need help with. How can I print the information that is in methodA to the main method?
The error that I've been receving is
java
edited Nov 25 '18 at 11:41
Gayan Mettananda
1,072713
asked Nov 25 '18 at 7:02
S. AhmedS. Ahmed
12
add a comment |
How can I output methodA to my main method?
public class A{
public static void methodA(int c){
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args){
System.out.println(methodA()); // the error that I recieve is cannot be applied to ()
System.out.println(c); // the error that I receive is Expression expected
System.out.println(methodA); // the error that I recieve is Expression expected
}
}
My code is a lot more complicated, but this is the outline of what I need help with. How can I print the information that is in methodA to the main method?
The error that I've been receving is
java
edited Nov 25 '18 at 11:41
Gayan Mettananda
1,072713
asked Nov 25 '18 at 7:02
S. AhmedS. Ahmed
12
1
You need to pass argument to methodA like thisSystem.out.println(methodA(1));
– Pushpesh Kumar Rajwanshi
Nov 25 '18 at 7:03
Return the string from methodA and print that value in the main
– Nicholas K
Nov 25 '18 at 7:04
Please read Minimal, Complete, and Verifiable example and enhance your question accordingly. Give an example what exactly you want to print.
– GhostCat
Nov 25 '18 at 7:05
add a comment |
How can I output methodA to my main method?
public class A{
public static void methodA(int c){
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args){
System.out.println(methodA()); // the error that I recieve is cannot be applied to ()
System.out.println(c); // the error that I receive is Expression expected
System.out.println(methodA); // the error that I recieve is Expression expected
}
}
My code is a lot more complicated, but this is the outline of what I need help with. How can I print the information that is in methodA to the main method?
The error that I've been receving is
java
edited Nov 25 '18 at 11:41
Gayan Mettananda
1,072713
asked Nov 25 '18 at 7:02
S. AhmedS. Ahmed
12
How can I output methodA to my main method?
public class A{
public static void methodA(int c){
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args){
System.out.println(methodA()); // the error that I recieve is cannot be applied to ()
System.out.println(c); // the error that I receive is Expression expected
System.out.println(methodA); // the error that I recieve is Expression expected
}
}
My code is a lot more complicated, but this is the outline of what I need help with. How can I print the information that is in methodA to the main method?
The error that I've been receving is
java
java
edited Nov 25 '18 at 11:41
Gayan Mettananda
1,072713
asked Nov 25 '18 at 7:02
S. AhmedS. Ahmed
12
edited Nov 25 '18 at 11:41
Gayan Mettananda
1,072713
asked Nov 25 '18 at 7:02
S. AhmedS. Ahmed
12
edited Nov 25 '18 at 11:41
Gayan Mettananda
1,072713
edited Nov 25 '18 at 11:41
Gayan Mettananda
1,072713
edited Nov 25 '18 at 11:41
Gayan Mettananda
1,072713
1,072713
asked Nov 25 '18 at 7:02
S. AhmedS. Ahmed
12
asked Nov 25 '18 at 7:02
S. AhmedS. Ahmed
12
asked Nov 25 '18 at 7:02
S. AhmedS. Ahmed
12
12
1
You need to pass argument to methodA like thisSystem.out.println(methodA(1));
– Pushpesh Kumar Rajwanshi
Nov 25 '18 at 7:03
Return the string from methodA and print that value in the main
– Nicholas K
Nov 25 '18 at 7:04
Please read Minimal, Complete, and Verifiable example and enhance your question accordingly. Give an example what exactly you want to print.
– GhostCat
Nov 25 '18 at 7:05
add a comment |
1
You need to pass argument to methodA like thisSystem.out.println(methodA(1));
– Pushpesh Kumar Rajwanshi
Nov 25 '18 at 7:03
Return the string from methodA and print that value in the main
– Nicholas K
Nov 25 '18 at 7:04
Please read Minimal, Complete, and Verifiable example and enhance your question accordingly. Give an example what exactly you want to print.
– GhostCat
Nov 25 '18 at 7:05
1
1
You need to pass argument to methodA like this
System.out.println(methodA(1));– Pushpesh Kumar Rajwanshi
Nov 25 '18 at 7:03
You need to pass argument to methodA like this
System.out.println(methodA(1));– Pushpesh Kumar Rajwanshi
Nov 25 '18 at 7:03
Return the string from methodA and print that value in the main
– Nicholas K
Nov 25 '18 at 7:04
Return the string from methodA and print that value in the main
– Nicholas K
Nov 25 '18 at 7:04
Please read Minimal, Complete, and Verifiable example and enhance your question accordingly. Give an example what exactly you want to print.
– GhostCat
Nov 25 '18 at 7:05
Please read Minimal, Complete, and Verifiable example and enhance your question accordingly. Give an example what exactly you want to print.
– GhostCat
Nov 25 '18 at 7:05
add a comment |
2 Answers
2
active
oldest
votes
You can't.
If you need to print a lot of information to understand the flow of your application, you should look into logging. I would recommend nlog or log4net, which are both great options for logging on the machine where your code is running.
If you need centralized logging, then look into Serilog and Elastichsearch.
What I think you are asking Ahmed, is how to print arguments passed to methodA, which is fairly simple.
public class A
{
public static void methodA(int c)
{
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args)
{
int c = 12;
methodA(12);
System.out.println(c);
}
}
answered Nov 25 '18 at 7:08
Ali Reza DehdarAli Reza Dehdar
694715
add a comment |
Since your method require one integer variable as an argument. You have to pass one integer as an argument to execute methodA method. For example:
public class A{
public static void methodA(int c){
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args){
int integerVariable = 5;
methodA(integerVariable);
}
}
Note: As given method is of void type , you can not write
System.out.println(methodA(integerVariable))inside main method.
answered Nov 25 '18 at 7:08
Bishal GautamBishal Gautam
820517
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can't.
If you need to print a lot of information to understand the flow of your application, you should look into logging. I would recommend nlog or log4net, which are both great options for logging on the machine where your code is running.
If you need centralized logging, then look into Serilog and Elastichsearch.
What I think you are asking Ahmed, is how to print arguments passed to methodA, which is fairly simple.
public class A
{
public static void methodA(int c)
{
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args)
{
int c = 12;
methodA(12);
System.out.println(c);
}
}
answered Nov 25 '18 at 7:08
Ali Reza DehdarAli Reza Dehdar
694715
add a comment |
You can't.
If you need to print a lot of information to understand the flow of your application, you should look into logging. I would recommend nlog or log4net, which are both great options for logging on the machine where your code is running.
If you need centralized logging, then look into Serilog and Elastichsearch.
What I think you are asking Ahmed, is how to print arguments passed to methodA, which is fairly simple.
public class A
{
public static void methodA(int c)
{
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args)
{
int c = 12;
methodA(12);
System.out.println(c);
}
}
answered Nov 25 '18 at 7:08
Ali Reza DehdarAli Reza Dehdar
694715
add a comment |
You can't.
If you need to print a lot of information to understand the flow of your application, you should look into logging. I would recommend nlog or log4net, which are both great options for logging on the machine where your code is running.
If you need centralized logging, then look into Serilog and Elastichsearch.
What I think you are asking Ahmed, is how to print arguments passed to methodA, which is fairly simple.
public class A
{
public static void methodA(int c)
{
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args)
{
int c = 12;
methodA(12);
System.out.println(c);
}
}
answered Nov 25 '18 at 7:08
Ali Reza DehdarAli Reza Dehdar
694715
You can't.
If you need to print a lot of information to understand the flow of your application, you should look into logging. I would recommend nlog or log4net, which are both great options for logging on the machine where your code is running.
If you need centralized logging, then look into Serilog and Elastichsearch.
What I think you are asking Ahmed, is how to print arguments passed to methodA, which is fairly simple.
public class A
{
public static void methodA(int c)
{
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args)
{
int c = 12;
methodA(12);
System.out.println(c);
}
}
answered Nov 25 '18 at 7:08
Ali Reza DehdarAli Reza Dehdar
694715
edited Nov 25 '18 at 7:14
answered Nov 25 '18 at 7:08
Ali Reza DehdarAli Reza Dehdar
694715
answered Nov 25 '18 at 7:08
Ali Reza DehdarAli Reza Dehdar
694715
answered Nov 25 '18 at 7:08
Ali Reza DehdarAli Reza Dehdar
694715
694715
add a comment |
add a comment |
Since your method require one integer variable as an argument. You have to pass one integer as an argument to execute methodA method. For example:
public class A{
public static void methodA(int c){
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args){
int integerVariable = 5;
methodA(integerVariable);
}
}
Note: As given method is of void type , you can not write
System.out.println(methodA(integerVariable))inside main method.
answered Nov 25 '18 at 7:08
Bishal GautamBishal Gautam
820517
add a comment |
Since your method require one integer variable as an argument. You have to pass one integer as an argument to execute methodA method. For example:
public class A{
public static void methodA(int c){
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args){
int integerVariable = 5;
methodA(integerVariable);
}
}
Note: As given method is of void type , you can not write
System.out.println(methodA(integerVariable))inside main method.
answered Nov 25 '18 at 7:08
Bishal GautamBishal Gautam
820517
add a comment |
Since your method require one integer variable as an argument. You have to pass one integer as an argument to execute methodA method. For example:
public class A{
public static void methodA(int c){
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args){
int integerVariable = 5;
methodA(integerVariable);
}
}
Note: As given method is of void type , you can not write
System.out.println(methodA(integerVariable))inside main method.
answered Nov 25 '18 at 7:08
Bishal GautamBishal Gautam
820517
Since your method require one integer variable as an argument. You have to pass one integer as an argument to execute methodA method. For example:
public class A{
public static void methodA(int c){
int b = 7;
System.out.println("output: " + b + " and " + c);
}
public static void main(String args){
int integerVariable = 5;
methodA(integerVariable);
}
}
Note: As given method is of void type , you can not write
System.out.println(methodA(integerVariable))inside main method.
answered Nov 25 '18 at 7:08
Bishal GautamBishal Gautam
820517
edited Nov 25 '18 at 7:15
answered Nov 25 '18 at 7:08
Bishal GautamBishal Gautam
820517
answered Nov 25 '18 at 7:08
Bishal GautamBishal Gautam
820517
answered Nov 25 '18 at 7:08
Bishal GautamBishal Gautam
820517
820517
add a comment |
add a comment |
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1
You need to pass argument to methodA like this
System.out.println(methodA(1));– Pushpesh Kumar Rajwanshi
Nov 25 '18 at 7:03
Return the string from methodA and print that value in the main
– Nicholas K
Nov 25 '18 at 7:04
Please read Minimal, Complete, and Verifiable example and enhance your question accordingly. Give an example what exactly you want to print.
– GhostCat
Nov 25 '18 at 7:05