Spacing after equals sign in align












12















I find that I have unpleasant spacing between the equals sign and (e.g.) the exponential function in this particular case, while using the align environment. I have a long expression which has to be split up in multiple rows. The alignment character & appears to gobble up all space when it comes after the equals sign. How could I remedy this while still preserving the plus sign alignment below?



Ideally, I would like to have the second row from the first equation, and the first row from the second equation.



Compiled document



documentclass{article}
usepackage{amsmath}
begin{document}
begin{align} % bad spacing at first row, but correctly placed second row
2 cosh t =& e^t \
&+ e^{-t}
end{align}
begin{align} % good spacing at first row, but incorrectly placed second row
2cosh t &= e^t \
&+ e^{-t}
end{align}
end{document}









share|improve this question


















  • 2





    Welcome to TeX.SE! To get the correct spacing around the = sign, one must write &= rather than =&.

    – Mico
    Nov 17 '14 at 13:50
















12















I find that I have unpleasant spacing between the equals sign and (e.g.) the exponential function in this particular case, while using the align environment. I have a long expression which has to be split up in multiple rows. The alignment character & appears to gobble up all space when it comes after the equals sign. How could I remedy this while still preserving the plus sign alignment below?



Ideally, I would like to have the second row from the first equation, and the first row from the second equation.



Compiled document



documentclass{article}
usepackage{amsmath}
begin{document}
begin{align} % bad spacing at first row, but correctly placed second row
2 cosh t =& e^t \
&+ e^{-t}
end{align}
begin{align} % good spacing at first row, but incorrectly placed second row
2cosh t &= e^t \
&+ e^{-t}
end{align}
end{document}









share|improve this question


















  • 2





    Welcome to TeX.SE! To get the correct spacing around the = sign, one must write &= rather than =&.

    – Mico
    Nov 17 '14 at 13:50














12












12








12


2






I find that I have unpleasant spacing between the equals sign and (e.g.) the exponential function in this particular case, while using the align environment. I have a long expression which has to be split up in multiple rows. The alignment character & appears to gobble up all space when it comes after the equals sign. How could I remedy this while still preserving the plus sign alignment below?



Ideally, I would like to have the second row from the first equation, and the first row from the second equation.



Compiled document



documentclass{article}
usepackage{amsmath}
begin{document}
begin{align} % bad spacing at first row, but correctly placed second row
2 cosh t =& e^t \
&+ e^{-t}
end{align}
begin{align} % good spacing at first row, but incorrectly placed second row
2cosh t &= e^t \
&+ e^{-t}
end{align}
end{document}









share|improve this question














I find that I have unpleasant spacing between the equals sign and (e.g.) the exponential function in this particular case, while using the align environment. I have a long expression which has to be split up in multiple rows. The alignment character & appears to gobble up all space when it comes after the equals sign. How could I remedy this while still preserving the plus sign alignment below?



Ideally, I would like to have the second row from the first equation, and the first row from the second equation.



Compiled document



documentclass{article}
usepackage{amsmath}
begin{document}
begin{align} % bad spacing at first row, but correctly placed second row
2 cosh t =& e^t \
&+ e^{-t}
end{align}
begin{align} % good spacing at first row, but incorrectly placed second row
2cosh t &= e^t \
&+ e^{-t}
end{align}
end{document}






math-mode align






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 17 '14 at 13:44









Martin LMartin L

16316




16316








  • 2





    Welcome to TeX.SE! To get the correct spacing around the = sign, one must write &= rather than =&.

    – Mico
    Nov 17 '14 at 13:50














  • 2





    Welcome to TeX.SE! To get the correct spacing around the = sign, one must write &= rather than =&.

    – Mico
    Nov 17 '14 at 13:50








2




2





Welcome to TeX.SE! To get the correct spacing around the = sign, one must write &= rather than =&.

– Mico
Nov 17 '14 at 13:50





Welcome to TeX.SE! To get the correct spacing around the = sign, one must write &= rather than =&.

– Mico
Nov 17 '14 at 13:50










5 Answers
5






active

oldest

votes


















7














Put the ampersand before the equals sign. Then use quad to create the indentation in the second row.



documentclass{article}
usepackage{amsmath}
begin{document}
begin{align}
2 cosh t &= e^t \
&quad+ e^{-t}
end{align}
end{document}


You can also use hspace if you want a different length for the indentation.



alignment






share|improve this answer



















  • 3





    Wouldn't begin{align} 2 cosh t &= e^t \ &phantom{{}={}} + e^{-t} end{align} be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.

    – Niel de Beaudrap
    Nov 17 '14 at 17:21











  • I'd say it's a matter of taste.

    – Ian Thompson
    Nov 18 '14 at 8:08



















6














I wouldn't try aligning the plus with e^t, but if you insist, here's how.



documentclass{article}
usepackage{amsmath}
begin{document}

noindent
The plus is flush with $e^t$ (I wouldn't recommend it):
begin{align}
2cosh t ={}& e^t \
& negmedspace+ e^{-t}
end{align}
The plus is moved right (better):
begin{align}
2cosh t &= e^t \
&qquad+ e^{-t}
end{align}
end{document}


With negmedspace we kill the space at the left of the binary operation symbol.



enter image description here



However, align is the wrong tool here:



documentclass{article}
usepackage{amsmath}
begin{document}

begin{equation}
begin{split}
2cosh t &= e^t \
&qquad + e^{-t}
end{split}
end{equation}


enter image description here






share|improve this answer































    5














    Suppose you wish to ensure that the two instances of e are aligned vertically, while respecting the fact that a binary operator (+) precedes the e in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom ("horizonal phantom") statements. The one in the first row mimics the + symbol (a binary operator) from the second row, and the hphantom statement in the second row mimics the = symbol (a relational operator) from the first row. The {} pairs are there to help TeX figure out which type of operator applies.



    enter image description here



    documentclass{article}
    usepackage{amsmath}
    setlengthtextwidth{3in} %% just for this example
    begin{document}
    begin{align}
    2cosh t &= phantom{{}+{}} mathrm{e}^t \
    &phantom{{}={}} + mathrm{e}^{-t}
    end{align}
    end{document}





    share|improve this answer































      3














      You have placed the & wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom to indent the expression in the second line to get the correct alignment. (Notice the {} before =.)



      documentclass{article}

      usepackage{amsmath}

      begin{document}

      begin{align}
      2cosh t
      &= e^{t} \
      &hphantom{{}=} + e^{-t}
      end{align}

      end{document}


      output






      share|improve this answer





















      • 1





        It is not wrong, one just have to be a bit more careful. Besides ` = {} &` is a lot short to type than &hphantom{{}=} ;-)

        – daleif
        Nov 17 '14 at 15:19











      • @daleif Good point. The reason why I used hphantom is that it's more 'universal'.

        – Svend Tveskæg
        Nov 17 '14 at 16:33



















      0














      Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.



      LaTeX encloses relation symbols with thick spaces ;, and binary symbols with medium spaces :. The symbols = and + in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:



      2 cosh t & ; mathord{=} ; e^t \
      & ; phantom{=} ; mathord{+} : e^{-t}


      A practical incarnation of the above is (see page 36 of l2kurz.pdf):



      2 cosh t & = e^{t} \
      & mathrel{phantom{=}} negmedspace {} + e^{-t}


      First, we redeem the relation status of = robbed by the phantom command. Second, we insert an empty group {} telling LaTeX to interpret + as a binary rather than a prefix symbol; but this creates a spurious medium space : that needs to be compensated.



      enter image description here






      share|improve this answer








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        5 Answers
        5






        active

        oldest

        votes








        5 Answers
        5






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        7














        Put the ampersand before the equals sign. Then use quad to create the indentation in the second row.



        documentclass{article}
        usepackage{amsmath}
        begin{document}
        begin{align}
        2 cosh t &= e^t \
        &quad+ e^{-t}
        end{align}
        end{document}


        You can also use hspace if you want a different length for the indentation.



        alignment






        share|improve this answer



















        • 3





          Wouldn't begin{align} 2 cosh t &= e^t \ &phantom{{}={}} + e^{-t} end{align} be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.

          – Niel de Beaudrap
          Nov 17 '14 at 17:21











        • I'd say it's a matter of taste.

          – Ian Thompson
          Nov 18 '14 at 8:08
















        7














        Put the ampersand before the equals sign. Then use quad to create the indentation in the second row.



        documentclass{article}
        usepackage{amsmath}
        begin{document}
        begin{align}
        2 cosh t &= e^t \
        &quad+ e^{-t}
        end{align}
        end{document}


        You can also use hspace if you want a different length for the indentation.



        alignment






        share|improve this answer



















        • 3





          Wouldn't begin{align} 2 cosh t &= e^t \ &phantom{{}={}} + e^{-t} end{align} be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.

          – Niel de Beaudrap
          Nov 17 '14 at 17:21











        • I'd say it's a matter of taste.

          – Ian Thompson
          Nov 18 '14 at 8:08














        7












        7








        7







        Put the ampersand before the equals sign. Then use quad to create the indentation in the second row.



        documentclass{article}
        usepackage{amsmath}
        begin{document}
        begin{align}
        2 cosh t &= e^t \
        &quad+ e^{-t}
        end{align}
        end{document}


        You can also use hspace if you want a different length for the indentation.



        alignment






        share|improve this answer













        Put the ampersand before the equals sign. Then use quad to create the indentation in the second row.



        documentclass{article}
        usepackage{amsmath}
        begin{document}
        begin{align}
        2 cosh t &= e^t \
        &quad+ e^{-t}
        end{align}
        end{document}


        You can also use hspace if you want a different length for the indentation.



        alignment







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 17 '14 at 13:49









        Ian ThompsonIan Thompson

        32.1k379155




        32.1k379155








        • 3





          Wouldn't begin{align} 2 cosh t &= e^t \ &phantom{{}={}} + e^{-t} end{align} be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.

          – Niel de Beaudrap
          Nov 17 '14 at 17:21











        • I'd say it's a matter of taste.

          – Ian Thompson
          Nov 18 '14 at 8:08














        • 3





          Wouldn't begin{align} 2 cosh t &= e^t \ &phantom{{}={}} + e^{-t} end{align} be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.

          – Niel de Beaudrap
          Nov 17 '14 at 17:21











        • I'd say it's a matter of taste.

          – Ian Thompson
          Nov 18 '14 at 8:08








        3




        3





        Wouldn't begin{align} 2 cosh t &= e^t \ &phantom{{}={}} + e^{-t} end{align} be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.

        – Niel de Beaudrap
        Nov 17 '14 at 17:21





        Wouldn't begin{align} 2 cosh t &= e^t \ &phantom{{}={}} + e^{-t} end{align} be better? Then the plus symbol would be inset by the width of the equals sign, with the correct spacing.

        – Niel de Beaudrap
        Nov 17 '14 at 17:21













        I'd say it's a matter of taste.

        – Ian Thompson
        Nov 18 '14 at 8:08





        I'd say it's a matter of taste.

        – Ian Thompson
        Nov 18 '14 at 8:08











        6














        I wouldn't try aligning the plus with e^t, but if you insist, here's how.



        documentclass{article}
        usepackage{amsmath}
        begin{document}

        noindent
        The plus is flush with $e^t$ (I wouldn't recommend it):
        begin{align}
        2cosh t ={}& e^t \
        & negmedspace+ e^{-t}
        end{align}
        The plus is moved right (better):
        begin{align}
        2cosh t &= e^t \
        &qquad+ e^{-t}
        end{align}
        end{document}


        With negmedspace we kill the space at the left of the binary operation symbol.



        enter image description here



        However, align is the wrong tool here:



        documentclass{article}
        usepackage{amsmath}
        begin{document}

        begin{equation}
        begin{split}
        2cosh t &= e^t \
        &qquad + e^{-t}
        end{split}
        end{equation}


        enter image description here






        share|improve this answer




























          6














          I wouldn't try aligning the plus with e^t, but if you insist, here's how.



          documentclass{article}
          usepackage{amsmath}
          begin{document}

          noindent
          The plus is flush with $e^t$ (I wouldn't recommend it):
          begin{align}
          2cosh t ={}& e^t \
          & negmedspace+ e^{-t}
          end{align}
          The plus is moved right (better):
          begin{align}
          2cosh t &= e^t \
          &qquad+ e^{-t}
          end{align}
          end{document}


          With negmedspace we kill the space at the left of the binary operation symbol.



          enter image description here



          However, align is the wrong tool here:



          documentclass{article}
          usepackage{amsmath}
          begin{document}

          begin{equation}
          begin{split}
          2cosh t &= e^t \
          &qquad + e^{-t}
          end{split}
          end{equation}


          enter image description here






          share|improve this answer


























            6












            6








            6







            I wouldn't try aligning the plus with e^t, but if you insist, here's how.



            documentclass{article}
            usepackage{amsmath}
            begin{document}

            noindent
            The plus is flush with $e^t$ (I wouldn't recommend it):
            begin{align}
            2cosh t ={}& e^t \
            & negmedspace+ e^{-t}
            end{align}
            The plus is moved right (better):
            begin{align}
            2cosh t &= e^t \
            &qquad+ e^{-t}
            end{align}
            end{document}


            With negmedspace we kill the space at the left of the binary operation symbol.



            enter image description here



            However, align is the wrong tool here:



            documentclass{article}
            usepackage{amsmath}
            begin{document}

            begin{equation}
            begin{split}
            2cosh t &= e^t \
            &qquad + e^{-t}
            end{split}
            end{equation}


            enter image description here






            share|improve this answer













            I wouldn't try aligning the plus with e^t, but if you insist, here's how.



            documentclass{article}
            usepackage{amsmath}
            begin{document}

            noindent
            The plus is flush with $e^t$ (I wouldn't recommend it):
            begin{align}
            2cosh t ={}& e^t \
            & negmedspace+ e^{-t}
            end{align}
            The plus is moved right (better):
            begin{align}
            2cosh t &= e^t \
            &qquad+ e^{-t}
            end{align}
            end{document}


            With negmedspace we kill the space at the left of the binary operation symbol.



            enter image description here



            However, align is the wrong tool here:



            documentclass{article}
            usepackage{amsmath}
            begin{document}

            begin{equation}
            begin{split}
            2cosh t &= e^t \
            &qquad + e^{-t}
            end{split}
            end{equation}


            enter image description here







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 17 '14 at 14:13









            egregegreg

            727k8819223231




            727k8819223231























                5














                Suppose you wish to ensure that the two instances of e are aligned vertically, while respecting the fact that a binary operator (+) precedes the e in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom ("horizonal phantom") statements. The one in the first row mimics the + symbol (a binary operator) from the second row, and the hphantom statement in the second row mimics the = symbol (a relational operator) from the first row. The {} pairs are there to help TeX figure out which type of operator applies.



                enter image description here



                documentclass{article}
                usepackage{amsmath}
                setlengthtextwidth{3in} %% just for this example
                begin{document}
                begin{align}
                2cosh t &= phantom{{}+{}} mathrm{e}^t \
                &phantom{{}={}} + mathrm{e}^{-t}
                end{align}
                end{document}





                share|improve this answer




























                  5














                  Suppose you wish to ensure that the two instances of e are aligned vertically, while respecting the fact that a binary operator (+) precedes the e in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom ("horizonal phantom") statements. The one in the first row mimics the + symbol (a binary operator) from the second row, and the hphantom statement in the second row mimics the = symbol (a relational operator) from the first row. The {} pairs are there to help TeX figure out which type of operator applies.



                  enter image description here



                  documentclass{article}
                  usepackage{amsmath}
                  setlengthtextwidth{3in} %% just for this example
                  begin{document}
                  begin{align}
                  2cosh t &= phantom{{}+{}} mathrm{e}^t \
                  &phantom{{}={}} + mathrm{e}^{-t}
                  end{align}
                  end{document}





                  share|improve this answer


























                    5












                    5








                    5







                    Suppose you wish to ensure that the two instances of e are aligned vertically, while respecting the fact that a binary operator (+) precedes the e in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom ("horizonal phantom") statements. The one in the first row mimics the + symbol (a binary operator) from the second row, and the hphantom statement in the second row mimics the = symbol (a relational operator) from the first row. The {} pairs are there to help TeX figure out which type of operator applies.



                    enter image description here



                    documentclass{article}
                    usepackage{amsmath}
                    setlengthtextwidth{3in} %% just for this example
                    begin{document}
                    begin{align}
                    2cosh t &= phantom{{}+{}} mathrm{e}^t \
                    &phantom{{}={}} + mathrm{e}^{-t}
                    end{align}
                    end{document}





                    share|improve this answer













                    Suppose you wish to ensure that the two instances of e are aligned vertically, while respecting the fact that a binary operator (+) precedes the e in the second row. The most direct way to obtain this type of alignment is to use a pair of hphantom ("horizonal phantom") statements. The one in the first row mimics the + symbol (a binary operator) from the second row, and the hphantom statement in the second row mimics the = symbol (a relational operator) from the first row. The {} pairs are there to help TeX figure out which type of operator applies.



                    enter image description here



                    documentclass{article}
                    usepackage{amsmath}
                    setlengthtextwidth{3in} %% just for this example
                    begin{document}
                    begin{align}
                    2cosh t &= phantom{{}+{}} mathrm{e}^t \
                    &phantom{{}={}} + mathrm{e}^{-t}
                    end{align}
                    end{document}






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 17 '14 at 14:03









                    MicoMico

                    283k31388775




                    283k31388775























                        3














                        You have placed the & wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom to indent the expression in the second line to get the correct alignment. (Notice the {} before =.)



                        documentclass{article}

                        usepackage{amsmath}

                        begin{document}

                        begin{align}
                        2cosh t
                        &= e^{t} \
                        &hphantom{{}=} + e^{-t}
                        end{align}

                        end{document}


                        output






                        share|improve this answer





















                        • 1





                          It is not wrong, one just have to be a bit more careful. Besides ` = {} &` is a lot short to type than &hphantom{{}=} ;-)

                          – daleif
                          Nov 17 '14 at 15:19











                        • @daleif Good point. The reason why I used hphantom is that it's more 'universal'.

                          – Svend Tveskæg
                          Nov 17 '14 at 16:33
















                        3














                        You have placed the & wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom to indent the expression in the second line to get the correct alignment. (Notice the {} before =.)



                        documentclass{article}

                        usepackage{amsmath}

                        begin{document}

                        begin{align}
                        2cosh t
                        &= e^{t} \
                        &hphantom{{}=} + e^{-t}
                        end{align}

                        end{document}


                        output






                        share|improve this answer





















                        • 1





                          It is not wrong, one just have to be a bit more careful. Besides ` = {} &` is a lot short to type than &hphantom{{}=} ;-)

                          – daleif
                          Nov 17 '14 at 15:19











                        • @daleif Good point. The reason why I used hphantom is that it's more 'universal'.

                          – Svend Tveskæg
                          Nov 17 '14 at 16:33














                        3












                        3








                        3







                        You have placed the & wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom to indent the expression in the second line to get the correct alignment. (Notice the {} before =.)



                        documentclass{article}

                        usepackage{amsmath}

                        begin{document}

                        begin{align}
                        2cosh t
                        &= e^{t} \
                        &hphantom{{}=} + e^{-t}
                        end{align}

                        end{document}


                        output






                        share|improve this answer















                        You have placed the & wrong; it should go before the equal sign to get the correct spacing. Also, I've used hphantom to indent the expression in the second line to get the correct alignment. (Notice the {} before =.)



                        documentclass{article}

                        usepackage{amsmath}

                        begin{document}

                        begin{align}
                        2cosh t
                        &= e^{t} \
                        &hphantom{{}=} + e^{-t}
                        end{align}

                        end{document}


                        output







                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited Nov 17 '14 at 14:03

























                        answered Nov 17 '14 at 13:51









                        Svend TveskægSvend Tveskæg

                        20.8k1052140




                        20.8k1052140








                        • 1





                          It is not wrong, one just have to be a bit more careful. Besides ` = {} &` is a lot short to type than &hphantom{{}=} ;-)

                          – daleif
                          Nov 17 '14 at 15:19











                        • @daleif Good point. The reason why I used hphantom is that it's more 'universal'.

                          – Svend Tveskæg
                          Nov 17 '14 at 16:33














                        • 1





                          It is not wrong, one just have to be a bit more careful. Besides ` = {} &` is a lot short to type than &hphantom{{}=} ;-)

                          – daleif
                          Nov 17 '14 at 15:19











                        • @daleif Good point. The reason why I used hphantom is that it's more 'universal'.

                          – Svend Tveskæg
                          Nov 17 '14 at 16:33








                        1




                        1





                        It is not wrong, one just have to be a bit more careful. Besides ` = {} &` is a lot short to type than &hphantom{{}=} ;-)

                        – daleif
                        Nov 17 '14 at 15:19





                        It is not wrong, one just have to be a bit more careful. Besides ` = {} &` is a lot short to type than &hphantom{{}=} ;-)

                        – daleif
                        Nov 17 '14 at 15:19













                        @daleif Good point. The reason why I used hphantom is that it's more 'universal'.

                        – Svend Tveskæg
                        Nov 17 '14 at 16:33





                        @daleif Good point. The reason why I used hphantom is that it's more 'universal'.

                        – Svend Tveskæg
                        Nov 17 '14 at 16:33











                        0














                        Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.



                        LaTeX encloses relation symbols with thick spaces ;, and binary symbols with medium spaces :. The symbols = and + in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:



                        2 cosh t & ; mathord{=} ; e^t \
                        & ; phantom{=} ; mathord{+} : e^{-t}


                        A practical incarnation of the above is (see page 36 of l2kurz.pdf):



                        2 cosh t & = e^{t} \
                        & mathrel{phantom{=}} negmedspace {} + e^{-t}


                        First, we redeem the relation status of = robbed by the phantom command. Second, we insert an empty group {} telling LaTeX to interpret + as a binary rather than a prefix symbol; but this creates a spurious medium space : that needs to be compensated.



                        enter image description here






                        share|improve this answer








                        New contributor




                        Christoph is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                          0














                          Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.



                          LaTeX encloses relation symbols with thick spaces ;, and binary symbols with medium spaces :. The symbols = and + in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:



                          2 cosh t & ; mathord{=} ; e^t \
                          & ; phantom{=} ; mathord{+} : e^{-t}


                          A practical incarnation of the above is (see page 36 of l2kurz.pdf):



                          2 cosh t & = e^{t} \
                          & mathrel{phantom{=}} negmedspace {} + e^{-t}


                          First, we redeem the relation status of = robbed by the phantom command. Second, we insert an empty group {} telling LaTeX to interpret + as a binary rather than a prefix symbol; but this creates a spurious medium space : that needs to be compensated.



                          enter image description here






                          share|improve this answer








                          New contributor




                          Christoph is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.























                            0












                            0








                            0







                            Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.



                            LaTeX encloses relation symbols with thick spaces ;, and binary symbols with medium spaces :. The symbols = and + in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:



                            2 cosh t & ; mathord{=} ; e^t \
                            & ; phantom{=} ; mathord{+} : e^{-t}


                            A practical incarnation of the above is (see page 36 of l2kurz.pdf):



                            2 cosh t & = e^{t} \
                            & mathrel{phantom{=}} negmedspace {} + e^{-t}


                            First, we redeem the relation status of = robbed by the phantom command. Second, we insert an empty group {} telling LaTeX to interpret + as a binary rather than a prefix symbol; but this creates a spurious medium space : that needs to be compensated.



                            enter image description here






                            share|improve this answer








                            New contributor




                            Christoph is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.










                            Strictly speaking, only the first part of egreg's answer solves the problem as intended by Martin L. All other answers require space corrections of at least 1 or 2 mu. Here is an alternative.



                            LaTeX encloses relation symbols with thick spaces ;, and binary symbols with medium spaces :. The symbols = and + in our example are respectively of these kinds. Therefore, downgrading them to ordinary symbols, what we want is:



                            2 cosh t & ; mathord{=} ; e^t \
                            & ; phantom{=} ; mathord{+} : e^{-t}


                            A practical incarnation of the above is (see page 36 of l2kurz.pdf):



                            2 cosh t & = e^{t} \
                            & mathrel{phantom{=}} negmedspace {} + e^{-t}


                            First, we redeem the relation status of = robbed by the phantom command. Second, we insert an empty group {} telling LaTeX to interpret + as a binary rather than a prefix symbol; but this creates a spurious medium space : that needs to be compensated.



                            enter image description here







                            share|improve this answer








                            New contributor




                            Christoph is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            share|improve this answer



                            share|improve this answer






                            New contributor




                            Christoph is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            answered 54 mins ago









                            ChristophChristoph

                            1




                            1




                            New contributor




                            Christoph is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                            New contributor





                            Christoph is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.






                            Christoph is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.






























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