Get Receiver Type and Method name from just a reference of function in Go
Given a code setup like this,
package main
import (
"fmt"
"reflect"
"runtime/debug"
)
type A struct{}
func (o *A) B() error {
debug.PrintStack()
return nil
}
func main() {
a := &A{}
b := a.B
// Note that if run b(), it can print the stack and show the info
// "(*A).B-fm" and "(*A).B"
m := reflect.ValueOf(b)
fmt.Println(m.Type().String())
}
Is it possible to get the information of b's receiver type A and B as a method? How if possible?
Note that b is value of method B of type A.
(Possible use scenario, generating a constant unique API ID based on only a reference like b, by forming a string like (*A).B. It's used to build a debug tool without a need to change existing code.)
update:
go
asked Nov 28 '18 at 8:43
Jason XuJason Xu
1,31621845
add a comment |
Given a code setup like this,
package main
import (
"fmt"
"reflect"
"runtime/debug"
)
type A struct{}
func (o *A) B() error {
debug.PrintStack()
return nil
}
func main() {
a := &A{}
b := a.B
// Note that if run b(), it can print the stack and show the info
// "(*A).B-fm" and "(*A).B"
m := reflect.ValueOf(b)
fmt.Println(m.Type().String())
}
Is it possible to get the information of b's receiver type A and B as a method? How if possible?
Note that b is value of method B of type A.
(Possible use scenario, generating a constant unique API ID based on only a reference like b, by forming a string like (*A).B. It's used to build a debug tool without a need to change existing code.)
update:
go
asked Nov 28 '18 at 8:43
Jason XuJason Xu
1,31621845
1
No you cannot. Sorry.
– Volker
Nov 28 '18 at 9:05
You can use:v := reflect.ValueOf(a) m := v.MethodByName("B")But to get A type from B is impossible, but from you example you can just access a by doingreflect.ValueOf(a)
– Alex Pliutau
Nov 28 '18 at 9:09
ah I only have access to "b". still learning.. maybe it's impossible. thanks for replies.
– Jason Xu
Nov 28 '18 at 9:11
add a comment |
Given a code setup like this,
package main
import (
"fmt"
"reflect"
"runtime/debug"
)
type A struct{}
func (o *A) B() error {
debug.PrintStack()
return nil
}
func main() {
a := &A{}
b := a.B
// Note that if run b(), it can print the stack and show the info
// "(*A).B-fm" and "(*A).B"
m := reflect.ValueOf(b)
fmt.Println(m.Type().String())
}
Is it possible to get the information of b's receiver type A and B as a method? How if possible?
Note that b is value of method B of type A.
(Possible use scenario, generating a constant unique API ID based on only a reference like b, by forming a string like (*A).B. It's used to build a debug tool without a need to change existing code.)
update:
go
asked Nov 28 '18 at 8:43
Jason XuJason Xu
1,31621845
Given a code setup like this,
package main
import (
"fmt"
"reflect"
"runtime/debug"
)
type A struct{}
func (o *A) B() error {
debug.PrintStack()
return nil
}
func main() {
a := &A{}
b := a.B
// Note that if run b(), it can print the stack and show the info
// "(*A).B-fm" and "(*A).B"
m := reflect.ValueOf(b)
fmt.Println(m.Type().String())
}
Is it possible to get the information of b's receiver type A and B as a method? How if possible?
Note that b is value of method B of type A.
(Possible use scenario, generating a constant unique API ID based on only a reference like b, by forming a string like (*A).B. It's used to build a debug tool without a need to change existing code.)
update:
go
go
asked Nov 28 '18 at 8:43
Jason XuJason Xu
1,31621845
asked Nov 28 '18 at 8:43
Jason XuJason Xu
1,31621845
edited Nov 28 '18 at 9:38
Jason Xu
asked Nov 28 '18 at 8:43
Jason XuJason Xu
1,31621845
asked Nov 28 '18 at 8:43
Jason XuJason Xu
1,31621845
asked Nov 28 '18 at 8:43
Jason XuJason Xu
1,31621845
1,31621845
1
No you cannot. Sorry.
– Volker
Nov 28 '18 at 9:05
You can use:v := reflect.ValueOf(a) m := v.MethodByName("B")But to get A type from B is impossible, but from you example you can just access a by doingreflect.ValueOf(a)
– Alex Pliutau
Nov 28 '18 at 9:09
ah I only have access to "b". still learning.. maybe it's impossible. thanks for replies.
– Jason Xu
Nov 28 '18 at 9:11
add a comment |
1
No you cannot. Sorry.
– Volker
Nov 28 '18 at 9:05
You can use:v := reflect.ValueOf(a) m := v.MethodByName("B")But to get A type from B is impossible, but from you example you can just access a by doingreflect.ValueOf(a)
– Alex Pliutau
Nov 28 '18 at 9:09
ah I only have access to "b". still learning.. maybe it's impossible. thanks for replies.
– Jason Xu
Nov 28 '18 at 9:11
1
1
No you cannot. Sorry.
– Volker
Nov 28 '18 at 9:05
No you cannot. Sorry.
– Volker
Nov 28 '18 at 9:05
You can use:
v := reflect.ValueOf(a) m := v.MethodByName("B") But to get A type from B is impossible, but from you example you can just access a by doing reflect.ValueOf(a)– Alex Pliutau
Nov 28 '18 at 9:09
You can use:
v := reflect.ValueOf(a) m := v.MethodByName("B") But to get A type from B is impossible, but from you example you can just access a by doing reflect.ValueOf(a)– Alex Pliutau
Nov 28 '18 at 9:09
ah I only have access to "b". still learning.. maybe it's impossible. thanks for replies.
– Jason Xu
Nov 28 '18 at 9:11
ah I only have access to "b". still learning.. maybe it's impossible. thanks for replies.
– Jason Xu
Nov 28 '18 at 9:11
add a comment |
1 Answer
1
active
oldest
votes
This will do the work.
fmt.Println(runtime.FuncForPC(m.Pointer()).Name())
Credits to this awesome article,
answered Nov 28 '18 at 9:29
Jason XuJason Xu
1,31621845
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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active
oldest
votes
This will do the work.
fmt.Println(runtime.FuncForPC(m.Pointer()).Name())
Credits to this awesome article,
answered Nov 28 '18 at 9:29
Jason XuJason Xu
1,31621845
add a comment |
This will do the work.
fmt.Println(runtime.FuncForPC(m.Pointer()).Name())
Credits to this awesome article,
answered Nov 28 '18 at 9:29
Jason XuJason Xu
1,31621845
add a comment |
This will do the work.
fmt.Println(runtime.FuncForPC(m.Pointer()).Name())
Credits to this awesome article,
answered Nov 28 '18 at 9:29
Jason XuJason Xu
1,31621845
This will do the work.
fmt.Println(runtime.FuncForPC(m.Pointer()).Name())
Credits to this awesome article,
answered Nov 28 '18 at 9:29
Jason XuJason Xu
1,31621845
answered Nov 28 '18 at 9:29
Jason XuJason Xu
1,31621845
answered Nov 28 '18 at 9:29
Jason XuJason Xu
1,31621845
answered Nov 28 '18 at 9:29
Jason XuJason Xu
1,31621845
1,31621845
add a comment |
add a comment |
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1
No you cannot. Sorry.
– Volker
Nov 28 '18 at 9:05
You can use:
v := reflect.ValueOf(a) m := v.MethodByName("B")But to get A type from B is impossible, but from you example you can just access a by doingreflect.ValueOf(a)– Alex Pliutau
Nov 28 '18 at 9:09
ah I only have access to "b". still learning.. maybe it's impossible. thanks for replies.
– Jason Xu
Nov 28 '18 at 9:11