How to select all href attribute in a html tag contain a common class. in Scrapy
I want to select all the href contains in tag ...
here is my html code
<a href="/gp/product/0545935172 ...." class="aok-block aok-nowrap" title="Dog Man: Lord of the Fleas: From the Creator of Captain Underpants (Dog Man #5)">
I used response.css('a.aok-block::attr(href)').extract()
but the result is: [ ]
scrapy-spider scrapy-shell
asked Nov 27 '18 at 1:34
Hossain MishoHossain Misho
11
add a comment |
I want to select all the href contains in tag ...
here is my html code
<a href="/gp/product/0545935172 ...." class="aok-block aok-nowrap" title="Dog Man: Lord of the Fleas: From the Creator of Captain Underpants (Dog Man #5)">
I used response.css('a.aok-block::attr(href)').extract()
but the result is: [ ]
scrapy-spider scrapy-shell
asked Nov 27 '18 at 1:34
Hossain MishoHossain Misho
11
add a comment |
I want to select all the href contains in tag ...
here is my html code
<a href="/gp/product/0545935172 ...." class="aok-block aok-nowrap" title="Dog Man: Lord of the Fleas: From the Creator of Captain Underpants (Dog Man #5)">
I used response.css('a.aok-block::attr(href)').extract()
but the result is: [ ]
scrapy-spider scrapy-shell
asked Nov 27 '18 at 1:34
Hossain MishoHossain Misho
11
I want to select all the href contains in tag ...
here is my html code
<a href="/gp/product/0545935172 ...." class="aok-block aok-nowrap" title="Dog Man: Lord of the Fleas: From the Creator of Captain Underpants (Dog Man #5)">
I used response.css('a.aok-block::attr(href)').extract()
but the result is: [ ]
scrapy-spider scrapy-shell
scrapy-spider scrapy-shell
asked Nov 27 '18 at 1:34
Hossain MishoHossain Misho
11
asked Nov 27 '18 at 1:34
Hossain MishoHossain Misho
11
asked Nov 27 '18 at 1:34
Hossain MishoHossain Misho
11
asked Nov 27 '18 at 1:34
Hossain MishoHossain Misho
11
asked Nov 27 '18 at 1:34
Hossain MishoHossain Misho
11
11
add a comment |
add a comment |
2 Answers
2
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oldest
votes
It is recommended that you use xpath expressions. For your example response.xpath("//a[class='aok-block aok-nowrap']").get_attribute('href')
answered Nov 28 '18 at 16:14
johnnydoejohnnydoe
236
add a comment |
Add to the answer johnnydoe
Will be:
response.xpath('*//a/@href').extract_first()
response.xpath('*//a/@class').extract_first()
response.xpath('*//a/@title').extract_first()
If you want get only href then you must find upper tag...like this:
<li>
<a id="nav-questions" href="/questions">
</li>
Will be:
response.xpath('...some uniq selector.../li/a/@href').extract_first()
answered Nov 29 '18 at 9:40
Иван ВасильевИван Васильев
1344
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
It is recommended that you use xpath expressions. For your example response.xpath("//a[class='aok-block aok-nowrap']").get_attribute('href')
answered Nov 28 '18 at 16:14
johnnydoejohnnydoe
236
add a comment |
It is recommended that you use xpath expressions. For your example response.xpath("//a[class='aok-block aok-nowrap']").get_attribute('href')
answered Nov 28 '18 at 16:14
johnnydoejohnnydoe
236
add a comment |
It is recommended that you use xpath expressions. For your example response.xpath("//a[class='aok-block aok-nowrap']").get_attribute('href')
answered Nov 28 '18 at 16:14
johnnydoejohnnydoe
236
It is recommended that you use xpath expressions. For your example response.xpath("//a[class='aok-block aok-nowrap']").get_attribute('href')
answered Nov 28 '18 at 16:14
johnnydoejohnnydoe
236
answered Nov 28 '18 at 16:14
johnnydoejohnnydoe
236
answered Nov 28 '18 at 16:14
johnnydoejohnnydoe
236
answered Nov 28 '18 at 16:14
johnnydoejohnnydoe
236
236
add a comment |
add a comment |
Add to the answer johnnydoe
Will be:
response.xpath('*//a/@href').extract_first()
response.xpath('*//a/@class').extract_first()
response.xpath('*//a/@title').extract_first()
If you want get only href then you must find upper tag...like this:
<li>
<a id="nav-questions" href="/questions">
</li>
Will be:
response.xpath('...some uniq selector.../li/a/@href').extract_first()
answered Nov 29 '18 at 9:40
Иван ВасильевИван Васильев
1344
add a comment |
Add to the answer johnnydoe
Will be:
response.xpath('*//a/@href').extract_first()
response.xpath('*//a/@class').extract_first()
response.xpath('*//a/@title').extract_first()
If you want get only href then you must find upper tag...like this:
<li>
<a id="nav-questions" href="/questions">
</li>
Will be:
response.xpath('...some uniq selector.../li/a/@href').extract_first()
answered Nov 29 '18 at 9:40
Иван ВасильевИван Васильев
1344
add a comment |
Add to the answer johnnydoe
Will be:
response.xpath('*//a/@href').extract_first()
response.xpath('*//a/@class').extract_first()
response.xpath('*//a/@title').extract_first()
If you want get only href then you must find upper tag...like this:
<li>
<a id="nav-questions" href="/questions">
</li>
Will be:
response.xpath('...some uniq selector.../li/a/@href').extract_first()
answered Nov 29 '18 at 9:40
Иван ВасильевИван Васильев
1344
Add to the answer johnnydoe
Will be:
response.xpath('*//a/@href').extract_first()
response.xpath('*//a/@class').extract_first()
response.xpath('*//a/@title').extract_first()
If you want get only href then you must find upper tag...like this:
<li>
<a id="nav-questions" href="/questions">
</li>
Will be:
response.xpath('...some uniq selector.../li/a/@href').extract_first()
answered Nov 29 '18 at 9:40
Иван ВасильевИван Васильев
1344
edited Nov 29 '18 at 10:13
answered Nov 29 '18 at 9:40
Иван ВасильевИван Васильев
1344
answered Nov 29 '18 at 9:40
Иван ВасильевИван Васильев
1344
answered Nov 29 '18 at 9:40
Иван ВасильевИван Васильев
1344
1344
add a comment |
add a comment |
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