Vector becomes null
-1
When I perform the following operation nothing goes wrong, however if I run the
below code for a second or third time my vector aaa vector becomes NULL type and I can´t repeat the operation unless I close R to re-open it, it absolutely makes no sense, even worse, when I change the vector for another vector R states that is also NULL type, any idea of what to do?
aaa=c()
for(i in 1:95){
for(j in 1:length(codigos[,1])){
if(Base[i,3]==codigos[j,1]){
aaa[i]=codigos[j,2]
Base[i,3]=codigos[j,2]
}
}
}
r vector null
edited Nov 22 at 20:45
zx8754
29.1k76398
asked Nov 22 at 20:21
Mario Coronel Maidana
1
add a comment |
-1
When I perform the following operation nothing goes wrong, however if I run the
below code for a second or third time my vector aaa vector becomes NULL type and I can´t repeat the operation unless I close R to re-open it, it absolutely makes no sense, even worse, when I change the vector for another vector R states that is also NULL type, any idea of what to do?
aaa=c()
for(i in 1:95){
for(j in 1:length(codigos[,1])){
if(Base[i,3]==codigos[j,1]){
aaa[i]=codigos[j,2]
Base[i,3]=codigos[j,2]
}
}
}
r vector null
edited Nov 22 at 20:45
zx8754
29.1k76398
asked Nov 22 at 20:21
Mario Coronel Maidana
1
4
It is best to explain what you are trying to do. Provide example reproducible data and expected output.
– zx8754
Nov 22 at 20:47
maybe the if statement is always false so aaa is empty from the beggining.
– Csd
Nov 22 at 20:59
If you get some "result" the first time, and then nothing later , then it's probable that after the first run Base[i,3]==codigos[j,1] is never TRUE. Therefore, aaa[i]=codigos[j,2] is never run, and aaa stays at its "original value", which is NULL.
– lbusett
Nov 22 at 21:14
I forgot to mention, the first time I run the operation I do get results, the vector is fillep with actual values, but most of them are NA, do you think it has something to do?
– Mario Coronel Maidana
Nov 23 at 10:57
Difficult to say without seeing your data and knowing what you are trying to do. However, given the "logic" of your code, it is not unexpected that you get different results on different runs:Base[i,3]=codigos[j,2]modifies theBased.f. on the first run. Since you use a condition onBaseto decide what to do withaaa, different runs can have different results, unless you "reset"Baseto its original value.
– lbusett
Nov 23 at 14:09
add a comment |
-1
-1
-1
When I perform the following operation nothing goes wrong, however if I run the
below code for a second or third time my vector aaa vector becomes NULL type and I can´t repeat the operation unless I close R to re-open it, it absolutely makes no sense, even worse, when I change the vector for another vector R states that is also NULL type, any idea of what to do?
aaa=c()
for(i in 1:95){
for(j in 1:length(codigos[,1])){
if(Base[i,3]==codigos[j,1]){
aaa[i]=codigos[j,2]
Base[i,3]=codigos[j,2]
}
}
}
r vector null
edited Nov 22 at 20:45
zx8754
29.1k76398
asked Nov 22 at 20:21
Mario Coronel Maidana
1
When I perform the following operation nothing goes wrong, however if I run the
below code for a second or third time my vector aaa vector becomes NULL type and I can´t repeat the operation unless I close R to re-open it, it absolutely makes no sense, even worse, when I change the vector for another vector R states that is also NULL type, any idea of what to do?
aaa=c()
for(i in 1:95){
for(j in 1:length(codigos[,1])){
if(Base[i,3]==codigos[j,1]){
aaa[i]=codigos[j,2]
Base[i,3]=codigos[j,2]
}
}
}
r vector null
r vector null
edited Nov 22 at 20:45
zx8754
29.1k76398
asked Nov 22 at 20:21
Mario Coronel Maidana
1
edited Nov 22 at 20:45
zx8754
29.1k76398
asked Nov 22 at 20:21
Mario Coronel Maidana
1
edited Nov 22 at 20:45
zx8754
29.1k76398
edited Nov 22 at 20:45
zx8754
29.1k76398
edited Nov 22 at 20:45
zx8754
29.1k76398
29.1k76398
asked Nov 22 at 20:21
Mario Coronel Maidana
1
asked Nov 22 at 20:21
Mario Coronel Maidana
1
asked Nov 22 at 20:21
Mario Coronel Maidana
1
1
4
It is best to explain what you are trying to do. Provide example reproducible data and expected output.
– zx8754
Nov 22 at 20:47
maybe the if statement is always false so aaa is empty from the beggining.
– Csd
Nov 22 at 20:59
If you get some "result" the first time, and then nothing later , then it's probable that after the first run Base[i,3]==codigos[j,1] is never TRUE. Therefore, aaa[i]=codigos[j,2] is never run, and aaa stays at its "original value", which is NULL.
– lbusett
Nov 22 at 21:14
I forgot to mention, the first time I run the operation I do get results, the vector is fillep with actual values, but most of them are NA, do you think it has something to do?
– Mario Coronel Maidana
Nov 23 at 10:57
Difficult to say without seeing your data and knowing what you are trying to do. However, given the "logic" of your code, it is not unexpected that you get different results on different runs:Base[i,3]=codigos[j,2]modifies theBased.f. on the first run. Since you use a condition onBaseto decide what to do withaaa, different runs can have different results, unless you "reset"Baseto its original value.
– lbusett
Nov 23 at 14:09
add a comment |
4
It is best to explain what you are trying to do. Provide example reproducible data and expected output.
– zx8754
Nov 22 at 20:47
maybe the if statement is always false so aaa is empty from the beggining.
– Csd
Nov 22 at 20:59
If you get some "result" the first time, and then nothing later , then it's probable that after the first run Base[i,3]==codigos[j,1] is never TRUE. Therefore, aaa[i]=codigos[j,2] is never run, and aaa stays at its "original value", which is NULL.
– lbusett
Nov 22 at 21:14
I forgot to mention, the first time I run the operation I do get results, the vector is fillep with actual values, but most of them are NA, do you think it has something to do?
– Mario Coronel Maidana
Nov 23 at 10:57
Difficult to say without seeing your data and knowing what you are trying to do. However, given the "logic" of your code, it is not unexpected that you get different results on different runs:Base[i,3]=codigos[j,2]modifies theBased.f. on the first run. Since you use a condition onBaseto decide what to do withaaa, different runs can have different results, unless you "reset"Baseto its original value.
– lbusett
Nov 23 at 14:09
4
4
It is best to explain what you are trying to do. Provide example reproducible data and expected output.
– zx8754
Nov 22 at 20:47
It is best to explain what you are trying to do. Provide example reproducible data and expected output.
– zx8754
Nov 22 at 20:47
maybe the if statement is always false so aaa is empty from the beggining.
– Csd
Nov 22 at 20:59
maybe the if statement is always false so aaa is empty from the beggining.
– Csd
Nov 22 at 20:59
If you get some "result" the first time, and then nothing later , then it's probable that after the first run Base[i,3]==codigos[j,1] is never TRUE. Therefore, aaa[i]=codigos[j,2] is never run, and aaa stays at its "original value", which is NULL.
– lbusett
Nov 22 at 21:14
If you get some "result" the first time, and then nothing later , then it's probable that after the first run Base[i,3]==codigos[j,1] is never TRUE. Therefore, aaa[i]=codigos[j,2] is never run, and aaa stays at its "original value", which is NULL.
– lbusett
Nov 22 at 21:14
I forgot to mention, the first time I run the operation I do get results, the vector is fillep with actual values, but most of them are NA, do you think it has something to do?
– Mario Coronel Maidana
Nov 23 at 10:57
I forgot to mention, the first time I run the operation I do get results, the vector is fillep with actual values, but most of them are NA, do you think it has something to do?
– Mario Coronel Maidana
Nov 23 at 10:57
Difficult to say without seeing your data and knowing what you are trying to do. However, given the "logic" of your code, it is not unexpected that you get different results on different runs:
Base[i,3]=codigos[j,2] modifies the Base d.f. on the first run. Since you use a condition on Base to decide what to do with aaa, different runs can have different results, unless you "reset" Base to its original value.– lbusett
Nov 23 at 14:09
Difficult to say without seeing your data and knowing what you are trying to do. However, given the "logic" of your code, it is not unexpected that you get different results on different runs:
Base[i,3]=codigos[j,2] modifies the Base d.f. on the first run. Since you use a condition on Base to decide what to do with aaa, different runs can have different results, unless you "reset" Base to its original value.– lbusett
Nov 23 at 14:09
add a comment |
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4
It is best to explain what you are trying to do. Provide example reproducible data and expected output.
– zx8754
Nov 22 at 20:47
maybe the if statement is always false so aaa is empty from the beggining.
– Csd
Nov 22 at 20:59
If you get some "result" the first time, and then nothing later , then it's probable that after the first run Base[i,3]==codigos[j,1] is never TRUE. Therefore, aaa[i]=codigos[j,2] is never run, and aaa stays at its "original value", which is NULL.
– lbusett
Nov 22 at 21:14
I forgot to mention, the first time I run the operation I do get results, the vector is fillep with actual values, but most of them are NA, do you think it has something to do?
– Mario Coronel Maidana
Nov 23 at 10:57
Difficult to say without seeing your data and knowing what you are trying to do. However, given the "logic" of your code, it is not unexpected that you get different results on different runs:
Base[i,3]=codigos[j,2]modifies theBased.f. on the first run. Since you use a condition onBaseto decide what to do withaaa, different runs can have different results, unless you "reset"Baseto its original value.– lbusett
Nov 23 at 14:09