'str' object cannot be interpreted as an integer in python

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I am scrapping cricket test match details i have tested the results now i want to save it inside the file. while saving the html in file I am getting str object cannot be interedpreted as an integer

this is my code

for i in range(0, 2000):

    url = 'http://search.espncricinfo.com/ci/content/match/search.html?search=test;all=1;page=%s' %i

    html = requests.get(url)



    print ('Checking page %s of 2000' %(i+1))



    soupy = bs4.BeautifulSoup(html.text, 'html.parser')



    time.sleep(1)

    for new_host in soupy.findAll('a', {'class' : 'srchPlyrNmTxt'}):

        try:

            new_host = new_host['href']

        except:

            continue

        odiurl = BASE_URL + new_host

        new_host = odiurl

        print(new_host)

        html = requests.get(new_host).text

        with open('espncricinfo-fc/{0!s}'.format(str.split(new_host, "/")[4]), "wb") as f:

                f.write(html)

I am getting this error str object cannot be interedpreted as an integer

I am getting error in this line

with open('espncricinfo-fc/{0!s}'.format(str.split(new_host, "/")[4]), "wb") as f:

edited Nov 29 '18 at 5:51

asked Nov 29 '18 at 5:24

Tayyab Gulsher Vohra

1681318

Where are you getting the error? (which line?)

– Tomothy32
Nov 29 '18 at 5:25

last two lines i am getting error

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:26

What is BASE_URL?

– Shivam Singh
Nov 29 '18 at 5:36

You're writing in byte mode ("wb"), but I'm guessing you're trying to write str data rather than bytes. What happens if you change requests.get(new_host).text to requests.get(new_host).text.encode()?

– JaminSore
Nov 29 '18 at 5:39

@ShivamSingh BASE_URL = 'espncricinfo.com'

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:39

|
show 7 more comments

this is my code

for i in range(0, 2000):

    url = 'http://search.espncricinfo.com/ci/content/match/search.html?search=test;all=1;page=%s' %i

    html = requests.get(url)



    print ('Checking page %s of 2000' %(i+1))



    soupy = bs4.BeautifulSoup(html.text, 'html.parser')



    time.sleep(1)

    for new_host in soupy.findAll('a', {'class' : 'srchPlyrNmTxt'}):

        try:

            new_host = new_host['href']

        except:

            continue

        odiurl = BASE_URL + new_host

        new_host = odiurl

        print(new_host)

        html = requests.get(new_host).text

        with open('espncricinfo-fc/{0!s}'.format(str.split(new_host, "/")[4]), "wb") as f:

                f.write(html)

I am getting this error str object cannot be interedpreted as an integer

I am getting error in this line

with open('espncricinfo-fc/{0!s}'.format(str.split(new_host, "/")[4]), "wb") as f:

edited Nov 29 '18 at 5:51

asked Nov 29 '18 at 5:24

Tayyab Gulsher Vohra

1681318

Where are you getting the error? (which line?)

– Tomothy32
Nov 29 '18 at 5:25

last two lines i am getting error

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:26

What is BASE_URL?

– Shivam Singh
Nov 29 '18 at 5:36

You're writing in byte mode ("wb"), but I'm guessing you're trying to write str data rather than bytes. What happens if you change requests.get(new_host).text to requests.get(new_host).text.encode()?

– JaminSore
Nov 29 '18 at 5:39

@ShivamSingh BASE_URL = 'espncricinfo.com'

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:39

|
show 7 more comments

this is my code

for i in range(0, 2000):

    url = 'http://search.espncricinfo.com/ci/content/match/search.html?search=test;all=1;page=%s' %i

    html = requests.get(url)



    print ('Checking page %s of 2000' %(i+1))



    soupy = bs4.BeautifulSoup(html.text, 'html.parser')



    time.sleep(1)

    for new_host in soupy.findAll('a', {'class' : 'srchPlyrNmTxt'}):

        try:

            new_host = new_host['href']

        except:

            continue

        odiurl = BASE_URL + new_host

        new_host = odiurl

        print(new_host)

        html = requests.get(new_host).text

        with open('espncricinfo-fc/{0!s}'.format(str.split(new_host, "/")[4]), "wb") as f:

                f.write(html)

I am getting this error str object cannot be interedpreted as an integer

I am getting error in this line

with open('espncricinfo-fc/{0!s}'.format(str.split(new_host, "/")[4]), "wb") as f:

edited Nov 29 '18 at 5:51

asked Nov 29 '18 at 5:24

Tayyab Gulsher Vohra

1681318

this is my code

for i in range(0, 2000):

    url = 'http://search.espncricinfo.com/ci/content/match/search.html?search=test;all=1;page=%s' %i

    html = requests.get(url)



    print ('Checking page %s of 2000' %(i+1))



    soupy = bs4.BeautifulSoup(html.text, 'html.parser')



    time.sleep(1)

    for new_host in soupy.findAll('a', {'class' : 'srchPlyrNmTxt'}):

        try:

            new_host = new_host['href']

        except:

            continue

        odiurl = BASE_URL + new_host

        new_host = odiurl

        print(new_host)

        html = requests.get(new_host).text

        with open('espncricinfo-fc/{0!s}'.format(str.split(new_host, "/")[4]), "wb") as f:

                f.write(html)

I am getting this error str object cannot be interedpreted as an integer

I am getting error in this line

with open('espncricinfo-fc/{0!s}'.format(str.split(new_host, "/")[4]), "wb") as f:

python beautifulsoup

edited Nov 29 '18 at 5:51

asked Nov 29 '18 at 5:24

Tayyab Gulsher Vohra

1681318

edited Nov 29 '18 at 5:51

asked Nov 29 '18 at 5:24

Tayyab Gulsher Vohra

1681318

edited Nov 29 '18 at 5:51

asked Nov 29 '18 at 5:24

Tayyab Gulsher Vohra

1681318

asked Nov 29 '18 at 5:24

Tayyab Gulsher Vohra

1681318

asked Nov 29 '18 at 5:24

Tayyab Gulsher Vohra

1681318

Where are you getting the error? (which line?)

– Tomothy32
Nov 29 '18 at 5:25

last two lines i am getting error

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:26

What is BASE_URL?

– Shivam Singh
Nov 29 '18 at 5:36

You're writing in byte mode ("wb"), but I'm guessing you're trying to write str data rather than bytes. What happens if you change requests.get(new_host).text to requests.get(new_host).text.encode()?

– JaminSore
Nov 29 '18 at 5:39

@ShivamSingh BASE_URL = 'espncricinfo.com'

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:39

|
show 7 more comments

Where are you getting the error? (which line?)

– Tomothy32
Nov 29 '18 at 5:25

last two lines i am getting error

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:26

What is BASE_URL?

– Shivam Singh
Nov 29 '18 at 5:36

You're writing in byte mode ("wb"), but I'm guessing you're trying to write str data rather than bytes. What happens if you change requests.get(new_host).text to requests.get(new_host).text.encode()?

– JaminSore
Nov 29 '18 at 5:39

@ShivamSingh BASE_URL = 'espncricinfo.com'

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:39

Where are you getting the error? (which line?)

– Tomothy32
Nov 29 '18 at 5:25

last two lines i am getting error

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:26

What is BASE_URL?

– Shivam Singh
Nov 29 '18 at 5:36

You're writing in byte mode ("wb"), but I'm guessing you're trying to write str data rather than bytes. What happens if you change requests.get(new_host).text to requests.get(new_host).text.encode()?

– JaminSore
Nov 29 '18 at 5:39

@ShivamSingh BASE_URL = 'espncricinfo.com'

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:39

|
show 7 more comments

2 Answers
2

active

oldest

votes

If you are using Python 3.x, try changing the last line to

f.write(bytes(html, 'UTF-8'))

Also try this,

new_host = str(new_host['href'])

edited Nov 29 '18 at 5:56

answered Nov 29 '18 at 5:43

Shivam Singh

1,271158

I am getting the same error as before 'str' object cannot be interpreted as an integer

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:47

Updated the answer

– Shivam Singh
Nov 29 '18 at 5:56

Shivam the error has been eliminated but nothing is saving the file...

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:00

You need to fix the split function, It should be str.split(new_host, "/")[6] and BASE_URL = "http://espncricinfo.com"

– Shivam Singh
Nov 29 '18 at 6:01

Shivam done both of these above edit but still it is not saving in the file.

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:05

|
show 2 more comments

The problem is your print statement.
It should read

print('checking %d etc.' % (i + 1))

answered Nov 29 '18 at 5:40

rhubarbdog

37119

its working i have checked i have also removed this line but the error remains same..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:41

What line number, does new_host as a class have a __str__ method. You print it and use str.split in the final line

– rhubarbdog
Nov 29 '18 at 5:47

its a variable..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:50

What does soupy.findall('a', { ... }) return. A range or a list of strings. You set new_host to BASE_URL + new_host. After setting it to a dictionary lookup new_host['href']

– rhubarbdog
Nov 29 '18 at 5:58

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

If you are using Python 3.x, try changing the last line to

f.write(bytes(html, 'UTF-8'))

Also try this,

new_host = str(new_host['href'])

edited Nov 29 '18 at 5:56

answered Nov 29 '18 at 5:43

Shivam Singh

1,271158

I am getting the same error as before 'str' object cannot be interpreted as an integer

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:47

Updated the answer

– Shivam Singh
Nov 29 '18 at 5:56

Shivam the error has been eliminated but nothing is saving the file...

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:00

You need to fix the split function, It should be str.split(new_host, "/")[6] and BASE_URL = "http://espncricinfo.com"

– Shivam Singh
Nov 29 '18 at 6:01

Shivam done both of these above edit but still it is not saving in the file.

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:05

|
show 2 more comments

If you are using Python 3.x, try changing the last line to

f.write(bytes(html, 'UTF-8'))

Also try this,

new_host = str(new_host['href'])

edited Nov 29 '18 at 5:56

answered Nov 29 '18 at 5:43

Shivam Singh

1,271158

I am getting the same error as before 'str' object cannot be interpreted as an integer

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:47

Updated the answer

– Shivam Singh
Nov 29 '18 at 5:56

Shivam the error has been eliminated but nothing is saving the file...

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:00

You need to fix the split function, It should be str.split(new_host, "/")[6] and BASE_URL = "http://espncricinfo.com"

– Shivam Singh
Nov 29 '18 at 6:01

Shivam done both of these above edit but still it is not saving in the file.

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:05

|
show 2 more comments

If you are using Python 3.x, try changing the last line to

f.write(bytes(html, 'UTF-8'))

Also try this,

new_host = str(new_host['href'])

edited Nov 29 '18 at 5:56

answered Nov 29 '18 at 5:43

Shivam Singh

1,271158

If you are using Python 3.x, try changing the last line to

f.write(bytes(html, 'UTF-8'))

Also try this,

new_host = str(new_host['href'])

edited Nov 29 '18 at 5:56

answered Nov 29 '18 at 5:43

Shivam Singh

1,271158

edited Nov 29 '18 at 5:56

answered Nov 29 '18 at 5:43

Shivam Singh

1,271158

answered Nov 29 '18 at 5:43

Shivam Singh

1,271158

answered Nov 29 '18 at 5:43

Shivam Singh

1,271158

I am getting the same error as before 'str' object cannot be interpreted as an integer

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:47

Updated the answer

– Shivam Singh
Nov 29 '18 at 5:56

Shivam the error has been eliminated but nothing is saving the file...

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:00

You need to fix the split function, It should be str.split(new_host, "/")[6] and BASE_URL = "http://espncricinfo.com"

– Shivam Singh
Nov 29 '18 at 6:01

Shivam done both of these above edit but still it is not saving in the file.

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:05

|
show 2 more comments

I am getting the same error as before 'str' object cannot be interpreted as an integer

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:47

Updated the answer

– Shivam Singh
Nov 29 '18 at 5:56

Shivam the error has been eliminated but nothing is saving the file...

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:00

You need to fix the split function, It should be str.split(new_host, "/")[6] and BASE_URL = "http://espncricinfo.com"

– Shivam Singh
Nov 29 '18 at 6:01

Shivam done both of these above edit but still it is not saving in the file.

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:05

I am getting the same error as before 'str' object cannot be interpreted as an integer

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:47

Updated the answer

– Shivam Singh
Nov 29 '18 at 5:56

Shivam the error has been eliminated but nothing is saving the file...

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:00

You need to fix the split function, It should be str.split(new_host, "/")[6] and BASE_URL = "http://espncricinfo.com"

– Shivam Singh
Nov 29 '18 at 6:01

Shivam done both of these above edit but still it is not saving in the file.

– Tayyab Gulsher Vohra
Nov 29 '18 at 6:05

|
show 2 more comments

The problem is your print statement.
It should read

print('checking %d etc.' % (i + 1))

answered Nov 29 '18 at 5:40

rhubarbdog

37119

its working i have checked i have also removed this line but the error remains same..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:41

What line number, does new_host as a class have a __str__ method. You print it and use str.split in the final line

– rhubarbdog
Nov 29 '18 at 5:47

its a variable..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:50

What does soupy.findall('a', { ... }) return. A range or a list of strings. You set new_host to BASE_URL + new_host. After setting it to a dictionary lookup new_host['href']

– rhubarbdog
Nov 29 '18 at 5:58

add a comment |

The problem is your print statement.
It should read

print('checking %d etc.' % (i + 1))

answered Nov 29 '18 at 5:40

rhubarbdog

37119

its working i have checked i have also removed this line but the error remains same..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:41

What line number, does new_host as a class have a __str__ method. You print it and use str.split in the final line

– rhubarbdog
Nov 29 '18 at 5:47

its a variable..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:50

What does soupy.findall('a', { ... }) return. A range or a list of strings. You set new_host to BASE_URL + new_host. After setting it to a dictionary lookup new_host['href']

– rhubarbdog
Nov 29 '18 at 5:58

add a comment |

The problem is your print statement.
It should read

print('checking %d etc.' % (i + 1))

answered Nov 29 '18 at 5:40

rhubarbdog

37119

The problem is your print statement.
It should read

print('checking %d etc.' % (i + 1))

answered Nov 29 '18 at 5:40

rhubarbdog

37119

answered Nov 29 '18 at 5:40

rhubarbdog

37119

answered Nov 29 '18 at 5:40

rhubarbdog

37119

answered Nov 29 '18 at 5:40

rhubarbdog

37119

its working i have checked i have also removed this line but the error remains same..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:41

What line number, does new_host as a class have a __str__ method. You print it and use str.split in the final line

– rhubarbdog
Nov 29 '18 at 5:47

its a variable..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:50

What does soupy.findall('a', { ... }) return. A range or a list of strings. You set new_host to BASE_URL + new_host. After setting it to a dictionary lookup new_host['href']

– rhubarbdog
Nov 29 '18 at 5:58

add a comment |

its working i have checked i have also removed this line but the error remains same..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:41

What line number, does new_host as a class have a __str__ method. You print it and use str.split in the final line

– rhubarbdog
Nov 29 '18 at 5:47

its a variable..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:50

What does soupy.findall('a', { ... }) return. A range or a list of strings. You set new_host to BASE_URL + new_host. After setting it to a dictionary lookup new_host['href']

– rhubarbdog
Nov 29 '18 at 5:58

its working i have checked i have also removed this line but the error remains same..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:41

What line number, does new_host as a class have a __str__ method. You print it and use str.split in the final line

– rhubarbdog
Nov 29 '18 at 5:47

its a variable..

– Tayyab Gulsher Vohra
Nov 29 '18 at 5:50

What does soupy.findall('a', { ... }) return. A range or a list of strings. You set new_host to BASE_URL + new_host. After setting it to a dictionary lookup new_host['href']

– rhubarbdog
Nov 29 '18 at 5:58

add a comment |

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