Issue with time command
-1
When I run several background jobs, I need to get a runtime for the set of jobs.
I use the following example successfully:
$ sleep 10 &
$ time wait
real 0m9.74s
user 0m0.00s
sys 0m0.00s
However, if I try to format the output to seconds, I get the following error:
$ time -f %e wait
time: cannot run wait: No such file or directory
0.00
This only seems to happen with shell builtins. Is there a workaround for this?
linux centos7
asked Nov 28 '18 at 15:02
usaousao
192
add a comment |
-1
When I run several background jobs, I need to get a runtime for the set of jobs.
I use the following example successfully:
$ sleep 10 &
$ time wait
real 0m9.74s
user 0m0.00s
sys 0m0.00s
However, if I try to format the output to seconds, I get the following error:
$ time -f %e wait
time: cannot run wait: No such file or directory
0.00
This only seems to happen with shell builtins. Is there a workaround for this?
linux centos7
asked Nov 28 '18 at 15:02
usaousao
192
Try TIMEFORMAT environment
– n.m.
Nov 28 '18 at 15:10
Typically if you want to time a shell built-in, you can do that by doing something like "time /bin/bash -c 'wait'" Unfortunately in this case, the wait is waiting on sub-processes associated with the shell it is running in, not the background process you started outside of the shell.
– Lewis M
Nov 28 '18 at 15:11
add a comment |
-1
-1
-1
When I run several background jobs, I need to get a runtime for the set of jobs.
I use the following example successfully:
$ sleep 10 &
$ time wait
real 0m9.74s
user 0m0.00s
sys 0m0.00s
However, if I try to format the output to seconds, I get the following error:
$ time -f %e wait
time: cannot run wait: No such file or directory
0.00
This only seems to happen with shell builtins. Is there a workaround for this?
linux centos7
asked Nov 28 '18 at 15:02
usaousao
192
When I run several background jobs, I need to get a runtime for the set of jobs.
I use the following example successfully:
$ sleep 10 &
$ time wait
real 0m9.74s
user 0m0.00s
sys 0m0.00s
However, if I try to format the output to seconds, I get the following error:
$ time -f %e wait
time: cannot run wait: No such file or directory
0.00
This only seems to happen with shell builtins. Is there a workaround for this?
linux centos7
linux centos7
asked Nov 28 '18 at 15:02
usaousao
192
asked Nov 28 '18 at 15:02
usaousao
192
asked Nov 28 '18 at 15:02
usaousao
192
asked Nov 28 '18 at 15:02
usaousao
192
asked Nov 28 '18 at 15:02
usaousao
192
192
Try TIMEFORMAT environment
– n.m.
Nov 28 '18 at 15:10
Typically if you want to time a shell built-in, you can do that by doing something like "time /bin/bash -c 'wait'" Unfortunately in this case, the wait is waiting on sub-processes associated with the shell it is running in, not the background process you started outside of the shell.
– Lewis M
Nov 28 '18 at 15:11
add a comment |
Try TIMEFORMAT environment
– n.m.
Nov 28 '18 at 15:10
Typically if you want to time a shell built-in, you can do that by doing something like "time /bin/bash -c 'wait'" Unfortunately in this case, the wait is waiting on sub-processes associated with the shell it is running in, not the background process you started outside of the shell.
– Lewis M
Nov 28 '18 at 15:11
Try TIMEFORMAT environment
– n.m.
Nov 28 '18 at 15:10
Try TIMEFORMAT environment
– n.m.
Nov 28 '18 at 15:10
Typically if you want to time a shell built-in, you can do that by doing something like "time /bin/bash -c 'wait'" Unfortunately in this case, the wait is waiting on sub-processes associated with the shell it is running in, not the background process you started outside of the shell.
– Lewis M
Nov 28 '18 at 15:11
Typically if you want to time a shell built-in, you can do that by doing something like "time /bin/bash -c 'wait'" Unfortunately in this case, the wait is waiting on sub-processes associated with the shell it is running in, not the background process you started outside of the shell.
– Lewis M
Nov 28 '18 at 15:11
add a comment |
1 Answer
1
active
oldest
votes
1
The problem here is two-fold.
- we don't know if you're using the bash (assuming you're using the centos default shell) built-in or the binary
timecommand. - in either case
waitis a bash built-in
Ways to deal with this:
/usr/bin/time -f %e bash -c wait
TIMEFORMAT="%pR" time bash -c wait
answered Nov 28 '18 at 16:52
tinktink
6,89232835
add a comment |
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1 Answer
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active
oldest
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oldest
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votes
1
The problem here is two-fold.
- we don't know if you're using the bash (assuming you're using the centos default shell) built-in or the binary
timecommand. - in either case
waitis a bash built-in
Ways to deal with this:
/usr/bin/time -f %e bash -c wait
TIMEFORMAT="%pR" time bash -c wait
answered Nov 28 '18 at 16:52
tinktink
6,89232835
add a comment |
1
The problem here is two-fold.
- we don't know if you're using the bash (assuming you're using the centos default shell) built-in or the binary
timecommand. - in either case
waitis a bash built-in
Ways to deal with this:
/usr/bin/time -f %e bash -c wait
TIMEFORMAT="%pR" time bash -c wait
answered Nov 28 '18 at 16:52
tinktink
6,89232835
add a comment |
1
1
1
The problem here is two-fold.
- we don't know if you're using the bash (assuming you're using the centos default shell) built-in or the binary
timecommand. - in either case
waitis a bash built-in
Ways to deal with this:
/usr/bin/time -f %e bash -c wait
TIMEFORMAT="%pR" time bash -c wait
answered Nov 28 '18 at 16:52
tinktink
6,89232835
The problem here is two-fold.
- we don't know if you're using the bash (assuming you're using the centos default shell) built-in or the binary
timecommand. - in either case
waitis a bash built-in
Ways to deal with this:
/usr/bin/time -f %e bash -c wait
TIMEFORMAT="%pR" time bash -c wait
answered Nov 28 '18 at 16:52
tinktink
6,89232835
answered Nov 28 '18 at 16:52
tinktink
6,89232835
answered Nov 28 '18 at 16:52
tinktink
6,89232835
answered Nov 28 '18 at 16:52
tinktink
6,89232835
6,89232835
add a comment |
add a comment |
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Try TIMEFORMAT environment
– n.m.
Nov 28 '18 at 15:10
Typically if you want to time a shell built-in, you can do that by doing something like "time /bin/bash -c 'wait'" Unfortunately in this case, the wait is waiting on sub-processes associated with the shell it is running in, not the background process you started outside of the shell.
– Lewis M
Nov 28 '18 at 15:11