Adding words from a file to a dictionary












0















I want to add each word from a text file to a dictionary, how do I do this?



(I have a file 'words.txt', I have opened and read the file and the list of words is in the variable "lines" below)



d = {}

for i in lines:
for word in i.split():
d[???] = word


What code do I put where the '???' is?



I basically want the dictionary to look like this:



{0: firstword, 1: secondword, 2: thirdword, 3: fourthword...}


I figured that getting the index position of each word in the list could work but I'm not exactly sure how to do this.



It doesn't seem too complicated to do but I'm stuck.










share|improve this question























  • If you just want have separate index for each element python2.7: d[len(d)] = word, python3: d[str(len(d))] = word

    – Filip Młynarski
    Nov 24 '18 at 15:55








  • 6





    Why do you need a dictionary for that? Why not a plain list containing all words from the file?

    – Some programmer dude
    Nov 24 '18 at 15:57











  • @FilipMłynarski Thanks

    – Mandingo
    Nov 24 '18 at 19:32











  • @Someprogrammerdude It's for a larger program that I need to write for my coursework. It's what they wanted as part of their instructions. Most of the tasks that were set specified a specific way of doing it - whether convenient or efficient or not.

    – Mandingo
    Nov 24 '18 at 19:33


















0















I want to add each word from a text file to a dictionary, how do I do this?



(I have a file 'words.txt', I have opened and read the file and the list of words is in the variable "lines" below)



d = {}

for i in lines:
for word in i.split():
d[???] = word


What code do I put where the '???' is?



I basically want the dictionary to look like this:



{0: firstword, 1: secondword, 2: thirdword, 3: fourthword...}


I figured that getting the index position of each word in the list could work but I'm not exactly sure how to do this.



It doesn't seem too complicated to do but I'm stuck.










share|improve this question























  • If you just want have separate index for each element python2.7: d[len(d)] = word, python3: d[str(len(d))] = word

    – Filip Młynarski
    Nov 24 '18 at 15:55








  • 6





    Why do you need a dictionary for that? Why not a plain list containing all words from the file?

    – Some programmer dude
    Nov 24 '18 at 15:57











  • @FilipMłynarski Thanks

    – Mandingo
    Nov 24 '18 at 19:32











  • @Someprogrammerdude It's for a larger program that I need to write for my coursework. It's what they wanted as part of their instructions. Most of the tasks that were set specified a specific way of doing it - whether convenient or efficient or not.

    – Mandingo
    Nov 24 '18 at 19:33
















0












0








0








I want to add each word from a text file to a dictionary, how do I do this?



(I have a file 'words.txt', I have opened and read the file and the list of words is in the variable "lines" below)



d = {}

for i in lines:
for word in i.split():
d[???] = word


What code do I put where the '???' is?



I basically want the dictionary to look like this:



{0: firstword, 1: secondword, 2: thirdword, 3: fourthword...}


I figured that getting the index position of each word in the list could work but I'm not exactly sure how to do this.



It doesn't seem too complicated to do but I'm stuck.










share|improve this question














I want to add each word from a text file to a dictionary, how do I do this?



(I have a file 'words.txt', I have opened and read the file and the list of words is in the variable "lines" below)



d = {}

for i in lines:
for word in i.split():
d[???] = word


What code do I put where the '???' is?



I basically want the dictionary to look like this:



{0: firstword, 1: secondword, 2: thirdword, 3: fourthword...}


I figured that getting the index position of each word in the list could work but I'm not exactly sure how to do this.



It doesn't seem too complicated to do but I'm stuck.







python dictionary






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 24 '18 at 15:53









MandingoMandingo

34229




34229













  • If you just want have separate index for each element python2.7: d[len(d)] = word, python3: d[str(len(d))] = word

    – Filip Młynarski
    Nov 24 '18 at 15:55








  • 6





    Why do you need a dictionary for that? Why not a plain list containing all words from the file?

    – Some programmer dude
    Nov 24 '18 at 15:57











  • @FilipMłynarski Thanks

    – Mandingo
    Nov 24 '18 at 19:32











  • @Someprogrammerdude It's for a larger program that I need to write for my coursework. It's what they wanted as part of their instructions. Most of the tasks that were set specified a specific way of doing it - whether convenient or efficient or not.

    – Mandingo
    Nov 24 '18 at 19:33





















  • If you just want have separate index for each element python2.7: d[len(d)] = word, python3: d[str(len(d))] = word

    – Filip Młynarski
    Nov 24 '18 at 15:55








  • 6





    Why do you need a dictionary for that? Why not a plain list containing all words from the file?

    – Some programmer dude
    Nov 24 '18 at 15:57











  • @FilipMłynarski Thanks

    – Mandingo
    Nov 24 '18 at 19:32











  • @Someprogrammerdude It's for a larger program that I need to write for my coursework. It's what they wanted as part of their instructions. Most of the tasks that were set specified a specific way of doing it - whether convenient or efficient or not.

    – Mandingo
    Nov 24 '18 at 19:33



















If you just want have separate index for each element python2.7: d[len(d)] = word, python3: d[str(len(d))] = word

– Filip Młynarski
Nov 24 '18 at 15:55







If you just want have separate index for each element python2.7: d[len(d)] = word, python3: d[str(len(d))] = word

– Filip Młynarski
Nov 24 '18 at 15:55






6




6





Why do you need a dictionary for that? Why not a plain list containing all words from the file?

– Some programmer dude
Nov 24 '18 at 15:57





Why do you need a dictionary for that? Why not a plain list containing all words from the file?

– Some programmer dude
Nov 24 '18 at 15:57













@FilipMłynarski Thanks

– Mandingo
Nov 24 '18 at 19:32





@FilipMłynarski Thanks

– Mandingo
Nov 24 '18 at 19:32













@Someprogrammerdude It's for a larger program that I need to write for my coursework. It's what they wanted as part of their instructions. Most of the tasks that were set specified a specific way of doing it - whether convenient or efficient or not.

– Mandingo
Nov 24 '18 at 19:33







@Someprogrammerdude It's for a larger program that I need to write for my coursework. It's what they wanted as part of their instructions. Most of the tasks that were set specified a specific way of doing it - whether convenient or efficient or not.

– Mandingo
Nov 24 '18 at 19:33














5 Answers
5






active

oldest

votes


















1














First open a file and write some lines.



fname = 'textfile.txt'
with open(fname, 'w') as textfile:
textfile.write('zero one two three four fiven')
textfile.write('six seven eight nine ten')


Enumerate through the words in whichever fashion you desire. If you use a generator expression it works nicely with a dict comprehension.



word_positions = {}
with open(fname, 'r') as textfile:
words = (word for line in textfile.readlines() for word in line.split())
word_positions = {i: word for i, word in enumerate(words)}


This yields,



word_positions

{0: 'zero',
1: 'one',
2: 'two',
3: 'three',
4: 'four',
5: 'five',
6: 'six',
7: 'seven',
8: 'eight',
9: 'nine',
10: 'ten'}





share|improve this answer
























  • if you add a middle line with duplicates like "textfile.write('zero one two three four fiven')", your output contains the duplicates.

    – user1269942
    Nov 24 '18 at 16:41











  • The question doesn't seem concerned with duplicates though. It's very easy to avoid duplicates by using a set if need be.

    – Austin Mackillop
    Nov 24 '18 at 17:05





















1














say you have a variable words having list of words ['firstword', 'secondword', 'thirdword', 'fourthword']



so your code would be like:



d = {}
for k, v in enumerate(words):
d[k] = v





share|improve this answer































    1














    You can keep track of the "current index" in a separate variable c and use that as the value for the word in your dictionary:



    d = {}
    c = 0

    for i in lines:
    for word in i.split():
    d[word] = c
    c += 1


    Note that here the dictionary will store the highest index of the duplicated word.






    share|improve this answer































      1














      Each line overwrites the line before it in your dictionary. But you can work around that like:



      d = {}
      k = 0
      for i in lines:
      for word in i.split():
      d[str(k)] = word
      k = k + 1


      Why are you using dictionary for this? Dictionaries are useful when they are used with keys with meanings. You could've just used a list for this task.



      Also, you can increase the performance by preallocating your list and then fill it with your algorithm.






      share|improve this answer































        1














        There are many answers questioning why you need to do this which is valid, however I'll try and answer the direct question. Also, I think dealing with duplicates is necessary. The lower index(first time word is seen) takes precedence...which is an assumption on my part, but it makes sense considering your question.



        #first populate a word:index dictionary
        #ensure duplicates don't overwrite...for this use "in" which is fast
        d1 = {}
        ix = 0
        for i in lines:
        for word in i.split():
        if word not in d1:
        #only add word to the dict if it is NOT already in (addressing duplicates)
        d1[word] = ix
        ix += 1

        #now "reverse" the dict
        d = {} #new dict
        for word in d1:
        d[d1[word]] = word


        now you have a dict word:index with unique words+index






        share|improve this answer

























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          5 Answers
          5






          active

          oldest

          votes








          5 Answers
          5






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          First open a file and write some lines.



          fname = 'textfile.txt'
          with open(fname, 'w') as textfile:
          textfile.write('zero one two three four fiven')
          textfile.write('six seven eight nine ten')


          Enumerate through the words in whichever fashion you desire. If you use a generator expression it works nicely with a dict comprehension.



          word_positions = {}
          with open(fname, 'r') as textfile:
          words = (word for line in textfile.readlines() for word in line.split())
          word_positions = {i: word for i, word in enumerate(words)}


          This yields,



          word_positions

          {0: 'zero',
          1: 'one',
          2: 'two',
          3: 'three',
          4: 'four',
          5: 'five',
          6: 'six',
          7: 'seven',
          8: 'eight',
          9: 'nine',
          10: 'ten'}





          share|improve this answer
























          • if you add a middle line with duplicates like "textfile.write('zero one two three four fiven')", your output contains the duplicates.

            – user1269942
            Nov 24 '18 at 16:41











          • The question doesn't seem concerned with duplicates though. It's very easy to avoid duplicates by using a set if need be.

            – Austin Mackillop
            Nov 24 '18 at 17:05


















          1














          First open a file and write some lines.



          fname = 'textfile.txt'
          with open(fname, 'w') as textfile:
          textfile.write('zero one two three four fiven')
          textfile.write('six seven eight nine ten')


          Enumerate through the words in whichever fashion you desire. If you use a generator expression it works nicely with a dict comprehension.



          word_positions = {}
          with open(fname, 'r') as textfile:
          words = (word for line in textfile.readlines() for word in line.split())
          word_positions = {i: word for i, word in enumerate(words)}


          This yields,



          word_positions

          {0: 'zero',
          1: 'one',
          2: 'two',
          3: 'three',
          4: 'four',
          5: 'five',
          6: 'six',
          7: 'seven',
          8: 'eight',
          9: 'nine',
          10: 'ten'}





          share|improve this answer
























          • if you add a middle line with duplicates like "textfile.write('zero one two three four fiven')", your output contains the duplicates.

            – user1269942
            Nov 24 '18 at 16:41











          • The question doesn't seem concerned with duplicates though. It's very easy to avoid duplicates by using a set if need be.

            – Austin Mackillop
            Nov 24 '18 at 17:05
















          1












          1








          1







          First open a file and write some lines.



          fname = 'textfile.txt'
          with open(fname, 'w') as textfile:
          textfile.write('zero one two three four fiven')
          textfile.write('six seven eight nine ten')


          Enumerate through the words in whichever fashion you desire. If you use a generator expression it works nicely with a dict comprehension.



          word_positions = {}
          with open(fname, 'r') as textfile:
          words = (word for line in textfile.readlines() for word in line.split())
          word_positions = {i: word for i, word in enumerate(words)}


          This yields,



          word_positions

          {0: 'zero',
          1: 'one',
          2: 'two',
          3: 'three',
          4: 'four',
          5: 'five',
          6: 'six',
          7: 'seven',
          8: 'eight',
          9: 'nine',
          10: 'ten'}





          share|improve this answer













          First open a file and write some lines.



          fname = 'textfile.txt'
          with open(fname, 'w') as textfile:
          textfile.write('zero one two three four fiven')
          textfile.write('six seven eight nine ten')


          Enumerate through the words in whichever fashion you desire. If you use a generator expression it works nicely with a dict comprehension.



          word_positions = {}
          with open(fname, 'r') as textfile:
          words = (word for line in textfile.readlines() for word in line.split())
          word_positions = {i: word for i, word in enumerate(words)}


          This yields,



          word_positions

          {0: 'zero',
          1: 'one',
          2: 'two',
          3: 'three',
          4: 'four',
          5: 'five',
          6: 'six',
          7: 'seven',
          8: 'eight',
          9: 'nine',
          10: 'ten'}






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 24 '18 at 16:27









          Austin MackillopAustin Mackillop

          35517




          35517













          • if you add a middle line with duplicates like "textfile.write('zero one two three four fiven')", your output contains the duplicates.

            – user1269942
            Nov 24 '18 at 16:41











          • The question doesn't seem concerned with duplicates though. It's very easy to avoid duplicates by using a set if need be.

            – Austin Mackillop
            Nov 24 '18 at 17:05





















          • if you add a middle line with duplicates like "textfile.write('zero one two three four fiven')", your output contains the duplicates.

            – user1269942
            Nov 24 '18 at 16:41











          • The question doesn't seem concerned with duplicates though. It's very easy to avoid duplicates by using a set if need be.

            – Austin Mackillop
            Nov 24 '18 at 17:05



















          if you add a middle line with duplicates like "textfile.write('zero one two three four fiven')", your output contains the duplicates.

          – user1269942
          Nov 24 '18 at 16:41





          if you add a middle line with duplicates like "textfile.write('zero one two three four fiven')", your output contains the duplicates.

          – user1269942
          Nov 24 '18 at 16:41













          The question doesn't seem concerned with duplicates though. It's very easy to avoid duplicates by using a set if need be.

          – Austin Mackillop
          Nov 24 '18 at 17:05







          The question doesn't seem concerned with duplicates though. It's very easy to avoid duplicates by using a set if need be.

          – Austin Mackillop
          Nov 24 '18 at 17:05















          1














          say you have a variable words having list of words ['firstword', 'secondword', 'thirdword', 'fourthword']



          so your code would be like:



          d = {}
          for k, v in enumerate(words):
          d[k] = v





          share|improve this answer




























            1














            say you have a variable words having list of words ['firstword', 'secondword', 'thirdword', 'fourthword']



            so your code would be like:



            d = {}
            for k, v in enumerate(words):
            d[k] = v





            share|improve this answer


























              1












              1








              1







              say you have a variable words having list of words ['firstword', 'secondword', 'thirdword', 'fourthword']



              so your code would be like:



              d = {}
              for k, v in enumerate(words):
              d[k] = v





              share|improve this answer













              say you have a variable words having list of words ['firstword', 'secondword', 'thirdword', 'fourthword']



              so your code would be like:



              d = {}
              for k, v in enumerate(words):
              d[k] = v






              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Nov 24 '18 at 15:58









              GahanGahan

              2,79531232




              2,79531232























                  1














                  You can keep track of the "current index" in a separate variable c and use that as the value for the word in your dictionary:



                  d = {}
                  c = 0

                  for i in lines:
                  for word in i.split():
                  d[word] = c
                  c += 1


                  Note that here the dictionary will store the highest index of the duplicated word.






                  share|improve this answer




























                    1














                    You can keep track of the "current index" in a separate variable c and use that as the value for the word in your dictionary:



                    d = {}
                    c = 0

                    for i in lines:
                    for word in i.split():
                    d[word] = c
                    c += 1


                    Note that here the dictionary will store the highest index of the duplicated word.






                    share|improve this answer


























                      1












                      1








                      1







                      You can keep track of the "current index" in a separate variable c and use that as the value for the word in your dictionary:



                      d = {}
                      c = 0

                      for i in lines:
                      for word in i.split():
                      d[word] = c
                      c += 1


                      Note that here the dictionary will store the highest index of the duplicated word.






                      share|improve this answer













                      You can keep track of the "current index" in a separate variable c and use that as the value for the word in your dictionary:



                      d = {}
                      c = 0

                      for i in lines:
                      for word in i.split():
                      d[word] = c
                      c += 1


                      Note that here the dictionary will store the highest index of the duplicated word.







                      share|improve this answer












                      share|improve this answer



                      share|improve this answer










                      answered Nov 24 '18 at 15:59









                      sliderslider

                      8,21811129




                      8,21811129























                          1














                          Each line overwrites the line before it in your dictionary. But you can work around that like:



                          d = {}
                          k = 0
                          for i in lines:
                          for word in i.split():
                          d[str(k)] = word
                          k = k + 1


                          Why are you using dictionary for this? Dictionaries are useful when they are used with keys with meanings. You could've just used a list for this task.



                          Also, you can increase the performance by preallocating your list and then fill it with your algorithm.






                          share|improve this answer




























                            1














                            Each line overwrites the line before it in your dictionary. But you can work around that like:



                            d = {}
                            k = 0
                            for i in lines:
                            for word in i.split():
                            d[str(k)] = word
                            k = k + 1


                            Why are you using dictionary for this? Dictionaries are useful when they are used with keys with meanings. You could've just used a list for this task.



                            Also, you can increase the performance by preallocating your list and then fill it with your algorithm.






                            share|improve this answer


























                              1












                              1








                              1







                              Each line overwrites the line before it in your dictionary. But you can work around that like:



                              d = {}
                              k = 0
                              for i in lines:
                              for word in i.split():
                              d[str(k)] = word
                              k = k + 1


                              Why are you using dictionary for this? Dictionaries are useful when they are used with keys with meanings. You could've just used a list for this task.



                              Also, you can increase the performance by preallocating your list and then fill it with your algorithm.






                              share|improve this answer













                              Each line overwrites the line before it in your dictionary. But you can work around that like:



                              d = {}
                              k = 0
                              for i in lines:
                              for word in i.split():
                              d[str(k)] = word
                              k = k + 1


                              Why are you using dictionary for this? Dictionaries are useful when they are used with keys with meanings. You could've just used a list for this task.



                              Also, you can increase the performance by preallocating your list and then fill it with your algorithm.







                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered Nov 24 '18 at 16:03









                              Talip Tolga SarıTalip Tolga Sarı

                              836




                              836























                                  1














                                  There are many answers questioning why you need to do this which is valid, however I'll try and answer the direct question. Also, I think dealing with duplicates is necessary. The lower index(first time word is seen) takes precedence...which is an assumption on my part, but it makes sense considering your question.



                                  #first populate a word:index dictionary
                                  #ensure duplicates don't overwrite...for this use "in" which is fast
                                  d1 = {}
                                  ix = 0
                                  for i in lines:
                                  for word in i.split():
                                  if word not in d1:
                                  #only add word to the dict if it is NOT already in (addressing duplicates)
                                  d1[word] = ix
                                  ix += 1

                                  #now "reverse" the dict
                                  d = {} #new dict
                                  for word in d1:
                                  d[d1[word]] = word


                                  now you have a dict word:index with unique words+index






                                  share|improve this answer






























                                    1














                                    There are many answers questioning why you need to do this which is valid, however I'll try and answer the direct question. Also, I think dealing with duplicates is necessary. The lower index(first time word is seen) takes precedence...which is an assumption on my part, but it makes sense considering your question.



                                    #first populate a word:index dictionary
                                    #ensure duplicates don't overwrite...for this use "in" which is fast
                                    d1 = {}
                                    ix = 0
                                    for i in lines:
                                    for word in i.split():
                                    if word not in d1:
                                    #only add word to the dict if it is NOT already in (addressing duplicates)
                                    d1[word] = ix
                                    ix += 1

                                    #now "reverse" the dict
                                    d = {} #new dict
                                    for word in d1:
                                    d[d1[word]] = word


                                    now you have a dict word:index with unique words+index






                                    share|improve this answer




























                                      1












                                      1








                                      1







                                      There are many answers questioning why you need to do this which is valid, however I'll try and answer the direct question. Also, I think dealing with duplicates is necessary. The lower index(first time word is seen) takes precedence...which is an assumption on my part, but it makes sense considering your question.



                                      #first populate a word:index dictionary
                                      #ensure duplicates don't overwrite...for this use "in" which is fast
                                      d1 = {}
                                      ix = 0
                                      for i in lines:
                                      for word in i.split():
                                      if word not in d1:
                                      #only add word to the dict if it is NOT already in (addressing duplicates)
                                      d1[word] = ix
                                      ix += 1

                                      #now "reverse" the dict
                                      d = {} #new dict
                                      for word in d1:
                                      d[d1[word]] = word


                                      now you have a dict word:index with unique words+index






                                      share|improve this answer















                                      There are many answers questioning why you need to do this which is valid, however I'll try and answer the direct question. Also, I think dealing with duplicates is necessary. The lower index(first time word is seen) takes precedence...which is an assumption on my part, but it makes sense considering your question.



                                      #first populate a word:index dictionary
                                      #ensure duplicates don't overwrite...for this use "in" which is fast
                                      d1 = {}
                                      ix = 0
                                      for i in lines:
                                      for word in i.split():
                                      if word not in d1:
                                      #only add word to the dict if it is NOT already in (addressing duplicates)
                                      d1[word] = ix
                                      ix += 1

                                      #now "reverse" the dict
                                      d = {} #new dict
                                      for word in d1:
                                      d[d1[word]] = word


                                      now you have a dict word:index with unique words+index







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                                      edited Nov 24 '18 at 16:40

























                                      answered Nov 24 '18 at 16:25









                                      user1269942user1269942

                                      2,1301420




                                      2,1301420






























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