Removing text from multiple tags from each in xml

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}

I'm struggling with this problem with a large xml file with a root of 'articles' and containing many individual articles under the tag 'article>. What I'm hoping to do is for each 'article' in 'articles' collect all text within the 'p' tags. An 'article' can have multiple 'p' tags as illustrated in below:

<articles>

    <article title="Blah" published-at="2018-01-01" id="00000">

      <p>Here is some text.</p>

      <p>Another line of text.</p>

      <a type="external" href="https://www.website.com/">Image</a>

      <p>Final line of text.</p>

    </article>

    <article title="Second blah" published-at="2018-01-02" id="00001">

      <p>Here is some new text.</p>

      <p>Final line of new text.</p>

    </article>

</articles>

So what I wanted to do was iterate over each article and generate a single line containing all text in the 'p' tags, not caring if I picked up the links and associated text in the 'a' tags.

I was hoping something like this would work but it produced a text file that was not separated by each respective 'article'

text = 



for p in root.iter('p'):

  text.append(p.text)

  with open("text.txt", "w", encoding = 'utf-8') as output:

    output.write(str(text))

Any help would be sincerely appreciated as this is a very difficult question for me to express in a search.

asked Nov 29 '18 at 5:59

nlp

add a comment |

<articles>

    <article title="Blah" published-at="2018-01-01" id="00000">

      <p>Here is some text.</p>

      <p>Another line of text.</p>

      <a type="external" href="https://www.website.com/">Image</a>

      <p>Final line of text.</p>

    </article>

    <article title="Second blah" published-at="2018-01-02" id="00001">

      <p>Here is some new text.</p>

      <p>Final line of new text.</p>

    </article>

</articles>

So what I wanted to do was iterate over each article and generate a single line containing all text in the 'p' tags, not caring if I picked up the links and associated text in the 'a' tags.

I was hoping something like this would work but it produced a text file that was not separated by each respective 'article'

text = 



for p in root.iter('p'):

  text.append(p.text)

  with open("text.txt", "w", encoding = 'utf-8') as output:

    output.write(str(text))

Any help would be sincerely appreciated as this is a very difficult question for me to express in a search.

asked Nov 29 '18 at 5:59

nlp

add a comment |

<articles>

    <article title="Blah" published-at="2018-01-01" id="00000">

      <p>Here is some text.</p>

      <p>Another line of text.</p>

      <a type="external" href="https://www.website.com/">Image</a>

      <p>Final line of text.</p>

    </article>

    <article title="Second blah" published-at="2018-01-02" id="00001">

      <p>Here is some new text.</p>

      <p>Final line of new text.</p>

    </article>

</articles>

So what I wanted to do was iterate over each article and generate a single line containing all text in the 'p' tags, not caring if I picked up the links and associated text in the 'a' tags.

I was hoping something like this would work but it produced a text file that was not separated by each respective 'article'

text = 



for p in root.iter('p'):

  text.append(p.text)

  with open("text.txt", "w", encoding = 'utf-8') as output:

    output.write(str(text))

Any help would be sincerely appreciated as this is a very difficult question for me to express in a search.

asked Nov 29 '18 at 5:59

nlp

<articles>

    <article title="Blah" published-at="2018-01-01" id="00000">

      <p>Here is some text.</p>

      <p>Another line of text.</p>

      <a type="external" href="https://www.website.com/">Image</a>

      <p>Final line of text.</p>

    </article>

    <article title="Second blah" published-at="2018-01-02" id="00001">

      <p>Here is some new text.</p>

      <p>Final line of new text.</p>

    </article>

</articles>

So what I wanted to do was iterate over each article and generate a single line containing all text in the 'p' tags, not caring if I picked up the links and associated text in the 'a' tags.

I was hoping something like this would work but it produced a text file that was not separated by each respective 'article'

text = 



for p in root.iter('p'):

  text.append(p.text)

  with open("text.txt", "w", encoding = 'utf-8') as output:

    output.write(str(text))

Any help would be sincerely appreciated as this is a very difficult question for me to express in a search.

xml python-3.x

asked Nov 29 '18 at 5:59

nlp

asked Nov 29 '18 at 5:59

nlp

asked Nov 29 '18 at 5:59

nlp

asked Nov 29 '18 at 5:59

nlp

asked Nov 29 '18 at 5:59

nlp

add a comment |

1 Answer
1

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oldest

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Python has xml.etree.ElementTree library (among others) for working with XML and with it you can do:

import xml.etree.ElementTree as ET

tree = ET.parse('test.xml')

root = tree.getroot()



text = 

for article in root.findall('article'):

    for paragraph in article.findall('p'):

        text.append(paragraph.text)

        paragraph.text = ''



tree.write('output.xml')

answered Nov 29 '18 at 10:23

Shadowchaser

864

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Python has xml.etree.ElementTree library (among others) for working with XML and with it you can do:

import xml.etree.ElementTree as ET

tree = ET.parse('test.xml')

root = tree.getroot()



text = 

for article in root.findall('article'):

    for paragraph in article.findall('p'):

        text.append(paragraph.text)

        paragraph.text = ''



tree.write('output.xml')

answered Nov 29 '18 at 10:23

Shadowchaser

864

add a comment |

Python has xml.etree.ElementTree library (among others) for working with XML and with it you can do:

import xml.etree.ElementTree as ET

tree = ET.parse('test.xml')

root = tree.getroot()



text = 

for article in root.findall('article'):

    for paragraph in article.findall('p'):

        text.append(paragraph.text)

        paragraph.text = ''



tree.write('output.xml')

answered Nov 29 '18 at 10:23

Shadowchaser

864

add a comment |

Python has xml.etree.ElementTree library (among others) for working with XML and with it you can do:

import xml.etree.ElementTree as ET

tree = ET.parse('test.xml')

root = tree.getroot()



text = 

for article in root.findall('article'):

    for paragraph in article.findall('p'):

        text.append(paragraph.text)

        paragraph.text = ''



tree.write('output.xml')

answered Nov 29 '18 at 10:23

Shadowchaser

864

Python has xml.etree.ElementTree library (among others) for working with XML and with it you can do:

import xml.etree.ElementTree as ET

tree = ET.parse('test.xml')

root = tree.getroot()



text = 

for article in root.findall('article'):

    for paragraph in article.findall('p'):

        text.append(paragraph.text)

        paragraph.text = ''



tree.write('output.xml')

answered Nov 29 '18 at 10:23

Shadowchaser

864

answered Nov 29 '18 at 10:23

Shadowchaser

864

answered Nov 29 '18 at 10:23

Shadowchaser

864

answered Nov 29 '18 at 10:23

Shadowchaser

864

add a comment |

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