Printing array in perl mason
I am new to Perl Mason and I am trying to print an array. I tried several ways, explored the web but nothing seems to work.
I tried -
my $arr = getArray();
print "Array : $arr"; # prints "Array : ARRAY(0xcd421774)"
my $size = scalar $arr;
print "Size : $size"; # prints "size ARRAY(0xcd421774)"
I also tried to print the first element of the array
print "Element : $arr[0]"; # throws error "Global symbol "@arr" requires explicit package name at ..."
arrays perl mason
add a comment |
I am new to Perl Mason and I am trying to print an array. I tried several ways, explored the web but nothing seems to work.
I tried -
my $arr = getArray();
print "Array : $arr"; # prints "Array : ARRAY(0xcd421774)"
my $size = scalar $arr;
print "Size : $size"; # prints "size ARRAY(0xcd421774)"
I also tried to print the first element of the array
print "Element : $arr[0]"; # throws error "Global symbol "@arr" requires explicit package name at ..."
arrays perl mason
add a comment |
I am new to Perl Mason and I am trying to print an array. I tried several ways, explored the web but nothing seems to work.
I tried -
my $arr = getArray();
print "Array : $arr"; # prints "Array : ARRAY(0xcd421774)"
my $size = scalar $arr;
print "Size : $size"; # prints "size ARRAY(0xcd421774)"
I also tried to print the first element of the array
print "Element : $arr[0]"; # throws error "Global symbol "@arr" requires explicit package name at ..."
arrays perl mason
I am new to Perl Mason and I am trying to print an array. I tried several ways, explored the web but nothing seems to work.
I tried -
my $arr = getArray();
print "Array : $arr"; # prints "Array : ARRAY(0xcd421774)"
my $size = scalar $arr;
print "Size : $size"; # prints "size ARRAY(0xcd421774)"
I also tried to print the first element of the array
print "Element : $arr[0]"; # throws error "Global symbol "@arr" requires explicit package name at ..."
arrays perl mason
arrays perl mason
asked Apr 3 '14 at 17:45
KevindraKevindra
82511139
82511139
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Your $arr
is an array reference. You need to dereference it with the @{ … }
operator: @{ $arr }
or the shorthand @$arr
.
my $arr = getArray();
print "Array : @$arr";
my $size = scalar @$arr;
print "Size : $size";
To access one element: ${ $arr }[0]
or the shorthands $$arr[0]
or $arr->[0]
, of which the last form should be preferred.
To learn more about Perl references, read perldoc perlreftut
.
Thanks a lot @amon, it works now.
– Kevindra
Apr 3 '14 at 17:57
add a comment |
I am not familiar with Perl Mason but it seems like getArray() does not return an array. It might be returning an array reference. I thought that's the reason why you assign it to a scalar variable $arr, not @arr;
You can confirm this using Data::Dumper
use Data::Dumper;
print Dumper $arr;
or ref.
if (ref($r) eq "ARRAY")
If it's indeed an array reference, you can access the first element like this:
$arr->[0];
Print the array like this:
print "Array : @$arr";
And get its size like this:
my $size = scalar @$arr;
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your $arr
is an array reference. You need to dereference it with the @{ … }
operator: @{ $arr }
or the shorthand @$arr
.
my $arr = getArray();
print "Array : @$arr";
my $size = scalar @$arr;
print "Size : $size";
To access one element: ${ $arr }[0]
or the shorthands $$arr[0]
or $arr->[0]
, of which the last form should be preferred.
To learn more about Perl references, read perldoc perlreftut
.
Thanks a lot @amon, it works now.
– Kevindra
Apr 3 '14 at 17:57
add a comment |
Your $arr
is an array reference. You need to dereference it with the @{ … }
operator: @{ $arr }
or the shorthand @$arr
.
my $arr = getArray();
print "Array : @$arr";
my $size = scalar @$arr;
print "Size : $size";
To access one element: ${ $arr }[0]
or the shorthands $$arr[0]
or $arr->[0]
, of which the last form should be preferred.
To learn more about Perl references, read perldoc perlreftut
.
Thanks a lot @amon, it works now.
– Kevindra
Apr 3 '14 at 17:57
add a comment |
Your $arr
is an array reference. You need to dereference it with the @{ … }
operator: @{ $arr }
or the shorthand @$arr
.
my $arr = getArray();
print "Array : @$arr";
my $size = scalar @$arr;
print "Size : $size";
To access one element: ${ $arr }[0]
or the shorthands $$arr[0]
or $arr->[0]
, of which the last form should be preferred.
To learn more about Perl references, read perldoc perlreftut
.
Your $arr
is an array reference. You need to dereference it with the @{ … }
operator: @{ $arr }
or the shorthand @$arr
.
my $arr = getArray();
print "Array : @$arr";
my $size = scalar @$arr;
print "Size : $size";
To access one element: ${ $arr }[0]
or the shorthands $$arr[0]
or $arr->[0]
, of which the last form should be preferred.
To learn more about Perl references, read perldoc perlreftut
.
edited Apr 3 '14 at 18:00
answered Apr 3 '14 at 17:51
amonamon
52.6k270126
52.6k270126
Thanks a lot @amon, it works now.
– Kevindra
Apr 3 '14 at 17:57
add a comment |
Thanks a lot @amon, it works now.
– Kevindra
Apr 3 '14 at 17:57
Thanks a lot @amon, it works now.
– Kevindra
Apr 3 '14 at 17:57
Thanks a lot @amon, it works now.
– Kevindra
Apr 3 '14 at 17:57
add a comment |
I am not familiar with Perl Mason but it seems like getArray() does not return an array. It might be returning an array reference. I thought that's the reason why you assign it to a scalar variable $arr, not @arr;
You can confirm this using Data::Dumper
use Data::Dumper;
print Dumper $arr;
or ref.
if (ref($r) eq "ARRAY")
If it's indeed an array reference, you can access the first element like this:
$arr->[0];
Print the array like this:
print "Array : @$arr";
And get its size like this:
my $size = scalar @$arr;
add a comment |
I am not familiar with Perl Mason but it seems like getArray() does not return an array. It might be returning an array reference. I thought that's the reason why you assign it to a scalar variable $arr, not @arr;
You can confirm this using Data::Dumper
use Data::Dumper;
print Dumper $arr;
or ref.
if (ref($r) eq "ARRAY")
If it's indeed an array reference, you can access the first element like this:
$arr->[0];
Print the array like this:
print "Array : @$arr";
And get its size like this:
my $size = scalar @$arr;
add a comment |
I am not familiar with Perl Mason but it seems like getArray() does not return an array. It might be returning an array reference. I thought that's the reason why you assign it to a scalar variable $arr, not @arr;
You can confirm this using Data::Dumper
use Data::Dumper;
print Dumper $arr;
or ref.
if (ref($r) eq "ARRAY")
If it's indeed an array reference, you can access the first element like this:
$arr->[0];
Print the array like this:
print "Array : @$arr";
And get its size like this:
my $size = scalar @$arr;
I am not familiar with Perl Mason but it seems like getArray() does not return an array. It might be returning an array reference. I thought that's the reason why you assign it to a scalar variable $arr, not @arr;
You can confirm this using Data::Dumper
use Data::Dumper;
print Dumper $arr;
or ref.
if (ref($r) eq "ARRAY")
If it's indeed an array reference, you can access the first element like this:
$arr->[0];
Print the array like this:
print "Array : @$arr";
And get its size like this:
my $size = scalar @$arr;
edited Apr 3 '14 at 18:00
answered Apr 3 '14 at 17:52
Carlisle18Carlisle18
299210
299210
add a comment |
add a comment |
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