find and collect values of all elements having `data-id` attribute

How to find all elements having data-id attribute and collect the values using map function.

var target = $('#parent');

var arr = target.find('all elements having data-id attribute');

var cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

<div class='title' data-id = 5>lorem</div>

<input type = 'text'>

<a href='google.com' data-id = 14>google</a>

<div class='title'>ipsum</div>

<img class='imgtop' src='' alt='img' data-id = 9>

</div>

Result should be 5,14,9

Any help?

asked Nov 22 at 22:35

puerto

925411

add a comment |

How to find all elements having data-id attribute and collect the values using map function.

var target = $('#parent');

var arr = target.find('all elements having data-id attribute');

var cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

<div class='title' data-id = 5>lorem</div>

<input type = 'text'>

<a href='google.com' data-id = 14>google</a>

<div class='title'>ipsum</div>

<img class='imgtop' src='' alt='img' data-id = 9>

</div>

Result should be 5,14,9

Any help?

asked Nov 22 at 22:35

puerto

925411

add a comment |

How to find all elements having data-id attribute and collect the values using map function.

var target = $('#parent');

var arr = target.find('all elements having data-id attribute');

var cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

<div class='title' data-id = 5>lorem</div>

<input type = 'text'>

<a href='google.com' data-id = 14>google</a>

<div class='title'>ipsum</div>

<img class='imgtop' src='' alt='img' data-id = 9>

</div>

Result should be 5,14,9

Any help?

asked Nov 22 at 22:35

puerto

925411

How to find all elements having data-id attribute and collect the values using map function.

var target = $('#parent');

var arr = target.find('all elements having data-id attribute');

var cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

<div class='title' data-id = 5>lorem</div>

<input type = 'text'>

<a href='google.com' data-id = 14>google</a>

<div class='title'>ipsum</div>

<img class='imgtop' src='' alt='img' data-id = 9>

</div>

Result should be 5,14,9

Any help?

var target = $('#parent');

var arr = target.find('all elements having data-id attribute');

var cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

<div class='title' data-id = 5>lorem</div>

<input type = 'text'>

<a href='google.com' data-id = 14>google</a>

<div class='title'>ipsum</div>

<img class='imgtop' src='' alt='img' data-id = 9>

</div>

var target = $('#parent');

var arr = target.find('all elements having data-id attribute');

var cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

<div class='title' data-id = 5>lorem</div>

<input type = 'text'>

<a href='google.com' data-id = 14>google</a>

<div class='title'>ipsum</div>

<img class='imgtop' src='' alt='img' data-id = 9>

</div>

jquery

asked Nov 22 at 22:35

puerto

925411

asked Nov 22 at 22:35

puerto

925411

asked Nov 22 at 22:35

puerto

925411

asked Nov 22 at 22:35

puerto

925411

asked Nov 22 at 22:35

puerto

925411

add a comment |

2 Answers
2

active

oldest

votes

You need to use attribute selector, like : target.find('[data-id]');

let target = $('#parent'),

  arr = target.find('[data-id]'),

  cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

  <div class='title' data-id="5">lorem</div>

  <input type='text'>

  <a href='google.com' data-id="14">google</a>

  <div class='title'>ipsum</div>

  <img class='imgtop' src='' alt='img' data-id="9">

</div>

Also see attributeHas selector

edited Nov 22 at 22:44

answered Nov 22 at 22:37

dippas

37.8k104374

add a comment |

This is as simple as

const arr = target.find('[data-id]')

See https://api.jquery.com/has-attribute-selector/

answered Nov 22 at 22:37

Phil

95.6k11136155

1

thanks a lot. solved
– puerto
Nov 22 at 22:38

@puerto: mark one of the 2 answers as accepted
– Louys Patrice Bessette
Nov 22 at 22:49

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

You need to use attribute selector, like : target.find('[data-id]');

let target = $('#parent'),

  arr = target.find('[data-id]'),

  cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

  <div class='title' data-id="5">lorem</div>

  <input type='text'>

  <a href='google.com' data-id="14">google</a>

  <div class='title'>ipsum</div>

  <img class='imgtop' src='' alt='img' data-id="9">

</div>

Also see attributeHas selector

edited Nov 22 at 22:44

answered Nov 22 at 22:37

dippas

37.8k104374

add a comment |

You need to use attribute selector, like : target.find('[data-id]');

let target = $('#parent'),

  arr = target.find('[data-id]'),

  cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

  <div class='title' data-id="5">lorem</div>

  <input type='text'>

  <a href='google.com' data-id="14">google</a>

  <div class='title'>ipsum</div>

  <img class='imgtop' src='' alt='img' data-id="9">

</div>

Also see attributeHas selector

edited Nov 22 at 22:44

answered Nov 22 at 22:37

dippas

37.8k104374

add a comment |

You need to use attribute selector, like : target.find('[data-id]');

let target = $('#parent'),

  arr = target.find('[data-id]'),

  cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

  <div class='title' data-id="5">lorem</div>

  <input type='text'>

  <a href='google.com' data-id="14">google</a>

  <div class='title'>ipsum</div>

  <img class='imgtop' src='' alt='img' data-id="9">

</div>

Also see attributeHas selector

edited Nov 22 at 22:44

answered Nov 22 at 22:37

dippas

37.8k104374

You need to use attribute selector, like : target.find('[data-id]');

let target = $('#parent'),

  arr = target.find('[data-id]'),

  cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

  <div class='title' data-id="5">lorem</div>

  <input type='text'>

  <a href='google.com' data-id="14">google</a>

  <div class='title'>ipsum</div>

  <img class='imgtop' src='' alt='img' data-id="9">

</div>

Also see attributeHas selector

let target = $('#parent'),

  arr = target.find('[data-id]'),

  cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

  <div class='title' data-id="5">lorem</div>

  <input type='text'>

  <a href='google.com' data-id="14">google</a>

  <div class='title'>ipsum</div>

  <img class='imgtop' src='' alt='img' data-id="9">

</div>

let target = $('#parent'),

  arr = target.find('[data-id]'),

  cnt = $.map(arr, (e) => $(e).data('id')).join(',');

console.log(cnt);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div id='parent'>

  <div class='title' data-id="5">lorem</div>

  <input type='text'>

  <a href='google.com' data-id="14">google</a>

  <div class='title'>ipsum</div>

  <img class='imgtop' src='' alt='img' data-id="9">

</div>

edited Nov 22 at 22:44

answered Nov 22 at 22:37

dippas

37.8k104374

edited Nov 22 at 22:44

answered Nov 22 at 22:37

dippas

37.8k104374

answered Nov 22 at 22:37

dippas

37.8k104374

answered Nov 22 at 22:37

dippas

37.8k104374

add a comment |

This is as simple as

const arr = target.find('[data-id]')

See https://api.jquery.com/has-attribute-selector/

answered Nov 22 at 22:37

Phil

95.6k11136155

1

thanks a lot. solved
– puerto
Nov 22 at 22:38

@puerto: mark one of the 2 answers as accepted
– Louys Patrice Bessette
Nov 22 at 22:49

add a comment |

This is as simple as

const arr = target.find('[data-id]')

See https://api.jquery.com/has-attribute-selector/

answered Nov 22 at 22:37

Phil

95.6k11136155

1

thanks a lot. solved
– puerto
Nov 22 at 22:38

@puerto: mark one of the 2 answers as accepted
– Louys Patrice Bessette
Nov 22 at 22:49

add a comment |

This is as simple as

const arr = target.find('[data-id]')

See https://api.jquery.com/has-attribute-selector/

answered Nov 22 at 22:37

Phil

95.6k11136155

This is as simple as

const arr = target.find('[data-id]')

See https://api.jquery.com/has-attribute-selector/

answered Nov 22 at 22:37

Phil

95.6k11136155

answered Nov 22 at 22:37

Phil

95.6k11136155

answered Nov 22 at 22:37

Phil

95.6k11136155

answered Nov 22 at 22:37

Phil

95.6k11136155

1

thanks a lot. solved
– puerto
Nov 22 at 22:38

@puerto: mark one of the 2 answers as accepted
– Louys Patrice Bessette
Nov 22 at 22:49

add a comment |

1

thanks a lot. solved
– puerto
Nov 22 at 22:38

@puerto: mark one of the 2 answers as accepted
– Louys Patrice Bessette
Nov 22 at 22:49

thanks a lot. solved
– puerto
Nov 22 at 22:38

@puerto: mark one of the 2 answers as accepted
– Louys Patrice Bessette
Nov 22 at 22:49

add a comment |

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