Initialize multiple instances inline c#
class Program
{
static void Main(string args)
{
List<Person> people = Enumerable.Repeat(new Person(), 3).ToList<Person>();
}
}
class Person
{
public Person()
{
Console.WriteLine("dd");
}
}
Output is a single line of "dd" instead of 3 lines, I don't understand
c#
asked Nov 24 '18 at 0:52
Todor YanevTodor Yanev
122
add a comment |
class Program
{
static void Main(string args)
{
List<Person> people = Enumerable.Repeat(new Person(), 3).ToList<Person>();
}
}
class Person
{
public Person()
{
Console.WriteLine("dd");
}
}
Output is a single line of "dd" instead of 3 lines, I don't understand
c#
asked Nov 24 '18 at 0:52
Todor YanevTodor Yanev
122
See stackoverflow.com/a/6078552/340760
– BrunoLM
Nov 24 '18 at 1:13
add a comment |
class Program
{
static void Main(string args)
{
List<Person> people = Enumerable.Repeat(new Person(), 3).ToList<Person>();
}
}
class Person
{
public Person()
{
Console.WriteLine("dd");
}
}
Output is a single line of "dd" instead of 3 lines, I don't understand
c#
asked Nov 24 '18 at 0:52
Todor YanevTodor Yanev
122
class Program
{
static void Main(string args)
{
List<Person> people = Enumerable.Repeat(new Person(), 3).ToList<Person>();
}
}
class Person
{
public Person()
{
Console.WriteLine("dd");
}
}
Output is a single line of "dd" instead of 3 lines, I don't understand
c#
c#
asked Nov 24 '18 at 0:52
Todor YanevTodor Yanev
122
asked Nov 24 '18 at 0:52
Todor YanevTodor Yanev
122
asked Nov 24 '18 at 0:52
Todor YanevTodor Yanev
122
asked Nov 24 '18 at 0:52
Todor YanevTodor Yanev
122
asked Nov 24 '18 at 0:52
Todor YanevTodor Yanev
122
122
See stackoverflow.com/a/6078552/340760
– BrunoLM
Nov 24 '18 at 1:13
add a comment |
See stackoverflow.com/a/6078552/340760
– BrunoLM
Nov 24 '18 at 1:13
See stackoverflow.com/a/6078552/340760
– BrunoLM
Nov 24 '18 at 1:13
See stackoverflow.com/a/6078552/340760
– BrunoLM
Nov 24 '18 at 1:13
add a comment |
1 Answer
1
active
oldest
votes
If you look at the documentation of Enumerable.Repeat method:
Generates a sequence that contains one repeated value.
So it repeats the given value as many times as specified. It doesn't re-create the same value for each repetition. Hence in your example, only one Person instance is created and added to the list three times.
This is the equivalent of your code which might make it more clear:
var person = new Person();
List<Person> people = Enumerable.Repeat(person, 3).ToList<Person>();
If you want to create a different instance each time you can use Select:
Enumerable.Repeat(null, 3).Select(_ => new Person()).ToList();
answered Nov 24 '18 at 0:56
Selman GençSelman Genç
83.6k1078139
Enumerable.Range(0, 3).Select(_ => ...would make more sense here.
– Xiaoy312
Nov 24 '18 at 2:00
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you look at the documentation of Enumerable.Repeat method:
Generates a sequence that contains one repeated value.
So it repeats the given value as many times as specified. It doesn't re-create the same value for each repetition. Hence in your example, only one Person instance is created and added to the list three times.
This is the equivalent of your code which might make it more clear:
var person = new Person();
List<Person> people = Enumerable.Repeat(person, 3).ToList<Person>();
If you want to create a different instance each time you can use Select:
Enumerable.Repeat(null, 3).Select(_ => new Person()).ToList();
answered Nov 24 '18 at 0:56
Selman GençSelman Genç
83.6k1078139
Enumerable.Range(0, 3).Select(_ => ...would make more sense here.
– Xiaoy312
Nov 24 '18 at 2:00
add a comment |
If you look at the documentation of Enumerable.Repeat method:
Generates a sequence that contains one repeated value.
So it repeats the given value as many times as specified. It doesn't re-create the same value for each repetition. Hence in your example, only one Person instance is created and added to the list three times.
This is the equivalent of your code which might make it more clear:
var person = new Person();
List<Person> people = Enumerable.Repeat(person, 3).ToList<Person>();
If you want to create a different instance each time you can use Select:
Enumerable.Repeat(null, 3).Select(_ => new Person()).ToList();
answered Nov 24 '18 at 0:56
Selman GençSelman Genç
83.6k1078139
Enumerable.Range(0, 3).Select(_ => ...would make more sense here.
– Xiaoy312
Nov 24 '18 at 2:00
add a comment |
If you look at the documentation of Enumerable.Repeat method:
Generates a sequence that contains one repeated value.
So it repeats the given value as many times as specified. It doesn't re-create the same value for each repetition. Hence in your example, only one Person instance is created and added to the list three times.
This is the equivalent of your code which might make it more clear:
var person = new Person();
List<Person> people = Enumerable.Repeat(person, 3).ToList<Person>();
If you want to create a different instance each time you can use Select:
Enumerable.Repeat(null, 3).Select(_ => new Person()).ToList();
answered Nov 24 '18 at 0:56
Selman GençSelman Genç
83.6k1078139
If you look at the documentation of Enumerable.Repeat method:
Generates a sequence that contains one repeated value.
So it repeats the given value as many times as specified. It doesn't re-create the same value for each repetition. Hence in your example, only one Person instance is created and added to the list three times.
This is the equivalent of your code which might make it more clear:
var person = new Person();
List<Person> people = Enumerable.Repeat(person, 3).ToList<Person>();
If you want to create a different instance each time you can use Select:
Enumerable.Repeat(null, 3).Select(_ => new Person()).ToList();
answered Nov 24 '18 at 0:56
Selman GençSelman Genç
83.6k1078139
edited Nov 24 '18 at 1:14
answered Nov 24 '18 at 0:56
Selman GençSelman Genç
83.6k1078139
answered Nov 24 '18 at 0:56
Selman GençSelman Genç
83.6k1078139
answered Nov 24 '18 at 0:56
Selman GençSelman Genç
83.6k1078139
83.6k1078139
Enumerable.Range(0, 3).Select(_ => ...would make more sense here.
– Xiaoy312
Nov 24 '18 at 2:00
add a comment |
Enumerable.Range(0, 3).Select(_ => ...would make more sense here.
– Xiaoy312
Nov 24 '18 at 2:00
Enumerable.Range(0, 3).Select(_ => ... would make more sense here.– Xiaoy312
Nov 24 '18 at 2:00
Enumerable.Range(0, 3).Select(_ => ... would make more sense here.– Xiaoy312
Nov 24 '18 at 2:00
add a comment |
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See stackoverflow.com/a/6078552/340760
– BrunoLM
Nov 24 '18 at 1:13