Data type that represents the proof that two functions are equivalent
I was trying to make a data type that represents that fact that two functions are equivalent. What does the error mean?
Code:
record FEq (f1 : a -> b) (f2 : a -> b) where
constructor MkFEq
unFEq : (x : a) -> (f1 x = f2 x)
Error:
Type checking ./FEq.idr
FEq.idr:1:1-3:36:
|
1 | record FEq (f1 : a -> b) (f2 : a -> b) where
| ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ...
When checking type of Main.FEq.unFEq:
When checking argument x to type constructor =:
Type mismatch between
free_a b a f1 f2 rec
and
a
idris
add a comment |
I was trying to make a data type that represents that fact that two functions are equivalent. What does the error mean?
Code:
record FEq (f1 : a -> b) (f2 : a -> b) where
constructor MkFEq
unFEq : (x : a) -> (f1 x = f2 x)
Error:
Type checking ./FEq.idr
FEq.idr:1:1-3:36:
|
1 | record FEq (f1 : a -> b) (f2 : a -> b) where
| ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ...
When checking type of Main.FEq.unFEq:
When checking argument x to type constructor =:
Type mismatch between
free_a b a f1 f2 rec
and
a
idris
add a comment |
I was trying to make a data type that represents that fact that two functions are equivalent. What does the error mean?
Code:
record FEq (f1 : a -> b) (f2 : a -> b) where
constructor MkFEq
unFEq : (x : a) -> (f1 x = f2 x)
Error:
Type checking ./FEq.idr
FEq.idr:1:1-3:36:
|
1 | record FEq (f1 : a -> b) (f2 : a -> b) where
| ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ...
When checking type of Main.FEq.unFEq:
When checking argument x to type constructor =:
Type mismatch between
free_a b a f1 f2 rec
and
a
idris
I was trying to make a data type that represents that fact that two functions are equivalent. What does the error mean?
Code:
record FEq (f1 : a -> b) (f2 : a -> b) where
constructor MkFEq
unFEq : (x : a) -> (f1 x = f2 x)
Error:
Type checking ./FEq.idr
FEq.idr:1:1-3:36:
|
1 | record FEq (f1 : a -> b) (f2 : a -> b) where
| ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ...
When checking type of Main.FEq.unFEq:
When checking argument x to type constructor =:
Type mismatch between
free_a b a f1 f2 rec
and
a
idris
idris
asked Nov 22 at 20:56
2426021684
1,7241928
1,7241928
add a comment |
add a comment |
1 Answer
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AFAIK you are not allowed to mention unbound parameters in a record.
So you have to add a
and b
as parameters like so:
record FEq a b (f1 : a -> b) (f2 : a -> b) where
constructor MkFEq
unFEq : (x : a) -> (f1 x = f2 x)
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
AFAIK you are not allowed to mention unbound parameters in a record.
So you have to add a
and b
as parameters like so:
record FEq a b (f1 : a -> b) (f2 : a -> b) where
constructor MkFEq
unFEq : (x : a) -> (f1 x = f2 x)
add a comment |
AFAIK you are not allowed to mention unbound parameters in a record.
So you have to add a
and b
as parameters like so:
record FEq a b (f1 : a -> b) (f2 : a -> b) where
constructor MkFEq
unFEq : (x : a) -> (f1 x = f2 x)
add a comment |
AFAIK you are not allowed to mention unbound parameters in a record.
So you have to add a
and b
as parameters like so:
record FEq a b (f1 : a -> b) (f2 : a -> b) where
constructor MkFEq
unFEq : (x : a) -> (f1 x = f2 x)
AFAIK you are not allowed to mention unbound parameters in a record.
So you have to add a
and b
as parameters like so:
record FEq a b (f1 : a -> b) (f2 : a -> b) where
constructor MkFEq
unFEq : (x : a) -> (f1 x = f2 x)
answered Nov 23 at 22:37
gallais
9,16321851
9,16321851
add a comment |
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