Regex pattern in Typescript











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1
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This pattern works, but it the opposite way than I intended, how do I change it so when I the pattern is matched, it causes an error? Thanks.



   <mat-form-field style="text-align: center">
<input type="text" pattern="^([aA]d{6})" placeholder="id" matInput="text" formControlName="id"
name="id" required>
</mat-form-field>









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  • 1




    Use pattern="^(?![aA]d{6}$).*"
    – Wiktor Stribiżew
    Nov 22 at 10:49










  • @WiktorStribiżew thank you, this works.
    – Katie Kennedy
    Nov 22 at 10:54















up vote
1
down vote

favorite












This pattern works, but it the opposite way than I intended, how do I change it so when I the pattern is matched, it causes an error? Thanks.



   <mat-form-field style="text-align: center">
<input type="text" pattern="^([aA]d{6})" placeholder="id" matInput="text" formControlName="id"
name="id" required>
</mat-form-field>









share|improve this question


















  • 1




    Use pattern="^(?![aA]d{6}$).*"
    – Wiktor Stribiżew
    Nov 22 at 10:49










  • @WiktorStribiżew thank you, this works.
    – Katie Kennedy
    Nov 22 at 10:54













up vote
1
down vote

favorite









up vote
1
down vote

favorite











This pattern works, but it the opposite way than I intended, how do I change it so when I the pattern is matched, it causes an error? Thanks.



   <mat-form-field style="text-align: center">
<input type="text" pattern="^([aA]d{6})" placeholder="id" matInput="text" formControlName="id"
name="id" required>
</mat-form-field>









share|improve this question













This pattern works, but it the opposite way than I intended, how do I change it so when I the pattern is matched, it causes an error? Thanks.



   <mat-form-field style="text-align: center">
<input type="text" pattern="^([aA]d{6})" placeholder="id" matInput="text" formControlName="id"
name="id" required>
</mat-form-field>






regex typescript pattern-matching angular2-forms






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share|improve this question










asked Nov 22 at 10:48









Katie Kennedy

496




496








  • 1




    Use pattern="^(?![aA]d{6}$).*"
    – Wiktor Stribiżew
    Nov 22 at 10:49










  • @WiktorStribiżew thank you, this works.
    – Katie Kennedy
    Nov 22 at 10:54














  • 1




    Use pattern="^(?![aA]d{6}$).*"
    – Wiktor Stribiżew
    Nov 22 at 10:49










  • @WiktorStribiżew thank you, this works.
    – Katie Kennedy
    Nov 22 at 10:54








1




1




Use pattern="^(?![aA]d{6}$).*"
– Wiktor Stribiżew
Nov 22 at 10:49




Use pattern="^(?![aA]d{6}$).*"
– Wiktor Stribiżew
Nov 22 at 10:49












@WiktorStribiżew thank you, this works.
– Katie Kennedy
Nov 22 at 10:54




@WiktorStribiżew thank you, this works.
– Katie Kennedy
Nov 22 at 10:54












1 Answer
1






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oldest

votes

















up vote
0
down vote













Your current pattern matches a string that starts with a or A and then has strictly 6 digits. The ^ is redundant in pattern regex since it is anchored by default.



So, in fact, the current regex is ^[Aa]d{6}$, and to write a reverse HTML5 pattern you may use



pattern="(?![aA]d{6}$).*"


This pattern will get parsed as /^(?:(?![aA]d{6}$).*)$/ pattern (with u modifier in Chrome, Firefox and other browsers supporting this feature).



The (?![Aa]d{6}$) negative lookahead will fail any string that starts with a or A and then having 6 digits to its end.



The .* matches any 0+ chars. Use .+ to match any 1 or more chars. This part is required since the HTML5 regex should match the whole input.



HTML5 demo:






input:valid {
color: black;
border: 5px solid #dadadada;
border-radius: 7px;
}
input:invalid {
color: navy;
outline: none;
border-color: #ff1050;
box-shadow: 0 0 10px #ff0000;
}

<form name="form1"> 
<input pattern="(?![aA]d{6}$).*" title="Please enter a valid string." placeholder="Please enter valid text" />
<input type="Submit"/>
</form>








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    Your current pattern matches a string that starts with a or A and then has strictly 6 digits. The ^ is redundant in pattern regex since it is anchored by default.



    So, in fact, the current regex is ^[Aa]d{6}$, and to write a reverse HTML5 pattern you may use



    pattern="(?![aA]d{6}$).*"


    This pattern will get parsed as /^(?:(?![aA]d{6}$).*)$/ pattern (with u modifier in Chrome, Firefox and other browsers supporting this feature).



    The (?![Aa]d{6}$) negative lookahead will fail any string that starts with a or A and then having 6 digits to its end.



    The .* matches any 0+ chars. Use .+ to match any 1 or more chars. This part is required since the HTML5 regex should match the whole input.



    HTML5 demo:






    input:valid {
    color: black;
    border: 5px solid #dadadada;
    border-radius: 7px;
    }
    input:invalid {
    color: navy;
    outline: none;
    border-color: #ff1050;
    box-shadow: 0 0 10px #ff0000;
    }

    <form name="form1"> 
    <input pattern="(?![aA]d{6}$).*" title="Please enter a valid string." placeholder="Please enter valid text" />
    <input type="Submit"/>
    </form>








    share|improve this answer



























      up vote
      0
      down vote













      Your current pattern matches a string that starts with a or A and then has strictly 6 digits. The ^ is redundant in pattern regex since it is anchored by default.



      So, in fact, the current regex is ^[Aa]d{6}$, and to write a reverse HTML5 pattern you may use



      pattern="(?![aA]d{6}$).*"


      This pattern will get parsed as /^(?:(?![aA]d{6}$).*)$/ pattern (with u modifier in Chrome, Firefox and other browsers supporting this feature).



      The (?![Aa]d{6}$) negative lookahead will fail any string that starts with a or A and then having 6 digits to its end.



      The .* matches any 0+ chars. Use .+ to match any 1 or more chars. This part is required since the HTML5 regex should match the whole input.



      HTML5 demo:






      input:valid {
      color: black;
      border: 5px solid #dadadada;
      border-radius: 7px;
      }
      input:invalid {
      color: navy;
      outline: none;
      border-color: #ff1050;
      box-shadow: 0 0 10px #ff0000;
      }

      <form name="form1"> 
      <input pattern="(?![aA]d{6}$).*" title="Please enter a valid string." placeholder="Please enter valid text" />
      <input type="Submit"/>
      </form>








      share|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        Your current pattern matches a string that starts with a or A and then has strictly 6 digits. The ^ is redundant in pattern regex since it is anchored by default.



        So, in fact, the current regex is ^[Aa]d{6}$, and to write a reverse HTML5 pattern you may use



        pattern="(?![aA]d{6}$).*"


        This pattern will get parsed as /^(?:(?![aA]d{6}$).*)$/ pattern (with u modifier in Chrome, Firefox and other browsers supporting this feature).



        The (?![Aa]d{6}$) negative lookahead will fail any string that starts with a or A and then having 6 digits to its end.



        The .* matches any 0+ chars. Use .+ to match any 1 or more chars. This part is required since the HTML5 regex should match the whole input.



        HTML5 demo:






        input:valid {
        color: black;
        border: 5px solid #dadadada;
        border-radius: 7px;
        }
        input:invalid {
        color: navy;
        outline: none;
        border-color: #ff1050;
        box-shadow: 0 0 10px #ff0000;
        }

        <form name="form1"> 
        <input pattern="(?![aA]d{6}$).*" title="Please enter a valid string." placeholder="Please enter valid text" />
        <input type="Submit"/>
        </form>








        share|improve this answer














        Your current pattern matches a string that starts with a or A and then has strictly 6 digits. The ^ is redundant in pattern regex since it is anchored by default.



        So, in fact, the current regex is ^[Aa]d{6}$, and to write a reverse HTML5 pattern you may use



        pattern="(?![aA]d{6}$).*"


        This pattern will get parsed as /^(?:(?![aA]d{6}$).*)$/ pattern (with u modifier in Chrome, Firefox and other browsers supporting this feature).



        The (?![Aa]d{6}$) negative lookahead will fail any string that starts with a or A and then having 6 digits to its end.



        The .* matches any 0+ chars. Use .+ to match any 1 or more chars. This part is required since the HTML5 regex should match the whole input.



        HTML5 demo:






        input:valid {
        color: black;
        border: 5px solid #dadadada;
        border-radius: 7px;
        }
        input:invalid {
        color: navy;
        outline: none;
        border-color: #ff1050;
        box-shadow: 0 0 10px #ff0000;
        }

        <form name="form1"> 
        <input pattern="(?![aA]d{6}$).*" title="Please enter a valid string." placeholder="Please enter valid text" />
        <input type="Submit"/>
        </form>








        input:valid {
        color: black;
        border: 5px solid #dadadada;
        border-radius: 7px;
        }
        input:invalid {
        color: navy;
        outline: none;
        border-color: #ff1050;
        box-shadow: 0 0 10px #ff0000;
        }

        <form name="form1"> 
        <input pattern="(?![aA]d{6}$).*" title="Please enter a valid string." placeholder="Please enter valid text" />
        <input type="Submit"/>
        </form>





        input:valid {
        color: black;
        border: 5px solid #dadadada;
        border-radius: 7px;
        }
        input:invalid {
        color: navy;
        outline: none;
        border-color: #ff1050;
        box-shadow: 0 0 10px #ff0000;
        }

        <form name="form1"> 
        <input pattern="(?![aA]d{6}$).*" title="Please enter a valid string." placeholder="Please enter valid text" />
        <input type="Submit"/>
        </form>






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 22 at 11:31

























        answered Nov 22 at 10:58









        Wiktor Stribiżew

        305k16124201




        305k16124201






























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