Btukfyl

i was learning async library and just tried some codes myself and i am issueing a problem that can`t handle, can you please look at the code down below:)

    async.parallel([

    function (cb) {

        setTimeout(() => {

          let a = "asd";



          console.log("AAA");

          cb(a, null);



        }, 2000);

    },

    function (cb) {

      setTimeout( () => {

        let b = "dasd";



        console.log("BBBBB");

        cb(b, null);

      }, 5000);

    }

  ], function (error, results) {

    console.log("CCC");



    console.log("Errors: " + error);

    console.log("Results: " + results);

  });

I supposed that BBB should NOT output to the screen, but to my surprise it DOES, can you help me understand why?

You are using async.parallel(). All asynchronous tasks will be executed without waiting for each other and the execution order is not guaranteed.

Here's a breakdown on how your script is executed:

1. Both setTimeout() are set.


2. 2000 milliseconds later, console.log("AAA") and cb(a, null) are called.


3. 
   cb(a, null) has an error. So the main callback is called, and async.parallel() ends.


4. But the story does not end here. The second setTimeout() is already set. Calling the main callback will not clear the timeout.


5. 
   console.log("BBBBB") and cb(b, null) are called. This is why you see the output BBBBB.


6. Because the main callback is already called, calling cb(b, null) will not do anything.