Drawing a curve with vertical arrows
That is what I've got so far, but I have no idea how to insert the arrow. I would really appreciate any kind of help! Thanks again to @marmot
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}
draw[-stealth] (-4,0) -- (-4,4.5);
draw[blue] plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}) node at (-1.3,3) [left]{G"utefunktion};
draw[-stealth] (-4.5,0) -- (4.5,0) node[below right]{$mu$};
draw[black,thick] (0.25,-0.5) -- (0.25,5) node at (0.25, -0.5)[below]{140};
draw[-latex] (0.5,4.5) -- (4,4.5) node[midway,above]{H0 Bereich};
draw[-latex] (-0.05,4.5) -- (-4,4.5) node[midway,above]{H1 Bereich};
draw [red] (-4.2,0.5) -- (3,0.5) node at (-4.3,0.5) [left]{$alpha$ = 0,05};
draw [black] (-4.2,4) -- (4.5,4) node at (-4.2,4) [left]{1};
end{tikzpicture}
end{document}

tikz-pgf tikz-arrows
|
show 1 more comment
That is what I've got so far, but I have no idea how to insert the arrow. I would really appreciate any kind of help! Thanks again to @marmot
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}
draw[-stealth] (-4,0) -- (-4,4.5);
draw[blue] plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}) node at (-1.3,3) [left]{G"utefunktion};
draw[-stealth] (-4.5,0) -- (4.5,0) node[below right]{$mu$};
draw[black,thick] (0.25,-0.5) -- (0.25,5) node at (0.25, -0.5)[below]{140};
draw[-latex] (0.5,4.5) -- (4,4.5) node[midway,above]{H0 Bereich};
draw[-latex] (-0.05,4.5) -- (-4,4.5) node[midway,above]{H1 Bereich};
draw [red] (-4.2,0.5) -- (3,0.5) node at (-4.3,0.5) [left]{$alpha$ = 0,05};
draw [black] (-4.2,4) -- (4.5,4) node at (-4.2,4) [left]{1};
end{tikzpicture}
end{document}

tikz-pgf tikz-arrows
4
it shouldn't be so difficult. you need to define math expression for function first and show us what you trayed so far or simply wait for someone who will be willing to draw your image instead of you ;-)..,
– Zarko
yesterday
6
I'm voting to close this question as off-topic because it is ajust-do-it-for-meclass of question. Most of your past questions belongs to the same class as well.
– Raaja
yesterday
2
Please don't downvote below a score of -1, even if the question in its current form needs some improvement. A score of -1 is enough to show that the question needs work, anything below that is of no use. Also, if you downvote or vote to close, please leave a comment explaining why you did so, but wait at least 24 hours after asking the OP for improvements to the question before voting to close.
– Kurt
yesterday
1
Looks like atanh:documentclass[tikz,border=3.14mm]{standalone} begin{document} begin{tikzpicture} draw plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}); draw[-stealth] (-4.5,0) -- (4.5,0); draw[-stealth] (0,0) -- (0,4.5); end{tikzpicture} end{document}
– marmot
yesterday
Possible duplicate of tex.stackexchange.com/questions/475602/…
– John Kormylo
yesterday
|
show 1 more comment
That is what I've got so far, but I have no idea how to insert the arrow. I would really appreciate any kind of help! Thanks again to @marmot
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}
draw[-stealth] (-4,0) -- (-4,4.5);
draw[blue] plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}) node at (-1.3,3) [left]{G"utefunktion};
draw[-stealth] (-4.5,0) -- (4.5,0) node[below right]{$mu$};
draw[black,thick] (0.25,-0.5) -- (0.25,5) node at (0.25, -0.5)[below]{140};
draw[-latex] (0.5,4.5) -- (4,4.5) node[midway,above]{H0 Bereich};
draw[-latex] (-0.05,4.5) -- (-4,4.5) node[midway,above]{H1 Bereich};
draw [red] (-4.2,0.5) -- (3,0.5) node at (-4.3,0.5) [left]{$alpha$ = 0,05};
draw [black] (-4.2,4) -- (4.5,4) node at (-4.2,4) [left]{1};
end{tikzpicture}
end{document}

tikz-pgf tikz-arrows
That is what I've got so far, but I have no idea how to insert the arrow. I would really appreciate any kind of help! Thanks again to @marmot
documentclass[tikz,border=3.14mm]{standalone}
begin{document}
begin{tikzpicture}
draw[-stealth] (-4,0) -- (-4,4.5);
draw[blue] plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}) node at (-1.3,3) [left]{G"utefunktion};
draw[-stealth] (-4.5,0) -- (4.5,0) node[below right]{$mu$};
draw[black,thick] (0.25,-0.5) -- (0.25,5) node at (0.25, -0.5)[below]{140};
draw[-latex] (0.5,4.5) -- (4,4.5) node[midway,above]{H0 Bereich};
draw[-latex] (-0.05,4.5) -- (-4,4.5) node[midway,above]{H1 Bereich};
draw [red] (-4.2,0.5) -- (3,0.5) node at (-4.3,0.5) [left]{$alpha$ = 0,05};
draw [black] (-4.2,4) -- (4.5,4) node at (-4.2,4) [left]{1};
end{tikzpicture}
end{document}

tikz-pgf tikz-arrows
tikz-pgf tikz-arrows
edited 6 hours ago
sheß
2,03711436
2,03711436
asked yesterday
RebeccaRebecca
675
675
4
it shouldn't be so difficult. you need to define math expression for function first and show us what you trayed so far or simply wait for someone who will be willing to draw your image instead of you ;-)..,
– Zarko
yesterday
6
I'm voting to close this question as off-topic because it is ajust-do-it-for-meclass of question. Most of your past questions belongs to the same class as well.
– Raaja
yesterday
2
Please don't downvote below a score of -1, even if the question in its current form needs some improvement. A score of -1 is enough to show that the question needs work, anything below that is of no use. Also, if you downvote or vote to close, please leave a comment explaining why you did so, but wait at least 24 hours after asking the OP for improvements to the question before voting to close.
– Kurt
yesterday
1
Looks like atanh:documentclass[tikz,border=3.14mm]{standalone} begin{document} begin{tikzpicture} draw plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}); draw[-stealth] (-4.5,0) -- (4.5,0); draw[-stealth] (0,0) -- (0,4.5); end{tikzpicture} end{document}
– marmot
yesterday
Possible duplicate of tex.stackexchange.com/questions/475602/…
– John Kormylo
yesterday
|
show 1 more comment
4
it shouldn't be so difficult. you need to define math expression for function first and show us what you trayed so far or simply wait for someone who will be willing to draw your image instead of you ;-)..,
– Zarko
yesterday
6
I'm voting to close this question as off-topic because it is ajust-do-it-for-meclass of question. Most of your past questions belongs to the same class as well.
– Raaja
yesterday
2
Please don't downvote below a score of -1, even if the question in its current form needs some improvement. A score of -1 is enough to show that the question needs work, anything below that is of no use. Also, if you downvote or vote to close, please leave a comment explaining why you did so, but wait at least 24 hours after asking the OP for improvements to the question before voting to close.
– Kurt
yesterday
1
Looks like atanh:documentclass[tikz,border=3.14mm]{standalone} begin{document} begin{tikzpicture} draw plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}); draw[-stealth] (-4.5,0) -- (4.5,0); draw[-stealth] (0,0) -- (0,4.5); end{tikzpicture} end{document}
– marmot
yesterday
Possible duplicate of tex.stackexchange.com/questions/475602/…
– John Kormylo
yesterday
4
4
it shouldn't be so difficult. you need to define math expression for function first and show us what you trayed so far or simply wait for someone who will be willing to draw your image instead of you ;-)..,
– Zarko
yesterday
it shouldn't be so difficult. you need to define math expression for function first and show us what you trayed so far or simply wait for someone who will be willing to draw your image instead of you ;-)..,
– Zarko
yesterday
6
6
I'm voting to close this question as off-topic because it is a
just-do-it-for-me class of question. Most of your past questions belongs to the same class as well.– Raaja
yesterday
I'm voting to close this question as off-topic because it is a
just-do-it-for-me class of question. Most of your past questions belongs to the same class as well.– Raaja
yesterday
2
2
Please don't downvote below a score of -1, even if the question in its current form needs some improvement. A score of -1 is enough to show that the question needs work, anything below that is of no use. Also, if you downvote or vote to close, please leave a comment explaining why you did so, but wait at least 24 hours after asking the OP for improvements to the question before voting to close.
– Kurt
yesterday
Please don't downvote below a score of -1, even if the question in its current form needs some improvement. A score of -1 is enough to show that the question needs work, anything below that is of no use. Also, if you downvote or vote to close, please leave a comment explaining why you did so, but wait at least 24 hours after asking the OP for improvements to the question before voting to close.
– Kurt
yesterday
1
1
Looks like a
tanh: documentclass[tikz,border=3.14mm]{standalone} begin{document} begin{tikzpicture} draw plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}); draw[-stealth] (-4.5,0) -- (4.5,0); draw[-stealth] (0,0) -- (0,4.5); end{tikzpicture} end{document}– marmot
yesterday
Looks like a
tanh: documentclass[tikz,border=3.14mm]{standalone} begin{document} begin{tikzpicture} draw plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}); draw[-stealth] (-4.5,0) -- (4.5,0); draw[-stealth] (0,0) -- (0,4.5); end{tikzpicture} end{document}– marmot
yesterday
Possible duplicate of tex.stackexchange.com/questions/475602/…
– John Kormylo
yesterday
Possible duplicate of tex.stackexchange.com/questions/475602/…
– John Kormylo
yesterday
|
show 1 more comment
1 Answer
1
active
oldest
votes
Actually with shade, drawing the arrow is not really complicated. However, the text is not really readable IMHO.
In this answer, I don't use tang function, but a simple curve using in and out. This helps me calculate the coordinates for drawing the arrow.
Next time you ask a question, please make sure that you put some efforts into solving it in advance, otherwise it is very likely that your question is closed (like this one).
documentclass[tikz]{standalone}
usetikzlibrary{intersections,decorations.markings}
usepackage{amsmath}
begin{document}
begin{tikzpicture}[scale=5,>=stealth]
draw[<->] (0,1.1) -- (0,0) coordinate (o) -- (1.75,0) coordinate (x) node[below] {$mu$};
path (0,1) coordinate (y);
draw (-.02,1) node[left] {$1$}--(.02,1);
draw (-.02,0) node[left] {$0$}--(0,0);
draw[name path=alpha,red] (-.1,.05) node[left] {$alpha=0.05$}--(1.75,.05);
draw[name path=curve,blue,postaction={
decorate,
decoration={
markings,
mark=at position 0.5 with coordinate (midarrow);,
mark=at position 0.55 with coordinate (nodename);
}
}] (0,1) to[out=0,in=180] (1.5,0);
path[name intersections={of=curve and alpha,by=inter}];
draw (inter) -- (inter |- o) -- ++ (0,-.1) node[below] {$140$};
draw (inter) -- (inter |- y) -- ++ (0,.2);
draw (y) -- ++ (1.75,0);
draw[->] ([shift={(-.02,.05)}]inter |- y) node[above left] {$H_1$-Bereich} -- ++ (-.5,0);
draw[->] ([shift={(.02,.05)}]inter |- y) node[above right] {$H_0$-Bereich} -- ++ (.5,0);
path[blue] (nodename) node[below left] {G"utefunktion};
path (o)--(y) node[midway,sloped,above,font=footnotesize] {$g(mu)=P(text{Ablehnung von }H_0)$};
shade[top color=yellow!60!black,bottom color=yellow] (midarrow) -- ++(.1,.1) --++(-.05,0) --++(0,.15) --++(-.1,0) --++(0,-.15) --++(-.05,0) --cycle;
shade[top color=yellow,bottom color=yellow!60!black] ([shift={(.05,.25)}]midarrow) --++(0,.15) --++(.05,0) --++(-.1,.1) --++(-.1,-.1) --++(.05,0) --++(0,-.15) -- cycle;
path[yellow!20!black] (midarrow) --++(0,.25) node {Some text};
node at (0,1.25) {$H_0:;mugemu_0$};
end{tikzpicture}
end{document}

add a comment |
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Actually with shade, drawing the arrow is not really complicated. However, the text is not really readable IMHO.
In this answer, I don't use tang function, but a simple curve using in and out. This helps me calculate the coordinates for drawing the arrow.
Next time you ask a question, please make sure that you put some efforts into solving it in advance, otherwise it is very likely that your question is closed (like this one).
documentclass[tikz]{standalone}
usetikzlibrary{intersections,decorations.markings}
usepackage{amsmath}
begin{document}
begin{tikzpicture}[scale=5,>=stealth]
draw[<->] (0,1.1) -- (0,0) coordinate (o) -- (1.75,0) coordinate (x) node[below] {$mu$};
path (0,1) coordinate (y);
draw (-.02,1) node[left] {$1$}--(.02,1);
draw (-.02,0) node[left] {$0$}--(0,0);
draw[name path=alpha,red] (-.1,.05) node[left] {$alpha=0.05$}--(1.75,.05);
draw[name path=curve,blue,postaction={
decorate,
decoration={
markings,
mark=at position 0.5 with coordinate (midarrow);,
mark=at position 0.55 with coordinate (nodename);
}
}] (0,1) to[out=0,in=180] (1.5,0);
path[name intersections={of=curve and alpha,by=inter}];
draw (inter) -- (inter |- o) -- ++ (0,-.1) node[below] {$140$};
draw (inter) -- (inter |- y) -- ++ (0,.2);
draw (y) -- ++ (1.75,0);
draw[->] ([shift={(-.02,.05)}]inter |- y) node[above left] {$H_1$-Bereich} -- ++ (-.5,0);
draw[->] ([shift={(.02,.05)}]inter |- y) node[above right] {$H_0$-Bereich} -- ++ (.5,0);
path[blue] (nodename) node[below left] {G"utefunktion};
path (o)--(y) node[midway,sloped,above,font=footnotesize] {$g(mu)=P(text{Ablehnung von }H_0)$};
shade[top color=yellow!60!black,bottom color=yellow] (midarrow) -- ++(.1,.1) --++(-.05,0) --++(0,.15) --++(-.1,0) --++(0,-.15) --++(-.05,0) --cycle;
shade[top color=yellow,bottom color=yellow!60!black] ([shift={(.05,.25)}]midarrow) --++(0,.15) --++(.05,0) --++(-.1,.1) --++(-.1,-.1) --++(.05,0) --++(0,-.15) -- cycle;
path[yellow!20!black] (midarrow) --++(0,.25) node {Some text};
node at (0,1.25) {$H_0:;mugemu_0$};
end{tikzpicture}
end{document}

add a comment |
Actually with shade, drawing the arrow is not really complicated. However, the text is not really readable IMHO.
In this answer, I don't use tang function, but a simple curve using in and out. This helps me calculate the coordinates for drawing the arrow.
Next time you ask a question, please make sure that you put some efforts into solving it in advance, otherwise it is very likely that your question is closed (like this one).
documentclass[tikz]{standalone}
usetikzlibrary{intersections,decorations.markings}
usepackage{amsmath}
begin{document}
begin{tikzpicture}[scale=5,>=stealth]
draw[<->] (0,1.1) -- (0,0) coordinate (o) -- (1.75,0) coordinate (x) node[below] {$mu$};
path (0,1) coordinate (y);
draw (-.02,1) node[left] {$1$}--(.02,1);
draw (-.02,0) node[left] {$0$}--(0,0);
draw[name path=alpha,red] (-.1,.05) node[left] {$alpha=0.05$}--(1.75,.05);
draw[name path=curve,blue,postaction={
decorate,
decoration={
markings,
mark=at position 0.5 with coordinate (midarrow);,
mark=at position 0.55 with coordinate (nodename);
}
}] (0,1) to[out=0,in=180] (1.5,0);
path[name intersections={of=curve and alpha,by=inter}];
draw (inter) -- (inter |- o) -- ++ (0,-.1) node[below] {$140$};
draw (inter) -- (inter |- y) -- ++ (0,.2);
draw (y) -- ++ (1.75,0);
draw[->] ([shift={(-.02,.05)}]inter |- y) node[above left] {$H_1$-Bereich} -- ++ (-.5,0);
draw[->] ([shift={(.02,.05)}]inter |- y) node[above right] {$H_0$-Bereich} -- ++ (.5,0);
path[blue] (nodename) node[below left] {G"utefunktion};
path (o)--(y) node[midway,sloped,above,font=footnotesize] {$g(mu)=P(text{Ablehnung von }H_0)$};
shade[top color=yellow!60!black,bottom color=yellow] (midarrow) -- ++(.1,.1) --++(-.05,0) --++(0,.15) --++(-.1,0) --++(0,-.15) --++(-.05,0) --cycle;
shade[top color=yellow,bottom color=yellow!60!black] ([shift={(.05,.25)}]midarrow) --++(0,.15) --++(.05,0) --++(-.1,.1) --++(-.1,-.1) --++(.05,0) --++(0,-.15) -- cycle;
path[yellow!20!black] (midarrow) --++(0,.25) node {Some text};
node at (0,1.25) {$H_0:;mugemu_0$};
end{tikzpicture}
end{document}

add a comment |
Actually with shade, drawing the arrow is not really complicated. However, the text is not really readable IMHO.
In this answer, I don't use tang function, but a simple curve using in and out. This helps me calculate the coordinates for drawing the arrow.
Next time you ask a question, please make sure that you put some efforts into solving it in advance, otherwise it is very likely that your question is closed (like this one).
documentclass[tikz]{standalone}
usetikzlibrary{intersections,decorations.markings}
usepackage{amsmath}
begin{document}
begin{tikzpicture}[scale=5,>=stealth]
draw[<->] (0,1.1) -- (0,0) coordinate (o) -- (1.75,0) coordinate (x) node[below] {$mu$};
path (0,1) coordinate (y);
draw (-.02,1) node[left] {$1$}--(.02,1);
draw (-.02,0) node[left] {$0$}--(0,0);
draw[name path=alpha,red] (-.1,.05) node[left] {$alpha=0.05$}--(1.75,.05);
draw[name path=curve,blue,postaction={
decorate,
decoration={
markings,
mark=at position 0.5 with coordinate (midarrow);,
mark=at position 0.55 with coordinate (nodename);
}
}] (0,1) to[out=0,in=180] (1.5,0);
path[name intersections={of=curve and alpha,by=inter}];
draw (inter) -- (inter |- o) -- ++ (0,-.1) node[below] {$140$};
draw (inter) -- (inter |- y) -- ++ (0,.2);
draw (y) -- ++ (1.75,0);
draw[->] ([shift={(-.02,.05)}]inter |- y) node[above left] {$H_1$-Bereich} -- ++ (-.5,0);
draw[->] ([shift={(.02,.05)}]inter |- y) node[above right] {$H_0$-Bereich} -- ++ (.5,0);
path[blue] (nodename) node[below left] {G"utefunktion};
path (o)--(y) node[midway,sloped,above,font=footnotesize] {$g(mu)=P(text{Ablehnung von }H_0)$};
shade[top color=yellow!60!black,bottom color=yellow] (midarrow) -- ++(.1,.1) --++(-.05,0) --++(0,.15) --++(-.1,0) --++(0,-.15) --++(-.05,0) --cycle;
shade[top color=yellow,bottom color=yellow!60!black] ([shift={(.05,.25)}]midarrow) --++(0,.15) --++(.05,0) --++(-.1,.1) --++(-.1,-.1) --++(.05,0) --++(0,-.15) -- cycle;
path[yellow!20!black] (midarrow) --++(0,.25) node {Some text};
node at (0,1.25) {$H_0:;mugemu_0$};
end{tikzpicture}
end{document}

Actually with shade, drawing the arrow is not really complicated. However, the text is not really readable IMHO.
In this answer, I don't use tang function, but a simple curve using in and out. This helps me calculate the coordinates for drawing the arrow.
Next time you ask a question, please make sure that you put some efforts into solving it in advance, otherwise it is very likely that your question is closed (like this one).
documentclass[tikz]{standalone}
usetikzlibrary{intersections,decorations.markings}
usepackage{amsmath}
begin{document}
begin{tikzpicture}[scale=5,>=stealth]
draw[<->] (0,1.1) -- (0,0) coordinate (o) -- (1.75,0) coordinate (x) node[below] {$mu$};
path (0,1) coordinate (y);
draw (-.02,1) node[left] {$1$}--(.02,1);
draw (-.02,0) node[left] {$0$}--(0,0);
draw[name path=alpha,red] (-.1,.05) node[left] {$alpha=0.05$}--(1.75,.05);
draw[name path=curve,blue,postaction={
decorate,
decoration={
markings,
mark=at position 0.5 with coordinate (midarrow);,
mark=at position 0.55 with coordinate (nodename);
}
}] (0,1) to[out=0,in=180] (1.5,0);
path[name intersections={of=curve and alpha,by=inter}];
draw (inter) -- (inter |- o) -- ++ (0,-.1) node[below] {$140$};
draw (inter) -- (inter |- y) -- ++ (0,.2);
draw (y) -- ++ (1.75,0);
draw[->] ([shift={(-.02,.05)}]inter |- y) node[above left] {$H_1$-Bereich} -- ++ (-.5,0);
draw[->] ([shift={(.02,.05)}]inter |- y) node[above right] {$H_0$-Bereich} -- ++ (.5,0);
path[blue] (nodename) node[below left] {G"utefunktion};
path (o)--(y) node[midway,sloped,above,font=footnotesize] {$g(mu)=P(text{Ablehnung von }H_0)$};
shade[top color=yellow!60!black,bottom color=yellow] (midarrow) -- ++(.1,.1) --++(-.05,0) --++(0,.15) --++(-.1,0) --++(0,-.15) --++(-.05,0) --cycle;
shade[top color=yellow,bottom color=yellow!60!black] ([shift={(.05,.25)}]midarrow) --++(0,.15) --++(.05,0) --++(-.1,.1) --++(-.1,-.1) --++(.05,0) --++(0,-.15) -- cycle;
path[yellow!20!black] (midarrow) --++(0,.25) node {Some text};
node at (0,1.25) {$H_0:;mugemu_0$};
end{tikzpicture}
end{document}

answered 6 hours ago
JouleVJouleV
9,91322558
9,91322558
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4
it shouldn't be so difficult. you need to define math expression for function first and show us what you trayed so far or simply wait for someone who will be willing to draw your image instead of you ;-)..,
– Zarko
yesterday
6
I'm voting to close this question as off-topic because it is a
just-do-it-for-meclass of question. Most of your past questions belongs to the same class as well.– Raaja
yesterday
2
Please don't downvote below a score of -1, even if the question in its current form needs some improvement. A score of -1 is enough to show that the question needs work, anything below that is of no use. Also, if you downvote or vote to close, please leave a comment explaining why you did so, but wait at least 24 hours after asking the OP for improvements to the question before voting to close.
– Kurt
yesterday
1
Looks like a
tanh:documentclass[tikz,border=3.14mm]{standalone} begin{document} begin{tikzpicture} draw plot[variable=x,smooth,domain=-4:4] (x,{2-2*tanh(1.5*(x+1))}); draw[-stealth] (-4.5,0) -- (4.5,0); draw[-stealth] (0,0) -- (0,4.5); end{tikzpicture} end{document}– marmot
yesterday
Possible duplicate of tex.stackexchange.com/questions/475602/…
– John Kormylo
yesterday