Register with a single Eureka server
I have an application that needs to communicate with 2 independent Eureka servers to fetch the service urls by service name. And it needs to register itself with one of the Eureka servers, not both. Different services will be running on each of the Eureka servers and the service registry shouldn't be shared by the Eureka servers. Is there a way in spring boot to achieve this behavior? This is my application.yml and I have provided 2 eureka servers as a list. The service is getting registered with both the servers.
Application:
@SpringBootApplication
@EnableDiscoveryClient
public class SampleApplication {
public static void main(String args) {
SpringApplication.run(SampleApplication.class, args);
}
}
pom.xml
<dependency>
<groupId>org.springframework.cloud</groupId>
<artifactId>spring-cloud-starter-netflix-eureka-client</artifactId>
</dependency>
application.yml :
spring:
application.name: mock
eureka:
client:
serviceUrl.defaultZone: url1, url2
spring-boot spring-cloud netflix-eureka spring-cloud-netflix
asked Nov 27 '18 at 20:42
JKtx5JKtx5
84
add a comment |
I have an application that needs to communicate with 2 independent Eureka servers to fetch the service urls by service name. And it needs to register itself with one of the Eureka servers, not both. Different services will be running on each of the Eureka servers and the service registry shouldn't be shared by the Eureka servers. Is there a way in spring boot to achieve this behavior? This is my application.yml and I have provided 2 eureka servers as a list. The service is getting registered with both the servers.
Application:
@SpringBootApplication
@EnableDiscoveryClient
public class SampleApplication {
public static void main(String args) {
SpringApplication.run(SampleApplication.class, args);
}
}
pom.xml
<dependency>
<groupId>org.springframework.cloud</groupId>
<artifactId>spring-cloud-starter-netflix-eureka-client</artifactId>
</dependency>
application.yml :
spring:
application.name: mock
eureka:
client:
serviceUrl.defaultZone: url1, url2
spring-boot spring-cloud netflix-eureka spring-cloud-netflix
asked Nov 27 '18 at 20:42
JKtx5JKtx5
84
There is not a way to communicate with 2 Eureka servers.
– spencergibb
Nov 27 '18 at 21:09
My answer is not possible do that, but you can create other discovery service adding so you will have two discovery services added to one, so you can use Eureka and Consul.
– Jonathan Johx
Nov 28 '18 at 0:36
add a comment |
I have an application that needs to communicate with 2 independent Eureka servers to fetch the service urls by service name. And it needs to register itself with one of the Eureka servers, not both. Different services will be running on each of the Eureka servers and the service registry shouldn't be shared by the Eureka servers. Is there a way in spring boot to achieve this behavior? This is my application.yml and I have provided 2 eureka servers as a list. The service is getting registered with both the servers.
Application:
@SpringBootApplication
@EnableDiscoveryClient
public class SampleApplication {
public static void main(String args) {
SpringApplication.run(SampleApplication.class, args);
}
}
pom.xml
<dependency>
<groupId>org.springframework.cloud</groupId>
<artifactId>spring-cloud-starter-netflix-eureka-client</artifactId>
</dependency>
application.yml :
spring:
application.name: mock
eureka:
client:
serviceUrl.defaultZone: url1, url2
spring-boot spring-cloud netflix-eureka spring-cloud-netflix
asked Nov 27 '18 at 20:42
JKtx5JKtx5
84
I have an application that needs to communicate with 2 independent Eureka servers to fetch the service urls by service name. And it needs to register itself with one of the Eureka servers, not both. Different services will be running on each of the Eureka servers and the service registry shouldn't be shared by the Eureka servers. Is there a way in spring boot to achieve this behavior? This is my application.yml and I have provided 2 eureka servers as a list. The service is getting registered with both the servers.
Application:
@SpringBootApplication
@EnableDiscoveryClient
public class SampleApplication {
public static void main(String args) {
SpringApplication.run(SampleApplication.class, args);
}
}
pom.xml
<dependency>
<groupId>org.springframework.cloud</groupId>
<artifactId>spring-cloud-starter-netflix-eureka-client</artifactId>
</dependency>
application.yml :
spring:
application.name: mock
eureka:
client:
serviceUrl.defaultZone: url1, url2
spring-boot spring-cloud netflix-eureka spring-cloud-netflix
spring-boot spring-cloud netflix-eureka spring-cloud-netflix
asked Nov 27 '18 at 20:42
JKtx5JKtx5
84
asked Nov 27 '18 at 20:42
JKtx5JKtx5
84
asked Nov 27 '18 at 20:42
JKtx5JKtx5
84
asked Nov 27 '18 at 20:42
JKtx5JKtx5
84
asked Nov 27 '18 at 20:42
JKtx5JKtx5
84
84
There is not a way to communicate with 2 Eureka servers.
– spencergibb
Nov 27 '18 at 21:09
My answer is not possible do that, but you can create other discovery service adding so you will have two discovery services added to one, so you can use Eureka and Consul.
– Jonathan Johx
Nov 28 '18 at 0:36
add a comment |
There is not a way to communicate with 2 Eureka servers.
– spencergibb
Nov 27 '18 at 21:09
My answer is not possible do that, but you can create other discovery service adding so you will have two discovery services added to one, so you can use Eureka and Consul.
– Jonathan Johx
Nov 28 '18 at 0:36
There is not a way to communicate with 2 Eureka servers.
– spencergibb
Nov 27 '18 at 21:09
There is not a way to communicate with 2 Eureka servers.
– spencergibb
Nov 27 '18 at 21:09
My answer is not possible do that, but you can create other discovery service adding so you will have two discovery services added to one, so you can use Eureka and Consul.
– Jonathan Johx
Nov 28 '18 at 0:36
My answer is not possible do that, but you can create other discovery service adding so you will have two discovery services added to one, so you can use Eureka and Consul.
– Jonathan Johx
Nov 28 '18 at 0:36
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53507805%2fregister-with-a-single-eureka-server%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53507805%2fregister-with-a-single-eureka-server%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
There is not a way to communicate with 2 Eureka servers.
– spencergibb
Nov 27 '18 at 21:09
My answer is not possible do that, but you can create other discovery service adding so you will have two discovery services added to one, so you can use Eureka and Consul.
– Jonathan Johx
Nov 28 '18 at 0:36