Python Remove last 3 characters of a string

109

I'm trying to remove the last 3 characters from a string in python, I don't know what these characters are so I can't use rstrip, I also need to remove any white space and convert to upper-case

an example would be:

foo = "Bs12 3ab"

foo.replace(" ", "").rstrip(foo[-3:]).upper()

This works and gives me BS12 which is what I want, however if the last 4th & 3rd characters are the same I loose both eg if foo = "BS11 1AA" I just get 'BS'

examples of foo could be:

BS1 1AB

bs11ab

BS111ab

The string could be 6 or 7 characters and I need to drop the last 3 (assuming no white space)

Any tips?

edited Nov 25 '09 at 17:19

abyx

43.7k1578111

asked Nov 25 '09 at 17:14

Sam Machin

1,19841017

add a comment |

109

I'm trying to remove the last 3 characters from a string in python, I don't know what these characters are so I can't use rstrip, I also need to remove any white space and convert to upper-case

an example would be:

foo = "Bs12 3ab"

foo.replace(" ", "").rstrip(foo[-3:]).upper()

This works and gives me BS12 which is what I want, however if the last 4th & 3rd characters are the same I loose both eg if foo = "BS11 1AA" I just get 'BS'

examples of foo could be:

BS1 1AB

bs11ab

BS111ab

The string could be 6 or 7 characters and I need to drop the last 3 (assuming no white space)

Any tips?

edited Nov 25 '09 at 17:19

abyx

43.7k1578111

asked Nov 25 '09 at 17:14

Sam Machin

1,19841017

add a comment |

109

I'm trying to remove the last 3 characters from a string in python, I don't know what these characters are so I can't use rstrip, I also need to remove any white space and convert to upper-case

an example would be:

foo = "Bs12 3ab"

foo.replace(" ", "").rstrip(foo[-3:]).upper()

This works and gives me BS12 which is what I want, however if the last 4th & 3rd characters are the same I loose both eg if foo = "BS11 1AA" I just get 'BS'

examples of foo could be:

BS1 1AB

bs11ab

BS111ab

The string could be 6 or 7 characters and I need to drop the last 3 (assuming no white space)

Any tips?

edited Nov 25 '09 at 17:19

abyx

43.7k1578111

asked Nov 25 '09 at 17:14

Sam Machin

1,19841017

I'm trying to remove the last 3 characters from a string in python, I don't know what these characters are so I can't use rstrip, I also need to remove any white space and convert to upper-case

an example would be:

foo = "Bs12 3ab"

foo.replace(" ", "").rstrip(foo[-3:]).upper()

This works and gives me BS12 which is what I want, however if the last 4th & 3rd characters are the same I loose both eg if foo = "BS11 1AA" I just get 'BS'

examples of foo could be:

BS1 1AB

bs11ab

BS111ab

The string could be 6 or 7 characters and I need to drop the last 3 (assuming no white space)

Any tips?

python string

edited Nov 25 '09 at 17:19

abyx

43.7k1578111

asked Nov 25 '09 at 17:14

Sam Machin

1,19841017

edited Nov 25 '09 at 17:19

abyx

43.7k1578111

asked Nov 25 '09 at 17:14

Sam Machin

1,19841017

edited Nov 25 '09 at 17:19

abyx

43.7k1578111

edited Nov 25 '09 at 17:19

abyx

43.7k1578111

edited Nov 25 '09 at 17:19

abyx

43.7k1578111

asked Nov 25 '09 at 17:14

Sam Machin

1,19841017

asked Nov 25 '09 at 17:14

Sam Machin

1,19841017

asked Nov 25 '09 at 17:14

Sam Machin

1,19841017

add a comment |

10 Answers
10

active

oldest

votes

199

Removing any and all whitespace:

foo = ''.join(foo.split())

Removing last three characters:

foo = foo[:-3]

Converting to capital letters:

foo = foo.upper()

All of that code in one line:

foo = ''.join(foo.split())[:-3].upper()

answered Nov 25 '09 at 17:23

Noctis Skytower

14k126090

9

I would like to note that ''.join(foo.split()) is better than foo.replace(' ', ''), when used on unicode strings because it removes any whitespace character, in addition to the ' ' character (in particular, non-breaking spaces are also removed). That said replace() is probably much faster, so it can be used if, say, the input strings are known to be encoded in ASCII, which only has one space character (I'm using Python 2 terminology, here.)

– Eric O Lebigot
Mar 14 '13 at 1:33

add a comment |

It doesn't work as you expect because strip is character based. You need to do this instead:

foo = foo.replace(' ', '')[:-3].upper()

answered Nov 25 '09 at 17:17

Nadia Alramli

80.1k25153147

11

That doesn't remove WHITESPACE as the OP requested; it removes only SPACE characters.

– John Machin
Nov 26 '09 at 6:04

add a comment |

>>> foo = "Bs12 3ab"

>>> foo[:-3]

'Bs12 '

>>> foo[:-3].strip()

'Bs12'

>>> foo[:-3].strip().replace(" ","")

'Bs12'

>>> foo[:-3].strip().replace(" ","").upper()

'BS12'

answered Nov 26 '09 at 1:15

ghostdog74

222k42212303

Is replace needed if strip already removes all whitespace?

– Lidia
Mar 31 '16 at 5:20

2

@Lidia Yes, strip only removes whitespace from the beginning and end of the string.

– Eliezer Miron
Sep 9 '16 at 20:31

It should be noted that you cannot chain this for example foo[3:]foo[:-3]

– crafter
Feb 4 '18 at 13:21

add a comment |

You might have misunderstood rstrip slightly, it strips not a string but any character in the string you specify.

Like this:

>>> text = "xxxxcbaabc"

>>> text.rstrip("abc")

'xxxx'

So instead, just use

text = text[:-3]

(after replacing whitespace with nothing)

answered Nov 25 '09 at 17:22

Mattias Nilsson

2,97311526

add a comment |

I try to avoid regular expressions, but this appears to work:

string = re.sub("s","",(string.lower()))[:-3]

answered Nov 25 '09 at 17:29

krs1

944515

1

string.lower() should be string.upper(). My mistake.

– krs1
Nov 25 '09 at 17:34

this is the only solution that addresses whitespace well

– Erik Aronesty
May 14 '18 at 22:40

add a comment |

What's wrong with this?

foo.replace(" ", "")[:-3].upper()

answered Nov 25 '09 at 17:18

abyx

43.7k1578111

add a comment |

>>> foo = 'BS1 1AB'

>>> foo.replace(" ", "").rstrip()[:-3].upper()

'BS1'

answered Nov 25 '09 at 17:18

SilentGhost

197k47268264

add a comment |

split

slice

concentrate

This is a good workout for beginners and it's easy to achieve.

Another advanced method is a function like this:

def trim(s):

    return trim(s[slice])

And for this question, you just want to remove the last characters, so you can write like this:

def trim(s):

    return s[ : -3]

I think you are over to care about what those three characters are, so you lost. You just want to remove last three, nevertheless who they are!

If you want to remove some specific characters, you can add some if judgements:

def trim(s):

    if [conditions]:   ### for some cases, I recommend using isinstance().

        return trim(s[slice])

edited Nov 29 '18 at 6:15

answered Nov 28 '18 at 1:50

Jaylin

163

add a comment |

Aren't you performing the operations in the wrong order? You requirement seems to be foo[:-3].replace(" ", "").upper()

answered Nov 25 '09 at 17:26

AndreaG

7902925

points at the following in the question >>> (assuming no white space)

– Noctis Skytower
Nov 25 '09 at 17:32

add a comment |

It some what depends on your definition of whitespace. I would generally call whitespace to be spaces, tabs, line breaks and carriage returns. If this is your definition you want to use a regex with s to replace all whitespace charactors:

import re



def myCleaner(foo):

    print 'dirty: ', foo

    foo = re.sub(r's', '', foo)

    foo = foo[:-3]

    foo = foo.upper()

    print 'clean:', foo

    print



myCleaner("BS1 1AB")

myCleaner("bs11ab")

myCleaner("BS111ab")

answered Nov 25 '09 at 17:33

Lee Joramo

465

add a comment |

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10 Answers
10

active

oldest

votes

10 Answers
10

active

oldest

votes

199

Removing any and all whitespace:

foo = ''.join(foo.split())

Removing last three characters:

foo = foo[:-3]

Converting to capital letters:

foo = foo.upper()

All of that code in one line:

foo = ''.join(foo.split())[:-3].upper()

answered Nov 25 '09 at 17:23

Noctis Skytower

14k126090

9

I would like to note that ''.join(foo.split()) is better than foo.replace(' ', ''), when used on unicode strings because it removes any whitespace character, in addition to the ' ' character (in particular, non-breaking spaces are also removed). That said replace() is probably much faster, so it can be used if, say, the input strings are known to be encoded in ASCII, which only has one space character (I'm using Python 2 terminology, here.)

– Eric O Lebigot
Mar 14 '13 at 1:33

add a comment |

199

Removing any and all whitespace:

foo = ''.join(foo.split())

Removing last three characters:

foo = foo[:-3]

Converting to capital letters:

foo = foo.upper()

All of that code in one line:

foo = ''.join(foo.split())[:-3].upper()

answered Nov 25 '09 at 17:23

Noctis Skytower

14k126090

9

I would like to note that ''.join(foo.split()) is better than foo.replace(' ', ''), when used on unicode strings because it removes any whitespace character, in addition to the ' ' character (in particular, non-breaking spaces are also removed). That said replace() is probably much faster, so it can be used if, say, the input strings are known to be encoded in ASCII, which only has one space character (I'm using Python 2 terminology, here.)

– Eric O Lebigot
Mar 14 '13 at 1:33

add a comment |

199

Removing any and all whitespace:

foo = ''.join(foo.split())

Removing last three characters:

foo = foo[:-3]

Converting to capital letters:

foo = foo.upper()

All of that code in one line:

foo = ''.join(foo.split())[:-3].upper()

answered Nov 25 '09 at 17:23

Noctis Skytower

14k126090

Removing any and all whitespace:

foo = ''.join(foo.split())

Removing last three characters:

foo = foo[:-3]

Converting to capital letters:

foo = foo.upper()

All of that code in one line:

foo = ''.join(foo.split())[:-3].upper()

answered Nov 25 '09 at 17:23

Noctis Skytower

14k126090

answered Nov 25 '09 at 17:23

Noctis Skytower

14k126090

answered Nov 25 '09 at 17:23

Noctis Skytower

14k126090

answered Nov 25 '09 at 17:23

Noctis Skytower

14k126090

9

I would like to note that ''.join(foo.split()) is better than foo.replace(' ', ''), when used on unicode strings because it removes any whitespace character, in addition to the ' ' character (in particular, non-breaking spaces are also removed). That said replace() is probably much faster, so it can be used if, say, the input strings are known to be encoded in ASCII, which only has one space character (I'm using Python 2 terminology, here.)

– Eric O Lebigot
Mar 14 '13 at 1:33

add a comment |

9

I would like to note that ''.join(foo.split()) is better than foo.replace(' ', ''), when used on unicode strings because it removes any whitespace character, in addition to the ' ' character (in particular, non-breaking spaces are also removed). That said replace() is probably much faster, so it can be used if, say, the input strings are known to be encoded in ASCII, which only has one space character (I'm using Python 2 terminology, here.)

– Eric O Lebigot
Mar 14 '13 at 1:33

I would like to note that ''.join(foo.split()) is better than foo.replace(' ', ''), when used on unicode strings because it removes any whitespace character, in addition to the ' ' character (in particular, non-breaking spaces are also removed). That said replace() is probably much faster, so it can be used if, say, the input strings are known to be encoded in ASCII, which only has one space character (I'm using Python 2 terminology, here.)

– Eric O Lebigot
Mar 14 '13 at 1:33

add a comment |

It doesn't work as you expect because strip is character based. You need to do this instead:

foo = foo.replace(' ', '')[:-3].upper()

answered Nov 25 '09 at 17:17

Nadia Alramli

80.1k25153147

11

That doesn't remove WHITESPACE as the OP requested; it removes only SPACE characters.

– John Machin
Nov 26 '09 at 6:04

add a comment |

It doesn't work as you expect because strip is character based. You need to do this instead:

foo = foo.replace(' ', '')[:-3].upper()

answered Nov 25 '09 at 17:17

Nadia Alramli

80.1k25153147

11

That doesn't remove WHITESPACE as the OP requested; it removes only SPACE characters.

– John Machin
Nov 26 '09 at 6:04

add a comment |

It doesn't work as you expect because strip is character based. You need to do this instead:

foo = foo.replace(' ', '')[:-3].upper()

answered Nov 25 '09 at 17:17

Nadia Alramli

80.1k25153147

It doesn't work as you expect because strip is character based. You need to do this instead:

foo = foo.replace(' ', '')[:-3].upper()

answered Nov 25 '09 at 17:17

Nadia Alramli

80.1k25153147

answered Nov 25 '09 at 17:17

Nadia Alramli

80.1k25153147

answered Nov 25 '09 at 17:17

Nadia Alramli

80.1k25153147

answered Nov 25 '09 at 17:17

Nadia Alramli

80.1k25153147

11

That doesn't remove WHITESPACE as the OP requested; it removes only SPACE characters.

– John Machin
Nov 26 '09 at 6:04

add a comment |

11

That doesn't remove WHITESPACE as the OP requested; it removes only SPACE characters.

– John Machin
Nov 26 '09 at 6:04

That doesn't remove WHITESPACE as the OP requested; it removes only SPACE characters.

– John Machin
Nov 26 '09 at 6:04

add a comment |

>>> foo = "Bs12 3ab"

>>> foo[:-3]

'Bs12 '

>>> foo[:-3].strip()

'Bs12'

>>> foo[:-3].strip().replace(" ","")

'Bs12'

>>> foo[:-3].strip().replace(" ","").upper()

'BS12'

answered Nov 26 '09 at 1:15

ghostdog74

222k42212303

Is replace needed if strip already removes all whitespace?

– Lidia
Mar 31 '16 at 5:20

2

@Lidia Yes, strip only removes whitespace from the beginning and end of the string.

– Eliezer Miron
Sep 9 '16 at 20:31

It should be noted that you cannot chain this for example foo[3:]foo[:-3]

– crafter
Feb 4 '18 at 13:21

add a comment |

>>> foo = "Bs12 3ab"

>>> foo[:-3]

'Bs12 '

>>> foo[:-3].strip()

'Bs12'

>>> foo[:-3].strip().replace(" ","")

'Bs12'

>>> foo[:-3].strip().replace(" ","").upper()

'BS12'

answered Nov 26 '09 at 1:15

ghostdog74

222k42212303

Is replace needed if strip already removes all whitespace?

– Lidia
Mar 31 '16 at 5:20

2

@Lidia Yes, strip only removes whitespace from the beginning and end of the string.

– Eliezer Miron
Sep 9 '16 at 20:31

It should be noted that you cannot chain this for example foo[3:]foo[:-3]

– crafter
Feb 4 '18 at 13:21

add a comment |

>>> foo = "Bs12 3ab"

>>> foo[:-3]

'Bs12 '

>>> foo[:-3].strip()

'Bs12'

>>> foo[:-3].strip().replace(" ","")

'Bs12'

>>> foo[:-3].strip().replace(" ","").upper()

'BS12'

answered Nov 26 '09 at 1:15

ghostdog74

222k42212303

>>> foo = "Bs12 3ab"

>>> foo[:-3]

'Bs12 '

>>> foo[:-3].strip()

'Bs12'

>>> foo[:-3].strip().replace(" ","")

'Bs12'

>>> foo[:-3].strip().replace(" ","").upper()

'BS12'

answered Nov 26 '09 at 1:15

ghostdog74

222k42212303

answered Nov 26 '09 at 1:15

ghostdog74

222k42212303

answered Nov 26 '09 at 1:15

ghostdog74

222k42212303

answered Nov 26 '09 at 1:15

ghostdog74

222k42212303

Is replace needed if strip already removes all whitespace?

– Lidia
Mar 31 '16 at 5:20

2

@Lidia Yes, strip only removes whitespace from the beginning and end of the string.

– Eliezer Miron
Sep 9 '16 at 20:31

It should be noted that you cannot chain this for example foo[3:]foo[:-3]

– crafter
Feb 4 '18 at 13:21

add a comment |

Is replace needed if strip already removes all whitespace?

– Lidia
Mar 31 '16 at 5:20

2

@Lidia Yes, strip only removes whitespace from the beginning and end of the string.

– Eliezer Miron
Sep 9 '16 at 20:31

It should be noted that you cannot chain this for example foo[3:]foo[:-3]

– crafter
Feb 4 '18 at 13:21

Is replace needed if strip already removes all whitespace?

– Lidia
Mar 31 '16 at 5:20

@Lidia Yes, strip only removes whitespace from the beginning and end of the string.

– Eliezer Miron
Sep 9 '16 at 20:31

It should be noted that you cannot chain this for example foo[3:]foo[:-3]

– crafter
Feb 4 '18 at 13:21

add a comment |

You might have misunderstood rstrip slightly, it strips not a string but any character in the string you specify.

Like this:

>>> text = "xxxxcbaabc"

>>> text.rstrip("abc")

'xxxx'

So instead, just use

text = text[:-3]

(after replacing whitespace with nothing)

answered Nov 25 '09 at 17:22

Mattias Nilsson

2,97311526

add a comment |

You might have misunderstood rstrip slightly, it strips not a string but any character in the string you specify.

Like this:

>>> text = "xxxxcbaabc"

>>> text.rstrip("abc")

'xxxx'

So instead, just use

text = text[:-3]

(after replacing whitespace with nothing)

answered Nov 25 '09 at 17:22

Mattias Nilsson

2,97311526

add a comment |

You might have misunderstood rstrip slightly, it strips not a string but any character in the string you specify.

Like this:

>>> text = "xxxxcbaabc"

>>> text.rstrip("abc")

'xxxx'

So instead, just use

text = text[:-3]

(after replacing whitespace with nothing)

answered Nov 25 '09 at 17:22

Mattias Nilsson

2,97311526

You might have misunderstood rstrip slightly, it strips not a string but any character in the string you specify.

Like this:

>>> text = "xxxxcbaabc"

>>> text.rstrip("abc")

'xxxx'

So instead, just use

text = text[:-3]

(after replacing whitespace with nothing)

answered Nov 25 '09 at 17:22

Mattias Nilsson

2,97311526

answered Nov 25 '09 at 17:22

Mattias Nilsson

2,97311526

answered Nov 25 '09 at 17:22

Mattias Nilsson

2,97311526

answered Nov 25 '09 at 17:22

Mattias Nilsson

2,97311526

add a comment |

I try to avoid regular expressions, but this appears to work:

string = re.sub("s","",(string.lower()))[:-3]

answered Nov 25 '09 at 17:29

krs1

944515

1

string.lower() should be string.upper(). My mistake.

– krs1
Nov 25 '09 at 17:34

this is the only solution that addresses whitespace well

– Erik Aronesty
May 14 '18 at 22:40

add a comment |

I try to avoid regular expressions, but this appears to work:

string = re.sub("s","",(string.lower()))[:-3]

answered Nov 25 '09 at 17:29

krs1

944515

1

string.lower() should be string.upper(). My mistake.

– krs1
Nov 25 '09 at 17:34

this is the only solution that addresses whitespace well

– Erik Aronesty
May 14 '18 at 22:40

add a comment |

I try to avoid regular expressions, but this appears to work:

string = re.sub("s","",(string.lower()))[:-3]

answered Nov 25 '09 at 17:29

krs1

944515

I try to avoid regular expressions, but this appears to work:

string = re.sub("s","",(string.lower()))[:-3]

answered Nov 25 '09 at 17:29

krs1

944515

answered Nov 25 '09 at 17:29

krs1

944515

answered Nov 25 '09 at 17:29

krs1

944515

answered Nov 25 '09 at 17:29

krs1

944515

1

string.lower() should be string.upper(). My mistake.

– krs1
Nov 25 '09 at 17:34

this is the only solution that addresses whitespace well

– Erik Aronesty
May 14 '18 at 22:40

add a comment |

1

string.lower() should be string.upper(). My mistake.

– krs1
Nov 25 '09 at 17:34

this is the only solution that addresses whitespace well

– Erik Aronesty
May 14 '18 at 22:40

string.lower() should be string.upper(). My mistake.

– krs1
Nov 25 '09 at 17:34

this is the only solution that addresses whitespace well

– Erik Aronesty
May 14 '18 at 22:40

add a comment |

What's wrong with this?

foo.replace(" ", "")[:-3].upper()

answered Nov 25 '09 at 17:18

abyx

43.7k1578111

add a comment |

What's wrong with this?

foo.replace(" ", "")[:-3].upper()

answered Nov 25 '09 at 17:18

abyx

43.7k1578111

add a comment |

What's wrong with this?

foo.replace(" ", "")[:-3].upper()

answered Nov 25 '09 at 17:18

abyx

43.7k1578111

What's wrong with this?

foo.replace(" ", "")[:-3].upper()

answered Nov 25 '09 at 17:18

abyx

43.7k1578111

answered Nov 25 '09 at 17:18

abyx

43.7k1578111

answered Nov 25 '09 at 17:18

abyx

43.7k1578111

answered Nov 25 '09 at 17:18

abyx

43.7k1578111

add a comment |

>>> foo = 'BS1 1AB'

>>> foo.replace(" ", "").rstrip()[:-3].upper()

'BS1'

answered Nov 25 '09 at 17:18

SilentGhost

197k47268264

add a comment |

>>> foo = 'BS1 1AB'

>>> foo.replace(" ", "").rstrip()[:-3].upper()

'BS1'

answered Nov 25 '09 at 17:18

SilentGhost

197k47268264

add a comment |

>>> foo = 'BS1 1AB'

>>> foo.replace(" ", "").rstrip()[:-3].upper()

'BS1'

answered Nov 25 '09 at 17:18

SilentGhost

197k47268264

>>> foo = 'BS1 1AB'

>>> foo.replace(" ", "").rstrip()[:-3].upper()

'BS1'

answered Nov 25 '09 at 17:18

SilentGhost

197k47268264

answered Nov 25 '09 at 17:18

SilentGhost

197k47268264

answered Nov 25 '09 at 17:18

SilentGhost

197k47268264

answered Nov 25 '09 at 17:18

SilentGhost

197k47268264

add a comment |

split

slice

concentrate

This is a good workout for beginners and it's easy to achieve.

Another advanced method is a function like this:

def trim(s):

    return trim(s[slice])

And for this question, you just want to remove the last characters, so you can write like this:

def trim(s):

    return s[ : -3]

I think you are over to care about what those three characters are, so you lost. You just want to remove last three, nevertheless who they are!

If you want to remove some specific characters, you can add some if judgements:

def trim(s):

    if [conditions]:   ### for some cases, I recommend using isinstance().

        return trim(s[slice])

edited Nov 29 '18 at 6:15

answered Nov 28 '18 at 1:50

Jaylin

163

add a comment |

split

slice

concentrate

This is a good workout for beginners and it's easy to achieve.

Another advanced method is a function like this:

def trim(s):

    return trim(s[slice])

And for this question, you just want to remove the last characters, so you can write like this:

def trim(s):

    return s[ : -3]

I think you are over to care about what those three characters are, so you lost. You just want to remove last three, nevertheless who they are!

If you want to remove some specific characters, you can add some if judgements:

def trim(s):

    if [conditions]:   ### for some cases, I recommend using isinstance().

        return trim(s[slice])

edited Nov 29 '18 at 6:15

answered Nov 28 '18 at 1:50

Jaylin

163

add a comment |

split

slice

concentrate

This is a good workout for beginners and it's easy to achieve.

Another advanced method is a function like this:

def trim(s):

    return trim(s[slice])

And for this question, you just want to remove the last characters, so you can write like this:

def trim(s):

    return s[ : -3]

I think you are over to care about what those three characters are, so you lost. You just want to remove last three, nevertheless who they are!

If you want to remove some specific characters, you can add some if judgements:

def trim(s):

    if [conditions]:   ### for some cases, I recommend using isinstance().

        return trim(s[slice])

edited Nov 29 '18 at 6:15

answered Nov 28 '18 at 1:50

Jaylin

163

split

slice

concentrate

This is a good workout for beginners and it's easy to achieve.

Another advanced method is a function like this:

def trim(s):

    return trim(s[slice])

And for this question, you just want to remove the last characters, so you can write like this:

def trim(s):

    return s[ : -3]

I think you are over to care about what those three characters are, so you lost. You just want to remove last three, nevertheless who they are!

If you want to remove some specific characters, you can add some if judgements:

def trim(s):

    if [conditions]:   ### for some cases, I recommend using isinstance().

        return trim(s[slice])

edited Nov 29 '18 at 6:15

answered Nov 28 '18 at 1:50

Jaylin

163

edited Nov 29 '18 at 6:15

answered Nov 28 '18 at 1:50

Jaylin

163

answered Nov 28 '18 at 1:50

Jaylin

163

answered Nov 28 '18 at 1:50

Jaylin

163

add a comment |

Aren't you performing the operations in the wrong order? You requirement seems to be foo[:-3].replace(" ", "").upper()

answered Nov 25 '09 at 17:26

AndreaG

7902925

points at the following in the question >>> (assuming no white space)

– Noctis Skytower
Nov 25 '09 at 17:32

add a comment |

Aren't you performing the operations in the wrong order? You requirement seems to be foo[:-3].replace(" ", "").upper()

answered Nov 25 '09 at 17:26

AndreaG

7902925

points at the following in the question >>> (assuming no white space)

– Noctis Skytower
Nov 25 '09 at 17:32

add a comment |

Aren't you performing the operations in the wrong order? You requirement seems to be foo[:-3].replace(" ", "").upper()

answered Nov 25 '09 at 17:26

AndreaG

7902925

Aren't you performing the operations in the wrong order? You requirement seems to be foo[:-3].replace(" ", "").upper()

answered Nov 25 '09 at 17:26

AndreaG

7902925

answered Nov 25 '09 at 17:26

AndreaG

7902925

answered Nov 25 '09 at 17:26

AndreaG

7902925

answered Nov 25 '09 at 17:26

AndreaG

7902925

points at the following in the question >>> (assuming no white space)

– Noctis Skytower
Nov 25 '09 at 17:32

add a comment |

points at the following in the question >>> (assuming no white space)

– Noctis Skytower
Nov 25 '09 at 17:32

points at the following in the question >>> (assuming no white space)

– Noctis Skytower
Nov 25 '09 at 17:32

add a comment |

import re



def myCleaner(foo):

    print 'dirty: ', foo

    foo = re.sub(r's', '', foo)

    foo = foo[:-3]

    foo = foo.upper()

    print 'clean:', foo

    print



myCleaner("BS1 1AB")

myCleaner("bs11ab")

myCleaner("BS111ab")

answered Nov 25 '09 at 17:33

Lee Joramo

465

add a comment |

import re



def myCleaner(foo):

    print 'dirty: ', foo

    foo = re.sub(r's', '', foo)

    foo = foo[:-3]

    foo = foo.upper()

    print 'clean:', foo

    print



myCleaner("BS1 1AB")

myCleaner("bs11ab")

myCleaner("BS111ab")

answered Nov 25 '09 at 17:33

Lee Joramo

465

add a comment |

import re



def myCleaner(foo):

    print 'dirty: ', foo

    foo = re.sub(r's', '', foo)

    foo = foo[:-3]

    foo = foo.upper()

    print 'clean:', foo

    print



myCleaner("BS1 1AB")

myCleaner("bs11ab")

myCleaner("BS111ab")

answered Nov 25 '09 at 17:33

Lee Joramo

465

import re



def myCleaner(foo):

    print 'dirty: ', foo

    foo = re.sub(r's', '', foo)

    foo = foo[:-3]

    foo = foo.upper()

    print 'clean:', foo

    print



myCleaner("BS1 1AB")

myCleaner("bs11ab")

myCleaner("BS111ab")

answered Nov 25 '09 at 17:33

Lee Joramo

465

answered Nov 25 '09 at 17:33

Lee Joramo

465

answered Nov 25 '09 at 17:33

Lee Joramo

465

answered Nov 25 '09 at 17:33

Lee Joramo

465

add a comment |

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