PostgreSQL count in calendar week
I am trying to use PostgreSQL to count the occurrences of something in the past calendar week (Monday through present day). I have tried a few different things, currently I am looking at using EXTRACT dow to return the day of the week however this will return the same value for something that happened this Tuesday or last Tuesday.
SELECT COUNT(date_mastered) FROM words WHERE date_mastered EXTRACT dow >0;
If any one can point me in the right direction it would be appreciated.
sql postgresql
asked Nov 25 '18 at 21:38
user8735495user8735495
1449
add a comment |
I am trying to use PostgreSQL to count the occurrences of something in the past calendar week (Monday through present day). I have tried a few different things, currently I am looking at using EXTRACT dow to return the day of the week however this will return the same value for something that happened this Tuesday or last Tuesday.
SELECT COUNT(date_mastered) FROM words WHERE date_mastered EXTRACT dow >0;
If any one can point me in the right direction it would be appreciated.
sql postgresql
asked Nov 25 '18 at 21:38
user8735495user8735495
1449
add a comment |
I am trying to use PostgreSQL to count the occurrences of something in the past calendar week (Monday through present day). I have tried a few different things, currently I am looking at using EXTRACT dow to return the day of the week however this will return the same value for something that happened this Tuesday or last Tuesday.
SELECT COUNT(date_mastered) FROM words WHERE date_mastered EXTRACT dow >0;
If any one can point me in the right direction it would be appreciated.
sql postgresql
asked Nov 25 '18 at 21:38
user8735495user8735495
1449
I am trying to use PostgreSQL to count the occurrences of something in the past calendar week (Monday through present day). I have tried a few different things, currently I am looking at using EXTRACT dow to return the day of the week however this will return the same value for something that happened this Tuesday or last Tuesday.
SELECT COUNT(date_mastered) FROM words WHERE date_mastered EXTRACT dow >0;
If any one can point me in the right direction it would be appreciated.
sql postgresql
sql postgresql
asked Nov 25 '18 at 21:38
user8735495user8735495
1449
asked Nov 25 '18 at 21:38
user8735495user8735495
1449
asked Nov 25 '18 at 21:38
user8735495user8735495
1449
asked Nov 25 '18 at 21:38
user8735495user8735495
1449
asked Nov 25 '18 at 21:38
user8735495user8735495
1449
1449
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
How about date_trunc()?
SELECT COUNT(date_mastered)
FROM words
WHERE date_trunc('week', date_mastered) = date_trunc('week', now());
Actually, I think a better practice is:
SELECT COUNT(*)
FROM words
WHERE date_mastered >= date_trunc('week', now());
This assumes no future dates, but it allows the use of an index on date_mastered).
answered Nov 25 '18 at 21:39
Gordon LinoffGordon Linoff
770k35303404
This looks like it will work. I am a little confused how date mastered (yyyy-mm-dd) can be compared to date_trunc('week',now())
– user8735495
Nov 25 '18 at 21:43
@user8735495 . . . I am assuming thatdate_masteredis stored as adate. That makes the most sense.
– Gordon Linoff
Nov 25 '18 at 21:55
yes date_mastered is stored as a date. What I am unclear about is howdate_trunc('week',now())return the date of the most recent Sunday.
– user8735495
Nov 25 '18 at 21:57
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
How about date_trunc()?
SELECT COUNT(date_mastered)
FROM words
WHERE date_trunc('week', date_mastered) = date_trunc('week', now());
Actually, I think a better practice is:
SELECT COUNT(*)
FROM words
WHERE date_mastered >= date_trunc('week', now());
This assumes no future dates, but it allows the use of an index on date_mastered).
answered Nov 25 '18 at 21:39
Gordon LinoffGordon Linoff
770k35303404
This looks like it will work. I am a little confused how date mastered (yyyy-mm-dd) can be compared to date_trunc('week',now())
– user8735495
Nov 25 '18 at 21:43
@user8735495 . . . I am assuming thatdate_masteredis stored as adate. That makes the most sense.
– Gordon Linoff
Nov 25 '18 at 21:55
yes date_mastered is stored as a date. What I am unclear about is howdate_trunc('week',now())return the date of the most recent Sunday.
– user8735495
Nov 25 '18 at 21:57
add a comment |
How about date_trunc()?
SELECT COUNT(date_mastered)
FROM words
WHERE date_trunc('week', date_mastered) = date_trunc('week', now());
Actually, I think a better practice is:
SELECT COUNT(*)
FROM words
WHERE date_mastered >= date_trunc('week', now());
This assumes no future dates, but it allows the use of an index on date_mastered).
answered Nov 25 '18 at 21:39
Gordon LinoffGordon Linoff
770k35303404
This looks like it will work. I am a little confused how date mastered (yyyy-mm-dd) can be compared to date_trunc('week',now())
– user8735495
Nov 25 '18 at 21:43
@user8735495 . . . I am assuming thatdate_masteredis stored as adate. That makes the most sense.
– Gordon Linoff
Nov 25 '18 at 21:55
yes date_mastered is stored as a date. What I am unclear about is howdate_trunc('week',now())return the date of the most recent Sunday.
– user8735495
Nov 25 '18 at 21:57
add a comment |
How about date_trunc()?
SELECT COUNT(date_mastered)
FROM words
WHERE date_trunc('week', date_mastered) = date_trunc('week', now());
Actually, I think a better practice is:
SELECT COUNT(*)
FROM words
WHERE date_mastered >= date_trunc('week', now());
This assumes no future dates, but it allows the use of an index on date_mastered).
answered Nov 25 '18 at 21:39
Gordon LinoffGordon Linoff
770k35303404
How about date_trunc()?
SELECT COUNT(date_mastered)
FROM words
WHERE date_trunc('week', date_mastered) = date_trunc('week', now());
Actually, I think a better practice is:
SELECT COUNT(*)
FROM words
WHERE date_mastered >= date_trunc('week', now());
This assumes no future dates, but it allows the use of an index on date_mastered).
answered Nov 25 '18 at 21:39
Gordon LinoffGordon Linoff
770k35303404
answered Nov 25 '18 at 21:39
Gordon LinoffGordon Linoff
770k35303404
answered Nov 25 '18 at 21:39
Gordon LinoffGordon Linoff
770k35303404
answered Nov 25 '18 at 21:39
Gordon LinoffGordon Linoff
770k35303404
770k35303404
This looks like it will work. I am a little confused how date mastered (yyyy-mm-dd) can be compared to date_trunc('week',now())
– user8735495
Nov 25 '18 at 21:43
@user8735495 . . . I am assuming thatdate_masteredis stored as adate. That makes the most sense.
– Gordon Linoff
Nov 25 '18 at 21:55
yes date_mastered is stored as a date. What I am unclear about is howdate_trunc('week',now())return the date of the most recent Sunday.
– user8735495
Nov 25 '18 at 21:57
add a comment |
This looks like it will work. I am a little confused how date mastered (yyyy-mm-dd) can be compared to date_trunc('week',now())
– user8735495
Nov 25 '18 at 21:43
@user8735495 . . . I am assuming thatdate_masteredis stored as adate. That makes the most sense.
– Gordon Linoff
Nov 25 '18 at 21:55
yes date_mastered is stored as a date. What I am unclear about is howdate_trunc('week',now())return the date of the most recent Sunday.
– user8735495
Nov 25 '18 at 21:57
This looks like it will work. I am a little confused how date mastered (yyyy-mm-dd) can be compared to date_trunc('week',now())
– user8735495
Nov 25 '18 at 21:43
This looks like it will work. I am a little confused how date mastered (yyyy-mm-dd) can be compared to date_trunc('week',now())
– user8735495
Nov 25 '18 at 21:43
@user8735495 . . . I am assuming that
date_mastered is stored as a date. That makes the most sense.– Gordon Linoff
Nov 25 '18 at 21:55
@user8735495 . . . I am assuming that
date_mastered is stored as a date. That makes the most sense.– Gordon Linoff
Nov 25 '18 at 21:55
yes date_mastered is stored as a date. What I am unclear about is how
date_trunc('week',now()) return the date of the most recent Sunday.– user8735495
Nov 25 '18 at 21:57
yes date_mastered is stored as a date. What I am unclear about is how
date_trunc('week',now()) return the date of the most recent Sunday.– user8735495
Nov 25 '18 at 21:57
add a comment |
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