tikz-3dplot, geodesics and adressing endpoints in polar coordinates
I am trying to draw geodesics on a sphere. While many approaches, like for example this one, i am more interested in another way. If i specify two points, say q
and p
on the Sphere, i would like to join them by a geodesic, i.e. arc. Whether thats the longer or shorter arc, might be a problem for further stuff, i managed to do the following
documentclass[a4paper]{standalone}
usepackage{tikz,tikz-3dplot}
tikzstyle{point}=[inner sep=0pt, outer sep=0pt,%
minimum size=2pt,fill=black,shape=circle]
begin{document}
tdplotsetmaincoords{70}{110}
begin{tikzpicture}
begin{scope}[tdplot_main_coords]
%draw sphere
tdplotsphericalsurfaceplot{72}{36}{1}{black!75!white}{blue!20!white}%
{draw[color=black,thick,->] (1,0,0) -- (1.5,0,0) node[anchor=north east]{$x$};}%
{draw[color=black,thick,->] (0,1,0) -- (0,1.5,0) node[anchor=north west]{$y$};}%
{draw[color=black,thick,->] (0,0,1) -- (0,0,1.5) node[anchor=south]{$z$};}%
% draw geodesics
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,red!50!black]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0.7071,0.7071,0)
tdplotdrawpolytopearc[thick,blue!50!black]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,green!50!black]{1}{}{}
%draw point
tdplotsetcoord{P}{1}{30}{60}
node[point,label={0:(p)}] at (P) {};
end{scope}
end{tikzpicture}
end{document}
which yields
and leads me to my two questions:
1) I would like to be able to specify both “spanning” points (the second and third of tdplotdefinepoints
in polar coordinates. It would be enough, to have a function performing theta,phi
into px,py,pz
, similar to the function used for the point P
. Or maybe one could also kind of extract these coordinates from a label; is either of that possible?
2) when drawing an arc, is there a possibility – similar to the usual draw
to access the mid point? It would be enough to be able to place a node (with style) and label there, otherwhise a coordinate
would of course do the job, too. Any ideas on how to get that?
tikz-pgf 3d tikz-3dplot
add a comment |
I am trying to draw geodesics on a sphere. While many approaches, like for example this one, i am more interested in another way. If i specify two points, say q
and p
on the Sphere, i would like to join them by a geodesic, i.e. arc. Whether thats the longer or shorter arc, might be a problem for further stuff, i managed to do the following
documentclass[a4paper]{standalone}
usepackage{tikz,tikz-3dplot}
tikzstyle{point}=[inner sep=0pt, outer sep=0pt,%
minimum size=2pt,fill=black,shape=circle]
begin{document}
tdplotsetmaincoords{70}{110}
begin{tikzpicture}
begin{scope}[tdplot_main_coords]
%draw sphere
tdplotsphericalsurfaceplot{72}{36}{1}{black!75!white}{blue!20!white}%
{draw[color=black,thick,->] (1,0,0) -- (1.5,0,0) node[anchor=north east]{$x$};}%
{draw[color=black,thick,->] (0,1,0) -- (0,1.5,0) node[anchor=north west]{$y$};}%
{draw[color=black,thick,->] (0,0,1) -- (0,0,1.5) node[anchor=south]{$z$};}%
% draw geodesics
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,red!50!black]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0.7071,0.7071,0)
tdplotdrawpolytopearc[thick,blue!50!black]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,green!50!black]{1}{}{}
%draw point
tdplotsetcoord{P}{1}{30}{60}
node[point,label={0:(p)}] at (P) {};
end{scope}
end{tikzpicture}
end{document}
which yields
and leads me to my two questions:
1) I would like to be able to specify both “spanning” points (the second and third of tdplotdefinepoints
in polar coordinates. It would be enough, to have a function performing theta,phi
into px,py,pz
, similar to the function used for the point P
. Or maybe one could also kind of extract these coordinates from a label; is either of that possible?
2) when drawing an arc, is there a possibility – similar to the usual draw
to access the mid point? It would be enough to be able to place a node (with style) and label there, otherwhise a coordinate
would of course do the job, too. Any ideas on how to get that?
tikz-pgf 3d tikz-3dplot
Would you be interested in a solution that is entirely based on spherical coordinates? (IMHO it does not no make too much sense to use cartesian coordinates to parametrize points on the surface of a sphere.)
– marmot
Dec 30 '18 at 0:22
In most of my calculations its easier to have cartesian coordinates, since for geodesics (great arcs) you would have to calculate several modulo cases in spherical coordinates; tangent vectors are cartesian anyways. However, I would be interested in any solution :)
– Ronny
21 hours ago
add a comment |
I am trying to draw geodesics on a sphere. While many approaches, like for example this one, i am more interested in another way. If i specify two points, say q
and p
on the Sphere, i would like to join them by a geodesic, i.e. arc. Whether thats the longer or shorter arc, might be a problem for further stuff, i managed to do the following
documentclass[a4paper]{standalone}
usepackage{tikz,tikz-3dplot}
tikzstyle{point}=[inner sep=0pt, outer sep=0pt,%
minimum size=2pt,fill=black,shape=circle]
begin{document}
tdplotsetmaincoords{70}{110}
begin{tikzpicture}
begin{scope}[tdplot_main_coords]
%draw sphere
tdplotsphericalsurfaceplot{72}{36}{1}{black!75!white}{blue!20!white}%
{draw[color=black,thick,->] (1,0,0) -- (1.5,0,0) node[anchor=north east]{$x$};}%
{draw[color=black,thick,->] (0,1,0) -- (0,1.5,0) node[anchor=north west]{$y$};}%
{draw[color=black,thick,->] (0,0,1) -- (0,0,1.5) node[anchor=south]{$z$};}%
% draw geodesics
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,red!50!black]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0.7071,0.7071,0)
tdplotdrawpolytopearc[thick,blue!50!black]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,green!50!black]{1}{}{}
%draw point
tdplotsetcoord{P}{1}{30}{60}
node[point,label={0:(p)}] at (P) {};
end{scope}
end{tikzpicture}
end{document}
which yields
and leads me to my two questions:
1) I would like to be able to specify both “spanning” points (the second and third of tdplotdefinepoints
in polar coordinates. It would be enough, to have a function performing theta,phi
into px,py,pz
, similar to the function used for the point P
. Or maybe one could also kind of extract these coordinates from a label; is either of that possible?
2) when drawing an arc, is there a possibility – similar to the usual draw
to access the mid point? It would be enough to be able to place a node (with style) and label there, otherwhise a coordinate
would of course do the job, too. Any ideas on how to get that?
tikz-pgf 3d tikz-3dplot
I am trying to draw geodesics on a sphere. While many approaches, like for example this one, i am more interested in another way. If i specify two points, say q
and p
on the Sphere, i would like to join them by a geodesic, i.e. arc. Whether thats the longer or shorter arc, might be a problem for further stuff, i managed to do the following
documentclass[a4paper]{standalone}
usepackage{tikz,tikz-3dplot}
tikzstyle{point}=[inner sep=0pt, outer sep=0pt,%
minimum size=2pt,fill=black,shape=circle]
begin{document}
tdplotsetmaincoords{70}{110}
begin{tikzpicture}
begin{scope}[tdplot_main_coords]
%draw sphere
tdplotsphericalsurfaceplot{72}{36}{1}{black!75!white}{blue!20!white}%
{draw[color=black,thick,->] (1,0,0) -- (1.5,0,0) node[anchor=north east]{$x$};}%
{draw[color=black,thick,->] (0,1,0) -- (0,1.5,0) node[anchor=north west]{$y$};}%
{draw[color=black,thick,->] (0,0,1) -- (0,0,1.5) node[anchor=south]{$z$};}%
% draw geodesics
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,red!50!black]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0.7071,0.7071,0)
tdplotdrawpolytopearc[thick,blue!50!black]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,green!50!black]{1}{}{}
%draw point
tdplotsetcoord{P}{1}{30}{60}
node[point,label={0:(p)}] at (P) {};
end{scope}
end{tikzpicture}
end{document}
which yields
and leads me to my two questions:
1) I would like to be able to specify both “spanning” points (the second and third of tdplotdefinepoints
in polar coordinates. It would be enough, to have a function performing theta,phi
into px,py,pz
, similar to the function used for the point P
. Or maybe one could also kind of extract these coordinates from a label; is either of that possible?
2) when drawing an arc, is there a possibility – similar to the usual draw
to access the mid point? It would be enough to be able to place a node (with style) and label there, otherwhise a coordinate
would of course do the job, too. Any ideas on how to get that?
tikz-pgf 3d tikz-3dplot
tikz-pgf 3d tikz-3dplot
edited Apr 13 '17 at 12:36
Community♦
1
1
asked Nov 9 '14 at 19:12
Ronny
3,88511941
3,88511941
Would you be interested in a solution that is entirely based on spherical coordinates? (IMHO it does not no make too much sense to use cartesian coordinates to parametrize points on the surface of a sphere.)
– marmot
Dec 30 '18 at 0:22
In most of my calculations its easier to have cartesian coordinates, since for geodesics (great arcs) you would have to calculate several modulo cases in spherical coordinates; tangent vectors are cartesian anyways. However, I would be interested in any solution :)
– Ronny
21 hours ago
add a comment |
Would you be interested in a solution that is entirely based on spherical coordinates? (IMHO it does not no make too much sense to use cartesian coordinates to parametrize points on the surface of a sphere.)
– marmot
Dec 30 '18 at 0:22
In most of my calculations its easier to have cartesian coordinates, since for geodesics (great arcs) you would have to calculate several modulo cases in spherical coordinates; tangent vectors are cartesian anyways. However, I would be interested in any solution :)
– Ronny
21 hours ago
Would you be interested in a solution that is entirely based on spherical coordinates? (IMHO it does not no make too much sense to use cartesian coordinates to parametrize points on the surface of a sphere.)
– marmot
Dec 30 '18 at 0:22
Would you be interested in a solution that is entirely based on spherical coordinates? (IMHO it does not no make too much sense to use cartesian coordinates to parametrize points on the surface of a sphere.)
– marmot
Dec 30 '18 at 0:22
In most of my calculations its easier to have cartesian coordinates, since for geodesics (great arcs) you would have to calculate several modulo cases in spherical coordinates; tangent vectors are cartesian anyways. However, I would be interested in any solution :)
– Ronny
21 hours ago
In most of my calculations its easier to have cartesian coordinates, since for geodesics (great arcs) you would have to calculate several modulo cases in spherical coordinates; tangent vectors are cartesian anyways. However, I would be interested in any solution :)
– Ronny
21 hours ago
add a comment |
1 Answer
1
active
oldest
votes
This is at best 50% of an answer because I simply do not understand the first request. tdplotsetcoord{P}{1}{30}{60}
does define a point in 3d. Could you please rephrase the first request?
The second point is straightforward. decorations.markings
allows you to mark a point at any position of the path, of course including the middle. The style add coordinate={<name> at <pos>}
does that in the following MWE.
documentclass[a4paper]{standalone}
usepackage{tikz,tikz-3dplot}
usetikzlibrary{decorations.markings}
tikzset{point/.style={inner sep=0pt, outer sep=0pt,%
minimum size=2pt,fill=black,shape=circle},
add coordinate/.style args={#1 at #2}{postaction={decorate,
decoration={markings,mark=at position #2 with {coordinate (#1);}}}}}
begin{document}
tdplotsetmaincoords{70}{110}
begin{tikzpicture}
begin{scope}[tdplot_main_coords]
%draw sphere
tdplotsphericalsurfaceplot{72}{36}{1}{black!75!white}{blue!20!white}%
{draw[color=black,thick,->] (1,0,0) -- (1.5,0,0) node[anchor=north east]{$x$};}%
{draw[color=black,thick,->] (0,1,0) -- (0,1.5,0) node[anchor=north west]{$y$};}%
{draw[color=black,thick,->] (0,0,1) -- (0,0,1.5) node[anchor=south]{$z$};}%
% draw geodesics
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,red!50!black,add coordinate={M1 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0.7071,0.7071,0)
tdplotdrawpolytopearc[thick,blue!50!black,add coordinate={M2 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,green!50!black,add coordinate={M3 at 0.5}]{1}{}{}
%draw point
tdplotsetcoord{P}{1}{30}{60}
node[point,label={0:(p)}] at (P) {};
node[point,label={90:{$M_1$}}] at (M1){};
node[point,label={-90:{$M_2$}}] at (M2){};
node[point,label={0:{$M_3$}}] at (M3){};
end{scope}
end{tikzpicture}
end{document}
add a comment |
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1 Answer
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1 Answer
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active
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active
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votes
This is at best 50% of an answer because I simply do not understand the first request. tdplotsetcoord{P}{1}{30}{60}
does define a point in 3d. Could you please rephrase the first request?
The second point is straightforward. decorations.markings
allows you to mark a point at any position of the path, of course including the middle. The style add coordinate={<name> at <pos>}
does that in the following MWE.
documentclass[a4paper]{standalone}
usepackage{tikz,tikz-3dplot}
usetikzlibrary{decorations.markings}
tikzset{point/.style={inner sep=0pt, outer sep=0pt,%
minimum size=2pt,fill=black,shape=circle},
add coordinate/.style args={#1 at #2}{postaction={decorate,
decoration={markings,mark=at position #2 with {coordinate (#1);}}}}}
begin{document}
tdplotsetmaincoords{70}{110}
begin{tikzpicture}
begin{scope}[tdplot_main_coords]
%draw sphere
tdplotsphericalsurfaceplot{72}{36}{1}{black!75!white}{blue!20!white}%
{draw[color=black,thick,->] (1,0,0) -- (1.5,0,0) node[anchor=north east]{$x$};}%
{draw[color=black,thick,->] (0,1,0) -- (0,1.5,0) node[anchor=north west]{$y$};}%
{draw[color=black,thick,->] (0,0,1) -- (0,0,1.5) node[anchor=south]{$z$};}%
% draw geodesics
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,red!50!black,add coordinate={M1 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0.7071,0.7071,0)
tdplotdrawpolytopearc[thick,blue!50!black,add coordinate={M2 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,green!50!black,add coordinate={M3 at 0.5}]{1}{}{}
%draw point
tdplotsetcoord{P}{1}{30}{60}
node[point,label={0:(p)}] at (P) {};
node[point,label={90:{$M_1$}}] at (M1){};
node[point,label={-90:{$M_2$}}] at (M2){};
node[point,label={0:{$M_3$}}] at (M3){};
end{scope}
end{tikzpicture}
end{document}
add a comment |
This is at best 50% of an answer because I simply do not understand the first request. tdplotsetcoord{P}{1}{30}{60}
does define a point in 3d. Could you please rephrase the first request?
The second point is straightforward. decorations.markings
allows you to mark a point at any position of the path, of course including the middle. The style add coordinate={<name> at <pos>}
does that in the following MWE.
documentclass[a4paper]{standalone}
usepackage{tikz,tikz-3dplot}
usetikzlibrary{decorations.markings}
tikzset{point/.style={inner sep=0pt, outer sep=0pt,%
minimum size=2pt,fill=black,shape=circle},
add coordinate/.style args={#1 at #2}{postaction={decorate,
decoration={markings,mark=at position #2 with {coordinate (#1);}}}}}
begin{document}
tdplotsetmaincoords{70}{110}
begin{tikzpicture}
begin{scope}[tdplot_main_coords]
%draw sphere
tdplotsphericalsurfaceplot{72}{36}{1}{black!75!white}{blue!20!white}%
{draw[color=black,thick,->] (1,0,0) -- (1.5,0,0) node[anchor=north east]{$x$};}%
{draw[color=black,thick,->] (0,1,0) -- (0,1.5,0) node[anchor=north west]{$y$};}%
{draw[color=black,thick,->] (0,0,1) -- (0,0,1.5) node[anchor=south]{$z$};}%
% draw geodesics
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,red!50!black,add coordinate={M1 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0.7071,0.7071,0)
tdplotdrawpolytopearc[thick,blue!50!black,add coordinate={M2 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,green!50!black,add coordinate={M3 at 0.5}]{1}{}{}
%draw point
tdplotsetcoord{P}{1}{30}{60}
node[point,label={0:(p)}] at (P) {};
node[point,label={90:{$M_1$}}] at (M1){};
node[point,label={-90:{$M_2$}}] at (M2){};
node[point,label={0:{$M_3$}}] at (M3){};
end{scope}
end{tikzpicture}
end{document}
add a comment |
This is at best 50% of an answer because I simply do not understand the first request. tdplotsetcoord{P}{1}{30}{60}
does define a point in 3d. Could you please rephrase the first request?
The second point is straightforward. decorations.markings
allows you to mark a point at any position of the path, of course including the middle. The style add coordinate={<name> at <pos>}
does that in the following MWE.
documentclass[a4paper]{standalone}
usepackage{tikz,tikz-3dplot}
usetikzlibrary{decorations.markings}
tikzset{point/.style={inner sep=0pt, outer sep=0pt,%
minimum size=2pt,fill=black,shape=circle},
add coordinate/.style args={#1 at #2}{postaction={decorate,
decoration={markings,mark=at position #2 with {coordinate (#1);}}}}}
begin{document}
tdplotsetmaincoords{70}{110}
begin{tikzpicture}
begin{scope}[tdplot_main_coords]
%draw sphere
tdplotsphericalsurfaceplot{72}{36}{1}{black!75!white}{blue!20!white}%
{draw[color=black,thick,->] (1,0,0) -- (1.5,0,0) node[anchor=north east]{$x$};}%
{draw[color=black,thick,->] (0,1,0) -- (0,1.5,0) node[anchor=north west]{$y$};}%
{draw[color=black,thick,->] (0,0,1) -- (0,0,1.5) node[anchor=south]{$z$};}%
% draw geodesics
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,red!50!black,add coordinate={M1 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0.7071,0.7071,0)
tdplotdrawpolytopearc[thick,blue!50!black,add coordinate={M2 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,green!50!black,add coordinate={M3 at 0.5}]{1}{}{}
%draw point
tdplotsetcoord{P}{1}{30}{60}
node[point,label={0:(p)}] at (P) {};
node[point,label={90:{$M_1$}}] at (M1){};
node[point,label={-90:{$M_2$}}] at (M2){};
node[point,label={0:{$M_3$}}] at (M3){};
end{scope}
end{tikzpicture}
end{document}
This is at best 50% of an answer because I simply do not understand the first request. tdplotsetcoord{P}{1}{30}{60}
does define a point in 3d. Could you please rephrase the first request?
The second point is straightforward. decorations.markings
allows you to mark a point at any position of the path, of course including the middle. The style add coordinate={<name> at <pos>}
does that in the following MWE.
documentclass[a4paper]{standalone}
usepackage{tikz,tikz-3dplot}
usetikzlibrary{decorations.markings}
tikzset{point/.style={inner sep=0pt, outer sep=0pt,%
minimum size=2pt,fill=black,shape=circle},
add coordinate/.style args={#1 at #2}{postaction={decorate,
decoration={markings,mark=at position #2 with {coordinate (#1);}}}}}
begin{document}
tdplotsetmaincoords{70}{110}
begin{tikzpicture}
begin{scope}[tdplot_main_coords]
%draw sphere
tdplotsphericalsurfaceplot{72}{36}{1}{black!75!white}{blue!20!white}%
{draw[color=black,thick,->] (1,0,0) -- (1.5,0,0) node[anchor=north east]{$x$};}%
{draw[color=black,thick,->] (0,1,0) -- (0,1.5,0) node[anchor=north west]{$y$};}%
{draw[color=black,thick,->] (0,0,1) -- (0,0,1.5) node[anchor=south]{$z$};}%
% draw geodesics
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,red!50!black,add coordinate={M1 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,-0.7071,0)(0.7071,0.7071,0)
tdplotdrawpolytopearc[thick,blue!50!black,add coordinate={M2 at 0.5}]{1}{}{}
tdplotdefinepoints(0,0,0)(0.7071,0.7071,0)(0,0.7071,0.7071)
tdplotdrawpolytopearc[thick,green!50!black,add coordinate={M3 at 0.5}]{1}{}{}
%draw point
tdplotsetcoord{P}{1}{30}{60}
node[point,label={0:(p)}] at (P) {};
node[point,label={90:{$M_1$}}] at (M1){};
node[point,label={-90:{$M_2$}}] at (M2){};
node[point,label={0:{$M_3$}}] at (M3){};
end{scope}
end{tikzpicture}
end{document}
answered 11 mins ago
marmot
88.7k4102190
88.7k4102190
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Would you be interested in a solution that is entirely based on spherical coordinates? (IMHO it does not no make too much sense to use cartesian coordinates to parametrize points on the surface of a sphere.)
– marmot
Dec 30 '18 at 0:22
In most of my calculations its easier to have cartesian coordinates, since for geodesics (great arcs) you would have to calculate several modulo cases in spherical coordinates; tangent vectors are cartesian anyways. However, I would be interested in any solution :)
– Ronny
21 hours ago