Parse particular fields from XML using JAXB
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I am working on a project where I need to parse an XML file using JAXB. Below is the sample XML:
<FirstLevel>
<Second>
<Third>
<ProductName>Computer</ProductName>
</Third>
</Second>
<Second>
<Third>
<ProductName>Mobile</ProductName>
</Third>
</Second>
</FirstLevel>
I only need the product names. In order to get that I have tried the following but it didn't work:
@XmlRootElement(name="FirstLevel")
public class DTOClass {
private String productName;
public String getProductName() {
return productName;
}
@XmlElement(name="ProductName")
public void setProductName(String productName) {
this.productName = productName;
}
}
But this works:
@XmlRootElement(name="FirstLevel")
public class DTOClass {
private List<Second> second;
public List<Second> getSecond() {
return second;
}
@XmlElement(name="Second")
public void setSecond(List<Second> second) {
this.second = second;
}
static class Second{
private Third third;
public Third getThird() {
return third;
}
@XmlElement(name="Third")
public void setThird(Third third) {
this.third = third;
}
static class Third{
private String productName;
public String getProductName() {
return productName;
}
@XmlElement(name="ProductName")
public void setProductName(String productName) {
this.productName = productName;
}
}
}
}
My questions are
Do I need to create the inner classes(or classes) for each level of
the XML to parse the XML(like the second one)?Is it possible to have only certain fields in java class which are
needed(like the first one)?
java xml-parsing jaxb
asked Nov 22 at 13:46
Antony Vimal Raj
586
add a comment |
up vote
0
down vote
favorite
I am working on a project where I need to parse an XML file using JAXB. Below is the sample XML:
<FirstLevel>
<Second>
<Third>
<ProductName>Computer</ProductName>
</Third>
</Second>
<Second>
<Third>
<ProductName>Mobile</ProductName>
</Third>
</Second>
</FirstLevel>
I only need the product names. In order to get that I have tried the following but it didn't work:
@XmlRootElement(name="FirstLevel")
public class DTOClass {
private String productName;
public String getProductName() {
return productName;
}
@XmlElement(name="ProductName")
public void setProductName(String productName) {
this.productName = productName;
}
}
But this works:
@XmlRootElement(name="FirstLevel")
public class DTOClass {
private List<Second> second;
public List<Second> getSecond() {
return second;
}
@XmlElement(name="Second")
public void setSecond(List<Second> second) {
this.second = second;
}
static class Second{
private Third third;
public Third getThird() {
return third;
}
@XmlElement(name="Third")
public void setThird(Third third) {
this.third = third;
}
static class Third{
private String productName;
public String getProductName() {
return productName;
}
@XmlElement(name="ProductName")
public void setProductName(String productName) {
this.productName = productName;
}
}
}
}
My questions are
Do I need to create the inner classes(or classes) for each level of
the XML to parse the XML(like the second one)?Is it possible to have only certain fields in java class which are
needed(like the first one)?
java xml-parsing jaxb
asked Nov 22 at 13:46
Antony Vimal Raj
586
As far as I know, you have 2 options: 1. create classes and properly map your xml (or inner classes as is in your code). 2. use xmlPath, you will need to tweak jaxb configuration a bit: stackoverflow.com/questions/17466534/…
– CrazySabbath
Nov 22 at 15:22
@CrazySabbath - Thanks. It really helped.
– Antony Vimal Raj
Nov 23 at 5:47
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am working on a project where I need to parse an XML file using JAXB. Below is the sample XML:
<FirstLevel>
<Second>
<Third>
<ProductName>Computer</ProductName>
</Third>
</Second>
<Second>
<Third>
<ProductName>Mobile</ProductName>
</Third>
</Second>
</FirstLevel>
I only need the product names. In order to get that I have tried the following but it didn't work:
@XmlRootElement(name="FirstLevel")
public class DTOClass {
private String productName;
public String getProductName() {
return productName;
}
@XmlElement(name="ProductName")
public void setProductName(String productName) {
this.productName = productName;
}
}
But this works:
@XmlRootElement(name="FirstLevel")
public class DTOClass {
private List<Second> second;
public List<Second> getSecond() {
return second;
}
@XmlElement(name="Second")
public void setSecond(List<Second> second) {
this.second = second;
}
static class Second{
private Third third;
public Third getThird() {
return third;
}
@XmlElement(name="Third")
public void setThird(Third third) {
this.third = third;
}
static class Third{
private String productName;
public String getProductName() {
return productName;
}
@XmlElement(name="ProductName")
public void setProductName(String productName) {
this.productName = productName;
}
}
}
}
My questions are
Do I need to create the inner classes(or classes) for each level of
the XML to parse the XML(like the second one)?Is it possible to have only certain fields in java class which are
needed(like the first one)?
java xml-parsing jaxb
asked Nov 22 at 13:46
Antony Vimal Raj
586
I am working on a project where I need to parse an XML file using JAXB. Below is the sample XML:
<FirstLevel>
<Second>
<Third>
<ProductName>Computer</ProductName>
</Third>
</Second>
<Second>
<Third>
<ProductName>Mobile</ProductName>
</Third>
</Second>
</FirstLevel>
I only need the product names. In order to get that I have tried the following but it didn't work:
@XmlRootElement(name="FirstLevel")
public class DTOClass {
private String productName;
public String getProductName() {
return productName;
}
@XmlElement(name="ProductName")
public void setProductName(String productName) {
this.productName = productName;
}
}
But this works:
@XmlRootElement(name="FirstLevel")
public class DTOClass {
private List<Second> second;
public List<Second> getSecond() {
return second;
}
@XmlElement(name="Second")
public void setSecond(List<Second> second) {
this.second = second;
}
static class Second{
private Third third;
public Third getThird() {
return third;
}
@XmlElement(name="Third")
public void setThird(Third third) {
this.third = third;
}
static class Third{
private String productName;
public String getProductName() {
return productName;
}
@XmlElement(name="ProductName")
public void setProductName(String productName) {
this.productName = productName;
}
}
}
}
My questions are
Do I need to create the inner classes(or classes) for each level of
the XML to parse the XML(like the second one)?Is it possible to have only certain fields in java class which are
needed(like the first one)?
java xml-parsing jaxb
java xml-parsing jaxb
asked Nov 22 at 13:46
Antony Vimal Raj
586
asked Nov 22 at 13:46
Antony Vimal Raj
586
asked Nov 22 at 13:46
Antony Vimal Raj
586
asked Nov 22 at 13:46
Antony Vimal Raj
586
asked Nov 22 at 13:46
Antony Vimal Raj
586
586
As far as I know, you have 2 options: 1. create classes and properly map your xml (or inner classes as is in your code). 2. use xmlPath, you will need to tweak jaxb configuration a bit: stackoverflow.com/questions/17466534/…
– CrazySabbath
Nov 22 at 15:22
@CrazySabbath - Thanks. It really helped.
– Antony Vimal Raj
Nov 23 at 5:47
add a comment |
As far as I know, you have 2 options: 1. create classes and properly map your xml (or inner classes as is in your code). 2. use xmlPath, you will need to tweak jaxb configuration a bit: stackoverflow.com/questions/17466534/…
– CrazySabbath
Nov 22 at 15:22
@CrazySabbath - Thanks. It really helped.
– Antony Vimal Raj
Nov 23 at 5:47
As far as I know, you have 2 options: 1. create classes and properly map your xml (or inner classes as is in your code). 2. use xmlPath, you will need to tweak jaxb configuration a bit: stackoverflow.com/questions/17466534/…
– CrazySabbath
Nov 22 at 15:22
As far as I know, you have 2 options: 1. create classes and properly map your xml (or inner classes as is in your code). 2. use xmlPath, you will need to tweak jaxb configuration a bit: stackoverflow.com/questions/17466534/…
– CrazySabbath
Nov 22 at 15:22
@CrazySabbath - Thanks. It really helped.
– Antony Vimal Raj
Nov 23 at 5:47
@CrazySabbath - Thanks. It really helped.
– Antony Vimal Raj
Nov 23 at 5:47
add a comment |
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As far as I know, you have 2 options: 1. create classes and properly map your xml (or inner classes as is in your code). 2. use xmlPath, you will need to tweak jaxb configuration a bit: stackoverflow.com/questions/17466534/…
– CrazySabbath
Nov 22 at 15:22
@CrazySabbath - Thanks. It really helped.
– Antony Vimal Raj
Nov 23 at 5:47