My app doesn't do the code I've been write Swift
I'm trying to understand why my code is not totally played by my application?
In fact I have a button on a viewController when the user press the button two textfield is normal become interactive and the background will change to show the possibility of interaction. When I've do the code and make the first test it work ! It work also in an other view but after some tests the button juste change his hidden property but do nothing else. Cf code :
@IBAction func modifyBtnWasPressed(_ sender: UIButton) {
//We change the button by the save button
modifyBtn.isHidden = true
saveBtn.isHidden = false
//We enable 2 tf and we show to the user the 2 TF which will be enable
acftRegistrationTxt.isUserInteractionEnabled = true
acftModelTxt.isUserInteractionEnabled = true
acftRegistrationTxt.backgroundColor = UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0);
acftModelTxt.backgroundColor = UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0);
}
Now in this case only the isHidden property work the next 4 lines doesn't apply on the application.
ios swift uitextfield
|
show 5 more comments
I'm trying to understand why my code is not totally played by my application?
In fact I have a button on a viewController when the user press the button two textfield is normal become interactive and the background will change to show the possibility of interaction. When I've do the code and make the first test it work ! It work also in an other view but after some tests the button juste change his hidden property but do nothing else. Cf code :
@IBAction func modifyBtnWasPressed(_ sender: UIButton) {
//We change the button by the save button
modifyBtn.isHidden = true
saveBtn.isHidden = false
//We enable 2 tf and we show to the user the 2 TF which will be enable
acftRegistrationTxt.isUserInteractionEnabled = true
acftModelTxt.isUserInteractionEnabled = true
acftRegistrationTxt.backgroundColor = UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0);
acftModelTxt.backgroundColor = UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0);
}
Now in this case only the isHidden property work the next 4 lines doesn't apply on the application.
ios swift uitextfield
What is your view background color ? Does it as same as UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0) ?
– Sateesh
Nov 27 '18 at 9:58
bad views connected?
– Sulthan
Nov 27 '18 at 10:20
@Sateesh It's totally white but the.isUserInteractionEnableddon't work too ... @sulthan, in this case the button will not change for the other one ?
– flyer74
Nov 27 '18 at 10:40
Put some breakpoints before and after you change the userInteractionEnabled and see if the textField interaction is effectively enabled by that two lines of code
– Francesco Destino
Nov 27 '18 at 11:12
1
Mm that's not okay! When your app is in debug type this on your Xcode terminal "po acftRegistrationTxt.isUserInteractionEnabled" and tell me what you get! Do the same for acftModelTxt Type this command when in debug before and after those two lines acftRegistrationTxt.isUserInteractionEnabled = true acftModelTxt.isUserInteractionEnabled = true
– Francesco Destino
Nov 27 '18 at 13:17
|
show 5 more comments
I'm trying to understand why my code is not totally played by my application?
In fact I have a button on a viewController when the user press the button two textfield is normal become interactive and the background will change to show the possibility of interaction. When I've do the code and make the first test it work ! It work also in an other view but after some tests the button juste change his hidden property but do nothing else. Cf code :
@IBAction func modifyBtnWasPressed(_ sender: UIButton) {
//We change the button by the save button
modifyBtn.isHidden = true
saveBtn.isHidden = false
//We enable 2 tf and we show to the user the 2 TF which will be enable
acftRegistrationTxt.isUserInteractionEnabled = true
acftModelTxt.isUserInteractionEnabled = true
acftRegistrationTxt.backgroundColor = UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0);
acftModelTxt.backgroundColor = UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0);
}
Now in this case only the isHidden property work the next 4 lines doesn't apply on the application.
ios swift uitextfield
I'm trying to understand why my code is not totally played by my application?
In fact I have a button on a viewController when the user press the button two textfield is normal become interactive and the background will change to show the possibility of interaction. When I've do the code and make the first test it work ! It work also in an other view but after some tests the button juste change his hidden property but do nothing else. Cf code :
@IBAction func modifyBtnWasPressed(_ sender: UIButton) {
//We change the button by the save button
modifyBtn.isHidden = true
saveBtn.isHidden = false
//We enable 2 tf and we show to the user the 2 TF which will be enable
acftRegistrationTxt.isUserInteractionEnabled = true
acftModelTxt.isUserInteractionEnabled = true
acftRegistrationTxt.backgroundColor = UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0);
acftModelTxt.backgroundColor = UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0);
}
Now in this case only the isHidden property work the next 4 lines doesn't apply on the application.
ios swift uitextfield
ios swift uitextfield
edited Nov 27 '18 at 10:20
Sulthan
97.4k16158202
97.4k16158202
asked Nov 27 '18 at 9:54
flyer74flyer74
678
678
What is your view background color ? Does it as same as UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0) ?
– Sateesh
Nov 27 '18 at 9:58
bad views connected?
– Sulthan
Nov 27 '18 at 10:20
@Sateesh It's totally white but the.isUserInteractionEnableddon't work too ... @sulthan, in this case the button will not change for the other one ?
– flyer74
Nov 27 '18 at 10:40
Put some breakpoints before and after you change the userInteractionEnabled and see if the textField interaction is effectively enabled by that two lines of code
– Francesco Destino
Nov 27 '18 at 11:12
1
Mm that's not okay! When your app is in debug type this on your Xcode terminal "po acftRegistrationTxt.isUserInteractionEnabled" and tell me what you get! Do the same for acftModelTxt Type this command when in debug before and after those two lines acftRegistrationTxt.isUserInteractionEnabled = true acftModelTxt.isUserInteractionEnabled = true
– Francesco Destino
Nov 27 '18 at 13:17
|
show 5 more comments
What is your view background color ? Does it as same as UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0) ?
– Sateesh
Nov 27 '18 at 9:58
bad views connected?
– Sulthan
Nov 27 '18 at 10:20
@Sateesh It's totally white but the.isUserInteractionEnableddon't work too ... @sulthan, in this case the button will not change for the other one ?
– flyer74
Nov 27 '18 at 10:40
Put some breakpoints before and after you change the userInteractionEnabled and see if the textField interaction is effectively enabled by that two lines of code
– Francesco Destino
Nov 27 '18 at 11:12
1
Mm that's not okay! When your app is in debug type this on your Xcode terminal "po acftRegistrationTxt.isUserInteractionEnabled" and tell me what you get! Do the same for acftModelTxt Type this command when in debug before and after those two lines acftRegistrationTxt.isUserInteractionEnabled = true acftModelTxt.isUserInteractionEnabled = true
– Francesco Destino
Nov 27 '18 at 13:17
What is your view background color ? Does it as same as UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0) ?
– Sateesh
Nov 27 '18 at 9:58
What is your view background color ? Does it as same as UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0) ?
– Sateesh
Nov 27 '18 at 9:58
bad views connected?
– Sulthan
Nov 27 '18 at 10:20
bad views connected?
– Sulthan
Nov 27 '18 at 10:20
@Sateesh It's totally white but the
.isUserInteractionEnabled don't work too ... @sulthan, in this case the button will not change for the other one ?– flyer74
Nov 27 '18 at 10:40
@Sateesh It's totally white but the
.isUserInteractionEnabled don't work too ... @sulthan, in this case the button will not change for the other one ?– flyer74
Nov 27 '18 at 10:40
Put some breakpoints before and after you change the userInteractionEnabled and see if the textField interaction is effectively enabled by that two lines of code
– Francesco Destino
Nov 27 '18 at 11:12
Put some breakpoints before and after you change the userInteractionEnabled and see if the textField interaction is effectively enabled by that two lines of code
– Francesco Destino
Nov 27 '18 at 11:12
1
1
Mm that's not okay! When your app is in debug type this on your Xcode terminal "po acftRegistrationTxt.isUserInteractionEnabled" and tell me what you get! Do the same for acftModelTxt Type this command when in debug before and after those two lines acftRegistrationTxt.isUserInteractionEnabled = true acftModelTxt.isUserInteractionEnabled = true
– Francesco Destino
Nov 27 '18 at 13:17
Mm that's not okay! When your app is in debug type this on your Xcode terminal "po acftRegistrationTxt.isUserInteractionEnabled" and tell me what you get! Do the same for acftModelTxt Type this command when in debug before and after those two lines acftRegistrationTxt.isUserInteractionEnabled = true acftModelTxt.isUserInteractionEnabled = true
– Francesco Destino
Nov 27 '18 at 13:17
|
show 5 more comments
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What is your view background color ? Does it as same as UIColor(red: 0.9, green: 0.9, blue: 0.9, alpha: 1.0) ?
– Sateesh
Nov 27 '18 at 9:58
bad views connected?
– Sulthan
Nov 27 '18 at 10:20
@Sateesh It's totally white but the
.isUserInteractionEnableddon't work too ... @sulthan, in this case the button will not change for the other one ?– flyer74
Nov 27 '18 at 10:40
Put some breakpoints before and after you change the userInteractionEnabled and see if the textField interaction is effectively enabled by that two lines of code
– Francesco Destino
Nov 27 '18 at 11:12
1
Mm that's not okay! When your app is in debug type this on your Xcode terminal "po acftRegistrationTxt.isUserInteractionEnabled" and tell me what you get! Do the same for acftModelTxt Type this command when in debug before and after those two lines acftRegistrationTxt.isUserInteractionEnabled = true acftModelTxt.isUserInteractionEnabled = true
– Francesco Destino
Nov 27 '18 at 13:17