gremlin order by with coalesce duplicates some values
In some cases, I get inexplicable result when I use order().by(...) with coalesce(...).
Using the standard Modern graph,
gremlin> g.V()
.hasLabel("person")
.out("created")
.coalesce(values("name"), constant("x"))
.fold()
==>[lop,lop,ripple,lop]
But if I sort by name before the coalesce I get 9 lop instead of 3:
gremlin> g.V()
.hasLabel("person")
.out("created")
.order().by("name")
.coalesce(values("name"), constant("x"))
.fold()
==>[lop,lop,lop,lop,lop,lop,lop,lop,lop,ripple]
Why the number of elements differs between the two queries ?
gremlin tinkerpop
add a comment |
In some cases, I get inexplicable result when I use order().by(...) with coalesce(...).
Using the standard Modern graph,
gremlin> g.V()
.hasLabel("person")
.out("created")
.coalesce(values("name"), constant("x"))
.fold()
==>[lop,lop,ripple,lop]
But if I sort by name before the coalesce I get 9 lop instead of 3:
gremlin> g.V()
.hasLabel("person")
.out("created")
.order().by("name")
.coalesce(values("name"), constant("x"))
.fold()
==>[lop,lop,lop,lop,lop,lop,lop,lop,lop,ripple]
Why the number of elements differs between the two queries ?
gremlin tinkerpop
add a comment |
In some cases, I get inexplicable result when I use order().by(...) with coalesce(...).
Using the standard Modern graph,
gremlin> g.V()
.hasLabel("person")
.out("created")
.coalesce(values("name"), constant("x"))
.fold()
==>[lop,lop,ripple,lop]
But if I sort by name before the coalesce I get 9 lop instead of 3:
gremlin> g.V()
.hasLabel("person")
.out("created")
.order().by("name")
.coalesce(values("name"), constant("x"))
.fold()
==>[lop,lop,lop,lop,lop,lop,lop,lop,lop,ripple]
Why the number of elements differs between the two queries ?
gremlin tinkerpop
In some cases, I get inexplicable result when I use order().by(...) with coalesce(...).
Using the standard Modern graph,
gremlin> g.V()
.hasLabel("person")
.out("created")
.coalesce(values("name"), constant("x"))
.fold()
==>[lop,lop,ripple,lop]
But if I sort by name before the coalesce I get 9 lop instead of 3:
gremlin> g.V()
.hasLabel("person")
.out("created")
.order().by("name")
.coalesce(values("name"), constant("x"))
.fold()
==>[lop,lop,lop,lop,lop,lop,lop,lop,lop,ripple]
Why the number of elements differs between the two queries ?
gremlin tinkerpop
gremlin tinkerpop
asked Nov 26 '18 at 13:21
To-omTo-om
33
33
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add a comment |
1 Answer
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That looks like a bug - I've created an issue in JIRA. There is a workaround but first consider that your traversal isn't really going to work even with the bug set aside, order() will fail because you're referencing a key that possibly doesn't exist in the by() modulator. So you need to account for that differently:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x')))
I then used choose() to do what coalesce() is supposed to do:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x'))).
choose(has("name"),values('name'),constant('x')).
fold()
and that seems to work fine.
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
That looks like a bug - I've created an issue in JIRA. There is a workaround but first consider that your traversal isn't really going to work even with the bug set aside, order() will fail because you're referencing a key that possibly doesn't exist in the by() modulator. So you need to account for that differently:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x')))
I then used choose() to do what coalesce() is supposed to do:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x'))).
choose(has("name"),values('name'),constant('x')).
fold()
and that seems to work fine.
add a comment |
That looks like a bug - I've created an issue in JIRA. There is a workaround but first consider that your traversal isn't really going to work even with the bug set aside, order() will fail because you're referencing a key that possibly doesn't exist in the by() modulator. So you need to account for that differently:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x')))
I then used choose() to do what coalesce() is supposed to do:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x'))).
choose(has("name"),values('name'),constant('x')).
fold()
and that seems to work fine.
add a comment |
That looks like a bug - I've created an issue in JIRA. There is a workaround but first consider that your traversal isn't really going to work even with the bug set aside, order() will fail because you're referencing a key that possibly doesn't exist in the by() modulator. So you need to account for that differently:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x')))
I then used choose() to do what coalesce() is supposed to do:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x'))).
choose(has("name"),values('name'),constant('x')).
fold()
and that seems to work fine.
That looks like a bug - I've created an issue in JIRA. There is a workaround but first consider that your traversal isn't really going to work even with the bug set aside, order() will fail because you're referencing a key that possibly doesn't exist in the by() modulator. So you need to account for that differently:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x')))
I then used choose() to do what coalesce() is supposed to do:
g.V().
hasLabel("person").
out("created").
order().by(coalesce(values('name'),constant('x'))).
choose(has("name"),values('name'),constant('x')).
fold()
and that seems to work fine.
answered Nov 26 '18 at 14:49
stephen mallettestephen mallette
25.8k32877
25.8k32877
add a comment |
add a comment |
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