Case insensitive String split() method

When I perform

String test="23x34 ";

String array=test.split("x"); //splitting using simple letter

I got two items in array as 23 and 34

but when I did

String test="23x34 ";

String array=test.split("X"); //splitting using capitalletter

I got one item in array 23x34

So is there any way I can use the split method as case insensitive or whether there is any other method that can help?

asked May 16 '13 at 8:00

Sanjaya Liyanage

3,37172648

add a comment |

When I perform

String test="23x34 ";

String array=test.split("x"); //splitting using simple letter

I got two items in array as 23 and 34

but when I did

String test="23x34 ";

String array=test.split("X"); //splitting using capitalletter

I got one item in array 23x34

So is there any way I can use the split method as case insensitive or whether there is any other method that can help?

asked May 16 '13 at 8:00

Sanjaya Liyanage

3,37172648

add a comment |

When I perform

String test="23x34 ";

String array=test.split("x"); //splitting using simple letter

I got two items in array as 23 and 34

but when I did

String test="23x34 ";

String array=test.split("X"); //splitting using capitalletter

I got one item in array 23x34

So is there any way I can use the split method as case insensitive or whether there is any other method that can help?

asked May 16 '13 at 8:00

Sanjaya Liyanage

3,37172648

When I perform

String test="23x34 ";

String array=test.split("x"); //splitting using simple letter

I got two items in array as 23 and 34

but when I did

String test="23x34 ";

String array=test.split("X"); //splitting using capitalletter

I got one item in array 23x34

So is there any way I can use the split method as case insensitive or whether there is any other method that can help?

java string split

asked May 16 '13 at 8:00

Sanjaya Liyanage

3,37172648

asked May 16 '13 at 8:00

Sanjaya Liyanage

3,37172648

asked May 16 '13 at 8:00

Sanjaya Liyanage

3,37172648

asked May 16 '13 at 8:00

Sanjaya Liyanage

3,37172648

asked May 16 '13 at 8:00

Sanjaya Liyanage

3,37172648

add a comment |

6 Answers
6

active

oldest

votes

Use regex pattern [xX] in split

String x = "24X45";

String res = x.split("[xX]");

System.out.println(Arrays.toString(res));

answered May 16 '13 at 8:01

harsh

5,96412230

thanks it works.

– Sanjaya Liyanage
May 16 '13 at 8:18

add a comment |

split uses, as the documentation suggests, a regexp. a regexp for your example would be :

"[xX]"

Also, the (?i) flag toggles case insensitivty. Therefore, the following is also correct :

"(?i)x"

In this case, x can be any litteral properly escaped.

answered May 16 '13 at 8:07

njzk2

32.8k44991

downvoter please comment.

– njzk2
May 16 '13 at 9:35

3

+1 for (?i), it can be used for sentences. Ex: String array = "24xXx45".split("(?i)XXX"); // [24, 45]

– Fernando Leal
Mar 28 '14 at 18:42

1

If you have unicode chars you should rather use (?iu) flag instead.

– NikolaB
Oct 14 '15 at 12:06

1

"24x45".split("(?i)X") not working in chrome 67

– Chan Tzish
Jun 18 '18 at 23:32

3

@ChanTzish this question is about Java

– njzk2
Jun 19 '18 at 3:06

|
show 1 more comment

You can also use an embedded flag in your regex:

String array = test.split("(?i)x"); // splits case insensitive

answered May 16 '13 at 8:08

jlordo

31.3k64371

add a comment |

I personally prefer using

String modified = Pattern.compile("x", Pattern.CASE_INSENSITIVE).matcher(stringContents).replaceAll(splitterValue);

String parts = modified.split(splitterValue);

In this way you can ensure any regex will work, as long as you have a unique splitter value

answered Dec 23 '14 at 23:29

user2981810

149210

add a comment |

Java's String class' split method also accepts regex.

To keep things short, this should help you: http://www.coderanch.com/t/480781/java/java/String-split

answered May 16 '13 at 8:04

zEro

1,1281223

1

"also accepts regex" actually only accepts regex.

– wchargin
Jun 4 '13 at 5:15

@WChargin So true. And I realized it just yesterday.

– zEro
Jun 6 '13 at 14:11

add a comment |

-1

You could use a regex as an argument to split, like this:

"32x23".split("[xX]");

Or you could use a StringTokenizer that lets you set its set of delimiters, like this:

StringTokenizer st = new StringTokenizer("32x23","xX");

//                                          ^^    ^^

//                                       string delimiter

This has the advantage that if you want to build the list of delimiters programatically, for example for each lowercase letter in the delimiter list add its uppercase corespondent, you can do this and then pass the result to the StringTokenizer.

answered May 16 '13 at 8:13

anana

1,251811

add a comment |

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6 Answers
6

active

oldest

votes

6 Answers
6

active

oldest

votes

Use regex pattern [xX] in split

String x = "24X45";

String res = x.split("[xX]");

System.out.println(Arrays.toString(res));

answered May 16 '13 at 8:01

harsh

5,96412230

thanks it works.

– Sanjaya Liyanage
May 16 '13 at 8:18

add a comment |

Use regex pattern [xX] in split

String x = "24X45";

String res = x.split("[xX]");

System.out.println(Arrays.toString(res));

answered May 16 '13 at 8:01

harsh

5,96412230

thanks it works.

– Sanjaya Liyanage
May 16 '13 at 8:18

add a comment |

Use regex pattern [xX] in split

String x = "24X45";

String res = x.split("[xX]");

System.out.println(Arrays.toString(res));

answered May 16 '13 at 8:01

harsh

5,96412230

Use regex pattern [xX] in split

String x = "24X45";

String res = x.split("[xX]");

System.out.println(Arrays.toString(res));

answered May 16 '13 at 8:01

harsh

5,96412230

answered May 16 '13 at 8:01

harsh

5,96412230

answered May 16 '13 at 8:01

harsh

5,96412230

answered May 16 '13 at 8:01

harsh

5,96412230

thanks it works.

– Sanjaya Liyanage
May 16 '13 at 8:18

add a comment |

thanks it works.

– Sanjaya Liyanage
May 16 '13 at 8:18

thanks it works.

– Sanjaya Liyanage
May 16 '13 at 8:18

add a comment |

split uses, as the documentation suggests, a regexp. a regexp for your example would be :

"[xX]"

Also, the (?i) flag toggles case insensitivty. Therefore, the following is also correct :

"(?i)x"

In this case, x can be any litteral properly escaped.

answered May 16 '13 at 8:07

njzk2

32.8k44991

downvoter please comment.

– njzk2
May 16 '13 at 9:35

3

+1 for (?i), it can be used for sentences. Ex: String array = "24xXx45".split("(?i)XXX"); // [24, 45]

– Fernando Leal
Mar 28 '14 at 18:42

1

If you have unicode chars you should rather use (?iu) flag instead.

– NikolaB
Oct 14 '15 at 12:06

1

"24x45".split("(?i)X") not working in chrome 67

– Chan Tzish
Jun 18 '18 at 23:32

3

@ChanTzish this question is about Java

– njzk2
Jun 19 '18 at 3:06

|
show 1 more comment

split uses, as the documentation suggests, a regexp. a regexp for your example would be :

"[xX]"

Also, the (?i) flag toggles case insensitivty. Therefore, the following is also correct :

"(?i)x"

In this case, x can be any litteral properly escaped.

answered May 16 '13 at 8:07

njzk2

32.8k44991

downvoter please comment.

– njzk2
May 16 '13 at 9:35

3

+1 for (?i), it can be used for sentences. Ex: String array = "24xXx45".split("(?i)XXX"); // [24, 45]

– Fernando Leal
Mar 28 '14 at 18:42

1

If you have unicode chars you should rather use (?iu) flag instead.

– NikolaB
Oct 14 '15 at 12:06

1

"24x45".split("(?i)X") not working in chrome 67

– Chan Tzish
Jun 18 '18 at 23:32

3

@ChanTzish this question is about Java

– njzk2
Jun 19 '18 at 3:06

|
show 1 more comment

split uses, as the documentation suggests, a regexp. a regexp for your example would be :

"[xX]"

Also, the (?i) flag toggles case insensitivty. Therefore, the following is also correct :

"(?i)x"

In this case, x can be any litteral properly escaped.

answered May 16 '13 at 8:07

njzk2

32.8k44991

split uses, as the documentation suggests, a regexp. a regexp for your example would be :

"[xX]"

Also, the (?i) flag toggles case insensitivty. Therefore, the following is also correct :

"(?i)x"

In this case, x can be any litteral properly escaped.

answered May 16 '13 at 8:07

njzk2

32.8k44991

answered May 16 '13 at 8:07

njzk2

32.8k44991

answered May 16 '13 at 8:07

njzk2

32.8k44991

answered May 16 '13 at 8:07

njzk2

32.8k44991

downvoter please comment.

– njzk2
May 16 '13 at 9:35

3

+1 for (?i), it can be used for sentences. Ex: String array = "24xXx45".split("(?i)XXX"); // [24, 45]

– Fernando Leal
Mar 28 '14 at 18:42

1

If you have unicode chars you should rather use (?iu) flag instead.

– NikolaB
Oct 14 '15 at 12:06

1

"24x45".split("(?i)X") not working in chrome 67

– Chan Tzish
Jun 18 '18 at 23:32

3

@ChanTzish this question is about Java

– njzk2
Jun 19 '18 at 3:06

|
show 1 more comment

downvoter please comment.

– njzk2
May 16 '13 at 9:35

3

+1 for (?i), it can be used for sentences. Ex: String array = "24xXx45".split("(?i)XXX"); // [24, 45]

– Fernando Leal
Mar 28 '14 at 18:42

1

If you have unicode chars you should rather use (?iu) flag instead.

– NikolaB
Oct 14 '15 at 12:06

1

"24x45".split("(?i)X") not working in chrome 67

– Chan Tzish
Jun 18 '18 at 23:32

3

@ChanTzish this question is about Java

– njzk2
Jun 19 '18 at 3:06

downvoter please comment.

– njzk2
May 16 '13 at 9:35

+1 for (?i), it can be used for sentences. Ex: String array = "24xXx45".split("(?i)XXX"); // [24, 45]

– Fernando Leal
Mar 28 '14 at 18:42

If you have unicode chars you should rather use (?iu) flag instead.

– NikolaB
Oct 14 '15 at 12:06

"24x45".split("(?i)X") not working in chrome 67

– Chan Tzish
Jun 18 '18 at 23:32

@ChanTzish this question is about Java

– njzk2
Jun 19 '18 at 3:06

|
show 1 more comment

You can also use an embedded flag in your regex:

String array = test.split("(?i)x"); // splits case insensitive

answered May 16 '13 at 8:08

jlordo

31.3k64371

add a comment |

You can also use an embedded flag in your regex:

String array = test.split("(?i)x"); // splits case insensitive

answered May 16 '13 at 8:08

jlordo

31.3k64371

add a comment |

You can also use an embedded flag in your regex:

String array = test.split("(?i)x"); // splits case insensitive

answered May 16 '13 at 8:08

jlordo

31.3k64371

You can also use an embedded flag in your regex:

String array = test.split("(?i)x"); // splits case insensitive

answered May 16 '13 at 8:08

jlordo

31.3k64371

answered May 16 '13 at 8:08

jlordo

31.3k64371

answered May 16 '13 at 8:08

jlordo

31.3k64371

answered May 16 '13 at 8:08

jlordo

31.3k64371

add a comment |

I personally prefer using

String modified = Pattern.compile("x", Pattern.CASE_INSENSITIVE).matcher(stringContents).replaceAll(splitterValue);

String parts = modified.split(splitterValue);

In this way you can ensure any regex will work, as long as you have a unique splitter value

answered Dec 23 '14 at 23:29

user2981810

149210

add a comment |

I personally prefer using

String modified = Pattern.compile("x", Pattern.CASE_INSENSITIVE).matcher(stringContents).replaceAll(splitterValue);

String parts = modified.split(splitterValue);

In this way you can ensure any regex will work, as long as you have a unique splitter value

answered Dec 23 '14 at 23:29

user2981810

149210

add a comment |

I personally prefer using

String modified = Pattern.compile("x", Pattern.CASE_INSENSITIVE).matcher(stringContents).replaceAll(splitterValue);

String parts = modified.split(splitterValue);

In this way you can ensure any regex will work, as long as you have a unique splitter value

answered Dec 23 '14 at 23:29

user2981810

149210

I personally prefer using

String modified = Pattern.compile("x", Pattern.CASE_INSENSITIVE).matcher(stringContents).replaceAll(splitterValue);

String parts = modified.split(splitterValue);

In this way you can ensure any regex will work, as long as you have a unique splitter value

answered Dec 23 '14 at 23:29

user2981810

149210

answered Dec 23 '14 at 23:29

user2981810

149210

answered Dec 23 '14 at 23:29

user2981810

149210

answered Dec 23 '14 at 23:29

user2981810

149210

add a comment |

Java's String class' split method also accepts regex.

To keep things short, this should help you: http://www.coderanch.com/t/480781/java/java/String-split

answered May 16 '13 at 8:04

zEro

1,1281223

1

"also accepts regex" actually only accepts regex.

– wchargin
Jun 4 '13 at 5:15

@WChargin So true. And I realized it just yesterday.

– zEro
Jun 6 '13 at 14:11

add a comment |

Java's String class' split method also accepts regex.

To keep things short, this should help you: http://www.coderanch.com/t/480781/java/java/String-split

answered May 16 '13 at 8:04

zEro

1,1281223

1

"also accepts regex" actually only accepts regex.

– wchargin
Jun 4 '13 at 5:15

@WChargin So true. And I realized it just yesterday.

– zEro
Jun 6 '13 at 14:11

add a comment |

Java's String class' split method also accepts regex.

To keep things short, this should help you: http://www.coderanch.com/t/480781/java/java/String-split

answered May 16 '13 at 8:04

zEro

1,1281223

Java's String class' split method also accepts regex.

To keep things short, this should help you: http://www.coderanch.com/t/480781/java/java/String-split

answered May 16 '13 at 8:04

zEro

1,1281223

answered May 16 '13 at 8:04

zEro

1,1281223

answered May 16 '13 at 8:04

zEro

1,1281223

answered May 16 '13 at 8:04

zEro

1,1281223

1

"also accepts regex" actually only accepts regex.

– wchargin
Jun 4 '13 at 5:15

@WChargin So true. And I realized it just yesterday.

– zEro
Jun 6 '13 at 14:11

add a comment |

1

"also accepts regex" actually only accepts regex.

– wchargin
Jun 4 '13 at 5:15

@WChargin So true. And I realized it just yesterday.

– zEro
Jun 6 '13 at 14:11

"also accepts regex" actually only accepts regex.

– wchargin
Jun 4 '13 at 5:15

@WChargin So true. And I realized it just yesterday.

– zEro
Jun 6 '13 at 14:11

add a comment |

-1

You could use a regex as an argument to split, like this:

"32x23".split("[xX]");

Or you could use a StringTokenizer that lets you set its set of delimiters, like this:

StringTokenizer st = new StringTokenizer("32x23","xX");

//                                          ^^    ^^

//                                       string delimiter

answered May 16 '13 at 8:13

anana

1,251811

add a comment |

-1

You could use a regex as an argument to split, like this:

"32x23".split("[xX]");

Or you could use a StringTokenizer that lets you set its set of delimiters, like this:

StringTokenizer st = new StringTokenizer("32x23","xX");

//                                          ^^    ^^

//                                       string delimiter

answered May 16 '13 at 8:13

anana

1,251811

add a comment |

-1

You could use a regex as an argument to split, like this:

"32x23".split("[xX]");

Or you could use a StringTokenizer that lets you set its set of delimiters, like this:

StringTokenizer st = new StringTokenizer("32x23","xX");

//                                          ^^    ^^

//                                       string delimiter

answered May 16 '13 at 8:13

anana

1,251811

You could use a regex as an argument to split, like this:

"32x23".split("[xX]");

Or you could use a StringTokenizer that lets you set its set of delimiters, like this:

StringTokenizer st = new StringTokenizer("32x23","xX");

//                                          ^^    ^^

//                                       string delimiter

answered May 16 '13 at 8:13

anana

1,251811

answered May 16 '13 at 8:13

anana

1,251811

answered May 16 '13 at 8:13

anana

1,251811

answered May 16 '13 at 8:13

anana

1,251811

add a comment |

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