Use result of one query to query another in Postgres












0















I'm trying to get the column size for each row in a table. That's basically the combination of these two queries:



SELECT pg_size_pretty(sum(pg_column_size(COLUMN_NAME))) FROM TABLE_NAME;


And



SELECT column_name FROM information_schema.columns WHERE table_schema = 'public' AND table_name = 'TABLE_NAME';


My first attempt was to do these two queries:



 => SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME)  FROM information_schema.columns WHERE table_schema = 'public' AND table_name   = 'TABLE_NAME';
ERROR: column "columns.column_name" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_siz...
^
=> SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME) FROM information_schema.columns WHERE table_schema = 'public' AND table_name = 'TABLE_NAME' GROUP BY column_name;
ERROR: more than one row returned by a subquery used as an expression


Tried the following too:



SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME)  FROM information_schema.columns WHERE table_schema = 'public' AND table_name   = 'TABLE_NAME' GROUP BY 1;


Which returned:



ERROR:  more than one row returned by a subquery used as an expression


When I add a LIMIT 1, the result is incorrect:



SELECT column_name, 
(SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM main_apirequest LIMIT 1)
FROM information_schema.columns
WHERE table_schema = 'public' AND table_name = 'main_apirequest'
GROUP BY 1;


It looks something like this:



   column_name    | pg_size_pretty
------------------+----------------
api_key_id | 11 bytes
id | 3 bytes
...


When it should be something like this (which doesn't happen because of the limit 1)



=> SELECT pg_size_pretty(sum(pg_column_size(id))) FROM main_apirequest
;
pg_size_pretty
----------------
19 MB









share|improve this question




















  • 1





    Since you don't know the column names in advance, you will have to use dynamic sql.

    – 404
    Nov 24 '18 at 19:48











  • Ok, cool. Will look into that

    – Jorge Silva
    Nov 24 '18 at 19:51
















0















I'm trying to get the column size for each row in a table. That's basically the combination of these two queries:



SELECT pg_size_pretty(sum(pg_column_size(COLUMN_NAME))) FROM TABLE_NAME;


And



SELECT column_name FROM information_schema.columns WHERE table_schema = 'public' AND table_name = 'TABLE_NAME';


My first attempt was to do these two queries:



 => SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME)  FROM information_schema.columns WHERE table_schema = 'public' AND table_name   = 'TABLE_NAME';
ERROR: column "columns.column_name" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_siz...
^
=> SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME) FROM information_schema.columns WHERE table_schema = 'public' AND table_name = 'TABLE_NAME' GROUP BY column_name;
ERROR: more than one row returned by a subquery used as an expression


Tried the following too:



SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME)  FROM information_schema.columns WHERE table_schema = 'public' AND table_name   = 'TABLE_NAME' GROUP BY 1;


Which returned:



ERROR:  more than one row returned by a subquery used as an expression


When I add a LIMIT 1, the result is incorrect:



SELECT column_name, 
(SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM main_apirequest LIMIT 1)
FROM information_schema.columns
WHERE table_schema = 'public' AND table_name = 'main_apirequest'
GROUP BY 1;


It looks something like this:



   column_name    | pg_size_pretty
------------------+----------------
api_key_id | 11 bytes
id | 3 bytes
...


When it should be something like this (which doesn't happen because of the limit 1)



=> SELECT pg_size_pretty(sum(pg_column_size(id))) FROM main_apirequest
;
pg_size_pretty
----------------
19 MB









share|improve this question




















  • 1





    Since you don't know the column names in advance, you will have to use dynamic sql.

    – 404
    Nov 24 '18 at 19:48











  • Ok, cool. Will look into that

    – Jorge Silva
    Nov 24 '18 at 19:51














0












0








0








I'm trying to get the column size for each row in a table. That's basically the combination of these two queries:



SELECT pg_size_pretty(sum(pg_column_size(COLUMN_NAME))) FROM TABLE_NAME;


And



SELECT column_name FROM information_schema.columns WHERE table_schema = 'public' AND table_name = 'TABLE_NAME';


My first attempt was to do these two queries:



 => SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME)  FROM information_schema.columns WHERE table_schema = 'public' AND table_name   = 'TABLE_NAME';
ERROR: column "columns.column_name" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_siz...
^
=> SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME) FROM information_schema.columns WHERE table_schema = 'public' AND table_name = 'TABLE_NAME' GROUP BY column_name;
ERROR: more than one row returned by a subquery used as an expression


Tried the following too:



SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME)  FROM information_schema.columns WHERE table_schema = 'public' AND table_name   = 'TABLE_NAME' GROUP BY 1;


Which returned:



ERROR:  more than one row returned by a subquery used as an expression


When I add a LIMIT 1, the result is incorrect:



SELECT column_name, 
(SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM main_apirequest LIMIT 1)
FROM information_schema.columns
WHERE table_schema = 'public' AND table_name = 'main_apirequest'
GROUP BY 1;


It looks something like this:



   column_name    | pg_size_pretty
------------------+----------------
api_key_id | 11 bytes
id | 3 bytes
...


When it should be something like this (which doesn't happen because of the limit 1)



=> SELECT pg_size_pretty(sum(pg_column_size(id))) FROM main_apirequest
;
pg_size_pretty
----------------
19 MB









share|improve this question
















I'm trying to get the column size for each row in a table. That's basically the combination of these two queries:



SELECT pg_size_pretty(sum(pg_column_size(COLUMN_NAME))) FROM TABLE_NAME;


And



SELECT column_name FROM information_schema.columns WHERE table_schema = 'public' AND table_name = 'TABLE_NAME';


My first attempt was to do these two queries:



 => SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME)  FROM information_schema.columns WHERE table_schema = 'public' AND table_name   = 'TABLE_NAME';
ERROR: column "columns.column_name" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_siz...
^
=> SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME) FROM information_schema.columns WHERE table_schema = 'public' AND table_name = 'TABLE_NAME' GROUP BY column_name;
ERROR: more than one row returned by a subquery used as an expression


Tried the following too:



SELECT column_name, (SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM TABLE_NAME)  FROM information_schema.columns WHERE table_schema = 'public' AND table_name   = 'TABLE_NAME' GROUP BY 1;


Which returned:



ERROR:  more than one row returned by a subquery used as an expression


When I add a LIMIT 1, the result is incorrect:



SELECT column_name, 
(SELECT pg_size_pretty(sum(pg_column_size(column_name))) FROM main_apirequest LIMIT 1)
FROM information_schema.columns
WHERE table_schema = 'public' AND table_name = 'main_apirequest'
GROUP BY 1;


It looks something like this:



   column_name    | pg_size_pretty
------------------+----------------
api_key_id | 11 bytes
id | 3 bytes
...


When it should be something like this (which doesn't happen because of the limit 1)



=> SELECT pg_size_pretty(sum(pg_column_size(id))) FROM main_apirequest
;
pg_size_pretty
----------------
19 MB






postgresql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 19:43







Jorge Silva

















asked Nov 24 '18 at 19:32









Jorge SilvaJorge Silva

3,8911228




3,8911228








  • 1





    Since you don't know the column names in advance, you will have to use dynamic sql.

    – 404
    Nov 24 '18 at 19:48











  • Ok, cool. Will look into that

    – Jorge Silva
    Nov 24 '18 at 19:51














  • 1





    Since you don't know the column names in advance, you will have to use dynamic sql.

    – 404
    Nov 24 '18 at 19:48











  • Ok, cool. Will look into that

    – Jorge Silva
    Nov 24 '18 at 19:51








1




1





Since you don't know the column names in advance, you will have to use dynamic sql.

– 404
Nov 24 '18 at 19:48





Since you don't know the column names in advance, you will have to use dynamic sql.

– 404
Nov 24 '18 at 19:48













Ok, cool. Will look into that

– Jorge Silva
Nov 24 '18 at 19:51





Ok, cool. Will look into that

– Jorge Silva
Nov 24 '18 at 19:51












1 Answer
1






active

oldest

votes


















1














Since you don't know the columns names in advance, but want to use the column name in the query, you'll have to use dynamic sql. Here's a quick example:



CREATE TABLE t1 (id INTEGER, txt TEXT);

INSERT INTO t1
SELECT g, random()::TEXT
FROM generate_series(1, 10) g;


Then the SQL to generate the query is:



DO $$
DECLARE
query TEXT;
BEGIN
SELECT 'SELECT ' || STRING_AGG(FORMAT('sum(pg_column_size(%1$I)) AS %1$s', column_name), ', ') || ' FROM t1'
INTO query
FROM information_schema.columns
WHERE table_schema = 'public'
AND table_name = 't1';

RAISE NOTICE '%', query;
END $$


The query created is SELECT pg_size_pretty(sum(pg_column_size(id))) AS id, pg_size_pretty(sum(pg_column_size(txt))) AS txt FROM t1



Would work the same if you had hundreds of columns.



Now to get it to generate and run the query and return you results, it really depends on what you want. If you're happy just having it print to the screen, then maybe you can format it like this instead:



DO $$
DECLARE
query TEXT;
result TEXT;
BEGIN
SELECT 'SELECT CONCAT_WS(E''n'', ' || STRING_AGG(FORMAT('''%1$s: '' || pg_size_pretty(sum(pg_column_size(%1$I)))', column_name), ', ') || ') FROM t1'
INTO query
FROM information_schema.columns
WHERE table_schema = 'public'
AND table_name = 't1';

EXECUTE query
INTO result;

RAISE NOTICE '%', result;
END $$


That prints:



id: 40 bytes
txt: 181 bytes


If instead you want a record returned with multiple columns, I'm not too sure how you'd go about it because the number of columns and their names would be unknown. Best hack I can think around it would be to return it as JSON, then you return just one thing and there will be a variable number of fields in there with whatever column names:



CREATE OR REPLACE FUNCTION test1(_schema_name TEXT, _table_name TEXT)
RETURNS JSON AS
$$
DECLARE
query TEXT;
result JSON;
BEGIN
SELECT 'SELECT ROW_TO_JSON(cols) FROM (SELECT ' || STRING_AGG(FORMAT('pg_size_pretty(sum(pg_column_size(%1$I))) AS %1$s', column_name), ', ') || ' FROM t1) AS cols'
INTO query
FROM information_schema.columns
WHERE table_schema = _schema_name
AND table_name = _table_name;

EXECUTE query
INTO result;

RETURN result;
END
$$
LANGUAGE plpgsql;


Running it: SELECT test1('public', 't1')



Returns: {"id":"40 bytes","txt":"181 bytes"}






share|improve this answer

























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    active

    oldest

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    1














    Since you don't know the columns names in advance, but want to use the column name in the query, you'll have to use dynamic sql. Here's a quick example:



    CREATE TABLE t1 (id INTEGER, txt TEXT);

    INSERT INTO t1
    SELECT g, random()::TEXT
    FROM generate_series(1, 10) g;


    Then the SQL to generate the query is:



    DO $$
    DECLARE
    query TEXT;
    BEGIN
    SELECT 'SELECT ' || STRING_AGG(FORMAT('sum(pg_column_size(%1$I)) AS %1$s', column_name), ', ') || ' FROM t1'
    INTO query
    FROM information_schema.columns
    WHERE table_schema = 'public'
    AND table_name = 't1';

    RAISE NOTICE '%', query;
    END $$


    The query created is SELECT pg_size_pretty(sum(pg_column_size(id))) AS id, pg_size_pretty(sum(pg_column_size(txt))) AS txt FROM t1



    Would work the same if you had hundreds of columns.



    Now to get it to generate and run the query and return you results, it really depends on what you want. If you're happy just having it print to the screen, then maybe you can format it like this instead:



    DO $$
    DECLARE
    query TEXT;
    result TEXT;
    BEGIN
    SELECT 'SELECT CONCAT_WS(E''n'', ' || STRING_AGG(FORMAT('''%1$s: '' || pg_size_pretty(sum(pg_column_size(%1$I)))', column_name), ', ') || ') FROM t1'
    INTO query
    FROM information_schema.columns
    WHERE table_schema = 'public'
    AND table_name = 't1';

    EXECUTE query
    INTO result;

    RAISE NOTICE '%', result;
    END $$


    That prints:



    id: 40 bytes
    txt: 181 bytes


    If instead you want a record returned with multiple columns, I'm not too sure how you'd go about it because the number of columns and their names would be unknown. Best hack I can think around it would be to return it as JSON, then you return just one thing and there will be a variable number of fields in there with whatever column names:



    CREATE OR REPLACE FUNCTION test1(_schema_name TEXT, _table_name TEXT)
    RETURNS JSON AS
    $$
    DECLARE
    query TEXT;
    result JSON;
    BEGIN
    SELECT 'SELECT ROW_TO_JSON(cols) FROM (SELECT ' || STRING_AGG(FORMAT('pg_size_pretty(sum(pg_column_size(%1$I))) AS %1$s', column_name), ', ') || ' FROM t1) AS cols'
    INTO query
    FROM information_schema.columns
    WHERE table_schema = _schema_name
    AND table_name = _table_name;

    EXECUTE query
    INTO result;

    RETURN result;
    END
    $$
    LANGUAGE plpgsql;


    Running it: SELECT test1('public', 't1')



    Returns: {"id":"40 bytes","txt":"181 bytes"}






    share|improve this answer






























      1














      Since you don't know the columns names in advance, but want to use the column name in the query, you'll have to use dynamic sql. Here's a quick example:



      CREATE TABLE t1 (id INTEGER, txt TEXT);

      INSERT INTO t1
      SELECT g, random()::TEXT
      FROM generate_series(1, 10) g;


      Then the SQL to generate the query is:



      DO $$
      DECLARE
      query TEXT;
      BEGIN
      SELECT 'SELECT ' || STRING_AGG(FORMAT('sum(pg_column_size(%1$I)) AS %1$s', column_name), ', ') || ' FROM t1'
      INTO query
      FROM information_schema.columns
      WHERE table_schema = 'public'
      AND table_name = 't1';

      RAISE NOTICE '%', query;
      END $$


      The query created is SELECT pg_size_pretty(sum(pg_column_size(id))) AS id, pg_size_pretty(sum(pg_column_size(txt))) AS txt FROM t1



      Would work the same if you had hundreds of columns.



      Now to get it to generate and run the query and return you results, it really depends on what you want. If you're happy just having it print to the screen, then maybe you can format it like this instead:



      DO $$
      DECLARE
      query TEXT;
      result TEXT;
      BEGIN
      SELECT 'SELECT CONCAT_WS(E''n'', ' || STRING_AGG(FORMAT('''%1$s: '' || pg_size_pretty(sum(pg_column_size(%1$I)))', column_name), ', ') || ') FROM t1'
      INTO query
      FROM information_schema.columns
      WHERE table_schema = 'public'
      AND table_name = 't1';

      EXECUTE query
      INTO result;

      RAISE NOTICE '%', result;
      END $$


      That prints:



      id: 40 bytes
      txt: 181 bytes


      If instead you want a record returned with multiple columns, I'm not too sure how you'd go about it because the number of columns and their names would be unknown. Best hack I can think around it would be to return it as JSON, then you return just one thing and there will be a variable number of fields in there with whatever column names:



      CREATE OR REPLACE FUNCTION test1(_schema_name TEXT, _table_name TEXT)
      RETURNS JSON AS
      $$
      DECLARE
      query TEXT;
      result JSON;
      BEGIN
      SELECT 'SELECT ROW_TO_JSON(cols) FROM (SELECT ' || STRING_AGG(FORMAT('pg_size_pretty(sum(pg_column_size(%1$I))) AS %1$s', column_name), ', ') || ' FROM t1) AS cols'
      INTO query
      FROM information_schema.columns
      WHERE table_schema = _schema_name
      AND table_name = _table_name;

      EXECUTE query
      INTO result;

      RETURN result;
      END
      $$
      LANGUAGE plpgsql;


      Running it: SELECT test1('public', 't1')



      Returns: {"id":"40 bytes","txt":"181 bytes"}






      share|improve this answer




























        1












        1








        1







        Since you don't know the columns names in advance, but want to use the column name in the query, you'll have to use dynamic sql. Here's a quick example:



        CREATE TABLE t1 (id INTEGER, txt TEXT);

        INSERT INTO t1
        SELECT g, random()::TEXT
        FROM generate_series(1, 10) g;


        Then the SQL to generate the query is:



        DO $$
        DECLARE
        query TEXT;
        BEGIN
        SELECT 'SELECT ' || STRING_AGG(FORMAT('sum(pg_column_size(%1$I)) AS %1$s', column_name), ', ') || ' FROM t1'
        INTO query
        FROM information_schema.columns
        WHERE table_schema = 'public'
        AND table_name = 't1';

        RAISE NOTICE '%', query;
        END $$


        The query created is SELECT pg_size_pretty(sum(pg_column_size(id))) AS id, pg_size_pretty(sum(pg_column_size(txt))) AS txt FROM t1



        Would work the same if you had hundreds of columns.



        Now to get it to generate and run the query and return you results, it really depends on what you want. If you're happy just having it print to the screen, then maybe you can format it like this instead:



        DO $$
        DECLARE
        query TEXT;
        result TEXT;
        BEGIN
        SELECT 'SELECT CONCAT_WS(E''n'', ' || STRING_AGG(FORMAT('''%1$s: '' || pg_size_pretty(sum(pg_column_size(%1$I)))', column_name), ', ') || ') FROM t1'
        INTO query
        FROM information_schema.columns
        WHERE table_schema = 'public'
        AND table_name = 't1';

        EXECUTE query
        INTO result;

        RAISE NOTICE '%', result;
        END $$


        That prints:



        id: 40 bytes
        txt: 181 bytes


        If instead you want a record returned with multiple columns, I'm not too sure how you'd go about it because the number of columns and their names would be unknown. Best hack I can think around it would be to return it as JSON, then you return just one thing and there will be a variable number of fields in there with whatever column names:



        CREATE OR REPLACE FUNCTION test1(_schema_name TEXT, _table_name TEXT)
        RETURNS JSON AS
        $$
        DECLARE
        query TEXT;
        result JSON;
        BEGIN
        SELECT 'SELECT ROW_TO_JSON(cols) FROM (SELECT ' || STRING_AGG(FORMAT('pg_size_pretty(sum(pg_column_size(%1$I))) AS %1$s', column_name), ', ') || ' FROM t1) AS cols'
        INTO query
        FROM information_schema.columns
        WHERE table_schema = _schema_name
        AND table_name = _table_name;

        EXECUTE query
        INTO result;

        RETURN result;
        END
        $$
        LANGUAGE plpgsql;


        Running it: SELECT test1('public', 't1')



        Returns: {"id":"40 bytes","txt":"181 bytes"}






        share|improve this answer















        Since you don't know the columns names in advance, but want to use the column name in the query, you'll have to use dynamic sql. Here's a quick example:



        CREATE TABLE t1 (id INTEGER, txt TEXT);

        INSERT INTO t1
        SELECT g, random()::TEXT
        FROM generate_series(1, 10) g;


        Then the SQL to generate the query is:



        DO $$
        DECLARE
        query TEXT;
        BEGIN
        SELECT 'SELECT ' || STRING_AGG(FORMAT('sum(pg_column_size(%1$I)) AS %1$s', column_name), ', ') || ' FROM t1'
        INTO query
        FROM information_schema.columns
        WHERE table_schema = 'public'
        AND table_name = 't1';

        RAISE NOTICE '%', query;
        END $$


        The query created is SELECT pg_size_pretty(sum(pg_column_size(id))) AS id, pg_size_pretty(sum(pg_column_size(txt))) AS txt FROM t1



        Would work the same if you had hundreds of columns.



        Now to get it to generate and run the query and return you results, it really depends on what you want. If you're happy just having it print to the screen, then maybe you can format it like this instead:



        DO $$
        DECLARE
        query TEXT;
        result TEXT;
        BEGIN
        SELECT 'SELECT CONCAT_WS(E''n'', ' || STRING_AGG(FORMAT('''%1$s: '' || pg_size_pretty(sum(pg_column_size(%1$I)))', column_name), ', ') || ') FROM t1'
        INTO query
        FROM information_schema.columns
        WHERE table_schema = 'public'
        AND table_name = 't1';

        EXECUTE query
        INTO result;

        RAISE NOTICE '%', result;
        END $$


        That prints:



        id: 40 bytes
        txt: 181 bytes


        If instead you want a record returned with multiple columns, I'm not too sure how you'd go about it because the number of columns and their names would be unknown. Best hack I can think around it would be to return it as JSON, then you return just one thing and there will be a variable number of fields in there with whatever column names:



        CREATE OR REPLACE FUNCTION test1(_schema_name TEXT, _table_name TEXT)
        RETURNS JSON AS
        $$
        DECLARE
        query TEXT;
        result JSON;
        BEGIN
        SELECT 'SELECT ROW_TO_JSON(cols) FROM (SELECT ' || STRING_AGG(FORMAT('pg_size_pretty(sum(pg_column_size(%1$I))) AS %1$s', column_name), ', ') || ' FROM t1) AS cols'
        INTO query
        FROM information_schema.columns
        WHERE table_schema = _schema_name
        AND table_name = _table_name;

        EXECUTE query
        INTO result;

        RETURN result;
        END
        $$
        LANGUAGE plpgsql;


        Running it: SELECT test1('public', 't1')



        Returns: {"id":"40 bytes","txt":"181 bytes"}







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 24 '18 at 20:25

























        answered Nov 24 '18 at 20:20









        404404

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            A CLEAN and SIMPLE way to add appendices to Table of Contents and bookmarks