Error when generating dictionary from 2 lists

-1

I have some code that takes a string input,
translates it to a list of integers using a dictionary
then generates a dict from that list and a list of the alphabet
(I would like to use the alphabet list as the key)

alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','p','q','r',

            's','t','u','v','w','x','y','z',' ','.','-','-',',','!','?']



def gen_dict() :

    key_dict = {'a':'00', 'b':'01', 'c':'02', 'd':'03', 'e':'04', 'f':'05',

                'g':'06', 'h':'07', 'i':'08', 'j':'09', 'k':'10', 'l':'11',

                'm':'12', 'n':'13', 'o':'14', 'p':'15', 'q':'16', 'r':'17',

                's':'18', 't':'19', 'u':'20', 'v':'21', 'w':'22', 'x':'23',

                'y':'24', 'z':'25', ' ':'26', '.':'27', '-':'28', ',':'29',

                '!':'30', '?':'31'}

    print(key_dict)

    p= 0

    key = key.lower()

    for character in key:

        keyint.append(key_dict[message[p]])

        p += 1

    letter-num_dict = {k:v for k,v in zip(alphabet,keyint)}

    print(letter-num_dict)  

key = input()

gen_dict()

but the program won't even run,
instead it gives the error message:

letter-num_dict = {k:v for k,v in zip(alphabet,keyint)}
^ SyntaxError: can't assign to operator

I couldn't find anything else online getting this error message for similar reasons so any help is appreciated.

edited Nov 24 '18 at 14:53

petezurich

3,50581734

asked Nov 24 '18 at 13:59

LokiTheGAMER

163

Please use the Preview to check if your question looks alright before posting it. (It does not. You need to format your code correctly.)

– usr2564301
Nov 24 '18 at 14:01

Python cannot use variable names with an operator in them: letter-num_dict is as invalid as, say, 10 or a+b, for a variable name.

– usr2564301
Nov 24 '18 at 14:02

add a comment |

-1

alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','p','q','r',

            's','t','u','v','w','x','y','z',' ','.','-','-',',','!','?']



def gen_dict() :

    key_dict = {'a':'00', 'b':'01', 'c':'02', 'd':'03', 'e':'04', 'f':'05',

                'g':'06', 'h':'07', 'i':'08', 'j':'09', 'k':'10', 'l':'11',

                'm':'12', 'n':'13', 'o':'14', 'p':'15', 'q':'16', 'r':'17',

                's':'18', 't':'19', 'u':'20', 'v':'21', 'w':'22', 'x':'23',

                'y':'24', 'z':'25', ' ':'26', '.':'27', '-':'28', ',':'29',

                '!':'30', '?':'31'}

    print(key_dict)

    p= 0

    key = key.lower()

    for character in key:

        keyint.append(key_dict[message[p]])

        p += 1

    letter-num_dict = {k:v for k,v in zip(alphabet,keyint)}

    print(letter-num_dict)  

key = input()

gen_dict()

but the program won't even run,
instead it gives the error message:

letter-num_dict = {k:v for k,v in zip(alphabet,keyint)}
^ SyntaxError: can't assign to operator

I couldn't find anything else online getting this error message for similar reasons so any help is appreciated.

edited Nov 24 '18 at 14:53

petezurich

3,50581734

asked Nov 24 '18 at 13:59

LokiTheGAMER

163

Please use the Preview to check if your question looks alright before posting it. (It does not. You need to format your code correctly.)

– usr2564301
Nov 24 '18 at 14:01

Python cannot use variable names with an operator in them: letter-num_dict is as invalid as, say, 10 or a+b, for a variable name.

– usr2564301
Nov 24 '18 at 14:02

add a comment |

-1

alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','p','q','r',

            's','t','u','v','w','x','y','z',' ','.','-','-',',','!','?']



def gen_dict() :

    key_dict = {'a':'00', 'b':'01', 'c':'02', 'd':'03', 'e':'04', 'f':'05',

                'g':'06', 'h':'07', 'i':'08', 'j':'09', 'k':'10', 'l':'11',

                'm':'12', 'n':'13', 'o':'14', 'p':'15', 'q':'16', 'r':'17',

                's':'18', 't':'19', 'u':'20', 'v':'21', 'w':'22', 'x':'23',

                'y':'24', 'z':'25', ' ':'26', '.':'27', '-':'28', ',':'29',

                '!':'30', '?':'31'}

    print(key_dict)

    p= 0

    key = key.lower()

    for character in key:

        keyint.append(key_dict[message[p]])

        p += 1

    letter-num_dict = {k:v for k,v in zip(alphabet,keyint)}

    print(letter-num_dict)  

key = input()

gen_dict()

but the program won't even run,
instead it gives the error message:

letter-num_dict = {k:v for k,v in zip(alphabet,keyint)}
^ SyntaxError: can't assign to operator

I couldn't find anything else online getting this error message for similar reasons so any help is appreciated.

edited Nov 24 '18 at 14:53

petezurich

3,50581734

asked Nov 24 '18 at 13:59

LokiTheGAMER

163

alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','p','q','r',

            's','t','u','v','w','x','y','z',' ','.','-','-',',','!','?']



def gen_dict() :

    key_dict = {'a':'00', 'b':'01', 'c':'02', 'd':'03', 'e':'04', 'f':'05',

                'g':'06', 'h':'07', 'i':'08', 'j':'09', 'k':'10', 'l':'11',

                'm':'12', 'n':'13', 'o':'14', 'p':'15', 'q':'16', 'r':'17',

                's':'18', 't':'19', 'u':'20', 'v':'21', 'w':'22', 'x':'23',

                'y':'24', 'z':'25', ' ':'26', '.':'27', '-':'28', ',':'29',

                '!':'30', '?':'31'}

    print(key_dict)

    p= 0

    key = key.lower()

    for character in key:

        keyint.append(key_dict[message[p]])

        p += 1

    letter-num_dict = {k:v for k,v in zip(alphabet,keyint)}

    print(letter-num_dict)  

key = input()

gen_dict()

but the program won't even run,
instead it gives the error message:

letter-num_dict = {k:v for k,v in zip(alphabet,keyint)}
^ SyntaxError: can't assign to operator

I couldn't find anything else online getting this error message for similar reasons so any help is appreciated.

python list dictionary syntax-error assignment-operator

edited Nov 24 '18 at 14:53

petezurich

3,50581734

asked Nov 24 '18 at 13:59

LokiTheGAMER

163

edited Nov 24 '18 at 14:53

petezurich

3,50581734

asked Nov 24 '18 at 13:59

LokiTheGAMER

163

edited Nov 24 '18 at 14:53

petezurich

3,50581734

edited Nov 24 '18 at 14:53

petezurich

3,50581734

edited Nov 24 '18 at 14:53

petezurich

3,50581734

asked Nov 24 '18 at 13:59

LokiTheGAMER

163

asked Nov 24 '18 at 13:59

LokiTheGAMER

163

asked Nov 24 '18 at 13:59

LokiTheGAMER

163

Please use the Preview to check if your question looks alright before posting it. (It does not. You need to format your code correctly.)

– usr2564301
Nov 24 '18 at 14:01

Python cannot use variable names with an operator in them: letter-num_dict is as invalid as, say, 10 or a+b, for a variable name.

– usr2564301
Nov 24 '18 at 14:02

add a comment |

Please use the Preview to check if your question looks alright before posting it. (It does not. You need to format your code correctly.)

– usr2564301
Nov 24 '18 at 14:01

Python cannot use variable names with an operator in them: letter-num_dict is as invalid as, say, 10 or a+b, for a variable name.

– usr2564301
Nov 24 '18 at 14:02

Please use the Preview to check if your question looks alright before posting it. (It does not. You need to format your code correctly.)

– usr2564301
Nov 24 '18 at 14:01

Python cannot use variable names with an operator in them: letter-num_dict is as invalid as, say, 10 or a+b, for a variable name.

– usr2564301
Nov 24 '18 at 14:02

add a comment |

2 Answers
2

active

oldest

votes

You can't use hyphens in variable names.

Change letter-num_dict to letter_num_dict (or equivalent).

answered Nov 24 '18 at 14:02

Joe Iddon

15k31538

add a comment |

Variables cannot have a dash (-) as a part of the name, as Python interprets that as the minus operator. Change it to an underscore instead: letter_num_dict

answered Nov 24 '18 at 14:02

Jonah Bishop

8,76233057

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

You can't use hyphens in variable names.

Change letter-num_dict to letter_num_dict (or equivalent).

answered Nov 24 '18 at 14:02

Joe Iddon

15k31538

add a comment |

You can't use hyphens in variable names.

Change letter-num_dict to letter_num_dict (or equivalent).

answered Nov 24 '18 at 14:02

Joe Iddon

15k31538

add a comment |

You can't use hyphens in variable names.

Change letter-num_dict to letter_num_dict (or equivalent).

answered Nov 24 '18 at 14:02

Joe Iddon

15k31538

You can't use hyphens in variable names.

Change letter-num_dict to letter_num_dict (or equivalent).

answered Nov 24 '18 at 14:02

Joe Iddon

15k31538

answered Nov 24 '18 at 14:02

Joe Iddon

15k31538

answered Nov 24 '18 at 14:02

Joe Iddon

15k31538

answered Nov 24 '18 at 14:02

Joe Iddon

15k31538

add a comment |

Variables cannot have a dash (-) as a part of the name, as Python interprets that as the minus operator. Change it to an underscore instead: letter_num_dict

answered Nov 24 '18 at 14:02

Jonah Bishop

8,76233057

add a comment |

Variables cannot have a dash (-) as a part of the name, as Python interprets that as the minus operator. Change it to an underscore instead: letter_num_dict

answered Nov 24 '18 at 14:02

Jonah Bishop

8,76233057

add a comment |

Variables cannot have a dash (-) as a part of the name, as Python interprets that as the minus operator. Change it to an underscore instead: letter_num_dict

answered Nov 24 '18 at 14:02

Jonah Bishop

8,76233057

Variables cannot have a dash (-) as a part of the name, as Python interprets that as the minus operator. Change it to an underscore instead: letter_num_dict

answered Nov 24 '18 at 14:02

Jonah Bishop

8,76233057

answered Nov 24 '18 at 14:02

Jonah Bishop

8,76233057

answered Nov 24 '18 at 14:02

Jonah Bishop

8,76233057

answered Nov 24 '18 at 14:02

Jonah Bishop

8,76233057

add a comment |

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