How can I create a new Xamarin Element based on a Frame with a StackLayout inside of it?
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I have a Frame with a StackLayout inside of it:
<Frame CornerRadius="1" HasShadow="false" Margin="10"
BackgroundColor="White" BorderColor="Silver" Padding="0" >
<StackLayout Orientation="Vertical" Spacing="0" Padding="0" >
<xaml:PtiXaml />
<template:LineTemplate />
<xaml:AtiXaml />
<template:LineTemplate />
<xaml:StiXaml />
</StackLayout>
</Frame>
Can I create a new object called NewFrame that is the same as the Frame with the StackLayout inside?
<template:NewFrame>
<xaml:PtiXaml />
<template:LineTemplate />
<xaml:AtiXaml />
<template:LineTemplate />
<xaml:StiXaml />
</template:NewFrame>
or
<template:NewFrame>
<xaml:ABCXaml />
</template:NewFrame>
or
<template:NewFrame>
<Label Text="X" />
</template:NewFrame>
It was suggested I use a Custom View but I have looked and can not find an example of this where it contains other elements inside.
xamarin xamarin.forms
add a comment |
up vote
0
down vote
favorite
I have a Frame with a StackLayout inside of it:
<Frame CornerRadius="1" HasShadow="false" Margin="10"
BackgroundColor="White" BorderColor="Silver" Padding="0" >
<StackLayout Orientation="Vertical" Spacing="0" Padding="0" >
<xaml:PtiXaml />
<template:LineTemplate />
<xaml:AtiXaml />
<template:LineTemplate />
<xaml:StiXaml />
</StackLayout>
</Frame>
Can I create a new object called NewFrame that is the same as the Frame with the StackLayout inside?
<template:NewFrame>
<xaml:PtiXaml />
<template:LineTemplate />
<xaml:AtiXaml />
<template:LineTemplate />
<xaml:StiXaml />
</template:NewFrame>
or
<template:NewFrame>
<xaml:ABCXaml />
</template:NewFrame>
or
<template:NewFrame>
<Label Text="X" />
</template:NewFrame>
It was suggested I use a Custom View but I have looked and can not find an example of this where it contains other elements inside.
xamarin xamarin.forms
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a Frame with a StackLayout inside of it:
<Frame CornerRadius="1" HasShadow="false" Margin="10"
BackgroundColor="White" BorderColor="Silver" Padding="0" >
<StackLayout Orientation="Vertical" Spacing="0" Padding="0" >
<xaml:PtiXaml />
<template:LineTemplate />
<xaml:AtiXaml />
<template:LineTemplate />
<xaml:StiXaml />
</StackLayout>
</Frame>
Can I create a new object called NewFrame that is the same as the Frame with the StackLayout inside?
<template:NewFrame>
<xaml:PtiXaml />
<template:LineTemplate />
<xaml:AtiXaml />
<template:LineTemplate />
<xaml:StiXaml />
</template:NewFrame>
or
<template:NewFrame>
<xaml:ABCXaml />
</template:NewFrame>
or
<template:NewFrame>
<Label Text="X" />
</template:NewFrame>
It was suggested I use a Custom View but I have looked and can not find an example of this where it contains other elements inside.
xamarin xamarin.forms
I have a Frame with a StackLayout inside of it:
<Frame CornerRadius="1" HasShadow="false" Margin="10"
BackgroundColor="White" BorderColor="Silver" Padding="0" >
<StackLayout Orientation="Vertical" Spacing="0" Padding="0" >
<xaml:PtiXaml />
<template:LineTemplate />
<xaml:AtiXaml />
<template:LineTemplate />
<xaml:StiXaml />
</StackLayout>
</Frame>
Can I create a new object called NewFrame that is the same as the Frame with the StackLayout inside?
<template:NewFrame>
<xaml:PtiXaml />
<template:LineTemplate />
<xaml:AtiXaml />
<template:LineTemplate />
<xaml:StiXaml />
</template:NewFrame>
or
<template:NewFrame>
<xaml:ABCXaml />
</template:NewFrame>
or
<template:NewFrame>
<Label Text="X" />
</template:NewFrame>
It was suggested I use a Custom View but I have looked and can not find an example of this where it contains other elements inside.
xamarin xamarin.forms
xamarin xamarin.forms
asked Nov 22 at 0:10
Alan2
1,30854131250
1,30854131250
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add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
Right-Click at the desired position in your Shared Project (or PCL) in your Solution Explorer (I would recommend adding a folder named "Views" or "CustomViews" and creating the item inside that folder), select "Add new item" and choose "Content View" (without (C#) behind it. The filename should be something like "View1.xaml", you can change that due to your liking, however the important thing is that the xaml extension is there.
This will create a new ContentView with a xaml and xaml.cs file.
Inside the xaml file you can declare your xaml code posted above and write any code necessary into the xaml.cs file.
Now you can add a namespace declaration to the page you want to put your view into:
<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
...
xmlns:customs="clr-namespace:YourNamespace.Views;assembly=YourNamespace"
and declare the element in that Page's or any layout's content:
<customs:CustomViewName ... />
If you want to be able to control the element's behaviour you can add BindableProperties in the codebehind.
For more in-depth information on that, you might want to take a look into this article: https://visualstudiomagazine.com/articles/2017/10/01/add-custom-controls.aspx
The problem for me is that it's just a Frame and there are different XAML codes inside the frame. Not just one same set of XAML. Do you know how I can deal with that?
– Alan2
Nov 22 at 11:23
No, I don't see any good way to do that. You could create multiple classes, each for every variation
– Markus Michel
Nov 22 at 11:25
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Right-Click at the desired position in your Shared Project (or PCL) in your Solution Explorer (I would recommend adding a folder named "Views" or "CustomViews" and creating the item inside that folder), select "Add new item" and choose "Content View" (without (C#) behind it. The filename should be something like "View1.xaml", you can change that due to your liking, however the important thing is that the xaml extension is there.
This will create a new ContentView with a xaml and xaml.cs file.
Inside the xaml file you can declare your xaml code posted above and write any code necessary into the xaml.cs file.
Now you can add a namespace declaration to the page you want to put your view into:
<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
...
xmlns:customs="clr-namespace:YourNamespace.Views;assembly=YourNamespace"
and declare the element in that Page's or any layout's content:
<customs:CustomViewName ... />
If you want to be able to control the element's behaviour you can add BindableProperties in the codebehind.
For more in-depth information on that, you might want to take a look into this article: https://visualstudiomagazine.com/articles/2017/10/01/add-custom-controls.aspx
The problem for me is that it's just a Frame and there are different XAML codes inside the frame. Not just one same set of XAML. Do you know how I can deal with that?
– Alan2
Nov 22 at 11:23
No, I don't see any good way to do that. You could create multiple classes, each for every variation
– Markus Michel
Nov 22 at 11:25
add a comment |
up vote
0
down vote
Right-Click at the desired position in your Shared Project (or PCL) in your Solution Explorer (I would recommend adding a folder named "Views" or "CustomViews" and creating the item inside that folder), select "Add new item" and choose "Content View" (without (C#) behind it. The filename should be something like "View1.xaml", you can change that due to your liking, however the important thing is that the xaml extension is there.
This will create a new ContentView with a xaml and xaml.cs file.
Inside the xaml file you can declare your xaml code posted above and write any code necessary into the xaml.cs file.
Now you can add a namespace declaration to the page you want to put your view into:
<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
...
xmlns:customs="clr-namespace:YourNamespace.Views;assembly=YourNamespace"
and declare the element in that Page's or any layout's content:
<customs:CustomViewName ... />
If you want to be able to control the element's behaviour you can add BindableProperties in the codebehind.
For more in-depth information on that, you might want to take a look into this article: https://visualstudiomagazine.com/articles/2017/10/01/add-custom-controls.aspx
The problem for me is that it's just a Frame and there are different XAML codes inside the frame. Not just one same set of XAML. Do you know how I can deal with that?
– Alan2
Nov 22 at 11:23
No, I don't see any good way to do that. You could create multiple classes, each for every variation
– Markus Michel
Nov 22 at 11:25
add a comment |
up vote
0
down vote
up vote
0
down vote
Right-Click at the desired position in your Shared Project (or PCL) in your Solution Explorer (I would recommend adding a folder named "Views" or "CustomViews" and creating the item inside that folder), select "Add new item" and choose "Content View" (without (C#) behind it. The filename should be something like "View1.xaml", you can change that due to your liking, however the important thing is that the xaml extension is there.
This will create a new ContentView with a xaml and xaml.cs file.
Inside the xaml file you can declare your xaml code posted above and write any code necessary into the xaml.cs file.
Now you can add a namespace declaration to the page you want to put your view into:
<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
...
xmlns:customs="clr-namespace:YourNamespace.Views;assembly=YourNamespace"
and declare the element in that Page's or any layout's content:
<customs:CustomViewName ... />
If you want to be able to control the element's behaviour you can add BindableProperties in the codebehind.
For more in-depth information on that, you might want to take a look into this article: https://visualstudiomagazine.com/articles/2017/10/01/add-custom-controls.aspx
Right-Click at the desired position in your Shared Project (or PCL) in your Solution Explorer (I would recommend adding a folder named "Views" or "CustomViews" and creating the item inside that folder), select "Add new item" and choose "Content View" (without (C#) behind it. The filename should be something like "View1.xaml", you can change that due to your liking, however the important thing is that the xaml extension is there.
This will create a new ContentView with a xaml and xaml.cs file.
Inside the xaml file you can declare your xaml code posted above and write any code necessary into the xaml.cs file.
Now you can add a namespace declaration to the page you want to put your view into:
<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
...
xmlns:customs="clr-namespace:YourNamespace.Views;assembly=YourNamespace"
and declare the element in that Page's or any layout's content:
<customs:CustomViewName ... />
If you want to be able to control the element's behaviour you can add BindableProperties in the codebehind.
For more in-depth information on that, you might want to take a look into this article: https://visualstudiomagazine.com/articles/2017/10/01/add-custom-controls.aspx
answered Nov 22 at 11:05
Markus Michel
1,402214
1,402214
The problem for me is that it's just a Frame and there are different XAML codes inside the frame. Not just one same set of XAML. Do you know how I can deal with that?
– Alan2
Nov 22 at 11:23
No, I don't see any good way to do that. You could create multiple classes, each for every variation
– Markus Michel
Nov 22 at 11:25
add a comment |
The problem for me is that it's just a Frame and there are different XAML codes inside the frame. Not just one same set of XAML. Do you know how I can deal with that?
– Alan2
Nov 22 at 11:23
No, I don't see any good way to do that. You could create multiple classes, each for every variation
– Markus Michel
Nov 22 at 11:25
The problem for me is that it's just a Frame and there are different XAML codes inside the frame. Not just one same set of XAML. Do you know how I can deal with that?
– Alan2
Nov 22 at 11:23
The problem for me is that it's just a Frame and there are different XAML codes inside the frame. Not just one same set of XAML. Do you know how I can deal with that?
– Alan2
Nov 22 at 11:23
No, I don't see any good way to do that. You could create multiple classes, each for every variation
– Markus Michel
Nov 22 at 11:25
No, I don't see any good way to do that. You could create multiple classes, each for every variation
– Markus Michel
Nov 22 at 11:25
add a comment |
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