3D graphs and projections
I found this image on a presentation.
I am working on MWE but I was wondering if you had ever come through that type of representation with a projection on the 3d graph ?
It could look quite like TeXexample but impossible to adapt to real data so far. MWE to follow.
The green graph is projected on the 3D graph (transformation) and projected on the axis below.
pgfplots 3d
asked Oct 24 at 0:39
Julien-Elie Taieb
3816
add a comment |
I found this image on a presentation.
I am working on MWE but I was wondering if you had ever come through that type of representation with a projection on the 3d graph ?
It could look quite like TeXexample but impossible to adapt to real data so far. MWE to follow.
The green graph is projected on the 3D graph (transformation) and projected on the axis below.
pgfplots 3d
asked Oct 24 at 0:39
Julien-Elie Taieb
3816
The projection of the red graph (yielding the cyan and blue graphs) is almost trivial: just set the y or z coordinate to zero. What's not trivial is to guess the red graph from your screen shot. So please add an MWE. An example, though in a slightly different context, can be found here. Yet this is unlikely the only example of this kind.
– marmot
Oct 24 at 0:43
add a comment |
I found this image on a presentation.
I am working on MWE but I was wondering if you had ever come through that type of representation with a projection on the 3d graph ?
It could look quite like TeXexample but impossible to adapt to real data so far. MWE to follow.
The green graph is projected on the 3D graph (transformation) and projected on the axis below.
pgfplots 3d
asked Oct 24 at 0:39
Julien-Elie Taieb
3816
I found this image on a presentation.
I am working on MWE but I was wondering if you had ever come through that type of representation with a projection on the 3d graph ?
It could look quite like TeXexample but impossible to adapt to real data so far. MWE to follow.
The green graph is projected on the 3D graph (transformation) and projected on the axis below.
pgfplots 3d
pgfplots 3d
asked Oct 24 at 0:39
Julien-Elie Taieb
3816
asked Oct 24 at 0:39
Julien-Elie Taieb
3816
edited Oct 24 at 11:53
asked Oct 24 at 0:39
Julien-Elie Taieb
3816
asked Oct 24 at 0:39
Julien-Elie Taieb
3816
asked Oct 24 at 0:39
Julien-Elie Taieb
3816
3816
The projection of the red graph (yielding the cyan and blue graphs) is almost trivial: just set the y or z coordinate to zero. What's not trivial is to guess the red graph from your screen shot. So please add an MWE. An example, though in a slightly different context, can be found here. Yet this is unlikely the only example of this kind.
– marmot
Oct 24 at 0:43
add a comment |
The projection of the red graph (yielding the cyan and blue graphs) is almost trivial: just set the y or z coordinate to zero. What's not trivial is to guess the red graph from your screen shot. So please add an MWE. An example, though in a slightly different context, can be found here. Yet this is unlikely the only example of this kind.
– marmot
Oct 24 at 0:43
The projection of the red graph (yielding the cyan and blue graphs) is almost trivial: just set the y or z coordinate to zero. What's not trivial is to guess the red graph from your screen shot. So please add an MWE. An example, though in a slightly different context, can be found here. Yet this is unlikely the only example of this kind.
– marmot
Oct 24 at 0:43
The projection of the red graph (yielding the cyan and blue graphs) is almost trivial: just set the y or z coordinate to zero. What's not trivial is to guess the red graph from your screen shot. So please add an MWE. An example, though in a slightly different context, can be found here. Yet this is unlikely the only example of this kind.
– marmot
Oct 24 at 0:43
add a comment |
1 Answer
1
active
oldest
votes
If you have a function, you can do the projections by, well, projecting the result.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=1.8,declare function={f(x,y)=exp(0.1*y);
g(x)=sin(x*100)+0.2*cos(567*x);}]
begin{axis}[view={45}{40},axis on top,
xlabel=$x$,ylabel=$y$,
mesh/interior colormap name=hot,
colormap/hot]
addplot3[domain=0:5,samples y=1,samples=51,blue] (x,{g(x)},{f(0,-2.5)});
addplot3[domain=0:5,domain y=-2.5:2.5,surf,shader =faceted interp,opacity=0.5]
{f(x,y)};
addplot3[domain=0:5,samples y=1,samples=51] (x,{g(x)},{f(x,g(x))});
addplot3[domain=0:5,samples y=1,samples=51,red] (x,{-2.5},{f(x,g(x))});
end{axis}
end{tikzpicture}
end{document}
answered 42 mins ago
marmot
86.9k499185
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you have a function, you can do the projections by, well, projecting the result.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=1.8,declare function={f(x,y)=exp(0.1*y);
g(x)=sin(x*100)+0.2*cos(567*x);}]
begin{axis}[view={45}{40},axis on top,
xlabel=$x$,ylabel=$y$,
mesh/interior colormap name=hot,
colormap/hot]
addplot3[domain=0:5,samples y=1,samples=51,blue] (x,{g(x)},{f(0,-2.5)});
addplot3[domain=0:5,domain y=-2.5:2.5,surf,shader =faceted interp,opacity=0.5]
{f(x,y)};
addplot3[domain=0:5,samples y=1,samples=51] (x,{g(x)},{f(x,g(x))});
addplot3[domain=0:5,samples y=1,samples=51,red] (x,{-2.5},{f(x,g(x))});
end{axis}
end{tikzpicture}
end{document}
answered 42 mins ago
marmot
86.9k499185
add a comment |
If you have a function, you can do the projections by, well, projecting the result.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=1.8,declare function={f(x,y)=exp(0.1*y);
g(x)=sin(x*100)+0.2*cos(567*x);}]
begin{axis}[view={45}{40},axis on top,
xlabel=$x$,ylabel=$y$,
mesh/interior colormap name=hot,
colormap/hot]
addplot3[domain=0:5,samples y=1,samples=51,blue] (x,{g(x)},{f(0,-2.5)});
addplot3[domain=0:5,domain y=-2.5:2.5,surf,shader =faceted interp,opacity=0.5]
{f(x,y)};
addplot3[domain=0:5,samples y=1,samples=51] (x,{g(x)},{f(x,g(x))});
addplot3[domain=0:5,samples y=1,samples=51,red] (x,{-2.5},{f(x,g(x))});
end{axis}
end{tikzpicture}
end{document}
answered 42 mins ago
marmot
86.9k499185
add a comment |
If you have a function, you can do the projections by, well, projecting the result.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=1.8,declare function={f(x,y)=exp(0.1*y);
g(x)=sin(x*100)+0.2*cos(567*x);}]
begin{axis}[view={45}{40},axis on top,
xlabel=$x$,ylabel=$y$,
mesh/interior colormap name=hot,
colormap/hot]
addplot3[domain=0:5,samples y=1,samples=51,blue] (x,{g(x)},{f(0,-2.5)});
addplot3[domain=0:5,domain y=-2.5:2.5,surf,shader =faceted interp,opacity=0.5]
{f(x,y)};
addplot3[domain=0:5,samples y=1,samples=51] (x,{g(x)},{f(x,g(x))});
addplot3[domain=0:5,samples y=1,samples=51,red] (x,{-2.5},{f(x,g(x))});
end{axis}
end{tikzpicture}
end{document}
answered 42 mins ago
marmot
86.9k499185
If you have a function, you can do the projections by, well, projecting the result.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=1.8,declare function={f(x,y)=exp(0.1*y);
g(x)=sin(x*100)+0.2*cos(567*x);}]
begin{axis}[view={45}{40},axis on top,
xlabel=$x$,ylabel=$y$,
mesh/interior colormap name=hot,
colormap/hot]
addplot3[domain=0:5,samples y=1,samples=51,blue] (x,{g(x)},{f(0,-2.5)});
addplot3[domain=0:5,domain y=-2.5:2.5,surf,shader =faceted interp,opacity=0.5]
{f(x,y)};
addplot3[domain=0:5,samples y=1,samples=51] (x,{g(x)},{f(x,g(x))});
addplot3[domain=0:5,samples y=1,samples=51,red] (x,{-2.5},{f(x,g(x))});
end{axis}
end{tikzpicture}
end{document}
answered 42 mins ago
marmot
86.9k499185
answered 42 mins ago
marmot
86.9k499185
answered 42 mins ago
marmot
86.9k499185
answered 42 mins ago
marmot
86.9k499185
86.9k499185
add a comment |
add a comment |
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The projection of the red graph (yielding the cyan and blue graphs) is almost trivial: just set the y or z coordinate to zero. What's not trivial is to guess the red graph from your screen shot. So please add an MWE. An example, though in a slightly different context, can be found here. Yet this is unlikely the only example of this kind.
– marmot
Oct 24 at 0:43