Why do horizontal matrices look different than multistory matrices?
Multi tool use
3
This isn't necessarily a problem, but I wonder about it every time it occurs in my writing.
Horizontal matrices (or single row matrices) have thinner brackets and are differently put out than other matrices. Even Vertical matrices don't have this uniqueness.
Best shown with an example.
documentclass[10pt,norsk, fleqn]{article}
usepackage[a4paper, margin=1.2cm,includeheadfoot]{geometry}
usepackage{amsmath}
begin{document}
$begin{aligned}
vec{x} '(t) &= textbf{A}vec{x}(t) + textbf{B}vec{u}(t)\
vec{y}(t) &= textbf{C}vec{x}(t) + textbf{D}vec{u}(t)
end{aligned} to
begin{aligned}
dot{textbf{x}} & = begin{bmatrix}
2&1&1\3&-2&-2\1&1&2
end{bmatrix}vec{x} +
begin{bmatrix}
2\1\2
end{bmatrix}vec{u}\
vec{y} & = begin{bmatrix}0&-1&-1end{bmatrix}vec{x}
end{aligned}$
end{document}
amsmath
asked 3 hours ago
E. l4d3E. l4d3
31018
add a comment |
3
This isn't necessarily a problem, but I wonder about it every time it occurs in my writing.
Horizontal matrices (or single row matrices) have thinner brackets and are differently put out than other matrices. Even Vertical matrices don't have this uniqueness.
Best shown with an example.
documentclass[10pt,norsk, fleqn]{article}
usepackage[a4paper, margin=1.2cm,includeheadfoot]{geometry}
usepackage{amsmath}
begin{document}
$begin{aligned}
vec{x} '(t) &= textbf{A}vec{x}(t) + textbf{B}vec{u}(t)\
vec{y}(t) &= textbf{C}vec{x}(t) + textbf{D}vec{u}(t)
end{aligned} to
begin{aligned}
dot{textbf{x}} & = begin{bmatrix}
2&1&1\3&-2&-2\1&1&2
end{bmatrix}vec{x} +
begin{bmatrix}
2\1\2
end{bmatrix}vec{u}\
vec{y} & = begin{bmatrix}0&-1&-1end{bmatrix}vec{x}
end{aligned}$
end{document}
amsmath
asked 3 hours ago
E. l4d3E. l4d3
31018
1
The thickness of the one-line braces and the horizontal positioning is in the font design. It may not be the same with all possible fonts, so trying to "fix" the definition ofbmatrix(and friends) would not be advised. That said, if absolutely perfect alignment is desired, adding (very) small spaces (inmuunits) just before and after the opening bracket and perhaps before the closing bracket should be possible.
– barbara beeton
3 hours ago
add a comment |
3
3
3
This isn't necessarily a problem, but I wonder about it every time it occurs in my writing.
Horizontal matrices (or single row matrices) have thinner brackets and are differently put out than other matrices. Even Vertical matrices don't have this uniqueness.
Best shown with an example.
documentclass[10pt,norsk, fleqn]{article}
usepackage[a4paper, margin=1.2cm,includeheadfoot]{geometry}
usepackage{amsmath}
begin{document}
$begin{aligned}
vec{x} '(t) &= textbf{A}vec{x}(t) + textbf{B}vec{u}(t)\
vec{y}(t) &= textbf{C}vec{x}(t) + textbf{D}vec{u}(t)
end{aligned} to
begin{aligned}
dot{textbf{x}} & = begin{bmatrix}
2&1&1\3&-2&-2\1&1&2
end{bmatrix}vec{x} +
begin{bmatrix}
2\1\2
end{bmatrix}vec{u}\
vec{y} & = begin{bmatrix}0&-1&-1end{bmatrix}vec{x}
end{aligned}$
end{document}
amsmath
asked 3 hours ago
E. l4d3E. l4d3
31018
This isn't necessarily a problem, but I wonder about it every time it occurs in my writing.
Horizontal matrices (or single row matrices) have thinner brackets and are differently put out than other matrices. Even Vertical matrices don't have this uniqueness.
Best shown with an example.
documentclass[10pt,norsk, fleqn]{article}
usepackage[a4paper, margin=1.2cm,includeheadfoot]{geometry}
usepackage{amsmath}
begin{document}
$begin{aligned}
vec{x} '(t) &= textbf{A}vec{x}(t) + textbf{B}vec{u}(t)\
vec{y}(t) &= textbf{C}vec{x}(t) + textbf{D}vec{u}(t)
end{aligned} to
begin{aligned}
dot{textbf{x}} & = begin{bmatrix}
2&1&1\3&-2&-2\1&1&2
end{bmatrix}vec{x} +
begin{bmatrix}
2\1\2
end{bmatrix}vec{u}\
vec{y} & = begin{bmatrix}0&-1&-1end{bmatrix}vec{x}
end{aligned}$
end{document}
amsmath
amsmath
asked 3 hours ago
E. l4d3E. l4d3
31018
asked 3 hours ago
E. l4d3E. l4d3
31018
asked 3 hours ago
E. l4d3E. l4d3
31018
asked 3 hours ago
E. l4d3E. l4d3
31018
asked 3 hours ago
E. l4d3E. l4d3
31018
31018
1
The thickness of the one-line braces and the horizontal positioning is in the font design. It may not be the same with all possible fonts, so trying to "fix" the definition ofbmatrix(and friends) would not be advised. That said, if absolutely perfect alignment is desired, adding (very) small spaces (inmuunits) just before and after the opening bracket and perhaps before the closing bracket should be possible.
– barbara beeton
3 hours ago
add a comment |
1
The thickness of the one-line braces and the horizontal positioning is in the font design. It may not be the same with all possible fonts, so trying to "fix" the definition ofbmatrix(and friends) would not be advised. That said, if absolutely perfect alignment is desired, adding (very) small spaces (inmuunits) just before and after the opening bracket and perhaps before the closing bracket should be possible.
– barbara beeton
3 hours ago
1
1
The thickness of the one-line braces and the horizontal positioning is in the font design. It may not be the same with all possible fonts, so trying to "fix" the definition of
bmatrix (and friends) would not be advised. That said, if absolutely perfect alignment is desired, adding (very) small spaces (in mu units) just before and after the opening bracket and perhaps before the closing bracket should be possible.– barbara beeton
3 hours ago
The thickness of the one-line braces and the horizontal positioning is in the font design. It may not be the same with all possible fonts, so trying to "fix" the definition of
bmatrix (and friends) would not be advised. That said, if absolutely perfect alignment is desired, adding (very) small spaces (in mu units) just before and after the opening bracket and perhaps before the closing bracket should be possible.– barbara beeton
3 hours ago
add a comment |
1 Answer
1
active
oldest
votes
3
The bvector environment was specifically set up to match 1 row to 3 row matrices.
documentclass[10pt,norsk, fleqn]{article}
usepackage[a4paper, margin=1.2cm,includeheadfoot]{geometry}
usepackage{mathtools}
newlength{brackoff}
sbox0{$begin{bmatrix}strutend{bmatrix}$}
sbox1{$begin{bmatrix}strut\strut\strutend{bmatrix}$}
setlength{brackoff}{dimexpr 0.25wd1-0.25wd0}
newenvironment{bvector}%
{hspace{brackoff}begin{bmatrix}hspace{brackoff}}%
{hspace{brackoff}end{bmatrix}hspace{brackoff}}%
begin{document}
$begin{aligned}
vec{x} '(t) &= textbf{A}vec{x}(t) + textbf{B}vec{u}(t)\
vec{y}(t) &= textbf{C}vec{x}(t) + textbf{D}vec{u}(t)
end{aligned} to
begin{aligned}
dot{textbf{x}} & = begin{bmatrix}
2&1&1\3&-2&-2\1&1&2
end{bmatrix}vec{x} +
begin{bmatrix}
2\1\2
end{bmatrix}vec{u}\
vec{y} & = begin{bvector}0&-1&-1end{bvector}vec{x}\
end{aligned}$
end{document}
answered 1 hour ago
John KormyloJohn Kormylo
46k22672
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
The bvector environment was specifically set up to match 1 row to 3 row matrices.
documentclass[10pt,norsk, fleqn]{article}
usepackage[a4paper, margin=1.2cm,includeheadfoot]{geometry}
usepackage{mathtools}
newlength{brackoff}
sbox0{$begin{bmatrix}strutend{bmatrix}$}
sbox1{$begin{bmatrix}strut\strut\strutend{bmatrix}$}
setlength{brackoff}{dimexpr 0.25wd1-0.25wd0}
newenvironment{bvector}%
{hspace{brackoff}begin{bmatrix}hspace{brackoff}}%
{hspace{brackoff}end{bmatrix}hspace{brackoff}}%
begin{document}
$begin{aligned}
vec{x} '(t) &= textbf{A}vec{x}(t) + textbf{B}vec{u}(t)\
vec{y}(t) &= textbf{C}vec{x}(t) + textbf{D}vec{u}(t)
end{aligned} to
begin{aligned}
dot{textbf{x}} & = begin{bmatrix}
2&1&1\3&-2&-2\1&1&2
end{bmatrix}vec{x} +
begin{bmatrix}
2\1\2
end{bmatrix}vec{u}\
vec{y} & = begin{bvector}0&-1&-1end{bvector}vec{x}\
end{aligned}$
end{document}
answered 1 hour ago
John KormyloJohn Kormylo
46k22672
add a comment |
3
The bvector environment was specifically set up to match 1 row to 3 row matrices.
documentclass[10pt,norsk, fleqn]{article}
usepackage[a4paper, margin=1.2cm,includeheadfoot]{geometry}
usepackage{mathtools}
newlength{brackoff}
sbox0{$begin{bmatrix}strutend{bmatrix}$}
sbox1{$begin{bmatrix}strut\strut\strutend{bmatrix}$}
setlength{brackoff}{dimexpr 0.25wd1-0.25wd0}
newenvironment{bvector}%
{hspace{brackoff}begin{bmatrix}hspace{brackoff}}%
{hspace{brackoff}end{bmatrix}hspace{brackoff}}%
begin{document}
$begin{aligned}
vec{x} '(t) &= textbf{A}vec{x}(t) + textbf{B}vec{u}(t)\
vec{y}(t) &= textbf{C}vec{x}(t) + textbf{D}vec{u}(t)
end{aligned} to
begin{aligned}
dot{textbf{x}} & = begin{bmatrix}
2&1&1\3&-2&-2\1&1&2
end{bmatrix}vec{x} +
begin{bmatrix}
2\1\2
end{bmatrix}vec{u}\
vec{y} & = begin{bvector}0&-1&-1end{bvector}vec{x}\
end{aligned}$
end{document}
answered 1 hour ago
John KormyloJohn Kormylo
46k22672
add a comment |
3
3
3
The bvector environment was specifically set up to match 1 row to 3 row matrices.
documentclass[10pt,norsk, fleqn]{article}
usepackage[a4paper, margin=1.2cm,includeheadfoot]{geometry}
usepackage{mathtools}
newlength{brackoff}
sbox0{$begin{bmatrix}strutend{bmatrix}$}
sbox1{$begin{bmatrix}strut\strut\strutend{bmatrix}$}
setlength{brackoff}{dimexpr 0.25wd1-0.25wd0}
newenvironment{bvector}%
{hspace{brackoff}begin{bmatrix}hspace{brackoff}}%
{hspace{brackoff}end{bmatrix}hspace{brackoff}}%
begin{document}
$begin{aligned}
vec{x} '(t) &= textbf{A}vec{x}(t) + textbf{B}vec{u}(t)\
vec{y}(t) &= textbf{C}vec{x}(t) + textbf{D}vec{u}(t)
end{aligned} to
begin{aligned}
dot{textbf{x}} & = begin{bmatrix}
2&1&1\3&-2&-2\1&1&2
end{bmatrix}vec{x} +
begin{bmatrix}
2\1\2
end{bmatrix}vec{u}\
vec{y} & = begin{bvector}0&-1&-1end{bvector}vec{x}\
end{aligned}$
end{document}
answered 1 hour ago
John KormyloJohn Kormylo
46k22672
The bvector environment was specifically set up to match 1 row to 3 row matrices.
documentclass[10pt,norsk, fleqn]{article}
usepackage[a4paper, margin=1.2cm,includeheadfoot]{geometry}
usepackage{mathtools}
newlength{brackoff}
sbox0{$begin{bmatrix}strutend{bmatrix}$}
sbox1{$begin{bmatrix}strut\strut\strutend{bmatrix}$}
setlength{brackoff}{dimexpr 0.25wd1-0.25wd0}
newenvironment{bvector}%
{hspace{brackoff}begin{bmatrix}hspace{brackoff}}%
{hspace{brackoff}end{bmatrix}hspace{brackoff}}%
begin{document}
$begin{aligned}
vec{x} '(t) &= textbf{A}vec{x}(t) + textbf{B}vec{u}(t)\
vec{y}(t) &= textbf{C}vec{x}(t) + textbf{D}vec{u}(t)
end{aligned} to
begin{aligned}
dot{textbf{x}} & = begin{bmatrix}
2&1&1\3&-2&-2\1&1&2
end{bmatrix}vec{x} +
begin{bmatrix}
2\1\2
end{bmatrix}vec{u}\
vec{y} & = begin{bvector}0&-1&-1end{bvector}vec{x}\
end{aligned}$
end{document}
answered 1 hour ago
John KormyloJohn Kormylo
46k22672
edited 59 mins ago
answered 1 hour ago
John KormyloJohn Kormylo
46k22672
answered 1 hour ago
John KormyloJohn Kormylo
46k22672
answered 1 hour ago
John KormyloJohn Kormylo
46k22672
46k22672
add a comment |
add a comment |
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6VaAC8R5pFXUahLT6,PStP8w69gJF7R
1
The thickness of the one-line braces and the horizontal positioning is in the font design. It may not be the same with all possible fonts, so trying to "fix" the definition of
bmatrix(and friends) would not be advised. That said, if absolutely perfect alignment is desired, adding (very) small spaces (inmuunits) just before and after the opening bracket and perhaps before the closing bracket should be possible.– barbara beeton
3 hours ago