pymongo: Get result count
0
Goal: Search DB and get results and count of results.
In previous versions there was .count()
find_results = mycol.find({"source": "sensor"})
count_results = find_results.count()
Now, count() has been deprecated and instead there is "collection.count_documents"
Does that mean that to get results and qty of results I need to do two queries?
count_results = mycol.count_documents({"source": "sensor"})
find_results = mycol.find({"source": "sensor"})
mongodb pymongo
asked Nov 25 '18 at 0:48
Borisw37Borisw37
182214
add a comment |
0
Goal: Search DB and get results and count of results.
In previous versions there was .count()
find_results = mycol.find({"source": "sensor"})
count_results = find_results.count()
Now, count() has been deprecated and instead there is "collection.count_documents"
Does that mean that to get results and qty of results I need to do two queries?
count_results = mycol.count_documents({"source": "sensor"})
find_results = mycol.find({"source": "sensor"})
mongodb pymongo
asked Nov 25 '18 at 0:48
Borisw37Borisw37
182214
Well yes and no. It's deprecated for the very good reason that there are reliability issues, and mostly in order to support transactions. So YES you "should" be using a separate call in order to obtain your count. However NO, you don't actually need to IF you instead have an acceptable result size which could be converted to an Array/List first. Then you can just size the Array/List. For "paging" counts see Get a count of total documents with MongoDB when using limit
– Neil Lunn
Nov 25 '18 at 0:56
add a comment |
0
0
0
Goal: Search DB and get results and count of results.
In previous versions there was .count()
find_results = mycol.find({"source": "sensor"})
count_results = find_results.count()
Now, count() has been deprecated and instead there is "collection.count_documents"
Does that mean that to get results and qty of results I need to do two queries?
count_results = mycol.count_documents({"source": "sensor"})
find_results = mycol.find({"source": "sensor"})
mongodb pymongo
asked Nov 25 '18 at 0:48
Borisw37Borisw37
182214
Goal: Search DB and get results and count of results.
In previous versions there was .count()
find_results = mycol.find({"source": "sensor"})
count_results = find_results.count()
Now, count() has been deprecated and instead there is "collection.count_documents"
Does that mean that to get results and qty of results I need to do two queries?
count_results = mycol.count_documents({"source": "sensor"})
find_results = mycol.find({"source": "sensor"})
mongodb pymongo
mongodb pymongo
asked Nov 25 '18 at 0:48
Borisw37Borisw37
182214
asked Nov 25 '18 at 0:48
Borisw37Borisw37
182214
asked Nov 25 '18 at 0:48
Borisw37Borisw37
182214
asked Nov 25 '18 at 0:48
Borisw37Borisw37
182214
asked Nov 25 '18 at 0:48
Borisw37Borisw37
182214
182214
Well yes and no. It's deprecated for the very good reason that there are reliability issues, and mostly in order to support transactions. So YES you "should" be using a separate call in order to obtain your count. However NO, you don't actually need to IF you instead have an acceptable result size which could be converted to an Array/List first. Then you can just size the Array/List. For "paging" counts see Get a count of total documents with MongoDB when using limit
– Neil Lunn
Nov 25 '18 at 0:56
add a comment |
Well yes and no. It's deprecated for the very good reason that there are reliability issues, and mostly in order to support transactions. So YES you "should" be using a separate call in order to obtain your count. However NO, you don't actually need to IF you instead have an acceptable result size which could be converted to an Array/List first. Then you can just size the Array/List. For "paging" counts see Get a count of total documents with MongoDB when using limit
– Neil Lunn
Nov 25 '18 at 0:56
Well yes and no. It's deprecated for the very good reason that there are reliability issues, and mostly in order to support transactions. So YES you "should" be using a separate call in order to obtain your count. However NO, you don't actually need to IF you instead have an acceptable result size which could be converted to an Array/List first. Then you can just size the Array/List. For "paging" counts see Get a count of total documents with MongoDB when using limit
– Neil Lunn
Nov 25 '18 at 0:56
Well yes and no. It's deprecated for the very good reason that there are reliability issues, and mostly in order to support transactions. So YES you "should" be using a separate call in order to obtain your count. However NO, you don't actually need to IF you instead have an acceptable result size which could be converted to an Array/List first. Then you can just size the Array/List. For "paging" counts see Get a count of total documents with MongoDB when using limit
– Neil Lunn
Nov 25 '18 at 0:56
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53463738%2fpymongo-get-result-count%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53463738%2fpymongo-get-result-count%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Well yes and no. It's deprecated for the very good reason that there are reliability issues, and mostly in order to support transactions. So YES you "should" be using a separate call in order to obtain your count. However NO, you don't actually need to IF you instead have an acceptable result size which could be converted to an Array/List first. Then you can just size the Array/List. For "paging" counts see Get a count of total documents with MongoDB when using limit
– Neil Lunn
Nov 25 '18 at 0:56