Does Spark support BigInteger type?











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I know that old versions of Spark support only BigDecimal type from java.math. But I found this pull request: https://github.com/apache/spark/pull/10125. I tried to use it and I had no problems using BigInteger type. But in the spark documentation there is still no mention BigInteger.
So, can I safely use this type?










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  • BigInteger is 8 bytes numerical value ?
    – Balaji Reddy
    Nov 22 at 9:52






  • 2




    @BalajiReddy - No. It is an arbitrary precision integer type; see javadoc.
    – Stephen C
    Nov 22 at 9:58










  • @Stephen got it
    – Balaji Reddy
    Nov 22 at 10:00






  • 1




    It doesn't. In doubt you call always check type reference (nothing changed in 2.4, but its SQL docs are broken for now). There is bigint identifier in use, but it simply maps to long.
    – user6910411
    Nov 22 at 10:22

















up vote
0
down vote

favorite












I know that old versions of Spark support only BigDecimal type from java.math. But I found this pull request: https://github.com/apache/spark/pull/10125. I tried to use it and I had no problems using BigInteger type. But in the spark documentation there is still no mention BigInteger.
So, can I safely use this type?










share|improve this question
























  • BigInteger is 8 bytes numerical value ?
    – Balaji Reddy
    Nov 22 at 9:52






  • 2




    @BalajiReddy - No. It is an arbitrary precision integer type; see javadoc.
    – Stephen C
    Nov 22 at 9:58










  • @Stephen got it
    – Balaji Reddy
    Nov 22 at 10:00






  • 1




    It doesn't. In doubt you call always check type reference (nothing changed in 2.4, but its SQL docs are broken for now). There is bigint identifier in use, but it simply maps to long.
    – user6910411
    Nov 22 at 10:22















up vote
0
down vote

favorite









up vote
0
down vote

favorite











I know that old versions of Spark support only BigDecimal type from java.math. But I found this pull request: https://github.com/apache/spark/pull/10125. I tried to use it and I had no problems using BigInteger type. But in the spark documentation there is still no mention BigInteger.
So, can I safely use this type?










share|improve this question















I know that old versions of Spark support only BigDecimal type from java.math. But I found this pull request: https://github.com/apache/spark/pull/10125. I tried to use it and I had no problems using BigInteger type. But in the spark documentation there is still no mention BigInteger.
So, can I safely use this type?







java scala apache-spark apache-spark-sql






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share|improve this question













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edited Nov 22 at 9:59

























asked Nov 22 at 8:28









Stanislav Molchanovsky

447116




447116












  • BigInteger is 8 bytes numerical value ?
    – Balaji Reddy
    Nov 22 at 9:52






  • 2




    @BalajiReddy - No. It is an arbitrary precision integer type; see javadoc.
    – Stephen C
    Nov 22 at 9:58










  • @Stephen got it
    – Balaji Reddy
    Nov 22 at 10:00






  • 1




    It doesn't. In doubt you call always check type reference (nothing changed in 2.4, but its SQL docs are broken for now). There is bigint identifier in use, but it simply maps to long.
    – user6910411
    Nov 22 at 10:22




















  • BigInteger is 8 bytes numerical value ?
    – Balaji Reddy
    Nov 22 at 9:52






  • 2




    @BalajiReddy - No. It is an arbitrary precision integer type; see javadoc.
    – Stephen C
    Nov 22 at 9:58










  • @Stephen got it
    – Balaji Reddy
    Nov 22 at 10:00






  • 1




    It doesn't. In doubt you call always check type reference (nothing changed in 2.4, but its SQL docs are broken for now). There is bigint identifier in use, but it simply maps to long.
    – user6910411
    Nov 22 at 10:22


















BigInteger is 8 bytes numerical value ?
– Balaji Reddy
Nov 22 at 9:52




BigInteger is 8 bytes numerical value ?
– Balaji Reddy
Nov 22 at 9:52




2




2




@BalajiReddy - No. It is an arbitrary precision integer type; see javadoc.
– Stephen C
Nov 22 at 9:58




@BalajiReddy - No. It is an arbitrary precision integer type; see javadoc.
– Stephen C
Nov 22 at 9:58












@Stephen got it
– Balaji Reddy
Nov 22 at 10:00




@Stephen got it
– Balaji Reddy
Nov 22 at 10:00




1




1




It doesn't. In doubt you call always check type reference (nothing changed in 2.4, but its SQL docs are broken for now). There is bigint identifier in use, but it simply maps to long.
– user6910411
Nov 22 at 10:22






It doesn't. In doubt you call always check type reference (nothing changed in 2.4, but its SQL docs are broken for now). There is bigint identifier in use, but it simply maps to long.
– user6910411
Nov 22 at 10:22



















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